the conflict is 0.09. Thus, the masses are given by:

mDPCR(A) = 0.14 + 0.21 + 0.21 · 7 18 · 1 6 · 36 13 + 0.14 · 7 16 · 1 6 · 16 5 ≃ 0.420 mDPCR(B) = 0.06 + 0.14 · 5 16 · 1 6 · 16 5 + 0.09 · 5 14 · 1 6 · 56 17 ≃ 0.101 mDPCR(A ∪ C) = 0.09 + 0.21 · 6 18 · 1 6 · 36 13 + 0.09 · 6 14 · 1 6 · 56 17 ≃ 0.143 mDPCR(A ∪ B ∪ C) = 0.21 · 2 3 = 0.14 mDPCR(A ∪ B ∪ C ∪ D) = 0.06 + 0.14 · 4 16 · 1 3 · 16 5 + 0.09 · 3 14 · 1 3 · 56 17 + 0.14 · 1 3 + 0.09 · 1 3 ≃ 0.196
This last rule of combination allows one to consider a "kind of degree" of conflict (a degree of pair of non-conflict), but this degree is not so easy to introduce in the combination rule.

C. A mixed discounting conflict repartition rule In this section, we propose a combination of the mixed rule (35) with the discounting PCR (37). This new mixed discounting conflict repartition rule (MDPCR for short) for two quantitative basic belief assignments m1(.) and m2(.) is defined by mMDPCR(∅**) = 0** and for all X ∈ GΘ, X 6= ∅ by:

mMDPCR(X) = X Y1∪Y2=X, Y1∩Y26≡∅ δ1(Y1, Y2) · m1(Y1)m2(Y2) +X Y1∩Y2=X, Y1∩Y26≡∅ (1 − δ1(Y1, Y2)) · m1(Y1)m2(Y2) Y ∈GΘ, X∩Y ≡∅ α · m1(X) 2m2(Y ) m1(X) + m2(Y ) +m2(X) 2m1(Y ) m2(X) + m1(Y )  +X +X Y1∪Y2=X, Y1∩Y2≡∅ (1 − α) · m1(Y1)m2(Y2). (44)
α can be given by the equation (39) and δ1(**., .**) by the equation (32) or (34). The weights must be taken in order to get a kind of continuity between the mixed and DPCR rules. In actuality, when the intersection of the responses is almost empty
(but not empty) we use the mixed rule, and when this intersection is empty we chose the **DPCR** rule. In the first case, all the mass is transferred on the union, and in the second case it will be the same according to the partial conflict. Indeed, α = 0 if the intersection is not empty and δ1 = 1 if the intersection is empty. We can also introduce αi given by the equation (40),
and this continuity is conserved.

This rule is given in a general case for M experts, by mMDPCR(∅**) = 0** and for all X ∈ GΘ, X 6= ∅ by: