And 

$$m_{CPRH}\left(I_{t}\right)=m_{20}(I_{t})+\sum_{X,Y=0^{\prime}}m_{1}(X)m_{2}(Y)\;.\tag{12}$$ $$\left\{x_{\left[Y\right]\leftrightarrow\phi\left(M\leftrightarrow\phi\;\right.}\sum_{i=0^{\prime}\left(i>0\right)}\right]\right\}$$  These formulas are easily extended for any $s\geq2$ sources $m_{1}(\cdot),m_{2}(\cdot),...,m_{s}(\cdot)\;.$  In the last section the construction of 

Let's denote, using the conjunctive rule: 
enove, using the conjunctive line.  $$m_{s(1)}(A)=\left(m_{1}\oplus m_{2}\oplus...\oplus m_{s}\right)(A)=\sum_{\begin{subarray}{c}x_{1},x_{2},...,x_{n}\in\mathbb{R}^{n}\oplus\\ \bigcap_{i=1}^{n}\mathbb{R}=A\end{subarray}}\prod_{i=1}^{s}m(x_{i})\tag{13}$$

$$m_{CRBM}\left(A\right)=m_{{}_{f1}}(A)+\text{f}(A)\cdot\sum_{\begin{subarray}{c}X_{i},X_{i},\ldots,X_{n}\in\mathcal{F}\\ \left\{\begin{subarray}{c}A_{0}\cdots\left\{\begin{subarray}{c}X_{i}\end{subarray}\right.\text{and}\;A_{i}\subseteq M\end{subarray}}\right\}\\ \text{or}\left\{\begin{subarray}{c}A_{0}\cdots\left\{\begin{subarray}{c}X_{i}\in\overline{S}_{i}^{n_{f}\times n}\text{and}\;A_{i}\subseteq\mathcal{V}\end{subarray}\right\}\end{subarray}\right.\tag{14}$$

where ( ), , and f ⋅ M N are similar to the above where instead of X UY (for two sources) we take 1 2 ... X **U UU** *X Xs* (for s sources), and instead of 2 m X( ) I for two sources we take ( ) m X sI
for s sources. 4. Application and Comparison with other Fusion Rules. 

Let's consider the frame of discernment Θ = {A, B, C}, and two independent sources m1(.) and 

$\rm m_{2}(.)$ that provide the following masses:  \begin{tabular}{l c c c c} A & B & C & AUBUC \\ m${}_{1}$(.) & 0.3 & 0.4 & 0.2 & 0.1 \\ m${}_{2}$(.) & 0.5 & 0.2 & 0.1 & 0.2 \\ \end{tabular}  
Now, we apply the conjunctive rule and we get:  \begin{tabular}{c c c c c c} A & B & C & AUBUC & A$\cap$B & A$\cap$C & B$\cap$C \\ m${}_{12\cap}$(.) & 0.26 & 0.18 & 0.07 & 0.02 & 0.26 & 0.13 & 0.08 \\ \end{tabular}  
Suppose that all intersections are non-empty {this case is called: free DSm (DezertSmarandache) Model}. See below the Venn Diagram using the Smarandache codification [3]: 