2+dx^3$ so
      that $P_3(0)=f(0)$, $P'_3(0)=f'(0)$, $P''_3(0)=f''(0)$, and
      $P'''_3(0)=f'''(0)$. In other words, give me a cubic that
      passes through the same point, has the same slope, the same
      concavity, and the same third derivative as $f(x)=e^x$ does
      at $x=0$.</li>

      <li>Now compute $e^{0.1}$ with a calculator. Then compute
      $P_1(.1)$, $P_2(.1)$, and $P_3(.1)$. How accurate are the
      line, parabola, and cubic in approximating $e^{.1}$?</li>
    </ul>
  </div>

  <di