a ^ 2 \gamma} \gamma 'b' - \frac {1} {2 \beta ^ 2 \gamma} \gamma''b + kb + \frac {2P} {(a + b)} + \frac {\epsilon_x ^ 2} {b ^ 3} \\
 \displaystyle \frac {db} {dz} = y
\end{matrix} \right.\end{split}\]</div>
<p>Let <span class="math notranslate nohighlight">\(\vec X = \begin{bmatrix} x \\ a \\ y \\ b \end{bmatrix}\)</span>, we now compose the differential equation <span class="math notranslate nohighlight">\(X '= F (X).\)</span></p>
</div>
<div class="section" id="Trajectory-equation-for-one-particle">
<h2>