Recall that $\dfrac{z_1}{z_2}=z_1z_2^{-1}.$ Use statement (\ref{arg-product})
                    to show that
                    \[
                    \arg\left(\frac{z_1}{z_2}\right) = \arg\left(z_1\right) -\arg\left(z_2\right).
                    \]
                </p>
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