y\right]) = 0
\]</span> for <span class="math inline">\(\mathrm{E}\left[x_\infty\right]\)</span> using
Newton’s method. This stationary mean is then used to solve <span class="math display">\[
\dfrac{d\mathrm{V}\left[x_\infty\right]}{dt} =
\dfrac{df}{dx}\bigg\vert_{(\mathrm{E}\left[x_\infty\right])}\mathrm{V}\left[x_\infty\right]
+
\mathrm{V}\left[x_\infty\right]\left[\dfrac{df}{dx}\bigg\vert_{(\mathrm{E}\left[x_\infty\right])}\right]^{T}
+
g(\mathrm{E}\left[x_\infty\right])g(\mathrm{E}\left[x_\infty\righ