at are fixed everywhere in the rspace L. Returns {&#39;0&#39;:1} if L is
        a self-contradictory.

    &#34;&#34;&#34;
    fL = [r[0] for r in L if len(r)==1]

    fd = {}
    for d in fL:
        for k,v in d.items():
            if k in fd and fd[k] != v:
                return {&#39;0&#39;:1}
            else:
                fd[k] = v

    imp,con = logical_domain_of_influence(fd,primes)

    if len(con) &gt; 0:
        return {&#39;0&#39;:1}
    fd.update(imp)
    return fd</code></pre>
</details>