%cx(j)%fixeddof((atomidx(1)-1)*3 + i) = .true.</div>
<div class="line"><a name="l00140"></a><span class="lineno">  140</span>&#160;<span class="keywordflow">       enddo</span></div>
<div class="line"><a name="l00141"></a><span class="lineno">  141</span>&#160;       <span class="keywordflow">if</span> (atomidx(2) .ne. 0 ) <span class="keywordflow">then</span></div>
<div class="line"><a name="l00142"></a><span class="lineno">  142</span>&#160;          <span class="keywordflow">do</span> i = 2, 3</div>
<div