pre>
  2/1 J1(1) = 0.880 -&gt; 1.000 (normalized to match fft)
  2/2 J2(2) = 0.353 -&gt; 0.401
  2/3 J3(3) = 0.206 -&gt; 0.234
  2/4 J4(4) = 0.141 -&gt; 0.159
  2/5 J5(5) = 0.104 -&gt; 0.118
  2/6 J6(6) = 0.082 -&gt; 0.093
  2/7 J7(7) = 0.066 -&gt; 0.076
</pre>
</td></tr></table>


<p>Why does the FFT show a 0 Hz component?
Increasing the sampling rate, or decreasing the carrier frequency reduces this component without
affecting the others, but low-pass filtering the output does not affect it (so it's unlik