lass="math inline">\(d \times d\)</span> matrix with ones on the
diagonal, <span class="math inline">\(-1\)</span> on the <span class="math inline">\((i, i+1)\)</span> entries for <span class="math inline">\(i=1, \ldots d-1\)</span> and zeros elsewhere. If
the matrix <span class="math inline">\(\boldsymbol{\Lambda} \in
\mathcal{D}\)</span>, then the eigenvalues of the leading <span class="math inline">\((d-1) \times (d-1)\)</span> submatrix of <span class="math inline">\(\tilde{\boldsymbol{\Lambda}}\)</span