or pseudo-inverse<a name="16"></a></h2>
         <p>If you want just a few entries from the inverse, it's still better to formulate the problem as a system of linear equations
            and use a matrix factorization instead of computing inv(A).  The FACTORIZE object does this for you, by overloading the subsref
            operator.
         </p><pre class="codeinput">A = rand (1000) ;

tic ; S = inv (A)     ; S (2:3,4), toc
tic ; S = inverse (A) ; S (2:3,4), toc
</pre><pre class="codeoutput">ans =
    0