precise).
         </p>
         <p>inv(A)*B and A\B are mathematically equivalent, as are B*inv(A) and B/A, so these three methods give the same results (ignoring
            computational errors, which are worse for inv(D)).  Only the first equation looks like the equation in your textbook, however.
         </p><pre class="codeinput">A = rand (200) ; B = rand (200) ; C = rand (200) ; D = rand (200) ;

tic ; S1 = A - B*inv(D)*C ; toc ;
tic ; S2 = A - B*(D\C) ;    toc ;
tic ; S3 = A - (B/D)*C ;    toc ;
</