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<pre>   KASE   (input/output) INT
          On the initial call to SLACON, KASE should be 0.   
          On an intermediate return, KASE will be 1 or 2, indicating   
          whether X should be overwritten by A * X  or A' * X.   
          On the final return from SLACON, KASE will again be 0.</pre><p>
<pre>   Further Details   
   ======= =======</pre><p>
<pre>   Contributed by Nick Higham, University of Manchester.   
   Originally named CONEST, dated March 16, 1988.</pre><p>
<pre>   Reference: N.J.