]</tt></td>
<td>Or the ith bit of <tt>b</tt> with the jth bit of <tt>b</tt>
and return <tt>b[i]</tt>.</td>
</tr>

<tr>
<td><tt>b[i] &amp;= b[j]</tt></td>
<td>And the ith bit of <tt>b</tt> with the jth bit of <tt>b</tt> and return <tt>b[i]</tt>.</td>
</tr>
<tr>
<td><tt>b[i] ^= b[j]</tt></td>
<td>Exclusive-Or the ith bit of <tt>b</tt> with the jth bit of <tt>b</tt> and return <tt>b[i]</tt>.</td>

</tr>
<tr>
<td><tt>b[i] -= b[j]</tt></td>
<td>If the jth bit of <tt>b</tt> is set, clear the ith bit of <tt>b</tt>