\phi) e^{\\frac25 \\pi}} =
1+\\cfrac{e^{-2\\pi}} {1+\\cfrac{e^{-4\\pi}} {1+\\cfrac{e^{-6\\pi}}
{1+\\cfrac{e^{-8\\pi}} {1+\\ldots} } } }`,
          },
          {
            title: 'A Rogers-Ramanujan Identity',
            class: 'small',
            latex: `  1 +  \\frac{q^2}{(1-q)}+\\frac{q^6}{(1-q)(1-q^2)}+\\cdots =
\\prod_{j=0}^{\\infty}\\frac{1}{(1-q^{5j+2})(1-q^{5j+3})},
\\quad\\quad \\text{for $|q|<1$}.`,
          },
          {
            title: 'DeMorgan‚Äôs law',
            latex: '\\neg(