">for</span> (i = 0, j = nvert-1; i &lt; nvert; j = i++)</div><div class="line"><a name="l00582"></a><span class="lineno">  582</span>&#160;        {</div><div class="line"><a name="l00583"></a><span class="lineno">  583</span>&#160;            <span class="keywordflow">if</span> ( ((verty[i]&gt;testy) != (verty[j]&gt;testy)) &amp;&amp;</div><div class="line"><a name="l00584"></a><span class="lineno">  584</span>&#160;                (testx &lt; (vertx[j]-vertx[i]) * (testy-verty[i]) / (verty[j]-verty[i]) +