{bmatrix}
   \begin{bmatrix}
		v_d \\ 
		v_q
	\end{bmatrix}
\end{equation}

Solving the system for the voltage:

\begin{equation}
	\begin{bmatrix}
	    v_d \\ 
        v_q
   \end{bmatrix}
   =
   \begin{bmatrix}
		1/R & -\omega C \\
		\omega C & 1/R
	\end{bmatrix} ^{-1}
   \begin{bmatrix}
		i_d \\ 
		i_q
	\end{bmatrix}
\end{equation}

The matrix of a static capacitive element remains:

\begin{equation}
	\begin{bmatrix}
		1/R & -\omega C \\
		\omega C & 1/R
	\end{bmatrix} ^{-1}
	= 
	\frac{1}{\left(1/R\right