\begin{align}
    V_0^2(\phi)&=\dfrac{2(1+m)^2}{6m^2 + 5m + 1}\left[(3m + 1)\phi^{({2m+1})/({1+m})} - (2m + 1)\phi^{({3m+1})/({1+m})} - m\right], \\
    V_1(\phi)&=-\dfrac{1}{V_0(\phi)}\int_{\phi}^{1} V_0(s)\;s^{-{m}/({1+m})} \,\mathrm{d}s.
\end{align}
