Kinetic theory of gases
Viscosity and kinetic momentum

Maxwell-Boltzmann distribution gives the average (equilibrium) molecular speed as v ¯ = 2 π v p = 2 2 π k B T m {\displaystyle {\bar {v}}={\frac {2}{\sqrt {\pi }}}v_{p}=2{\sqrt {{\frac {2}{\pi }}{\frac {k_{\mathrm {B} }T}{m}}}}} where v p {\displaystyle v_{p}} is the most probable speed. We note that k B N A = R and M = m N A {\displaystyle k_{\text{B}}N_{\text{A}}=R\quad {\text{and}}\quad M=mN_{\text{A}}}
language:response_language[Italian], keywords:forbidden_words