Cone
Volume

The volume V {\displaystyle V} of any conic solid is one third of the product of the area of the base A B {\displaystyle A_{B}} and the height h {\displaystyle h}

In modern mathematics, this formula can easily be computed using calculus — it is, up to scaling, the integral ∫ x 2 d x = 1 3 x 3 {\displaystyle \int x^{2}\,dx={\tfrac {1}{3}}x^{3}} Without using calculus, the formula can be proven by comparing the cone to a pyramid and applying Cavalieri's principle – specifically, comparing the cone to a (vertically scaled) right square pyramid, which forms one third of a cube. This formula cannot be proven without using such infinitesimal arguments – unlike the 2-dimensional formulae for polyhedral area, though similar to the area of the circle – and hence admitted less rigorous proofs before the advent of calculus, with the ancient Greeks using the method of exhaustion. This is essentially the content of Hilbert's third problem – more precisely, not all polyhedral pyramids are scissors congruent (can be cut apart into finite pieces and rearranged into the other), and thus volume cannot be computed purely by using a decomposition argument.
startend:end_checker