linguistic:translation
Electrostatics

In the special case of a steady state (stationary charges and currents), the Maxwell-Faraday inductive effect disappears. The resulting two equations (Gauss's law ∇ ⋅ E = ρ ε 0 {\displaystyle \nabla \cdot \mathbf {E} ={\frac {\rho }{\varepsilon _{0}}}} and Faraday's law with no induction term ∇ × E = 0 {\displaystyle \nabla \times \mathbf {E} =0}), taken together, are equivalent to Coulomb's law, which states that a particle with electric charge q 1 {\displaystyle q_{1}} at position r 1 {\displaystyle \mathbf {r} _{1}} exerts a force on a particle with charge q 0 {\displaystyle q_{0}} at position r 0 {\displaystyle \mathbf {r} _{0}} of: F 01 = q 1 q 0 4 π ε 0 r ^ 01 | r 01 | 2 = q 1 q 0 4 π ε 0 r 01 | r 01 | 3 {\displaystyle \mathbf {F} _{01}={\frac {q_{1}q_{0}}{4\pi \varepsilon _{0}}}{{\hat {\mathbf {r} }}_{01} \over {|\mathbf {r} _{01}|}^{2}}={\frac {q_{1}q_{0}}{4\pi \varepsilon _{0}}}{\mathbf {r} _{01} \over {|\mathbf {r} _{01}|}^{3}}} where