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Another proof in the acute case

Using more trigonometry, the law of cosines can be deduced by using the Pythagorean theorem only once. In fact, by using the right triangle on the left hand side of Fig. 6 it can be shown that:

using the trigonometric identity cos 2 γ + sin 2 γ = 1. {\displaystyle \cos ^{2}\gamma +\sin ^{2}\gamma =1.}

This proof needs a slight modification if b < a cos(γ). In this case, the right triangle to which the Pythagorean theorem is applied moves outside the triangle ABC. The only effect this has on the calculation is that the quantity b − a cos(γ) is replaced by a cos(γ) − b. As this quantity enters the calculation only through its square, the rest of the proof is unaffected. However, this problem only occurs when β is obtuse, and may be avoided by reflecting the triangle about the bisector of γ.

Referring to Fig. 6 it is worth noting that if the angle opposite side a is α then:

This is useful for direct calculation of a second angle when two sides and an included angle are given.