1. imaginary numbers

need to solve 6-6i/-9i

came up with the answer 2/3 + 2/3i

What am I doing wrong. It's showing up as incorrect.

Thank you.

2. Re: imaginary numbers

You're missing a negative sign

$\frac{6-6i}{-9i}=\frac{2-2i}{-3i}=\frac{2-2i}{-3i}\cdot \frac{i}{i}=\frac{2i-2i^2}{-3i^2}=\frac{2i+2}{3}$

3. Re: imaginary numbers

Hello, needhelpnow!

Simplify: $\frac{6-6i}{-9i}$

Came up with the answer 2/3 + 2/3i

What am I doing wrong? It's showing up as incorrect.

Your answer, $\tfrac{2}{3} + \tfrac{2}{3}i$, is correct.

. . it might be read as: $\tfrac{2}{3} + \tfrac{2}{3i}$

Try entering it as. 2/3 + 2i/3. or .2/3 + (2/3)i.
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 4, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}