## Intermediate Algebra for College Students (7th Edition)

$(5x-2)(25x^2+10x+4)$
The formula for factoring the sum of two cubes is: $A^3+B^3=(A+B)(A^2-AB+B^2)$. The formula for factoring the difference of two cubes is: $A^3-B^3=(A-B)(A^2+AB+B^2)$. Hence here: $125x^3-8=\\=(5x)^3-2^3\\=(5x-2)((5x)^2+5x\cdot2+2^2)\\=(5x-2)(25x^2+10x+4)$
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