## Value Labs Aptitude Interview Questions & Answers

1. Question 1. A Train 110 M Long Is Running With A Speed Of 60 Km/hr. In What Time Will It Pass A Man Who Is Running At 6 Km/hr In The Direction Opposite To That In Which The Train Is Going ?

Speed of train relative to man = 60 + 6 = 66 km/hr.

= 66 * 5/18 = 55/3 m/sec.

Time taken to pass the men = 110 * 3/55 = 6 sec.

2. Question 2. Ram Bought 4 Dozen Apples At Rs. 12 Per Dozen And 2 Dozen Apples At Rs. 16 Per Dozen. He Sold All Of Them To Earn 20%. At What Price Per Dozen Did He Sell The Apples ?

6 dozen apples = Rs. (12 × 4 + 16 × 2) = Rs. 80

Gain = 20%

S.P = Rs. (120/100 × 80) = Rs. 96

Per dozen = Rs. (96/6) = Rs. 16

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4. Question 3. In A Game Of 90 Points A Can Give B 15 Points And C 30 Points. How Many Points Can B Give C In A Game Of 100 Points ?

While A scores 90 points, B scores (90-15)=75 points and C scores (90-30)= 60 points

i.e., when B scores 75 points, C scores 60 points

=> When B scores 100 points, C scores 6075×100 = 80 points

i.e., in a game of 100 points, B can give C (100-80)=20 points

5. Question 4. 150 Men Consume 1050 Kg Of Rice In 30 Days. In How Many Days Will 70 Men Consume 980 Kg Of Rice?

Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = (7x/30) kg

Quantity consumed by 70 men in x days = (7/30 x)(70) kg

= (7/30 x) * (70)  = 960

x = 60 days.

6. Question 5. 22004 – 29303 + 101299 – 59532 = ?

22004 – 29303 + 101299 – 59532

123303 – 888.35 = 34468 = 34500

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8. Question 6. A Alone Can Do A Piece Of Work In 6 Days And B Alone In 8 Days. A And B Undertook To Do It For Rs. 3200. With The Help Of C, They Completed The Work In 3 Days. How Much Is To Be Paid To C ?

C’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24

A’s wages : B’s wages : C’s wages

1/6 : 1/8 : 1/24 = 4:3:1

C’s share = 1/8 * 3200 = Rs. 400

9. Question 7. In Digging A Pond 20 M * 10 M * 5 M The Volumes Of The Soil Extracted Will Be ?

20 * 10 * 5 = 1000

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11. Question 8. The Greatest Number Of Four Digits Which Is Divisible By 15, 25, 40 And 75 Is:

Greatest number of 4-digits is 9999.

L.C.M. of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399.

Required number (9999 – 399) = 9600.

12. Question 9. The Product Of Two Numbers Is 4107. If The H.c.f. Of These Numbers Is 37, Then The Greater Number Is:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

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14. Question 10. A Person Crosses A 600 M Long Street In 5 Minutes. What Is His Speed In Km Per Hour ?

Speed = 600/ 5 x 60 m/sec. = 2 m/sec. = 2 x 18/5km/hr =7.2 km/hr

15. Question 11. Worker A Takes 8 Hours To Do A Job. Worker B Takes 10 Hours To Do A Job. How Long Should It Take Both A And B, Working Together To Do The Same Job ?

first we need to calculate 1 hours work, then their collective work as A’s 1-hour work is 1/8

B’s 1-hour work is 1/10

(A+B)’s 1 hour work = 1/8 + 1/10= 9/40

So both will finish the work in 40/9 hours=4 4/9

16. Question 12. A And B Started A Business By Investing Rs.4000/- And Rs.5000/- Respectively. Find The A’s Share Out Of A Total Profit Of Rs.1800:

A = Rs.4000/-

B = Rs.5000/-

A share 4 parts & B share 5 parts

Total 9 parts —–> Rs.1800/-

—-> 1 part ——-> Rs.200/-

A share = 4 parts —–> Rs.800/-

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18. Question 13. A Mixture Contains Alcohol And Water In The Ratio 4 : 3. If 5 Liters Of Water Is Added To The Mixture, The Ratio Becomes 4: 5. Find The Quantity Of Alcohol In The Given Mixture.

Let the quantity of alcohol and water be 4x litres and 3x litres respectively

4x/(3x+5) = 4/5

20x = 4(3x+5)

8x = 20

x = 2.5

Quantity of alcohol = (4 x 2.5) litres = 10 litres.

19. Question 14. A Boat Can Travel With A Speed Of 13 Km/hr In Still Water. If The Speed Of The Stream Is 4 Km/hr, Find The Time Taken By The Boat To Go 68 Km Downstream.

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream =68/17hrs = 4 hrs.

20. Question 15. Sam And Joan Are Playing A Tennis Match. If The Probability Of Sam’s Win Is 0.59, Then Find The Probability Of Joan’s Win.

Let event A = Sam wins and event B = Joan wins. Then,

P(A) = 0.59

Since if Sam wins, Joan cannot win and if Joan wins, Sam cannot win, so we can say that the events A and B are mutually exclusive. Other than these two events, there are

no any other possible outcomes. So,

P(A)+P(B) = 1

0.59+P(B) = 1

P(B) = 1-0.59 = 0.41

21. Question 16. The Ratio Between The Length And The Breadth Of A Rectangular Park Is 3: 2. If A Man Cycling Along The Boundary Of The Park At The Speed Of 12 Km/hr Completes One Round In 8 Minutes, Then The Area Of The Park (in Sq. M) Is:

Perimeter = Distance covered in 8 min. =12000x 8m = 1600 m.

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.

Area = (480 x 320) m2 = 153600 m2.

22. Question 17. The Average Of Runs Of A Cricket Player Of 10 Innings Was 32. How Many Runs Must He Make In His Next Innings So As To Increase His Average Of Runs By 4?

Average = total runs / no.of innings = 32

So, total = Average x no.of innings = 32 x 10 = 320.

Now increase in avg = 4runs. So, new avg = 32+4 = 36runs

Total runs = new avg x new no. of innings = 36 x 11 = 396

Runs made in the 11th inning = 396 – 320 = 76

23. Question 18. The Greatest Number Which On Dividing 1657 And 2037 Leaves Remainders 6 And 5 Respectively, Is:

Required number = H.C.F. of (1657 – 6) and (2037 – 5)

= H.C.F. of 1651 and 2032 = 127.

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25. Question 19. Two Pipes A And B Can Fill A Tank In 20 And 30 Minutes Respectively. If Both The Pipes Are Used Together, Then How Long It Will Take To Fill The Tank ?
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