# Come consideri  x ^ 2- 6x + 8 ?

#### Risposta:

(x-2)(x-4)

#### Spiegazione:

"consider the factors of + 8 which sum to give the"
"coefficient of the x-term, that is - 6"

"the factors of + 8 which sum to - 6 are - 4 and - 2"

rArrx^2-6x+8=(x-4)(x-2)
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