## Intermediate Algebra (12th Edition)

$4rx(3m^2+mn+10n^2)$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $12m^2rx+4mnrx+40n^2rx ,$ factor the $GCF.$ $\bf{\text{Solution Details:}}$ The $GCF$ of the terms in the given expression is $4rx ,$ since it is the greatest expression that can divide all the terms evenly (no remainder.) Factoring the $GCF$ results to \begin{array}{l}\require{cancel} 4rx(3m^2+mn+10n^2) .\end{array}
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