# Quant Test for LIC AAO Prelims Exam Set – 1

Directions(1-10): The following questions consists of two statements,you have to decide whether the data provided in the statements are sufficient to answer.

1. Nik invested certain amount of money in a scheme offering 10% compound interest compounded annually. Kim invested Rs.1000 more than Nik in another scheme offering 9% simple interest. Find the amount invested by Nik.
Statement I: Difference in the interests earned by Nik and Kim after two years is Rs.90
Statement II: Difference in the interests earned by Nik and Kim after three years is Rs.279.

II alone is sufficient.
Both together necessary.
I alone is sufficient.
Either I or II.
Both are not sufficient.
Option A
Let the amount invested by Nik and Kim be Rs. x and Rs.(x+1000) resp.
From I: Interest earned by Nik after two years = x*{(1+0.10)^2 – 1} = Rs.0.21x
Interest earned by Kim after two years = (x+1000)*0.09*2 = Rs.0.18x+180
Either == 0.21x â€“ 0.18x â€“ 180 = 90
=>x = 9000
Or == 0.18x + 180 â€“ 0.21x = 90
=>x = 3000
value of x cannot be determined exactly.
Statement II: Interest earned by Nik after three years = x * {(1+0.10)^3 -1} = Rs.0.331x
Interest earned by Kim after three years = (x+1000)*0.09*3 = Rs.0.27x+270
Here ,0.061x = 549
=> x = 9000
II alone is sufficient.

2. A shopkeeper bought an article and sold it. What is the cost of the article?
Statement I: Profit earned by the shopkeeper is Rs.250 and selling price of the article is 30% less than the marked price of the article.
Statement II: Marked price of the article is 25% above the selling price. Shopkeeper marked the price of article Rs.2000 and profit percent earned is 60%.

I alone is sufficient.
Either I or II.
Both are not sufficient.
II alone is sufficient.
Both together necessary.
Option D
From I: Let the MP be Rs.x
SP = 70% of x = Rs.7x/10 Profit = Rs.250
Let CP be Rs.y.
So, y + 250 = 7x/10
I alone is not sufficient.
From II: Let SP be Rs.x
P = (2000/125)*100 = Rs.1600
CP = (1600*100)/160 = Rs.1000
II alone is sufficient.

3. After 3 years, ratio of age of P and Q will become 17:15. Find the difference between the age of P and Q.
Statement I: 3 years ago, the ratio of the age of P and age of Q was 7:6.
Statement II: The ratio of age P after 5 years and age of Q 7 years ago is 9:5.

Both together necessary.
II alone is sufficient.
Either I or II.
Both are not sufficient.
I alone is sufficient.
Option C
Let the present age of P and Q be x and y years.
So,(x+3)/(y+3) = 17/15 =>x = (6+17y)/15
From I: (x-3)/(y-3)= 7/6
=>y = 27
Then x = 31
Required Difference = 31 â€“ 27 = 4 years
I alone is sufficient.
From II: (x+5)/(y-7) = 9/5
=>y = 27
x = 31
Required Difference = 31 â€“ 27 = 4 years
II alone is sufficient.
Either I or II.

4. If an item is sold at 25% discount. Then it gives a profit of 25%. Find the selling price of the item.
Statement I: If it is sold for Rs.45 more, then the profit percentage is 40%.
Statement II: If the marked price of the item is increased by 10% and discount rate remains the same, then the profit percentage is 37.5%.

Either I or II.
Both are not sufficient.
II alone is sufficient.
I alone is sufficient.
Both together necessary.
Option D
Let CP be Rs.x
SP = Rs.1.25x
MP = 1.25x/0.75 = Rs.(5/3)x
From I: (1.25x + 45) = 1.4x
=> x = Rs.300
I alone is sufficient.
From II: New MP = (5/3)x*1.1 = Rs.(5.5/3)x
Now, (5.5/3)x *0.75 =1.375x
II is not sufficient.

5. Four persons A,B, C and D are hired to do a work. A,C and D can complete the task in 16 days while working together. Find the number of days taken by B alone to complete the task.
Statement I: C and D can complete the work in 24 days. B is 100% more efficient than A.
Statement II: A alone can complete the work in 48 days, and ratio of efficiency of C and D is 1:2 resp.

Both together necessary.
I alone is sufficient.
Both are not sufficient.
Either I or II.
II alone is sufficient.
Option B
From I: Let the total work LCM(16,24) = 48 units
Number of units of work done by A,C and D in one day = 48/16 = 3 units
Number of units of work done by C and D in one day = 48/24 = 2 units
Number of days taken by A to complete the work in one day = 3-2 = 1 units
Therefore, number of days taken by A to complete the work = 48/1 = 48 days
So, time taken by B to complete the work = 48/2 = 24 days
I alone is sufficient.
From II: Let the efficiency of C and D be x and 2x resp.
1/48 + x + 2x = 1/16
=> x = 1/72
II alone is not sufficient.

6. Find the marks obtained by Simran in half-yearly exam, if the sum of marks obtained by Simran and Raj in half-yearly exam is 1410.
Statement I: The ratio of marks obtained by Simran and Raj in quarterly exam was 9:8 resp.
Statement II: The ratio of marks obtained by Simran in quarterly exam to the half-yearly exam is 2:3 resp. while ratio of marks by Raj in quarterly exam to the half-yearly exam is 4:5 resp.

I alone is sufficient.
Both together necessary.
Both are not sufficient.
Either I or II.
II alone is sufficient.
Option B
From I: Let the marks obtained by Simran and Raj in quarterly exam be 9x and 8x resp.
This alone is not sufficient.
From II: Let the marks obtained by Simran in quarterly and half-yearly exam be 2y and 3y resp.
Let the marks obtained by Raj in quarterly and half-yearly exam by 4z and 5z resp.
This alone is not sufficient.
Combining these two equations,we get 9x*3/2 + 8x*5/4 = 1410
=> x = 60
Marks obtained by Simran in half-yearly exam = 9x*3/2 = 810
Both together necessary.

7. A bag contains a total of (x+6) balls of three colors like White,Black and Brown such that the ratio of number of White and Brown balls is 3:4 resp. and the probability of drawing a Black ball is 1/3. Find the number of balls in the bag.
Statement I: Probability of drawing a white ball is 2/7.
Statemnet II: The number of black balls in the bag is 2 less than the number of brown balls .

Either I or II.
I alone is sufficient.
II alone is sufficient.
Both are not sufficient.
Both together necessary.
Option C
Let the number of White and Brown color balls be 3x and 4x resp.
So, the number of Black balls = (y+6)- (3x+4x) = (y â€“ 7x +6)
Probability of drawing the Black ball = 1/3 (y â€“ 7x + 6)/(y+6) = 1/3
=>21x = 2y + 12 —-(1)
From I: Probability of drawing the White ball = 2/7
3x/(y+6) = 2/7
21x = (2y+12) —-(2)
Both the equations are same, so this canâ€™t be solved using Statement I.
From II: (y â€“ 7x + 6) = 4x â€“ 2
=> y = 11x â€“ 8 —-(3)
From equations (1) and (2), we get
21x â€“ 12 = 22x â€“ 16
=> x = 4
So, y = 11*4 â€“ 8 = 36
Total number of balls in the bag = 36+6 = 42
II is alone sufficient.

8. Find the time taken by 3 males and 5 females to plough the field while working together.
Statement I: 1 male can plough half of the field in 12 days, 2 females can plough two fields of the same area and same type in 20 days.
Statement II: 2 males can plough a field in 12 days and 2 females can plough the same field in 10 days.

Both are not sufficient.
I alone is sufficient.
Either I or II.
Both together necessary.
II alone is sufficient.
Option C
From I: Time taken by 3 male t plough the field = 12/(3/2) = 8 days
Time taken by 5 female to plough the field = (20*2)/(5*2 ) = 4 days
So, the time taken by 3 male and 5 female to plough the field while working together
= (8*4)/(8+4) = (8/3) days
I alone is sufficient.
From II: Time taken by 3 male t plough the field = 12/(3/2) = 8 days
Time taken by 5 female to plough the field = (10*2)/(5 ) = 4 days
So, the time taken by 3 male and 5 female to plough the field while working together = (8*4)/(8+4)
= (8/3) days
Either I or II.

9. A container contains â€˜xâ€™ litres of a mixture of water and alcohol in the ratio 7:22 resp. A man takes out â€˜yâ€™ litres of the mixture from the container and then mixes 28 litres of a mixture of water and alcohol in the ratio of 6:1 resp. in that container.
Find the value of x.
Statement I: The ratio of water and alcohol becomes 3:8 resp. after mixing 28 litres of a mixture of water and alcohol in the ratio of 6:1 resp.
Statement II: The amount of water in the container becomes 150 litres after mixing 28 litres of a mixture of water and alcohol in the ratio 6:1 resp.

Both together necessary.
Both are not sufficient.
II alone is sufficient.
Either I or II.
I alone is sufficient.
Option B
Initially amount of water and alcohol be 7x and 22x resp. Amount of water and alcohol taken out be 7y and 22y resp.
Statement I: (7x â€“ 7y + 24)/(22x â€“ 22y + 4) = 3/8
=>x â€“ y = 18
I alone is not sufficient.
From II: 7x â€“ 7y + 24 = 150
=> x â€“y = 18
II alone is not sufficient.
Combining both the equations, we get
(7x â€“ 7y + 24)/(22x â€“ 22y + 4 ) = 3/8
=>x â€“ y = 18
And 7x â€“ 7y + 24 = 150
=>x â€“ y = 18
Both are not sufficient.

10. A bag contains red,blue and green balls in the ratio of 4:5:3 resp. Find the total number of balls in the bag.
Statement I: Probability of drawing two blue balls from the bag is 1/6.
Statement II: Probability of drawing a green ball from the bag is Â¼.

Either I or II.
Both are not sufficient.
I alone is sufficient.
II alone is sufficient.
Both together necessary.
Option C
From I: Probability of choosing two blue ball from the bag = 5xC2/12xC2 = 1/6
=>x = 3
Total number of balls = 12*3 = 36
I alone is sufficient.
From II: Probability of drawing a green ball = 3xC1/12xC1 = Â¼
=> Â¼ = Â¼
II is not sufficient.
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}