# How many maximum moles of AgCl are obtained?

Contents

## How many moles of AgCl will be obtained when agno3?

2 moles because 2 Cl- ions are present as counter ion in the complex.

## How many moles of AgCl will be precipitated when an excess of agno3 is added to a molar solution of Cr h2o 5cl cl2?

Assuming that 1 litre of solution is taken.. It would give 2 moles of Cl . Hence, adding excess of AgNO3 will ppt out 2 moles of AgCl..

## Which gives only 25% mole of AgCl when reacts with AgNO3?

3 NH 3 or [ Pt ( NH 3 ) 3 Cl 3 ] Cl gives only 25 % of AgCl as we can see than here 4 Cl are present , but only 1 mol of AgCl is obtained i . e . 1 4 × 100 = 25 % . This is because here the 3 Cl atoms are inside the coordination sphere while 1 Cl is outside , therefore 1 Cl is only available for AgNO 3 .

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## What is the number of moles of AgCl precipitated when one mole of CoCl3 4NH3 is treated with excess of silver nitrate?

5nh3 was treated with excess of silver nitrate solution, 2 mol of agcl was precipitated.

## How many moles of AgCl will be obtained when AgNO3 solution is completely react with solution?

of moles of AgCl obtained when excess AgNO_(3) is added to one mole of [Cr(NH_(3))_(4)Cl_(2)]Cl. [Cr(NH3)4Cl2]Cl ionises gives one Cl- ion. So it gives 1 mole AgCl ppt.

## What fraction of chlorine will be precipitated as AgCl?

– So, only these 2 chloride ions can be precipitated out by AgNO3 as AgCl. – So, the fraction of chloride precipitated is 2/3.

## How many grams of AgCl are produced after the reaction?

Therefore, the mass of AgCl formed by the reaction is 0.84 g.

## How many moles are in Ag’in AgCl?

Divide the given mass m by the molecular weight W of AgCl, which is given as 143 g/mole. That gives the number of moles of AgCl. Since there is one atom of Ag in each molecule of AgCl, the number of moles of Ag equals the number of moles of AgCl.
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