1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# In the given figure, if ∠BCA=∠RPQ=15∘, then ∠PQR is .

A
45
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 45∘In ΔABC and ΔPQR, ∠BCA=∠RPQ = 15∘ .... (Given) BC=PR=1 km ....... (Given) AC=PQ=1.3 km .... (Given) Thus, ΔACB≅ΔQPR by SAS congruency. ⇒∠PQR=∠BAC .... (CPCT) Along the horizontal line through point A, we have 90∘+∠BAC+45∘=180∘ ∠BAC=180∘−45∘−90∘ ⇒∠PQR=∠BAC=45∘

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Introduction to Congruent Triangles
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}