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1. Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!
2. (Original post by algebrax1)
Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!
The quadratic expression should be equal to 0.
3. (Original post by algebrax1)
Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!

Now try again.

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