# Geoemetry

posted by .

Write an equation in point slope form for the perpendicular bisector of the segment with endpoints A(-3,-3) and B(5,6)

• Geoemetry -

A(-3,-3), M(x,y), B(5,6).
x = (-3+5) / 2 = 1.
y = (-3+6) / 2 = 1 1/2 = 3/2.

The slope of a straight line is the same at all points on the line.

m = (6-(-3)) / (5-(-3)) = 9/8.

m2 = -8/9 = Negative reciprocal of m.

(1,3/2),(x,y),

m2 = (y-3/2) / (x-1) = -8/9,
Cross multiply:
y-3/2 = -8/9(x-1).

• Geoemetry -

write an equation in point-slope form for the perpendicular bisector of the segment with the given end points M(-5,4),N(1,-2)
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}