# A 100-gram mass is attached to a spring and undergoes simple harmonic motion with a period of T =...

## Question:

A 100-gram mass is attached to a spring and undergoes simple harmonic motion with a period of {eq}T = 2 sec. {/eq} If the total energy of the system is {eq}E = 5 J, {/eq} find

(a) force constant k, and

(b) the amplitude of motion A.

## Spring-mass System:

The motion of the spring-mass system under the absence of damping force is the constant period oscillatory motion. The period of motion can be varied by changing the magnitude of modulus or force constant of the spring and the mass at the free end of the spring. When the spring-mass system is deformed from the mean position, then the mechanical energy stored in the spring is called the spring potential energy.

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Given data:

• {eq}m=\rm 100 \ gram=0.1 \ kg {/eq} is the mass attached to the spring
• {eq}T=\rm 2 \ s {/eq} is the period of motion
• {eq}k {/eq} is...

Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
201K

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.
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