Mathematics

An angle is $14^{o}$ more than its complementary angle. What is the measure?

SOLUTION

Let first angle is $={{x}^{o}}$

Then, IInd angle is $=x+{{14}^{o}}$

According to given question,

$x+x+14={{90}^{o}}$

$2x={{90}^{o}}-{{14}^{o}}$

$2x={{76}^{o}}$

$x={{38}^{o}}$

Then, IInd angle is $x+{{14}^{o}}={{38}^{o}}+{{14}^{o}}={{52}^{o}}$

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Subjective Medium Published on 09th 09, 2020
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