# A dc shunt generator has emf of 100 V when the useful flux per pole is 20 mWb and the speed is 800 rpm. What is the generated emf when flux per pole is 24 mWb at a speed of 1000 rpm?

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1. 120 V
2. 125 V
3. 150 V
4. 66.7 V

## Answer (Detailed Solution Below)

Option 3 : 150 V
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## Detailed Solution

Concept

In a DC shunt generator, the relationship between induced EMF and speed is:

E α ϕN

where, E = Induced EMF

ϕ = Flux per pole

N = Speed

Calculation

Given, E1 = 100 V at ϕ1 = 20 mWb and N= 800 rpm

The emf at  ϕ2 = 24 mWb and N2 = 1000 rpm

$${E_1\over E_2}={\phi_1\times N_1\over \phi_2\times N_2}$$

$${100\over E_2}={20\times 800\over 24\times 1000}$$

E2 = 150 V

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