## Algebra 2 (1st Edition)

Plugging in the given values into the inequality: $0.25(\frac{4}{3})-0=\frac{1}{3}\leq1$, thus $(\frac{4}{3},0)$ is not a solution. $0.25(\frac{2}{3})-(-4)=\frac{25}{6}\gt$, thus $(\frac{2}{3},-4)$ is a solution.
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