1. ## Height of Ball

The formula for the height of a ball as a function of time is given by the equation h = -16t^2 + vt + h, where h is the height of a ball in feet, v is the initial velocity of the ball in feet per second, h is the initial height of the ball in feet, and t is the time in seconds after the ball was thrown.
If a ball is thrown from an initial height of 5 feet at an initial velocity of 20 feet per second, what is its height after 1 second?

Do I plug and chug here?

2. Originally Posted by magentarita
The formula for the height of a ball as a function of time is given by the equation h = -16t^2 + vt + h, where h is the height of a ball in feet, v is the initial velocity of the ball in feet per second, h is the initial height of the ball in feet, and t is the time in seconds after the ball was thrown.
If a ball is thrown from an initial height of 5 feet at an initial velocity of 20 feet per second, what is its height after 1 second?

Do I plug and chug here?

Yes that's right but remember to plug in h which is the initial height into the correct h in the equation as the equation has 2 h's in it.

3. ## ok...

Originally Posted by tester85
Yes that's right but remember to plug in h which is the initial height into the correct h in the equation as the equation has 2 h's in it.
So, h = 5 in the function.

Plug the rest for v and t and simplify, right?

4. Originally Posted by magentarita
So, h = 5 in the function.

Plug the rest for v and t and simplify, right?
Correct. The equation you should get should be $\displaystyle h\left(t\right)=-16t^2+20t+5$

Now, what do you think $\displaystyle h\left(1\right)$ should be?
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