## Calculus (3rd Edition)

$$\lim _{x \rightarrow \infty} \left(\frac{1}{4}\right)^{-x}=\frac{1}{0}=\infty.$$
Since $\frac{1}{4}<1$, then we have $$\lim _{x \rightarrow \infty} \left(\frac{1}{4}\right)^{x}=0.$$ and hence $$\lim _{x \rightarrow \infty} \left(\frac{1}{4}\right)^{-x}=\frac{1}{0}=\infty.$$
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