## Algebra 1: Common Core (15th Edition)

You are given $g(x)=$ $4 {\times}10^{x}$. Plug in the values $-2,-1,0,1,2,3$ for the X-variable: $g(-2)=$ $4 {\times}10^{-2}={\dfrac{1}{25}}$ $g(-1)=$ $4 {\times}10^{-1}={\dfrac{2}{5}}$ $g(0)=$ $4 {\times}10^{0}=4$ $g(1)=$ $4 {\times}10^{1}=40$ $g(2)=$ $4 {\times}10^{2}=400$ $g(3)=$ $4 {\times}10^{3}=4000$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}