## Precalculus (6th Edition) Blitzer

$(5,-3)$
The line passing containing the point $P(a,b,c)$ and parallel to the normal vector $n=\lt p,q,r\gt$ can be represented by the parametric equations as shown below: $x=a+pt; y=b+qt; z=c+qt$ Here, $t \to$ Real number. Therefore, $x=(2)^2+1=5; y=5-(2)^3=-3$ So, point is: $(5,-3)$
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