# If V is the design speed in kmph

By Mona Kumari|Updated : June 22nd, 2022

If V is the design speed in kmph and R is the radius of the curve of a hill road, the super-elevation is

1. e=V/127R
2. e=V2/127R
3. e=V/225R
4. e=V2/225R

## If V is the design speed in kmph and R is the radius of the curve of a hill road, the super-elevation is e = V2/225R

### Solution

We know that equation of centrifugal ratio is,

P/V2/127R=e+f

Where,

• P is the centrifugal force acting on the vehicle
• W is the weight of the vehicle
• V is the design speed in kmph
• R is the radius of the curve
• e is the superelevation
• f is the coefficient of lateral friction

As per IRC, provide superelevation to counteract centrifugal force due to 75% of design speed by neglecting the coefficient of lateral friction

e = (0.75V)2/127R

e = V2/225R

☛ Related Questions:
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}