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# HW - Section 1.6 Number 53 www.math.u.edu/harringt We want...

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Section 1.6 Number 53 www.math.ufl.edu/˜harringt January 24, 2008 We want to Find the range of f ( x ) = 3 - e 2 x . From the quiz 3A we know that that f - 1 ( x ) = 1 2 ln(3 - x 2 ). Recall that the range of f ( x ) is the domain of f - 1 ( x ). Since we need to know the domain of f - 1 ( x ) = 1 2 ln(3 - x 2 ), then we must have that 3 - x 2 > 0 3 - x 2 > 0 3 > x 2 3 > x 2 3 > | x | | x | < 3 So - 3 < x <
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