## Intermediate Algebra (6th Edition)

1. Factor the expression. $z^{2}$/6 - z/2 - 3 = (z/3 + 1)(z/2 - 3) 2. Apply the zero factor property. a) z/3 + 1 = 0 b) z/2 - 3 = 0 3. Solve each linear equation. a) z = -3 b) z = 6 The solutions are {-3, 6}.
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