## Algebra 1

$(7g-6)^{2}$
Given the polynomial $(7g)^{2}$ - 84g + $(6)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ In this polynomial a= 7g and b=6 $(7g)^{2}$ - 2(7g)(6) + $(6)^{2}$ = $(7g-6)^{2}$
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