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#21
04-17-2012, 04:16 PM
 Unregistered Guest Posts: n/a
Re: g/kwh to gal/h

may i know in the previous calculation whether you consider the efficiency already? i looks the genset has a round 50% efficiency.
#22
05-05-2012, 09:48 PM
 Unregistered Guest Posts: n/a
Re: g/kwh to gal/h

how to compute kwh/liter?
#23
05-06-2012, 04:24 AM
 JohnS Double Ultimate Supreme Member Join Date: Dec 2007 Location: SE Michigan, USA Posts: 8,706 Rep Power: 17
Re: g/kwh to gal/h

Quote:
 Originally Posted by Unregistered how to compute kwh/liter?
Measure the engine's power output (kilowatts) and fuel flow (liters per hour). Divide.

It varies with the heat content of the fuel and the efficiency of the engine. For a particular engine and fuel, it varies considerably with torque and rpm (the plot is called an engine map, and shows brake specific fuel consumption contours vs torque and rpm).
#24
06-03-2012, 09:11 PM
 PLOPPO Guest Posts: n/a
Re: g/kwh to gal/h

There are 453.6 grams per pound.

230 g/kw hr = ( 230/453.6 ) lb/kw hr ~= 0.507 lbm/kw-hr

There are approximately 7.4 pounds / gallon for #2 D diesel fuel

0.507 lbm/kw-hr / 7.4 lbm / gal ~= 0.069 gal / kw-hr

If 60 kw, then hourly fuel oil usage ~= 0.069 x 60 kw ( kw drops out ) = 4.11 gal/hr

The reciprocal of "gal/kw-hr" i.e. "kw-hr/ gal" is a more used term of electric generator efficiency using diesel engines.

In this case 1 / 0.069 ~= 14.5 kw-hr / gal. a very competitive level.
#25
06-20-2012, 12:14 AM
 Nahidh Guest Posts: n/a
Re: g/kwh to gal/h

each KWh will consume 0.31 liters for small machines ( under 50 KVA ) , 0.26 to 0.28 for mid machines under 250 KVA , and 0.252 litres for large machines , for DS#2 fuel
#26
04-23-2013, 03:05 AM
 Unregistered Guest Posts: n/a
Re: g/kwh to gal/h

If a 2650 kW Main Engine has a fuel consumption of 210.2 g/kWh at full load. How much it will be at t/h ? Thanks
#27
04-23-2013, 12:53 PM
 JohnS Double Ultimate Supreme Member Join Date: Dec 2007 Location: SE Michigan, USA Posts: 8,706 Rep Power: 17
Re: g/kwh to gal/h

Quote:
 Originally Posted by Unregistered If a 2650 kW Main Engine has a fuel consumption of 210.2 g/kWh at full load. How much it will be at t/h ? Thanks
210.2 g/kWh x 2650 kW x 1 t/10^6 g = 0.557 t/h
#28
04-24-2013, 04:33 PM
 Unregistered Guest Posts: n/a
Re: g/kwh to gal/h

Quote:
 Originally Posted by JohnS 210.2 g/kWh x 2650 kW x 1 t/10^6 g = 0.557 t/h
Thank you....

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