1. ## optimization with constraint

question: $z=100x^{.25}y^{.75}$ where $x=48-4y$ Use chain rule to find $\frac{dz}{dy}$. Solve $\frac{dz}{dy}=0$ for y in terms of x and use the constraint to find x and y to maximize z.
NOTE: these are normal derivatives, not partial

work:
$z=100(48-4y)^{.25}y^{.75}$
I take the derivative and subsitute x back in to get $\frac{dz}{dy}=-x^{-.75}y^{.75}+\frac{3}{4}y^{-.25}x^{.25}$
Then I set it equal to 0 to get $\frac{3}{4}y^{-.25}x^{.25}=x^{-.75}y^{.75}$

2. Looks good so far. To solve for y, use power properties. $y^a*y^b=y^{a+b}$. You can multiply both sides by y^a, where a will both cancel one y term and make the other y^1, which is very convenient.
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