# Given the waveforms of Figure 1, compute the following convolution integrals using MATLAB. Use a... 1 answer below »

C.1 Given the waveforms of Figure 1, compute the following convolution integrals using
MATLAB. Use a time axis of -5 to 5 (seconds) with a resolution of 0.01 (including
the results of convolution) [in MATLAB t = -5:0.01:5]. Plot the results of the
convolution and the input signals.
a. ??(??) ? ??(??)
b. ??(??) ? ??(??)
c. ??(??) ? ??(??)
d. ??(??) ? ??(??)
C.2 Given the waveforms in Figure 2, compute the convolutional integral ??(??) ? h(??)
using MATLAB. Use a time axis of 0 to 8 (seconds) with a resolution of 0.01
(including the results of convolution) [in MATLAB t = 0:0.01:8]. Plot the result
of the convolution and the input signals.
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Lab 4 – Convolutional Example t ?? -10t Find the result of the convolution of signals x(t)= 2e u(t) and h(t)= rect . ?? 2 ?? 8 If we use the convolution integral in the form of y(t)= x(?)h(t-?)d? ? -8 There are 3 possible scenarios: (i) for t+1< 0 there is no overlap. Hence for t<-1 y(t)= 0 for t<-1 (ii) for t+1= 0 and t-1= 0 ? there is partial overlap. Therefore for -1=t=1, t+1 1 -10?-10(t+1) [ ] y(t)= 2e d?= 1-e for -1=t=1 ? 5 0 (iii) for t-1>0 ? there is full overlap. t+1 1 -10?-10(t-1)-10(t+1) Therefore, for t > 1, we have y(t)= 2e d?=[] e-e for t>1. ? 5 t-1

Attachments:

Vijay K

Matlab Program :  lab4_studentId.m

del_t = .001;
t = -5:del_t:5;
L = length(t);
a = (abs(t) < 1="">
b = t.*((abs(t) < 1="">
f = exp(-t).*(t > 0 ).*(t <=>
g = (t >=2).*(t <=>
figure,
subplot(2,2,1);
plot(t, a), xlabel('t'), ylabel('a(t)')
subplot(2,2,2);
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