## Algebra 1

$8*12=96$ $96/2 = 48$ $(8-2x)(12-2x)=48$ $96-16x-24x+4x^2=48$ $4x^2-40x+96=48$ $4(x^2-10x+24=12)$ $x^2-10x+24=12$ $x^2-10x+12 = 0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-10)±\sqrt {(-10)^2-4*1*12)}/2*1$ $x=(10±\sqrt {100-48})/2$ $x=(10±\sqrt {52})/2$ $x=(10±7.21)/2$ $x=(10+7.21)/2$ $x=17.21/2$ $x=8.605$ (this is bigger than the frame, so this answer won't work) $x=(10-7.21)/2$ $x=2.79/2$ $x=1.395$
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