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## Q. 3.7

The molar mass of acetic acid, as determined with a mass spectrometer, is about 60 g/mol. Using that information along with the simplest formula found in Example 3.6, determine the molecular formula of acetic acid.

 ANALAYSIS simplest formula $(CH_{2}O)$ $MM_{a}$: actual molar mass (60 g/mol) Information given: molecular formula Asked for:

STRATEGY

1. Determine the molar mass of the simplest formula, $MM_{s}$
2. Find the ratio

$\frac{\text{ actual molar mass}}{\text{simplest formula molar mass}}$ = $\frac{MM_{a}}{MM_{s}}$

3. To get the molecular formula, multiply all subscripts in the simplest formula by the ratio.

## Verified Solution

 12.01 g C + 2(1.008) g H + 16.00 g O = 30.03 g $CH_{2}O/mol$ 1. $MM_{s}$ $\frac{MM_{a}}{MM_{s}}$ = $\frac{60}{30.03}$ = 2 2. ratio $C_{1×2}H_{2×2}O_{1×2}$ The molecular formula of acetic acid is $C_{2}H_{4}O_{2}$. 3. molecular formula
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