# sir how to solve itimage attached

viswanath
40 Points
9 years ago
Take tan7=a.
tan7tan53tan67=a{(√3-a)/(1+√3a)}{( √3+a)/(1-√3a)}         since tan60 =√3
=a(3-a2)/(1-3a2)  = (3a-a3)/(1-3a2) =(3tan7-tan37)/(1-3tan27)=tan (3×7)=tan 21
tan21 tan69=1.
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