# Construct a Triangle Xyz in Which ∠Y = 30°, ∠Z = 90° and Xy + Yz + Zx = 11. - Mathematics

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.

#### Solution

Steps of construction:
Step 1: Draw a line segment AB of 11cm.
Step 2: Draw∠DAB = Y = 30° and ∠FBA = ∠Z = 90°
Step 3: Draw the angle bisector of ∠DAB and ∠EBA which intersect each other at x
Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.
Step 5: Join XY and XZ
∴ Δ XYZ  is the required triangle

Concept: Some Constructions of Triangles
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 16 Constructions
Exercise 16.3 | Q 10 | Page 18

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