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# Problem: The left face of a biconvex lens has a radius of curvature of magnitude 12.0 cm, and the right face has a radius of curvature of magnitude 18.0 cm. The index of refraction of the glass is 1.44.(a) Calculate the focal length of the lens.(b) Calculate the focal length if the radii of curvature of the two faces are interchanged.

###### FREE Expert Solution

Lens equation:
$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

We're given the following:

• The radius of curvature of the left face, R1 = 12.0 cm
• The radius of curvature of the right face, R2 = 18.0 cm
• The glass index of refraction, μ = 1.44
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###### Problem Details

The left face of a biconvex lens has a radius of curvature of magnitude 12.0 cm, and the right face has a radius of curvature of magnitude 18.0 cm. The index of refraction of the glass is 1.44.
(a) Calculate the focal length of the lens.
(b) Calculate the focal length if the radii of curvature of the two faces are interchanged.
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