### Energy

```Part 6 - Power

…the rate at which energy is converted.

…the rate at which work is done.

…P

…measured in Watts (W), which is J/s.

P = ΔE/t

P = W/t
◦ But, W = FΔx, so P = FΔx/t
◦ And Δx/t = v, so P = Fv




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
ΔE = change in energy
t = time
W = work
F = force
Δx = displacement
v = velocity

Defined by James Watt:
◦ The amount of work a horse can do in one second.
◦ One horsepower = 746 Watts
A 50.0 kg student climbs 5.00 m up a rope at a
constant speed. if the student's power output
is 200.0 W, how long does it take the student
to climb the rope? How much work does he do?
P = FΔx/t
m=50 kg
Pt = FΔx
Δx=5 m
200t = (490*5)
P=200 W
200t = (2450)
t=?
t = (2450)/200
F=?
W = FΔx
t = 12.25 s
W=?
W = (490)(5)
W = 2,450 J
```
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