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# pring as huwin below- 0- -n iti 5n tint e af the hil it rikes to the h.docx

pring as huwin below. 0- ?n iti 5n tint e af the hil it rikes to the height nialLaach
Solution
if h = 6.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*6.3 - (1/2)*100*A^2
==> A = 0.366 m <<<<<<------------------Answer
====================================
if h = 0.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*0.3 - (1/2)*100*A^2
==> A = 0.128 m
.

pring as huwin below. 0- ?n iti 5n tint e af the hil it rikes to the height nialLaach
Solution
if h = 6.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*6.3 - (1/2)*100*A^2
==> A = 0.366 m <<<<<<------------------Answer
====================================
if h = 0.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*0.3 - (1/2)*100*A^2
==> A = 0.128 m
.

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### pring as huwin below- 0- -n iti 5n tint e af the hil it rikes to the h.docx

1. 1. pring as huwin below. 0- ?n iti 5n tint e af the hil it rikes to the height nialLaach Solution if h = 6.3 m here the block moves through the rough path 9 times. let A is the initial compression of the spring. Workdone by friction = change in mechanical energy fk*d*cos(180) = m*g*h - (1/2)*k*A^2 -fk*d = m*g*h - (1/2)*k*A^2 -mue_k*m*g*d = m*g*h - (1/2)*k*A^2 -0.2*0.1*9.8*9*0.3 = 0.1*9.8*6.3 - (1/2)*100*A^2 ==> A = 0.366 m <<<<<<------------------Answer ==================================== if h = 0.3 m here the block moves through the rough path 9 times. let A is the initial compression of the spring. Workdone by friction = change in mechanical energy fk*d*cos(180) = m*g*h - (1/2)*k*A^2 -fk*d = m*g*h - (1/2)*k*A^2
2. 2. -mue_k*m*g*d = m*g*h - (1/2)*k*A^2 -0.2*0.1*9.8*9*0.3 = 0.1*9.8*0.3 - (1/2)*100*A^2 ==> A = 0.128 m
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