# Derivative of e^x^x^2?

derivative of e^x^x^2??

can someone explain to me how this could be solved?

so far i have:
f(x)=e^x^x^2
lnf(x)= x^2lne^x)

(e and ln cancel?)

f'(x)/f(x)= (x^2)x
f'(x)= f(x) x^3

= (e^x^x^2)(x^3)??

is that right? or do i need to use the power rule or something?

$$y=e^{x^{x^2}}$$
$$lny=x^{x^2}$$
use the fact that if $$Y=u^v$$
then $$\frac{1}{Y}\frac{dY}{dx}=\frac{v}{u}\frac{du}{dx}+\frac{dv}{dx}lnu$$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}