Q. 93.7( 6 Votes )

If the equation (

If the roots are equal then d = b2 – 4ac = 0

Here a = (a2 + b2), b = 2 (ac + bd), c = (c2 + d2)

D = b2 – 4ac = 0

b2 = 4ac

{– 2(ac + bd)}2 = 4{(a2 + b2) (c2 + d2)}

4(a2c2 + b2d2 + 2acbd) = 4(a2c2 + a2d2 + b2c2 + b2d2)

2acbd = a2d2 + b2c2

a2d2 + b2c2 – 2abcd = 0

(ad – bc)2 = 0

ad – bc = 0
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}