# How do you find g(3a) given f(x)=2x-1 and g(x)=3x and h(x)=x^2+1?

$g \left(3 a\right) = 9 a$
$\Rightarrow g \left(\textcolor{red}{3 a}\right) = 3 \times \textcolor{red}{3 a} = 9 a$
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