# I am a prime number. Double of myself is equal to the square if myself. Which number am I ?

453 views
I am a prime number. Double of myself is equal to the square if myself. Which number am I ?
posted Mar 2, 2018

2X = X^2
X^2 - 2X = 0
X(X - 2)=0
X = 0, 2
So the answer is 2 (because its a prime) and not 0.

answer Mar 2, 2018
+1 vote

2 is also prime number
when, we double this is equal to 4
if, we square its is equal to 4
so, required answer is 2

answer Mar 3, 2018
+1 vote

answe----------------- two

answer Mar 8, 2018

Similar Puzzles

I am thinking of a two-digit number.

If I write 3 to the left of my number, and double this three-digit number, the result is 27 times my original number.

What is my number?
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}