I am in the process of packing boxes onto my lorry (truck). : GMAT Critical Reasoning (CR)
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# I am in the process of packing boxes onto my lorry (truck).

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Senior Manager
Joined: 12 Oct 2003
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I am in the process of packing boxes onto my lorry (truck). [#permalink]

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29 Feb 2004, 09:54
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50% (04:40) correct 50% (01:43) wrong based on 1 sessions

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I am in the process of packing boxes onto my lorry (truck). I cannot load box A onto the lorry because that would exceed the maximum weight allowance. On the other hand, if I unloaded box B from the lorry, I would be able to load box C on to the lorry without
exceeding the allowance.
Which of the following must be true?

I. If I didn't unload any boxes (including box B), then I wouldn't be able
to load box C onto the lorry.

II. The remaining weight that can be loaded onto the lorry must be at
least as big as the difference in weight between boxes B and C.

III. The weight of box A must be bigger than the difference in weight of
boxes B and C

I only
II only
III only
I and II only
II and III only
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29 Feb 2004, 14:42
I would go with E on this one. I solved half this problem with formula and the other half with logically plugging in numbers.
Let A = weight of box A
Let B = weight of box B
Let C = weight of box C
Let T = total weight available in the truck
Let X = total weight of all other boxes in the truck

In this problem, we have to assume that the weight ALREADY in the truck is B + X
From stem 1: A + B > T - (B + X) --> A + B > T - B - X
From stem 2: (T - X) - B > C --> T - B - X > C
Combining both formulas, we get A + B > T - B - X > C

I) says that T - B - X < C which is total opposite of the combined formula. This is false
II) At this point, I plugged in numbers. Say for instance that box B is 25 pounds and box C is 30 pounds, then in order to be able to load box C after removing box B, the available weight left on the truck must be at least 5 pounds; the difference between box B and C. This is true.
III) This says A > abs val (B - C). The combined formula from above is A + B > T - B - X > C which simplifies to A + B > C
A > C - B. This is true

Therefore, II and III are true and E is the answer
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Paul

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01 Mar 2004, 02:34
Mine answer is (C) ---> III only

Well For II II. The remaining weight that can be loaded onto the lorry must be at least as big as the difference in weight between boxes B and C.
it means you can load any weight greater than or equal to 5, (as per paul's assumption!)
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01 Mar 2004, 02:34
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