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# Help Please!!! Im stuck w this

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Let a1, a2 ,a3,...be an arithmetic sequence.

If $$a_{23} = \dfrac23 and a_{53} = \dfrac32 what is a_{35}$$

May 9, 2022

#1
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$$a_{35} = 6/5$$

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May 9, 2022
#2
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I already tried that. It's not it. im soo confused

Guest May 9, 2022
#3
+118459
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you use the formula     Tn=a+(n-1)d

$$a+22d=\frac{2}{3}\qquad (1)\\ a+52d=\frac{3}{2}\qquad (2)\\~\\ (2)-(1)\\ 30d=\frac{3}{2}-\frac{2}{3}\\ 30d=\frac{5}{6}\\ d=\frac{1}{36}\\$$

Check what i have done, then sub d in to find a

Then find  a35

Any questions? , then i am happy to discuss further.

May 9, 2022
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