A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:(i) Minor segment(ii) Major sector (Use π = 3.14)

Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OADB = () * r2

= () r2

= * 3.14 * 10 * 10

= 235.5 cm2

Area of minor sector OACB = * r2

= * 3.14 * 10 * 10

= 78.5 cm2

Area of ΔOAB = * OA * OB

= * 10 * 10

= 50 cm2

Area of minor segment ACB = Area of minor sector OACB -Area of ΔOAB

= 78.5 - 50

= 28.5 cm2

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