# If x is the square of the number when $$(\frac{2}{5}of6\frac{1}{4} \div \frac{3}{7}) of 1\frac{2}{7}$$ is divided by $$11\frac{1}{4}$$, then the value of 81x is:

Free Practice With Testbook Mock Tests

## Options:

1. 9

2. 36

3. 4

4. 16

### Correct Answer: Option 2 (Solution Below)

This question was previously asked in

SSC CHSL Previous Paper 117 (Held On: 18 March 2020 Shift 1)

## Solution:

Given:

Value of x is square of $$(\frac{2}{5}of6\frac{1}{4} \div \frac{3}{7}) of 1\frac{2}{7}$$$$11\frac{1}{4}$$

Formula used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

Value of x is square of $$(\frac{2}{5}of6\frac{1}{4} \div \frac{3}{7}) of 1\frac{2}{7}$$$$11\frac{1}{4}$$

⇒ $$(\frac{2}{5}of6\frac{1}{4} \div \frac{3}{7}) of 1\frac{2}{7}$$$$11\frac{1}{4}$$

⇒ $$(\frac{2}{5}of\frac{25}{4} \div \frac{3}{7}) of \frac{9}{7}$$$$\frac{45}{4}$$

⇒ $$(\frac{5}{2} \div \frac{3}{7}) × \frac{9}{7}$$$$\frac{45}{4}$$

⇒ $$\frac{35}{6} × \frac{9}{7} \div \frac{45}{4}$$

⇒ $$\frac{35}{6} × \frac{9}{7} × \frac{4}{45}$$

⇒ 2/3

Value of x is square of 2/3 = 4/9

Value of 81x is

⇒ 81 × (4/9) = 36

∴ value of 81x is 36
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}