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If a car hits a wall at thea speed of v$$v$$, and an identical car hits a wall at a speed of 2v$$2\,v$$, with the kinetic energy equation KE = 1/2mv^2$$E_K = \frac{1}{2}mv^2$$ (the speed goes from v$$v$$ to 0$$0$$) the second car will lose 4 times the energy, and therefore cause 4 times the damage, but with the force equation F = ma$$F = ma$$ (the car hits the wall and decelerates), it will hit with 2 times the force, and cause 2 times the damage.

How can this be explained?

If a car hits a wall at the speed of v, and an identical car hits a wall at a speed of 2v, with the kinetic energy equation KE = 1/2mv^2 (the speed goes from v to 0) the second car will lose 4 times the energy, and therefore cause 4 times the damage, but with the force equation F = ma (the car hits the wall and decelerates), it will hit with 2 times the force, and cause 2 times the damage. How can this be explained?

If a car hits a wall at a speed of $$v$$, and an identical car hits a wall at a speed of $$2\,v$$, with the kinetic energy equation $$E_K = \frac{1}{2}mv^2$$ (the speed goes from $$v$$ to $$0$$) the second car will lose 4 times the energy, and therefore cause 4 times the damage, but with the force equation $$F = ma$$ (the car hits the wall and decelerates), it will hit with 2 times the force, and cause 2 times the damage.

How can this be explained?

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# Please help understanding the difference between force and kinetic energy for an object hitting a wall?

If a car hits a wall at the speed of v, and an identical car hits a wall at a speed of 2v, with the kinetic energy equation KE = 1/2mv^2 (the speed goes from v to 0) the second car will lose 4 times the energy, and therefore cause 4 times the damage, but with the force equation F = ma (the car hits the wall and decelerates), it will hit with 2 times the force, and cause 2 times the damage. How can this be explained?
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