# The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is

Question : The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is

(A) $1-\left( \dfrac{4}{5}\right) ^{10}$

(B) $\left( \dfrac{1}{5}\right) ^{10}$

(C) $1-\left( \dfrac{1}{5}\right) ^{10}$

(D) $\left( \dfrac{4}{5}\right) ^{10}$

The probability of hitting a target is $p=\dfrac{1}{5}$.
Therefore, the probability of not hitting a target is $q=1-\dfrac{1}{5}=\dfrac{4}{5}$.
Hence, the required probability is $1-\left( \dfrac{4}{5}\right) ^{10}$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 7, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}