  series\: can\: be\: written\: in\: the\: following\: way\: also:\\ (3 * 1^2), (5 * 2^2), (7 * 3^2), (9 * 4^2), .......up t n terms\\ Tn = (\:General\; term\; of \;series\; 3, 5, 7, 9 ....\;)\; X\; (\;General\; term\; of\; series\; 1^2, 2^2, 3^2, 4^2 ....\;)\\ Tn = (3 + (n-1) * 2) X ( n^2 )\\ Tn = 2*n^3 + n^2  