From savicky at cs.cas.cz  Thu Dec 31 11:17:36 2009
From: savicky at cs.cas.cz (Petr Savicky)
Date: Thu, 31 Dec 2009 11:17:36 +0100
Subject: [Rd] seq.int broken (seq as well) (PR#14169)
In-Reply-To: <20091228195013.29A1E282EF4F@mail.pubhealth.ku.dk>
References: <20091228195013.29A1E282EF4F@mail.pubhealth.ku.dk>
Message-ID: <20091231101736.GC10897@cs.cas.cz>

On Mon, Dec 28, 2009 at 08:50:13PM +0100, oehl_list at gmx.de wrote:
[...]
> # fine as expected from help page: 
> # "from+by, ..., up to the sequence value less than or equal to to"
> # thus 1+10=11 is not in
> > seq.int(1L, 10L, by=10L)
> [1] 1
> 
> # of course 1+1e7 should also not be in
> # but is: wrong
> > seq.int(1L, 1e7L, by=1e7L)
> [1] 1e+00 1e+07
> 
> # since we use seq.int AND are within integer range, rounding should not be an
> issue

In my opinion, this is a documented behavior. The Details section of the help
page says

     Note that the computed final value
     can go just beyond 'to' to allow for rounding error, but (as from
     R 2.9.0) is truncated to 'to'.

Since "by" is 1e7, going by 1 more than 'to' is "just beyond 'to'".

What can be a bit misleading is the following difference between the type
of seq() and seq.int(), which is only partially documented.

  x <- seq.int(from=1L, to=10000000L, by=10000000L); typeof(x); x
  # [1] "double"
  # [1] 1e+00 1e+07

  x <- seq(from=1L, to=10000000L, by=10000000L); typeof(x); x
  # [1] "integer"
  # [1]        1 10000000

The Value section of the help page says:

     Currently, 'seq.int' and the default method of 'seq' return a
     result of type '"integer"' (if it is representable as that and) if
     'from' is (numerically equal to an) integer and, e.g., only 'to'
     is specified, or also if only 'length' or only 'along.with' is
     specified.  *Note:* this may change in the future and programmers
     should not rely on it.

This suggests that we should get "double" in both cases, since all three
arguments "from", "to", and "by" are specified. I do not know, whether
having an "integer" result in seq() in the above case is intended or not.

Petr Savicky.



[Rd] seq.int broken (seq as well) (PR#14169)
Petr Savicky