From wsimpson@uwinnipeg.ca  Tue Jul  7 22:17:51 1998
From: wsimpson@uwinnipeg.ca (Bill Simpson)
Date: Tue, 7 Jul 1998 16:17:51 -0500 (CDT)
Subject: S speedup in R
Message-ID: <Pine.OSF.3.95.980707160152.21173A-100000@io.uwinnipeg.ca>

Venables and Ripley describe a speedup where you take a structure like

x<-NULL
for(i in sequence)
	y<-c(y,function(x,i))
	
and convert it to one like

x<-numeric(its length)
for(i in sequence)
	y[i]<-function(x,i)

I tried this speedup on some simple examples and it made them twice as
fast.

But now I am hitting a snag with some real code.

This original version works:
cif<-function(x, y, tau, h=tau[2]-tau[1])
{
# conditional cross-intensity function for two point process realizations.
# estimated at tau.
# x and y are vectors of event times (sorting is not necessary).
# tau is the lag (or vector of lags) 
# h is binwidth.
# see Brillinger, Bryant, & Segundo (1976) eq 13, mhatAB(u)
n <- length(x)
cif.numerator <- NULL
for(tt in tau)
	{
	point.counter <- sum(round(rank(c(x + tt + h/2, y))[1:n], 0) -
	round(rank(c(x + tt - h/2, y))[1:n], 0))
	cif.numerator <- c(cif.numerator,point.counter)
	}
cif.numerator/(n * h)
}

But the sped-up version just returns a vector of zeros:

cif<-function(x, y, tau, h=tau[2]-tau[1])
{
# conditional cross-intensity function for two point process realizations.
# estimated at tau.
# x and y are vectors of event times (sorting is not necessary).
# tau is the lag (or vector of lags) 
# h is binwidth.
# see Brillinger, Bryant, & Segundo (1976) eq 13, mhatAB(u)
n <- length(x)
cif.numerator <- numeric(length(tau))
for(tt in tau)
	{
	cif.numerator[tt] <- sum(round(rank(c(x + tt + h/2, y))[1:n], 0) -
	round(rank(c(x + tt - h/2, y))[1:n], 0))
	}
cif.numerator/(n * h)
}

I can't see why this isn't working. Is this hitting a peculiarity of 
R? Thanks very much for any help.

Bill Simpson

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S speedup in R
Bill Simpson