From spencer.graves at prodsyse.com  Mon Jan  9 16:01:04 2017
From: spencer.graves at prodsyse.com (Spencer Graves)
Date: Mon, 9 Jan 2017 09:01:04 -0600
Subject: [Rd] problem with print.generic(x)deparse(substitute(x))
In-Reply-To: <3cf3250f-f6bd-b3d1-a442-f2611bd41d86@prodsyse.com>
References: <f96d2039-6760-6cff-c42d-bda85015f7e0@prodsyse.com>
	<0E4497A7-60AF-4804-8BD9-66836198A7AE@gmail.com>
	<3cf3250f-f6bd-b3d1-a442-f2611bd41d86@prodsyse.com>
Message-ID: <d671cc8d-0d11-58f5-61e3-d798f3021df6@prodsyse.com>



On 2017-01-09 8:19 AM, Spencer Graves wrote:
> Hi, Peter et al.:
>
>
> On 2017-01-09 4:24 AM, peter dalgaard wrote:
>> On 09 Jan 2017, at 10:53 , Spencer Graves 
>> <spencer.graves at prodsyse.com> wrote:
>>
>>> # Define an object of class 'dum'
>>> k <- 1
>>> class(k) <- 'dum'
>>> str(k) # as expected
>>>
>>> # Define print.dum
>>> print.dum <- function(x, ...)
>>>   deparse(substitute(x))
>>>
>>> print(k) # Prints "k" as expected
>>> #####**** THE FOLLOWING PRINTS NOTHING:
>>> k # Why?
>>
>> Because it doesn't work that way...
>>
>> First of all, your print.dum relies on autoprinting of its return 
>> value, it doesn't print anything itself. That's not how one usually 
>> writes print methods: You should print something and (usually) return 
>> the argument invisibly.
>>
>> Autoprinting calls the print method to do the actual printing and 
>> returns the object invisibly, irrespective of the return value from 
>> the print method. To wit:
>>
>>> k
>>> dput(.Last.value)
>> structure(1, class = "dum")
>>
>> (Trying to print the return value would invite infinite looping.)
>>
>> However, there's another catch: deparse(substitute(...)) relies on 
>> knowing the argument to print() before evaluation, but autoprinting 
>> does not retain that information, it just looks at the object that 
>> has been computed and passes it to the relevant print method, so you 
>> get this effect:
>>
>>> print.dum <- function(x, ...)
>> +  print(deparse(substitute(x)))
>>> k
>> [1] "x"
>
>       Thanks.  Permit me to ask my real question:  Is there a way to 
> modify print.findFn{sos} so I can print "k" in the second line of the 
> HTML from the following:
>
>
> (k <- findFn('spline', 1))
>
>
>       Currently, the HTML starts as follows:
>
>
> findFunction Results
> call: findFn(string = "spline", maxPages = 1)
>
>
>       I want it to start as follows:
>
>
> findFn Results
>
> call: (k <- findFn(string = "spline", maxPages = 1))
> For a package summary:  installPackages(k); writeFindFn2xls(k)
>
>
>       When I added "ds <- deparse(substitute(x))" to "print.findFn", I 
> got ds = "x", not "k" from "(k <- findFn('spline', 1))" and from "k" 
> by itself (autoprint) but 

> "k" [correction;  please excuse] from "print(k)". Thanks to Peter for 
> explaining this problem.  Is there a work around?
>
>
>       Spencer
>
>> -pd
>>
>>
>>
>
> ______________________________________________
> R-devel at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-devel



[Rd] problem with print.generic(x)deparse(substitute(x))
Spencer Graves