From wolbers@stat.math.ethz.ch  Fri Jun  1 12:47:18 2001
From: wolbers@stat.math.ethz.ch (wolbers@stat.math.ethz.ch)
Date: Fri, 1 Jun 2001 13:47:18 +0200 (MET DST)
Subject: [Rd] v matrix of svd(X) loses dimensions if nrow(X)==1 (PR#963)
Message-ID: <200106011147.NAA00152@pubhealth.ku.dk>

Dear R-developers

I'm not very sure whether this is really a bug and not a feature:

> is.matrix(svd(matrix(1:12,nrow=1))$v)  
[1] FALSE

In all other cases the $v component is a matrix. Also, the $u component
always seems to be a matrix as indicated in the doc.

My R-version:
> version
         _                
platform i686-pc-linux-gnu
arch     i686             
os       linux-gnu        
system   i686, linux-gnu  
status                    
major    1                
minor    2.3              
year     2001             
month    04               
day      26               
language R  

Yours
Marcel Wolbers

PS: 
- On S-Plus Version 5.1 Release 1 for Linux 2.0.31 : 1999 
  > is.matrix(svd(matrix(1:12,nrow=1))$v)
  [1] T
- Thanks a lot for the great piece of software you've written

-- 
Marcel Wolbers, LEO C14, Seminar for Statistics, ETH Zurich
CH-8092 Zurich, Switzerland; phone: (01) 632 2252	

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[Rd] v matrix of svd(X) loses dimensions if nrow(X)==1 (PR#963)
wolbers@stat.math.ethz.ch