From c.farrow@compserv.gla.ac.uk  Fri Feb 25 14:19:43 2000
From: c.farrow@compserv.gla.ac.uk (c.farrow@compserv.gla.ac.uk)
Date: Fri, 25 Feb 2000 15:19:43 +0100 (MET)
Subject: [Rd] bug and fix : using panel.first with plot() in do.call() (PR#457)
Message-ID: <200002251419.PAA13937@pubhealth.ku.dk>

The following works as expected
        plot(1:5, panel.first=grid(2,2))
and if
        my.panel<-function() grid(2,2)
then
        plot(1:5, panel.first=my.panel() )
is also OK

but, 
        do.call("plot", list(x=1:5, panel.first=grid(2,2))
        do.call("plot", list(x=1:5, panel.first=my.panel)) 
        do.plot("plot", list(x=1:5, panel.first=my.panel() ))
do not draw the grid because the panel.first expression is evaluated
before the plot gets drawn.


A solution is to modify plot.default such that the line

panel.first
is replaced by

if(is.function(panel.first)) {
        panel.first()
}else {
        panel.first
}
This allows the previous behaviour, but also allows a function name to
be passed to plot using do.call()
now all the following produce the expected graph
plot(1:5, panel.first=grid(2,2))
plot(1:5, panel.first=my.panel())
plot(1:5,panel.first=my.panel)

do.call("plot", list(x=1:5, panel.first=my.panel ))

Similarly the line 

panel.last 
should be replaced by 
if(is.function(panel.last)) {
        panel.last()
} else {
panel.last
}

As far as I am aware this affects all recent versions.
Cheers, Colin.


-- 
Colin Farrow
Computing Service, University of Glasgow, Glasgow G12 8QQ
Tel: 0141 330 4862, c.farrow@compserv.gla.ac.uk

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[Rd] bug and fix : using panel.first with plot() in do.call() (PR#457)
c.farrow@compserv.gla.ac.uk