From hb at biostat.ucsf.edu  Fri May  2 18:54:33 2014
From: hb at biostat.ucsf.edu (Henrik Bengtsson)
Date: Fri, 2 May 2014 09:54:33 -0700
Subject: [Rd] How to test if an object/argument is "parse tree" -
 without evaluating it?
In-Reply-To: <7DB406E2-F74E-4BE2-9E4D-4EA82EC865FD@gmail.com>
References: <CAFDcVCRpqqPkhFhaNpqe3ye-jo-8sWOODShKHneonTSB7m5Uvg@mail.gmail.com>
	<7DB406E2-F74E-4BE2-9E4D-4EA82EC865FD@gmail.com>
Message-ID: <CAFDcVCQxhdQTxUt57Z09JtN-JvSDn2Vdk2O9rYk8gX25u64E4w@mail.gmail.com>

Thank you all for great feedback - very helpful.

They view was great half way up the tree, but I'll add this one to "It
may be possible, but don't do it. Rethink what you're doing".

Hadley touches on this in his write up
[http://adv-r.had.co.nz/Computing-on-the-language.html#calling-from-another-function].


On Thu, May 1, 2014 at 2:44 PM, peter dalgaard <pdalgd at gmail.com> wrote:
> My take would be that this is barking up the wrong tree. If you want to pass expressions in a way that a function can recognize, use formulas or expression objects.
>
> One problem is that pretty much every unevaluated argument is a "parse tree". The only other thing it can be is a constant object, but that is really just the simplest possible parse tree.
>
> In what situation exactly were you expecting isParseTree to return FALSE?

I guess this (and Duncan's) question is more of a rhetorical kind,
which is also what I hoped for, but specifically I wanted to test it
on the 'expr0' object as in my example.

Thanks,

Henrik

PS. Duncan, I was trying find a good name for it and got "parse tree"
from ?substitute.

>
> -pd
>
>
> On 01 May 2014, at 22:39 , Henrik Bengtsson <hb at biostat.ucsf.edu> wrote:
>
>> This may have been asked before, but is there an elegant way to check
>> whether an variable/argument passed to a function is a "parse tree"
>> for an (unevaluated) expression or not, *without* evaluating it if
>> not?
>>
>> Currently, I do various rather ad hoc eval()+substitute() tricks for
>> this that most likely only work under certain circumstances. Ideally,
>> I'm looking for a isParseTree() function such that I can call:
>>
>> expr0 <- foo({ x <- 1 })
>> expr1 <- foo(expr0)
>> stopifnot(identical(expr1, expr0))
>>
>> where foo() is:
>>
>> foo <- function(expr) {
>> if (!isParseTree(expr))
>>   expr <- substitute(expr)
>> expr
>> }
>>
>> I also want to be able to do:
>>
>> expr2 <- foo(foo(foo(foo(expr0))))
>> stopifnot(identical(expr2, expr0))
>>
>> and calling foo() from within other functions that may use the same
>> "tricks".  The alternative is of course to do:
>>
>> foo <- function(expr, substitute=TRUE) {
>> if (substitute) expr <- substitute(expr)
>> expr
>> }
>>
>> but it would be neat to do this without passing an extra argument.  If
>> this is not possible to implement in plain R, can this be done
>> internally inspecting SEXP:s and so on?  Even better would be if
>> substitute() could do this for me, e.g.
>>
>> expr <- substitute(expr, unlessAlreadyDone=TRUE)
>>
>> Any suggestions?
>>
>> Thanks,
>>
>> Henrik
>>
>> ______________________________________________
>> R-devel at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-devel
>
> --
> Peter Dalgaard, Professor,
> Center for Statistics, Copenhagen Business School
> Solbjerg Plads 3, 2000 Frederiksberg, Denmark
> Phone: (+45)38153501
> Email: pd.mes at cbs.dk  Priv: PDalgd at gmail.com
>
>
>
>
>
>
>
>



[Rd] How to test if an object/argument is "parse tree" - without evaluating it?
Henrik Bengtsson