直线 $x+y-1=0$ 上与点 $P(-2,3)$ 的距离等于 $\sqrt{2}$ 的点的坐标是 $(\quad)$
求点的坐标为 $\left(x_{0}, y_{0}\right)$, 有

$x_{0}+y_{0}-1=0$, 且 $\sqrt{\left(x_{0}+2\right)^{2}+\left(y_{0}-3\right)^{2}}=\sqrt{2}$,

两式联立解得 $\left\{\begin{array}{l}x_{0}=-3, \\ y_{0}=4\end{array}\right.$ 或 $\left\{\begin{array}{l}x_{0}=-1, \\ y_{0}=2 .\end{array}\right.$ 故选 C.