若 $x_{1}, x_{2}$ 是方程 $2^{x}=\left(\frac{1}{2}\right)^{-\frac{1}{x}+1}$ 的两个实数解, 则 $x_{1}+x_{2}=$
because 2^{x}=\left(\frac{1}{2}\right)^{-\frac{1}{x}+1}$,

$\therefore 2^{x}=2^{\frac{1}{x}-1}, \therefore x=\frac{1}{x}-1$,

$\therefore x^{2}+x-1=0$.
$\therefore x_{1}+x_{2}=-1$.

答案: -1