如图, $A B / / C D, E F$ 分别与 $A B, C D$ 交于点 $B, F$.若 $\angle E=30^{\circ}, \angle E F C=130^{\circ}$, 则 $\angle A=$ $\qquad$ .

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解【答案】 $20^{\circ}$

【解析】解: $\because A B / / C D$,

$\therefore \angle A B F+\angle E F C=180^{\circ}$,

$\because \angle E F C=130^{\circ}$,

$\therefore \angle A B F=50^{\circ}$,

$\because \angle A+\angle E=180^{\circ}-\angle A B E=\angle A B F=50^{\circ}, \angle E=30^{\circ}$,

$\therefore \angle A=20^{\circ}$.

故答案为: $20^{\circ}$.