8.如图，<ImageHere>终边在阴影部分内的角的集合为
先写出边界角, 再按逆时针顺序写出区域角, 则得 $\left\{\alpha \mid 30^{\circ}+k \cdot 360^{\circ} \leqslant \alpha \leqslant 150^{\circ}+k \cdot 360^{\circ}, k \in \mathbf{Z}\right\}$.

答案: $\left\{\alpha \mid 30^{\circ}+k \cdot 360^{\circ} \leqslant \alpha \leqslant 150^{\circ}+k \cdot 360^{\circ}, k \in \mathbf{Z}\right\}$