The number of upbeat metropolis comedy in Rêves de Belleville equals the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont exists, and its number is greater than 0. The total number of movies in Festival Lumière de Valmont equals 9. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4 plus the difference between the total number of movies in Rêves de Belleville and the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 4.

Question: How many intense detective thriller does Festival Lumière de Valmont have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Rêves de Belleville as K; so K = 4. Define upbeat metropolis comedy in Rêves de Belleville as y; so y = K = 4. Define total number of movies in Rêves de Belleville as O; so O = y + K = 4 + 4 = 8. Define upbeat metropolis comedy in Festival Lumière de Valmont as Y; t = O - K = (8) - (4) = 4; so Y = 4 + t = 4 + 4 = 8. Define intense detective thriller in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival Lumière de Valmont as M; so M = Y + x = 8 + x = x + 8. We know M = 9, so we have x + 8 = 9 and we solve it through the following steps: Simplifying the equation: x + 8 = 9. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of adult owl in Beverly Forest equals 4. The number of adult owl in Cedar Valley equals 2 times the difference between the total number of adult animals in Beverly Forest and the number of adult eagle in Beverly Forest. The number of adult eagle in Beverly Forest equals the number of adult owl in Beverly Forest. The number of adult eagle in Cedar Valley equals the number of adult eagle in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult owl in Beverly Forest as E; so E = 4. Define adult eagle in Beverly Forest as J; so J = E = 4. Define total number of adult animals in Beverly Forest as q; so q = J + E = 4 + 4 = 8. Define adult owl in Cedar Valley as h; v = q - J = 8 - 4 = 4; so h = 2 * v = 2 * 4 = 8. Define adult eagle in Cedar Valley as p; so p = J = 4. Define total number of adult animals in Cedar Valley as j; so j = p + h = 4 + 8 = 12. Answer: 12.


The number of public highschool in Shoreline City equals 2 plus the sum of the total number of schools in Riverton City, the number of public highschool in Riverton City, and the number of elementary school in Riverton City. The number of public highschool in Riverton City equals 3. The number of elementary school in Riverton City equals 4 plus the number of public highschool in Riverton City.

Question: What is the total number of schools in Shoreline City?

Solution: Define public highschool in Riverton City as Q; so Q = 3. Define elementary school in Riverton City as k; s = Q = 3; so k = 4 + s = 4 + 3 = 7. Define total number of schools in Riverton City as e; so e = Q + k = 3 + 7 = 10. Define public highschool in Shoreline City as u; b = e + Q = 10 + 3 = 13; V = b + k = 13 + 7 = 20; so u = 2 + V = 2 + 20 = 22. Define total number of schools in Shoreline City as q; so q = u = 22. Answer: 22.


The number of adult owl in South Zoo equals 4. The number of adult blue jay in South Zoo equals 4 plus the number of adult owl in South Zoo. The number of adult owl in Bundle Ranch equals 3 times the total number of adult animals in South Zoo. The number of adult eagle in Bundle Ranch equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult owl in South Zoo as Q; so Q = 4. Define adult blue jay in South Zoo as C; W = Q = 4; so C = 4 + W = 4 + 4 = 8. Define total number of adult animals in South Zoo as R; so R = C + Q = 8 + 4 = 12. Define adult owl in Bundle Ranch as c; M = R = 12; so c = 3 * M = 3 * 12 = 36. Define adult eagle in Bundle Ranch as y; so y = 4. Define total number of adult animals in Bundle Ranch as X; so X = y + c = 4 + 36 = 40. Answer: 40.


The number of culinarian school in Riverton City equals 2. The number of regional medical school in Riverton City equals 1. The number of culinarian school in Ruby Bay equals the sum of the number of culinarian school in Shoreline City, the number of regional medical school in Oakbridge City, and the number of regional medical school in Riverton City. The number of private middle school in Ruby Bay equals 4 times the total number of schools in Oakbridge City. The number of elementary school in Oakbridge City exists, and its number is greater than 0. The number of private middle school in Oakbridge City equals the number of public highschool in Oakbridge City. The number of culinarian school in Shoreline City equals 2. The number of regional medical school in Shoreline City equals 3 times the total number of schools in Oakbridge City. The number of regional medical school in Oakbridge City equals the number of public highschool in Oakbridge City. The number of culinarian school in Oakbridge City equals 3. The total number of schools in Oakbridge City equals 15. The number of elementary school in Ruby Bay equals 2. The number of public highschool in Riverton City equals 2 plus the sum of the number of regional medical school in Riverton City and the number of elementary school in Ruby Bay. The number of private middle school in Shoreline City equals 3. The number of private middle school in Riverton City equals the number of elementary school in Ruby Bay. The number of public highschool in Oakbridge City equals the number of culinarian school in Oakbridge City.

Question: How many elementary school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Oakbridge City as W; so W = 3. Define public highschool in Oakbridge City as M; so M = W = 3. Define private middle school in Oakbridge City as e; so e = M = 3. Define elementary school in Oakbridge City as x; we don't know its value yet but will find it out later. Define regional medical school in Oakbridge City as N; so N = M = 3. Define total number of schools in Oakbridge City as k; b = N + W = 3 + 3 = 6; J = b + M = 6 + 3 = 9; c = J + e = 9 + 3 = 12; so k = c + x = 12 + x = x + 12. We know k = 15, so we have x + 12 = 15 and we solve it through the following steps: Simplifying the equation: x + 12 = 15. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of adult wolf in South Zoo equals 1. The number of adult fox in South Zoo equals 3 times the number of adult wolf in South Zoo. The number of adult fox in Bundle Ranch equals 2 plus the sum of the total number of adult animals in South Zoo, the number of adult wolf in South Zoo, and the number of adult fox in South Zoo.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult wolf in South Zoo as L; so L = 1. Define adult fox in South Zoo as g; j = L = 1; so g = 3 * j = 3 * 1 = 3. Define total number of adult animals in South Zoo as F; so F = L + g = 1 + 3 = 4. Define adult fox in Bundle Ranch as w; q = F + L = 4 + 1 = 5; r = q + g = 5 + 3 = 8; so w = 2 + r = 2 + 8 = 10. Define total number of adult animals in Bundle Ranch as a; so a = w = 10. Answer: 10.


The number of adult wolf in Hamilton Farm equals 2 times the number of adult fox in Jefferson Circus. The number of adult racoon in Mayer Aquarium equals 1. The number of adult fox in Mayer Aquarium equals the difference between the number of adult fox in Jefferson Circus and the number of adult wolf in Hamilton Farm. The number of adult fox in Bundle Ranch equals 4 plus the sum of the number of adult racoon in Mayer Aquarium and the number of adult deer in Bundle Ranch. The number of adult deer in South Zoo equals 2. The number of adult deer in Hamilton Farm equals the sum of the number of adult fox in Mayer Aquarium and the number of adult fox in Jefferson Circus. The number of adult fox in South Zoo equals the number of adult fox in Bundle Ranch. The number of adult deer in Jefferson Circus equals 1. The number of adult racoon in Bundle Ranch equals the difference between the number of adult fox in Bundle Ranch and the number of adult racoon in Mayer Aquarium. The number of adult wolf in Jefferson Circus equals 3 times the sum of the number of adult fox in Mayer Aquarium, the number of adult racoon in Mayer Aquarium, and the number of adult racoon in Bundle Ranch. The number of adult racoon in Jefferson Circus equals the sum of the number of adult racoon in Bundle Ranch and the number of adult fox in South Zoo. The number of adult fox in Jefferson Circus equals 3. The number of adult deer in Bundle Ranch equals the number of adult racoon in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult racoon in Mayer Aquarium as Q; so Q = 1. Define adult deer in Bundle Ranch as i; so i = Q = 1. Define adult fox in Bundle Ranch as D; E = Q + i = 1 + 1 = 2; so D = 4 + E = 4 + 2 = 6. Define adult racoon in Bundle Ranch as O; so O = D - Q = 6 - 1 = 5. Define total number of adult animals in Bundle Ranch as d; w = O + D = 5 + 6 = 11; so d = w + i = 11 + 1 = 12. Answer: 12.


The number of adult deer in Maple Creek equals 4. The number of adult wolf in Maple Creek equals 1. The number of adult fox in Oakridge Riverside equals 2 plus the difference between the number of adult deer in Maple Creek and the number of adult deer in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals the sum of the number of adult fox in Oakridge Riverside and the number of adult deer in Maple Creek. The number of adult fox in Maple Creek equals 2. The number of adult deer in Oakridge Riverside equals the number of adult deer in Maple Creek.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult deer in Maple Creek as y; so y = 4. Define adult deer in Oakridge Riverside as J; so J = y = 4. Define adult fox in Oakridge Riverside as A; D = y - J = 4 - 4 = 0; so A = 2 + D = 2 + 0 = 2. Define adult wolf in Oakridge Riverside as q; so q = A + y = 2 + 4 = 6. Define total number of adult animals in Oakridge Riverside as F; p = J + A = 4 + 2 = 6; so F = p + q = 6 + 6 = 12. Answer: 12.


The number of intense detective thriller in West Sahara Movie Festival equals the difference between the number of futuristic sci-fi movie in West Sahara Movie Festival and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 4 times the difference between the number of intense detective thriller in West Sahara Movie Festival and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The total number of movies in West Sahara Movie Festival equals 14. The number of calm road movie in Taylor Movie Festival equals 3 plus the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4. The number of solemn period drama in Golden Banana Movie Festival equals 2 times the difference between the number of futuristic sci-fi movie in West Sahara Movie Festival and the number of intense detective thriller in Taylor Movie Festival.

Question: How many upbeat metropolis comedy does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Verdi Movie Festival as r; so r = x = x. Define total number of movies in Verdi Movie Festival as H; so H = r = x. Define solemn period drama in Northwood Movie Festival as b; v = H = x; so b = 4 * v = (4) * (x) = 4*x. Define futuristic sci-fi movie in West Sahara Movie Festival as e; so e = b = 4*x. Define intense detective thriller in West Sahara Movie Festival as w; so w = e - x = (4*x) - (x) = 3*x. Define total number of movies in West Sahara Movie Festival as W; so W = w + e = 3*x + 4*x = 7*x. We know W = 14, so we have 7*x = 14 and we solve it through the following steps: Simplifying the equation: 7*x = 14. Move all terms to one side: 7*x - 14 = 0. Isolate the term with x: 7*x = 14. Divide both sides by 7: x = 14 / 7. Solution: x = 2. Answer: 2.


The number of regional medical school in Hawkesbury equals 3 plus the sum of the total number of schools in Westhaven City and the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 1. The number of elementary school in Evervale City equals the sum of the total number of schools in Hawkesbury, the number of culinarian school in Westhaven City, and the number of regional medical school in Hawkesbury.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Westhaven City as L; so L = 1. Define total number of schools in Westhaven City as U; so U = L = 1. Define regional medical school in Hawkesbury as y; Y = U + L = 1 + 1 = 2; so y = 3 + Y = 3 + 2 = 5. Define total number of schools in Hawkesbury as P; so P = y = 5. Define elementary school in Evervale City as C; c = P + L = 5 + 1 = 6; so C = c + y = 6 + 5 = 11. Define total number of schools in Evervale City as x; so x = C = 11. Answer: 11.


The number of adult blue jay in Hamilton Farm exists, and its number is greater than 0. The number of adult blue jay in Mayer Aquarium equals 2. The number of adult parrot in Mayer Aquarium equals the number of adult blue jay in Mayer Aquarium. The total number of adult animals in Hamilton Farm equals 11. The number of adult parrot in Hamilton Farm equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult blue jay in Mayer Aquarium, and the number of adult parrot in Mayer Aquarium.

Question: How many adult blue jay does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Mayer Aquarium as y; so y = 2. Define adult parrot in Mayer Aquarium as g; so g = y = 2. Define total number of adult animals in Mayer Aquarium as H; so H = y + g = 2 + 2 = 4. Define adult parrot in Hamilton Farm as L; m = H + y = 4 + 2 = 6; so L = m + g = 6 + 2 = 8. Define adult blue jay in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as o; so o = x + L = x + 8 = x + 8. We know o = 11, so we have x + 8 = 11 and we solve it through the following steps: Simplifying the equation: x + 8 = 11. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of intense detective thriller in Golden Banana Movie Festival exists, and its number is greater than 0. The total number of movies in West Sahara Movie Festival equals 40. The number of intense detective thriller in Golden Banana Movie Festival exists, and its number is greater than 0. The number of calm road movie in Golden Banana Movie Festival equals 4 plus the number of intense detective thriller in Golden Banana Movie Festival.

Question: How many intense detective thriller does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Golden Banana Movie Festival as h; Z = x = x; so h = 4 + Z = 4 + x = x + 4. Define total number of movies in Golden Banana Movie Festival as Q; so Q = h + x = x + 4 + x = 2*x + 4. Define intense detective thriller in West Sahara Movie Festival as f; z = Q + x = 2*x + 4 + x = 3*x + 4; V = z + h = 3*x + 4 + x + 4 = 4*x + 8; so f = 2 * V = (2) * (4*x + 8) = 8*x + 16. Define total number of movies in West Sahara Movie Festival as K; so K = f = 8*x + 16. We know K = 40, so we have 8*x + 16 = 40 and we solve it through the following steps: Simplifying the equation: 8*x + 16 = 40. Move all terms to one side: 8*x - 24 = 0. Isolate the term with x: 8*x = 24. Divide both sides by 8: x = 24 / 8. Solution: x = 3. Answer: 3.


The number of regional medical school in Shoreline City equals 3 times the number of private middle school in Clearwater Bay. The number of regional medical school in Riverton City equals the sum of the number of culinarian school in Clearwater Bay, the number of regional medical school in Clearwater Bay, and the number of culinarian school in Riverton City. The number of private middle school in Clearwater Bay equals 3. The number of culinarian school in Riverton City equals 4 plus the difference between the number of regional medical school in Clearwater Bay and the number of culinarian school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals the number of culinarian school in Clearwater Bay. The number of private middle school in Shoreline City equals the number of culinarian school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals 3. The number of culinarian school in Shoreline City equals 2 plus the number of private middle school in Shoreline City.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Clearwater Bay as y; so y = 3. Define regional medical school in Clearwater Bay as T; so T = y = 3. Define culinarian school in Riverton City as C; l = T - y = 3 - 3 = 0; so C = 4 + l = 4 + 0 = 4. Define regional medical school in Riverton City as G; O = y + T = 3 + 3 = 6; so G = O + C = 6 + 4 = 10. Define total number of schools in Riverton City as i; so i = G + C = 10 + 4 = 14. Answer: 14.


The number of public highschool in Shoreline City equals 3 plus the sum of the number of private middle school in Riverton City and the number of public highschool in Riverton City. The number of public highschool in Riverton City exists, and its number is greater than 0. The total number of schools in Shoreline City equals 71. The number of private middle school in Riverton City equals the number of public highschool in Riverton City. The number of private middle school in Shoreline City equals 4 times the sum of the number of public highschool in Shoreline City and the number of private middle school in Riverton City.

Question: How many public highschool does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define private middle school in Riverton City as U; so U = x = x. Define public highschool in Shoreline City as a; c = U + x = x + x = 2*x; so a = 3 + c = 3 + 2*x = 2*x + 3. Define private middle school in Shoreline City as f; P = a + U = 2*x + 3 + x = 3*x + 3; so f = 4 * P = (4) * (3*x + 3) = 12*x + 12. Define total number of schools in Shoreline City as O; so O = f + a = 12*x + 12 + 2*x + 3 = 14*x + 15. We know O = 71, so we have 14*x + 15 = 71 and we solve it through the following steps: Simplifying the equation: 14*x + 15 = 71. Move all terms to one side: 14*x - 56 = 0. Isolate the term with x: 14*x = 56. Divide both sides by 14: x = 56 / 14. Solution: x = 4. Answer: 4.


The number of culinarian school in Clearwater Bay equals 4 plus the number of public highschool in Clearwater Bay. The number of culinarian school in Shoreline City equals 1. The number of regional medical school in Oakbridge City equals 2 plus the difference between the number of culinarian school in Shoreline City and the number of culinarian school in Oakbridge City. The number of elementary school in Shoreline City equals 2 plus the difference between the number of regional medical school in Shoreline City and the number of regional medical school in Oakbridge City. The number of regional medical school in Riverton City equals 2. The number of elementary school in Oakbridge City equals 3 plus the sum of the number of culinarian school in Oakbridge City, the number of regional medical school in Shoreline City, and the number of culinarian school in Shoreline City. The number of public highschool in Oakbridge City equals 2. The number of culinarian school in Oakbridge City equals the number of public highschool in Oakbridge City. The number of regional medical school in Shoreline City equals 4 times the number of culinarian school in Clearwater Bay. The number of public highschool in Riverton City equals 4 plus the number of public highschool in Oakbridge City. The number of culinarian school in Riverton City equals 3. The number of elementary school in Clearwater Bay exists, and its number is greater than 0. The number of public highschool in Clearwater Bay equals the number of elementary school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 3 times the number of elementary school in Clearwater Bay. The total number of schools in Clearwater Bay equals 10. The number of elementary school in Riverton City equals 2.

Question: How many elementary school does Clearwater Bay have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define public highschool in Clearwater Bay as i; so i = x = x. Define regional medical school in Clearwater Bay as n; v = x = x; so n = 3 * v = (3) * (x) = 3*x. Define culinarian school in Clearwater Bay as m; e = i = x; so m = 4 + e = 4 + x = x + 4. Define total number of schools in Clearwater Bay as D; I = x + m = x + x + 4 = 2*x + 4; p = I + i = 2*x + 4 + x = 3*x + 4; so D = p + n = 3*x + 4 + 3*x = 6*x + 4. We know D = 10, so we have 6*x + 4 = 10 and we solve it through the following steps: Simplifying the equation: 6*x + 4 = 10. Move all terms to one side: 6*x - 6 = 0. Isolate the term with x: 6*x = 6. Divide both sides by 6: x = 6 / 6. Solution: x = 1. Answer: 1.


The number of adult wolf in Bundle Ranch equals 3 plus the total number of adult animals in Jefferson Circus. The number of adult deer in Jefferson Circus equals 4 times the number of adult wolf in Jefferson Circus. The number of adult deer in Bundle Ranch exists, and its number is greater than 0. The total number of adult animals in Bundle Ranch equals 14. The number of adult wolf in Jefferson Circus equals 2.

Question: How many adult deer does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Jefferson Circus as h; so h = 2. Define adult deer in Jefferson Circus as G; I = h = 2; so G = 4 * I = (4) * (2) = 8. Define total number of adult animals in Jefferson Circus as D; so D = G + h = 8 + 2 = 10. Define adult deer in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult wolf in Bundle Ranch as y; f = D = 10; so y = 3 + f = 3 + 10 = 13. Define total number of adult animals in Bundle Ranch as g; so g = x + y = x + 13 = x + 13. We know g = 14, so we have x + 13 = 14 and we solve it through the following steps: Simplifying the equation: x + 13 = 14. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of public highschool in Ruby Bay equals 2. The number of regional medical school in Clearwater Bay exists, and its number is greater than 0. The total number of schools in Shoreline City equals 25. The number of private middle school in Clearwater Bay equals the number of regional medical school in Clearwater Bay. The number of public highschool in Shoreline City equals 3 times the number of regional medical school in Clearwater Bay. The number of public highschool in Clearwater Bay equals the sum of the number of private middle school in Shoreline City and the total number of schools in Shoreline City. The number of regional medical school in Shoreline City equals the number of regional medical school in Clearwater Bay. The number of private middle school in Ruby Bay equals 2. The number of private middle school in Shoreline City equals 1 plus the sum of the number of public highschool in Shoreline City and the number of regional medical school in Clearwater Bay.

Question: How many regional medical school does Clearwater Bay have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define public highschool in Shoreline City as w; P = x = x; so w = 3 * P = (3) * (x) = 3*x. Define private middle school in Shoreline City as b; N = w + x = 3*x + x = 4*x; so b = 1 + N = 1 + 4*x = 4*x + 1. Define regional medical school in Shoreline City as J; so J = x = x. Define total number of schools in Shoreline City as S; H = w + b = 3*x + 4*x + 1 = 7*x + 1; so S = H + J = 7*x + 1 + x = 8*x + 1. We know S = 25, so we have 8*x + 1 = 25 and we solve it through the following steps: Simplifying the equation: 8*x + 1 = 25. Move all terms to one side: 8*x - 24 = 0. Isolate the term with x: 8*x = 24. Divide both sides by 8: x = 24 / 8. Solution: x = 3. Answer: 3.


The number of adult fox in Bundle Ranch equals the total number of adult animals in Mayer Aquarium. The number of adult deer in Mayer Aquarium exists, and its number is greater than 0. The number of adult wolf in Jefferson Circus equals the sum of the total number of adult animals in Bundle Ranch and the total number of adult animals in Mayer Aquarium. The number of adult deer in Jefferson Circus equals 3 plus the total number of adult animals in Mayer Aquarium. The total number of adult animals in Jefferson Circus equals 6.

Question: How many adult deer does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult deer in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define total number of adult animals in Mayer Aquarium as u; so u = x = x. Define adult fox in Bundle Ranch as w; so w = u = x. Define total number of adult animals in Bundle Ranch as z; so z = w = x. Define adult wolf in Jefferson Circus as J; so J = z + u = x + x = 2*x. Define adult deer in Jefferson Circus as Y; R = u = x; so Y = 3 + R = 3 + x = x + 3. Define total number of adult animals in Jefferson Circus as F; so F = J + Y = 2*x + x + 3 = 3*x + 3. We know F = 6, so we have 3*x + 3 = 6 and we solve it through the following steps: Simplifying the equation: 3*x + 3 = 6. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.


The number of adult owl in Cedar Valley equals 2. The number of adult parrot in Pine Ridge equals 3 plus the sum of the total number of adult animals in Cedar Valley, the number of adult owl in Cedar Valley, and the number of adult parrot in Cedar Valley. The number of adult parrot in Cedar Valley equals 2 plus the number of adult owl in Cedar Valley.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult owl in Cedar Valley as E; so E = 2. Define adult parrot in Cedar Valley as w; v = E = 2; so w = 2 + v = 2 + 2 = 4. Define total number of adult animals in Cedar Valley as R; so R = w + E = 4 + 2 = 6. Define adult parrot in Pine Ridge as I; r = R + E = 6 + 2 = 8; o = r + w = 8 + 4 = 12; so I = 3 + o = 3 + 12 = 15. Define total number of adult animals in Pine Ridge as c; so c = I = 15. Answer: 15.


The number of adult fox in Hamilton Farm exists, and its number is greater than 0. The number of adult fox in South Zoo equals 4 plus the difference between the total number of adult animals in Hamilton Farm and the number of adult fox in Hamilton Farm. The total number of adult animals in Mayer Aquarium equals 12. The number of adult fox in Mayer Aquarium equals 4 times the difference between the total number of adult animals in South Zoo and the number of adult fox in Hamilton Farm.

Question: How many adult fox does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as M; so M = x = x. Define adult fox in South Zoo as L; H = M - x = (x) - (x) = 0; so L = 4 + H = 4 + 0 = 4. Define total number of adult animals in South Zoo as i; so i = L = 4. Define adult fox in Mayer Aquarium as I; t = i - x = (4) - (x) = 4 - x; so I = 4 * t = (4) * (4 - x) = 16 - 4*x. Define total number of adult animals in Mayer Aquarium as c; so c = I = 16 - 4*x. We know c = 12, so we have 16 - 4*x = 12 and we solve it through the following steps: Simplifying the equation: 16 - 4*x = 12. Move all terms to one side: 4 - 4*x = 0. Isolate the term with x: -4*x = -4. Divide both sides by -4: x = -4 / -4. Solution: x = 1. Answer: 1.


The number of adult bear in Pine Ridge equals 2 times the sum of the total number of adult animals in Cedar Valley, the number of adult wolf in Cedar Valley, and the total number of adult animals in Beverly Forest. The number of adult wolf in Cedar Valley equals the sum of the total number of adult animals in Beverly Forest and the number of adult wolf in Beverly Forest. The number of adult wolf in Beverly Forest equals 3.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult wolf in Beverly Forest as o; so o = 3. Define total number of adult animals in Beverly Forest as B; so B = o = 3. Define adult wolf in Cedar Valley as c; so c = B + o = 3 + 3 = 6. Define total number of adult animals in Cedar Valley as l; so l = c = 6. Define adult bear in Pine Ridge as Q; M = l + c = 6 + 6 = 12; Y = M + B = 12 + 3 = 15; so Q = 2 * Y = 2 * 15 = 30. Define total number of adult animals in Pine Ridge as R; so R = Q = 30. Answer: 30.


The number of adult racoon in Jefferson Circus exists, and its number is greater than 0. The number of adult deer in Jefferson Circus equals the number of adult racoon in Jefferson Circus. The number of adult racoon in Hamilton Farm equals 3 plus the total number of adult animals in Jefferson Circus. The number of adult deer in Hamilton Farm equals the sum of the total number of adult animals in Jefferson Circus and the number of adult racoon in Jefferson Circus. The total number of adult animals in Hamilton Farm equals 23.

Question: How many adult racoon does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult deer in Jefferson Circus as T; so T = x = x. Define total number of adult animals in Jefferson Circus as v; so v = x + T = x + x = 2*x. Define adult deer in Hamilton Farm as O; so O = v + x = 2*x + x = 3*x. Define adult racoon in Hamilton Farm as l; r = v = 2*x; so l = 3 + r = 3 + 2*x = 2*x + 3. Define total number of adult animals in Hamilton Farm as G; so G = l + O = 2*x + 3 + 3*x = 5*x + 3. We know G = 23, so we have 5*x + 3 = 23 and we solve it through the following steps: Simplifying the equation: 5*x + 3 = 23. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.


The number of culinarian school in Brightford equals 4. The number of culinarian school in Glenfield City equals 4 plus the sum of the total number of schools in Brightford and the number of culinarian school in Brightford. The number of culinarian school in Hawkesbury equals the sum of the total number of schools in Glenfield City, the number of culinarian school in Brightford, and the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Brightford as b; so b = 4. Define total number of schools in Brightford as k; so k = b = 4. Define culinarian school in Glenfield City as z; s = k + b = 4 + 4 = 8; so z = 4 + s = 4 + 8 = 12. Define total number of schools in Glenfield City as Q; so Q = z = 12. Define culinarian school in Hawkesbury as p; q = Q + b = 12 + 4 = 16; so p = q + z = 16 + 12 = 28. Define total number of schools in Hawkesbury as S; so S = p = 28. Answer: 28.


The number of adult crow in Cedar Valley equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the number of adult parrot in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals the number of adult parrot in Oakridge Riverside. The number of adult parrot in Cedar Valley exists, and its number is greater than 0. The total number of adult animals in Cedar Valley equals 13. The number of adult parrot in Oakridge Riverside equals 3.

Question: How many adult parrot does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult parrot in Oakridge Riverside as z; so z = 3. Define adult crow in Oakridge Riverside as l; so l = z = 3. Define total number of adult animals in Oakridge Riverside as Y; so Y = z + l = 3 + 3 = 6. Define adult parrot in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult crow in Cedar Valley as D; a = Y + z = 6 + 3 = 9; so D = 2 + a = 2 + 9 = 11. Define total number of adult animals in Cedar Valley as Q; so Q = x + D = x + 11 = x + 11. We know Q = 13, so we have x + 11 = 13 and we solve it through the following steps: Simplifying the equation: x + 11 = 13. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of intense detective thriller in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 1 plus the total number of movies in Taylor Movie Festival. The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Northwood Movie Festival and the number of intense detective thriller in Taylor Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Taylor Movie Festival as y; so y = 2. Define intense detective thriller in Taylor Movie Festival as V; so V = y = 2. Define total number of movies in Taylor Movie Festival as H; so H = V + y = 2 + 2 = 4. Define calm road movie in Northwood Movie Festival as J; I = H = 4; so J = 1 + I = 1 + 4 = 5. Define total number of movies in Northwood Movie Festival as p; so p = J = 5. Define calm road movie in Verdi Movie Festival as q; so q = p + V = 5 + 2 = 7. Define total number of movies in Verdi Movie Festival as O; so O = q = 7. Answer: 7.


The number of adult wolf in Pine Ridge equals 1. The number of adult wolf in Cedar Valley equals 4 plus the total number of adult animals in Pine Ridge. The number of adult racoon in Pine Ridge equals 4 plus the number of adult wolf in Pine Ridge. The number of adult racoon in Cedar Valley equals the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Pine Ridge as V; so V = 1. Define adult racoon in Pine Ridge as i; X = V = 1; so i = 4 + X = 4 + 1 = 5. Define total number of adult animals in Pine Ridge as O; so O = V + i = 1 + 5 = 6. Define adult wolf in Cedar Valley as F; B = O = 6; so F = 4 + B = 4 + 6 = 10. Define adult racoon in Cedar Valley as D; so D = O = 6. Define total number of adult animals in Cedar Valley as h; so h = F + D = 10 + 6 = 16. Answer: 16.


The number of adult crow in Jefferson Circus equals 1 plus the number of adult eagle in Jefferson Circus. The number of adult crow in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Jefferson Circus, the number of adult eagle in Jefferson Circus, and the number of adult crow in Jefferson Circus. The number of adult eagle in Jefferson Circus equals 2.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult eagle in Jefferson Circus as M; so M = 2. Define adult crow in Jefferson Circus as j; K = M = 2; so j = 1 + K = 1 + 2 = 3. Define total number of adult animals in Jefferson Circus as u; so u = M + j = 2 + 3 = 5. Define adult crow in Mayer Aquarium as z; C = u + M = 5 + 2 = 7; E = C + j = 7 + 3 = 10; so z = 3 * E = 3 * 10 = 30. Define total number of adult animals in Mayer Aquarium as p; so p = z = 30. Answer: 30.


The number of culinarian school in Glenfield City equals the sum of the number of public highschool in Glenfield City, the number of private middle school in Glenfield City, and the number of regional medical school in Glenfield City. The number of regional medical school in Hawkesbury equals 2 times the number of private middle school in Glenfield City. The number of public highschool in Hawkesbury equals the number of private middle school in Glenfield City. The number of regional medical school in Glenfield City exists, and its number is greater than 0. The number of culinarian school in Hawkesbury equals the number of public highschool in Brightford. The number of private middle school in Glenfield City equals the number of regional medical school in Glenfield City. The number of regional medical school in Glenfield City exists, and its number is greater than 0. The number of public highschool in Glenfield City equals the number of regional medical school in Glenfield City. The total number of schools in Glenfield City equals 12. The number of private middle school in Hawkesbury equals the sum of the total number of schools in Brightford, the number of regional medical school in Hawkesbury, the number of culinarian school in Glenfield City, and the number of private middle school in Brightford. The number of public highschool in Brightford equals 3. The number of private middle school in Brightford equals 3.

Question: How many regional medical school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Glenfield City as x; we don't know its value yet but will find it out later. Define public highschool in Glenfield City as e; so e = x = x. Define private middle school in Glenfield City as f; so f = x = x. Define culinarian school in Glenfield City as K; E = e + f = x + x = 2*x; so K = E + x = 2*x + x = 3*x. Define total number of schools in Glenfield City as j; R = e + x = x + x = 2*x; G = R + K = 2*x + 3*x = 5*x; so j = G + f = 5*x + x = 6*x. We know j = 12, so we have 6*x = 12 and we solve it through the following steps: Simplifying the equation: 6*x = 12. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.


The number of culinarian school in Brightford equals 3 times the number of regional medical school in Brightford. The number of regional medical school in Brightford equals 1. The number of culinarian school in Hawkesbury equals 3 plus the sum of the total number of schools in Brightford, the number of regional medical school in Brightford, and the number of culinarian school in Brightford.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Brightford as o; so o = 1. Define culinarian school in Brightford as k; G = o = 1; so k = 3 * G = 3 * 1 = 3. Define total number of schools in Brightford as u; so u = o + k = 1 + 3 = 4. Define culinarian school in Hawkesbury as M; A = u + o = 4 + 1 = 5; t = A + k = 5 + 3 = 8; so M = 3 + t = 3 + 8 = 11. Define total number of schools in Hawkesbury as v; so v = M = 11. Answer: 11.


The number of adult deer in Cedar Valley equals 4. The number of adult fox in Beverly Forest equals 4 times the sum of the number of adult deer in Cedar Valley and the number of adult wolf in Beverly Forest. The number of adult fox in Oakridge Riverside equals 4. The number of adult wolf in Beverly Forest equals 2 times the number of adult deer in Cedar Valley. The number of adult wolf in Cedar Valley equals the sum of the number of adult deer in Cedar Valley and the number of adult fox in Beverly Forest. The number of adult deer in Beverly Forest equals the number of adult wolf in Beverly Forest. The number of adult fox in Cedar Valley equals 3 times the number of adult fox in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult deer in Cedar Valley as v; so v = 4. Define adult wolf in Beverly Forest as X; G = v = 4; so X = 2 * G = 2 * 4 = 8. Define adult fox in Beverly Forest as j; y = v + X = 4 + 8 = 12; so j = 4 * y = 4 * 12 = 48. Define adult deer in Beverly Forest as T; so T = X = 8. Define total number of adult animals in Beverly Forest as d; M = X + T = 8 + 8 = 16; so d = M + j = 16 + 48 = 64. Answer: 64.


The number of regional medical school in Hawkesbury equals 1 plus the sum of the total number of schools in Westhaven City, the number of regional medical school in Westhaven City, and the number of elementary school in Hawkesbury. The number of regional medical school in Westhaven City equals 1. The number of elementary school in Hawkesbury equals 2 plus the number of regional medical school in Westhaven City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Westhaven City as r; so r = 1. Define elementary school in Hawkesbury as C; g = r = 1; so C = 2 + g = 2 + 1 = 3. Define total number of schools in Westhaven City as V; so V = r = 1. Define regional medical school in Hawkesbury as N; y = V + r = 1 + 1 = 2; M = y + C = 2 + 3 = 5; so N = 1 + M = 1 + 5 = 6. Define total number of schools in Hawkesbury as S; so S = C + N = 3 + 6 = 9. Answer: 9.


The number of adult owl in Jefferson Circus exists, and its number is greater than 0. The total number of adult animals in Mayer Aquarium equals 7. The number of adult parrot in Mayer Aquarium equals 2 plus the difference between the total number of adult animals in Bundle Ranch and the number of adult owl in Jefferson Circus. The number of adult blue jay in Bundle Ranch equals 3 plus the sum of the total number of adult animals in Jefferson Circus and the number of adult owl in Jefferson Circus.

Question: How many adult owl does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Jefferson Circus as x; we don't know its value yet but will find it out later. Define total number of adult animals in Jefferson Circus as A; so A = x = x. Define adult blue jay in Bundle Ranch as a; H = A + x = x + x = 2*x; so a = 3 + H = 3 + 2*x = 2*x + 3. Define total number of adult animals in Bundle Ranch as T; so T = a = 2*x + 3. Define adult parrot in Mayer Aquarium as s; d = T - x = (2*x + 3) - (x) = x + 3; so s = 2 + d = 2 + x + 3 = x + 5. Define total number of adult animals in Mayer Aquarium as g; so g = s = x + 5. We know g = 7, so we have x + 5 = 7 and we solve it through the following steps: Simplifying the equation: x + 5 = 7. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of calm road movie in Northwood Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival exists, and its number is greater than 0. The number of calm road movie in Taylor Movie Festival equals 2. The total number of movies in Northwood Movie Festival equals 20. The number of intense detective thriller in Taylor Movie Festival exists, and its number is greater than 0.

Question: How many intense detective thriller does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Taylor Movie Festival as h; so h = 2. Define intense detective thriller in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Taylor Movie Festival as r; so r = h + x = 2 + x = x + 2. Define intense detective thriller in Northwood Movie Festival as K; Z = r + x = x + 2 + x = 2*x + 2; so K = Z + h = 2*x + 2 + 2 = 2*x + 4. Define calm road movie in Northwood Movie Festival as v; so v = K = 2*x + 4. Define total number of movies in Northwood Movie Festival as t; so t = v + K = 2*x + 4 + 2*x + 4 = 4*x + 8. We know t = 20, so we have 4*x + 8 = 20 and we solve it through the following steps: Simplifying the equation: 4*x + 8 = 20. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of elementary school in Westhaven City exists, and its number is greater than 0. The number of elementary school in Hawkesbury equals the sum of the total number of schools in Westhaven City and the number of private middle school in Evervale City. The number of elementary school in Westhaven City exists, and its number is greater than 0. The total number of schools in Westhaven City equals 11. The number of private middle school in Brightford equals 1. The number of private middle school in Westhaven City equals 2 plus the number of private middle school in Brightford. The number of private middle school in Glenfield City equals 4. The number of public highschool in Brightford equals 2 plus the total number of schools in Evervale City. The number of private middle school in Evervale City equals 1. The number of private middle school in Hawkesbury equals 1.

Question: How many elementary school does Westhaven City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Brightford as I; so I = 1. Define private middle school in Westhaven City as y; A = I = 1; so y = 2 + A = 2 + 1 = 3. Define elementary school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as i; P = y + x = 3 + x = x + 3; so i = P + I = x + 3 + 1 = x + 4. Define total number of schools in Westhaven City as z; p = x + y = x + 3 = x + 3; so z = p + i = x + 3 + x + 4 = 2*x + 7. We know z = 11, so we have 2*x + 7 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 7 = 11. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult parrot in Maple Creek equals 4 times the number of adult blue jay in Maple Creek. The number of adult blue jay in Oakridge Riverside equals 1 plus the total number of adult animals in Maple Creek. The total number of adult animals in Oakridge Riverside equals 28. The number of adult blue jay in Maple Creek exists, and its number is greater than 0. The number of adult parrot in Oakridge Riverside equals the number of adult parrot in Maple Creek.

Question: How many adult blue jay does Maple Creek have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Maple Creek as x; we don't know its value yet but will find it out later. Define adult parrot in Maple Creek as t; n = x = x; so t = 4 * n = (4) * (x) = 4*x. Define total number of adult animals in Maple Creek as F; so F = x + t = x + 4*x = 5*x. Define adult blue jay in Oakridge Riverside as u; Q = F = 5*x; so u = 1 + Q = 1 + 5*x = 5*x + 1. Define adult parrot in Oakridge Riverside as O; so O = t = 4*x. Define total number of adult animals in Oakridge Riverside as N; so N = u + O = 5*x + 1 + 4*x = 9*x + 1. We know N = 28, so we have 9*x + 1 = 28 and we solve it through the following steps: Simplifying the equation: 9*x + 1 = 28. Move all terms to one side: 9*x - 27 = 0. Isolate the term with x: 9*x = 27. Divide both sides by 9: x = 27 / 9. Solution: x = 3. Answer: 3.


The number of intense detective thriller in Golden Banana Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 times the number of intense detective thriller in Golden Banana Movie Festival. The total number of movies in Verdi Movie Festival equals 22.

Question: How many intense detective thriller does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Golden Banana Movie Festival as C; w = x = x; so C = 4 * w = (4) * (x) = 4*x. Define total number of movies in Golden Banana Movie Festival as K; so K = x + C = x + 4*x = 5*x. Define intense detective thriller in Verdi Movie Festival as o; G = K + x = 5*x + x = 6*x; f = G + C = 6*x + 4*x = 10*x; so o = 2 + f = 2 + 10*x = 10*x + 2. Define total number of movies in Verdi Movie Festival as v; so v = o = 10*x + 2. We know v = 22, so we have 10*x + 2 = 22 and we solve it through the following steps: Simplifying the equation: 10*x + 2 = 22. Move all terms to one side: 10*x - 20 = 0. Isolate the term with x: 10*x = 20. Divide both sides by 10: x = 20 / 10. Solution: x = 2. Answer: 2.


The number of adult racoon in Pine Ridge equals 4. The number of adult racoon in Oakridge Riverside equals the difference between the number of adult fox in Pine Ridge and the number of adult wolf in Pine Ridge. The number of adult fox in Beverly Forest equals 4 times the difference between the number of adult racoon in Beverly Forest and the number of adult fox in Oakridge Riverside. The total number of adult animals in Beverly Forest equals 39. The number of adult wolf in Beverly Forest equals the number of adult fox in Beverly Forest. The number of adult fox in Pine Ridge equals 4. The number of adult fox in Oakridge Riverside exists, and its number is greater than 0. The number of adult wolf in Pine Ridge equals the number of adult fox in Pine Ridge. The number of adult racoon in Beverly Forest equals 4 plus the number of adult fox in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals the total number of adult animals in Pine Ridge.

Question: How many adult fox does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult racoon in Beverly Forest as F; V = x = x; so F = 4 + V = 4 + x = x + 4. Define adult fox in Beverly Forest as w; M = F - x = (x + 4) - (x) = 4; so w = 4 * M = (4) * (4) = 16. Define adult wolf in Beverly Forest as R; so R = w = 16. Define total number of adult animals in Beverly Forest as t; T = w + R = 16 + 16 = 32; so t = T + F = 32 + x + 4 = x + 36. We know t = 39, so we have x + 36 = 39 and we solve it through the following steps: Simplifying the equation: x + 36 = 39. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3 plus the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3 times the sum of the total number of movies in West Sahara Movie Festival, the number of solemn period drama in West Sahara Movie Festival, and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define solemn period drama in West Sahara Movie Festival as j; so j = 2. Define futuristic sci-fi movie in West Sahara Movie Festival as i; w = j = 2; so i = 3 + w = 3 + 2 = 5. Define total number of movies in West Sahara Movie Festival as Q; so Q = j + i = 2 + 5 = 7. Define solemn period drama in Taylor Movie Festival as o; K = Q + j = 7 + 2 = 9; z = K + i = 9 + 5 = 14; so o = 3 * z = 3 * 14 = 42. Define total number of movies in Taylor Movie Festival as H; so H = o = 42. Answer: 42.


The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The number of calm road movie in Taylor Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of calm road movie in Northwood Movie Festival. The total number of movies in Northwood Movie Festival equals 12. The number of futuristic sci-fi movie in Taylor Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 times the total number of movies in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of calm road movie in Northwood Movie Festival.

Question: How many futuristic sci-fi movie does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Northwood Movie Festival as q; so q = x = x. Define calm road movie in Verdi Movie Festival as I; so I = q = x. Define total number of movies in Verdi Movie Festival as Y; so Y = I = x. Define upbeat metropolis comedy in Northwood Movie Festival as F; so F = q = x. Define futuristic sci-fi movie in Northwood Movie Festival as j; L = Y = x; so j = 2 * L = (2) * (x) = 2*x. Define total number of movies in Northwood Movie Festival as y; v = F + j = x + 2*x = 3*x; so y = v + q = 3*x + x = 4*x. We know y = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of solemn period drama in Festival Lumière de Valmont equals 3. The number of calm road movie in Rêves de Belleville equals 2 plus the number of solemn period drama in Festival de Clairmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2 plus the number of solemn period drama in Festival Lumière de Valmont. The number of calm road movie in Festival de Saint-Rivage equals 3 times the sum of the total number of movies in Festival Lumière de Valmont, the number of solemn period drama in Festival Lumière de Valmont, and the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Rêves de Belleville equals the total number of movies in Festival de Saint-Rivage. The number of solemn period drama in Festival de Clairmont equals 2. The number of calm road movie in Festival de Clairmont equals 2 plus the number of solemn period drama in Festival de Clairmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Festival Lumière de Valmont as R; so R = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as F; L = R = 3; so F = 2 + L = 2 + 3 = 5. Define total number of movies in Festival Lumière de Valmont as B; so B = F + R = 5 + 3 = 8. Define calm road movie in Festival de Saint-Rivage as X; C = B + R = 8 + 3 = 11; G = C + F = 11 + 5 = 16; so X = 3 * G = 3 * 16 = 48. Define total number of movies in Festival de Saint-Rivage as Z; so Z = X = 48. Answer: 48.


The total number of adult animals in Oakridge Riverside equals 12. The number of adult bear in Oakridge Riverside exists, and its number is greater than 0. The number of adult fox in Oakridge Riverside equals the number of adult bear in Oakridge Riverside. The number of adult racoon in Oakridge Riverside equals the number of adult fox in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals the sum of the number of adult bear in Oakridge Riverside, the number of adult racoon in Oakridge Riverside, and the number of adult fox in Oakridge Riverside.

Question: How many adult bear does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult fox in Oakridge Riverside as S; so S = x = x. Define adult racoon in Oakridge Riverside as M; so M = S = x. Define adult wolf in Oakridge Riverside as c; w = x + M = x + x = 2*x; so c = w + S = 2*x + x = 3*x. Define total number of adult animals in Oakridge Riverside as s; o = c + x = 3*x + x = 4*x; j = o + S = 4*x + x = 5*x; so s = j + M = 5*x + x = 6*x. We know s = 12, so we have 6*x = 12 and we solve it through the following steps: Simplifying the equation: 6*x = 12. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.


The number of adult owl in South Zoo equals 4 times the number of adult eagle in South Zoo. The number of adult eagle in South Zoo equals 4. The number of adult eagle in Jefferson Circus equals 2 times the sum of the total number of adult animals in South Zoo, the number of adult eagle in South Zoo, and the number of adult owl in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult eagle in South Zoo as a; so a = 4. Define adult owl in South Zoo as A; r = a = 4; so A = 4 * r = 4 * 4 = 16. Define total number of adult animals in South Zoo as x; so x = a + A = 4 + 16 = 20. Define adult eagle in Jefferson Circus as b; T = x + a = 20 + 4 = 24; q = T + A = 24 + 16 = 40; so b = 2 * q = 2 * 40 = 80. Define total number of adult animals in Jefferson Circus as j; so j = b = 80. Answer: 80.


The number of adult crow in Oakridge Riverside equals 3. The number of adult eagle in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult crow in Oakridge Riverside, and the number of adult eagle in Oakridge Riverside. The number of adult crow in Pine Ridge equals 4. The number of adult eagle in Oakridge Riverside equals 3.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult crow in Oakridge Riverside as F; so F = 3. Define adult eagle in Oakridge Riverside as Z; so Z = 3. Define total number of adult animals in Oakridge Riverside as a; so a = Z + F = 3 + 3 = 6. Define adult eagle in Pine Ridge as g; z = a + F = 6 + 3 = 9; so g = z + Z = 9 + 3 = 12. Define adult crow in Pine Ridge as b; so b = 4. Define total number of adult animals in Pine Ridge as r; so r = g + b = 12 + 4 = 16. Answer: 16.


The number of adult bear in Bundle Ranch equals 2. The number of adult bear in Hamilton Farm exists, and its number is greater than 0. The total number of adult animals in Hamilton Farm equals 11. The number of adult fox in Hamilton Farm equals 4 times the difference between the total number of adult animals in Bundle Ranch and the number of adult fox in Bundle Ranch. The number of adult fox in Bundle Ranch equals 4.

Question: How many adult bear does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Bundle Ranch as j; so j = 2. Define adult fox in Bundle Ranch as E; so E = 4. Define total number of adult animals in Bundle Ranch as M; so M = E + j = 4 + 2 = 6. Define adult fox in Hamilton Farm as v; S = M - E = (6) - (4) = 2; so v = 4 * S = (4) * (2) = 8. Define adult bear in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as U; so U = v + x = 8 + x = x + 8. We know U = 11, so we have x + 8 = 11 and we solve it through the following steps: Simplifying the equation: x + 8 = 11. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of intense detective thriller in Taylor Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 plus the sum of the total number of movies in Verdi Movie Festival and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define upbeat metropolis comedy in Verdi Movie Festival as B; so B = 4. Define intense detective thriller in Verdi Movie Festival as c; so c = B = 4. Define total number of movies in Verdi Movie Festival as X; so X = B + c = 4 + 4 = 8. Define upbeat metropolis comedy in Taylor Movie Festival as U; g = X + B = 8 + 4 = 12; so U = 2 + g = 2 + 12 = 14. Define intense detective thriller in Taylor Movie Festival as y; so y = B = 4. Define total number of movies in Taylor Movie Festival as t; so t = U + y = 14 + 4 = 18. Answer: 18.


The number of elementary school in Brightford exists, and its number is greater than 0. The number of elementary school in Brightford exists, and its number is greater than 0. The total number of schools in Glenfield City equals 21. The number of culinarian school in Brightford equals 4 plus the number of elementary school in Brightford.

Question: How many elementary school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Brightford as x; we don't know its value yet but will find it out later. Define culinarian school in Brightford as l; a = x = x; so l = 4 + a = 4 + x = x + 4. Define total number of schools in Brightford as E; so E = x + l = x + x + 4 = 2*x + 4. Define regional medical school in Glenfield City as v; L = E + x = 2*x + 4 + x = 3*x + 4; G = L + l = 3*x + 4 + x + 4 = 4*x + 8; so v = 1 + G = 1 + 4*x + 8 = 4*x + 9. Define total number of schools in Glenfield City as Q; so Q = v = 4*x + 9. We know Q = 21, so we have 4*x + 9 = 21 and we solve it through the following steps: Simplifying the equation: 4*x + 9 = 21. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of public highschool in Hawkesbury equals 2 times the number of private middle school in Hawkesbury. The total number of schools in Westhaven City equals 13. The number of public highschool in Westhaven City equals 1 plus the number of private middle school in Westhaven City. The number of private middle school in Hawkesbury exists, and its number is greater than 0. The number of private middle school in Westhaven City equals the total number of schools in Hawkesbury.

Question: How many private middle school does Hawkesbury have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Hawkesbury as x; we don't know its value yet but will find it out later. Define public highschool in Hawkesbury as R; i = x = x; so R = 2 * i = (2) * (x) = 2*x. Define total number of schools in Hawkesbury as Q; so Q = R + x = 2*x + x = 3*x. Define private middle school in Westhaven City as c; so c = Q = 3*x. Define public highschool in Westhaven City as D; L = c = 3*x; so D = 1 + L = 1 + 3*x = 3*x + 1. Define total number of schools in Westhaven City as b; so b = D + c = 3*x + 1 + 3*x = 6*x + 1. We know b = 13, so we have 6*x + 1 = 13 and we solve it through the following steps: Simplifying the equation: 6*x + 1 = 13. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.


The number of upbeat metropolis comedy in Taylor Movie Festival equals the sum of the number of solemn period drama in Taylor Movie Festival and the number of solemn period drama in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2. The number of intense detective thriller in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3 times the sum of the number of calm road movie in Golden Banana Movie Festival, the number of intense detective thriller in Verdi Movie Festival, and the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the sum of the number of intense detective thriller in Verdi Movie Festival, the total number of movies in Golden Banana Movie Festival, and the total number of movies in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 4. The number of solemn period drama in Northwood Movie Festival equals 2.

Question: How many calm road movie does Northwood Movie Festival have?

Solution: Define solemn period drama in Northwood Movie Festival as b; so b = 2. Define solemn period drama in Taylor Movie Festival as C; so C = b = 2. Define upbeat metropolis comedy in Taylor Movie Festival as O; so O = C + b = 2 + 2 = 4. Define intense detective thriller in Taylor Movie Festival as h; so h = C = 2. Define total number of movies in Taylor Movie Festival as o; y = O + C = 4 + 2 = 6; so o = y + h = 6 + 2 = 8. Define intense detective thriller in Verdi Movie Festival as s; so s = o = 8. Define calm road movie in Northwood Movie Festival as W; so W = s = 8. Answer: 8.


The number of adult parrot in Bundle Ranch equals 4 times the number of adult owl in Bundle Ranch. The number of adult parrot in Mayer Aquarium equals 3 times the number of adult parrot in Bundle Ranch. The number of adult owl in Bundle Ranch exists, and its number is greater than 0. The number of adult owl in Mayer Aquarium equals the total number of adult animals in Bundle Ranch. The total number of adult animals in Mayer Aquarium equals 17.

Question: How many adult owl does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult parrot in Bundle Ranch as t; W = x = x; so t = 4 * W = (4) * (x) = 4*x. Define total number of adult animals in Bundle Ranch as v; so v = x + t = x + 4*x = 5*x. Define adult owl in Mayer Aquarium as i; so i = v = 5*x. Define adult parrot in Mayer Aquarium as G; R = t = 4*x; so G = 3 * R = (3) * (4*x) = 12*x. Define total number of adult animals in Mayer Aquarium as O; so O = G + i = 12*x + 5*x = 17*x. We know O = 17, so we have 17*x = 17 and we solve it through the following steps: Simplifying the equation: 17*x = 17. Move all terms to one side: 17*x - 17 = 0. Isolate the term with x: 17*x = 17. Divide both sides by 17: x = 17 / 17. Solution: x = 1. Answer: 1.


The number of adult owl in Beverly Forest exists, and its number is greater than 0. The total number of adult animals in Maple Creek equals 17. The number of adult owl in Maple Creek equals 3 plus the total number of adult animals in Beverly Forest. The number of adult blue jay in Beverly Forest equals 4. The number of adult blue jay in Maple Creek equals the sum of the number of adult owl in Beverly Forest and the number of adult blue jay in Beverly Forest.

Question: How many adult owl does Beverly Forest have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Beverly Forest as i; so i = 4. Define adult owl in Beverly Forest as x; we don't know its value yet but will find it out later. Define total number of adult animals in Beverly Forest as e; so e = i + x = 4 + x = x + 4. Define adult blue jay in Maple Creek as F; so F = x + i = x + 4 = x + 4. Define adult owl in Maple Creek as D; h = e = x + 4; so D = 3 + h = 3 + x + 4 = x + 7. Define total number of adult animals in Maple Creek as U; so U = F + D = x + 4 + x + 7 = 2*x + 11. We know U = 17, so we have 2*x + 11 = 17 and we solve it through the following steps: Simplifying the equation: 2*x + 11 = 17. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult bear in Cedar Valley equals 3 times the number of adult fox in Maple Creek. The number of adult fox in Maple Creek exists, and its number is greater than 0. The number of adult fox in Maple Creek exists, and its number is greater than 0. The total number of adult animals in Cedar Valley equals 54.

Question: How many adult fox does Maple Creek have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Maple Creek as x; we don't know its value yet but will find it out later. Define adult bear in Cedar Valley as u; f = x = x; so u = 3 * f = (3) * (x) = 3*x. Define total number of adult animals in Maple Creek as R; so R = x = x. Define adult wolf in Cedar Valley as j; U = R + x = x + x = 2*x; q = U + u = 2*x + 3*x = 5*x; so j = 3 * q = (3) * (5*x) = 15*x. Define total number of adult animals in Cedar Valley as p; so p = u + j = 3*x + 15*x = 18*x. We know p = 54, so we have 18*x = 54 and we solve it through the following steps: Simplifying the equation: 18*x = 54. Move all terms to one side: 18*x - 54 = 0. Isolate the term with x: 18*x = 54. Divide both sides by 18: x = 54 / 18. Solution: x = 3. Answer: 3.


The total number of movies in West Sahara Movie Festival equals 26. The number of calm road movie in Golden Banana Movie Festival equals 4 plus the sum of the total number of movies in Northwood Movie Festival and the number of solemn period drama in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2 plus the sum of the total number of movies in Golden Banana Movie Festival and the number of calm road movie in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival exists, and its number is greater than 0.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Northwood Movie Festival as H; so H = x = x. Define calm road movie in Golden Banana Movie Festival as G; Z = H + x = x + x = 2*x; so G = 4 + Z = 4 + 2*x = 2*x + 4. Define total number of movies in Golden Banana Movie Festival as N; so N = G = 2*x + 4. Define upbeat metropolis comedy in West Sahara Movie Festival as e; I = N + G = 2*x + 4 + 2*x + 4 = 4*x + 8; so e = 2 + I = 2 + 4*x + 8 = 4*x + 10. Define total number of movies in West Sahara Movie Festival as R; so R = e = 4*x + 10. We know R = 26, so we have 4*x + 10 = 26 and we solve it through the following steps: Simplifying the equation: 4*x + 10 = 26. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.