The number of futuristic sci-fi movie in Taylor Movie Festival equals 4 times the total number of movies in Verdi Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of calm road movie in West Sahara Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 4. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3 plus the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 plus the number of calm road movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of calm road movie in Taylor Movie Festival equals the sum of the total number of movies in Verdi Movie Festival and the total number of movies in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals the difference between the number of solemn period drama in Golden Banana Movie Festival and the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as M; so M = 4. Define calm road movie in Golden Banana Movie Festival as x; so x = M = 4. Define futuristic sci-fi movie in Golden Banana Movie Festival as S; R = M = 4; so S = 3 + R = 3 + 4 = 7. Define upbeat metropolis comedy in Golden Banana Movie Festival as m; d = x = 4; so m = 2 + d = 2 + 4 = 6. Define total number of movies in Golden Banana Movie Festival as V; P = m + S = 6 + 7 = 13; W = P + x = 13 + 4 = 17; so V = W + M = 17 + 4 = 21. Answer: 21.


The number of adult eagle in Beverly Forest equals 4. The number of adult blue jay in Cedar Valley equals 4 plus the sum of the total number of adult animals in Beverly Forest, the number of adult eagle in Beverly Forest, and the number of adult blue jay in Beverly Forest. The number of adult blue jay in Beverly Forest equals 3 times the number of adult eagle in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult eagle in Beverly Forest as v; so v = 4. Define adult blue jay in Beverly Forest as o; S = v = 4; so o = 3 * S = 3 * 4 = 12. Define total number of adult animals in Beverly Forest as z; so z = v + o = 4 + 12 = 16. Define adult blue jay in Cedar Valley as x; C = z + v = 16 + 4 = 20; c = C + o = 20 + 12 = 32; so x = 4 + c = 4 + 32 = 36. Define total number of adult animals in Cedar Valley as u; so u = x = 36. Answer: 36.


The number of private middle school in Brightford equals 2 plus the difference between the number of regional medical school in Brightford and the number of culinarian school in Hawkesbury. The number of regional medical school in Brightford equals 4 plus the difference between the total number of schools in Hawkesbury and the number of culinarian school in Hawkesbury. The number of culinarian school in Hawkesbury equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Hawkesbury as Q; so Q = 2. Define total number of schools in Hawkesbury as J; so J = Q = 2. Define regional medical school in Brightford as h; A = J - Q = 2 - 2 = 0; so h = 4 + A = 4 + 0 = 4. Define private middle school in Brightford as O; m = h - Q = 4 - 2 = 2; so O = 2 + m = 2 + 2 = 4. Define total number of schools in Brightford as X; so X = O + h = 4 + 4 = 8. Answer: 8.


The number of calm road movie in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 2 times the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 2 times the number of calm road movie in Rêves de Belleville. The number of upbeat metropolis comedy in Cinéma de Montreval equals 2 plus the sum of the number of futuristic sci-fi movie in Rêves de Belleville and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Cinéma de Montreval equals 4. The number of intense detective thriller in Rêves de Belleville equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of intense detective thriller in Cinéma de Montreval equals the sum of the total number of movies in Festival Lumière de Valmont, the total number of movies in Festival de Clairmont, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 3 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of intense detective thriller in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Festival de Clairmont equals the total number of movies in Festival Lumière de Valmont. The number of calm road movie in Rêves de Belleville equals the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals 4.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Festival de Saint-Rivage as r; so r = 4. Define intense detective thriller in Festival Lumière de Valmont as z; X = r = 4; so z = 3 * X = 3 * 4 = 12. Define calm road movie in Festival Lumière de Valmont as H; so H = z = 12. Define futuristic sci-fi movie in Festival Lumière de Valmont as q; so q = r = 4. Define total number of movies in Festival Lumière de Valmont as h; G = z + H = 12 + 12 = 24; so h = G + q = 24 + 4 = 28. Define intense detective thriller in Festival de Clairmont as k; so k = h = 28. Define total number of movies in Festival de Clairmont as F; so F = k = 28. Answer: 28.


The number of solemn period drama in Rêves de Belleville equals 4 plus the sum of the total number of movies in Festival de Clairmont and the number of futuristic sci-fi movie in Rêves de Belleville. The number of solemn period drama in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 3 plus the difference between the total number of movies in Festival de Clairmont and the number of solemn period drama in Festival de Clairmont.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Festival de Clairmont as E; so E = 3. Define total number of movies in Festival de Clairmont as C; so C = E = 3. Define futuristic sci-fi movie in Rêves de Belleville as b; V = C - E = 3 - 3 = 0; so b = 3 + V = 3 + 0 = 3. Define solemn period drama in Rêves de Belleville as M; r = C + b = 3 + 3 = 6; so M = 4 + r = 4 + 6 = 10. Define total number of movies in Rêves de Belleville as U; so U = b + M = 3 + 10 = 13. Answer: 13.


The number of adult bear in Pine Ridge equals the number of adult wolf in Pine Ridge. The number of adult wolf in Pine Ridge equals 3. The number of adult bear in Cedar Valley equals 4 times the number of adult wolf in Cedar Valley. The number of adult wolf in Cedar Valley equals 2 plus the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Pine Ridge as G; so G = 3. Define adult bear in Pine Ridge as x; so x = G = 3. Define total number of adult animals in Pine Ridge as n; so n = G + x = 3 + 3 = 6. Define adult wolf in Cedar Valley as B; H = n = 6; so B = 2 + H = 2 + 6 = 8. Define adult bear in Cedar Valley as F; k = B = 8; so F = 4 * k = 4 * 8 = 32. Define total number of adult animals in Cedar Valley as U; so U = B + F = 8 + 32 = 40. Answer: 40.


The number of public highschool in Ruby Bay equals the total number of schools in Shoreline City. The number of regional medical school in Shoreline City equals the number of culinarian school in Shoreline City. The number of regional medical school in Clearwater Bay equals the number of public highschool in Shoreline City. The number of regional medical school in Ruby Bay equals the number of culinarian school in Shoreline City. The number of public highschool in Clearwater Bay equals the total number of schools in Shoreline City. The number of public highschool in Shoreline City equals 2 times the sum of the number of regional medical school in Ruby Bay and the number of culinarian school in Shoreline City. The number of culinarian school in Shoreline City equals 4.

Question: How many public highschool does Clearwater Bay have?

Solution: Define culinarian school in Shoreline City as M; so M = 4. Define regional medical school in Ruby Bay as b; so b = M = 4. Define public highschool in Shoreline City as L; e = b + M = 4 + 4 = 8; so L = 2 * e = 2 * 8 = 16. Define regional medical school in Shoreline City as v; so v = M = 4. Define total number of schools in Shoreline City as I; l = L + M = 16 + 4 = 20; so I = l + v = 20 + 4 = 24. Define public highschool in Clearwater Bay as S; so S = I = 24. Answer: 24.


The number of adult fox in South Zoo equals the total number of adult animals in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult fox in Hamilton Farm equals 3. The number of adult racoon in Jefferson Circus equals 2 plus the number of adult fox in Hamilton Farm. The number of adult fox in Jefferson Circus equals the number of adult fox in Hamilton Farm.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult fox in Hamilton Farm as M; so M = 3. Define adult racoon in Jefferson Circus as V; F = M = 3; so V = 2 + F = 2 + 3 = 5. Define adult fox in Jefferson Circus as y; so y = M = 3. Define adult wolf in Jefferson Circus as g; so g = y = 3. Define total number of adult animals in Jefferson Circus as v; A = y + V = 3 + 5 = 8; so v = A + g = 8 + 3 = 11. Define adult fox in South Zoo as e; so e = v = 11. Define total number of adult animals in South Zoo as b; so b = e = 11. Answer: 11.


The number of adult parrot in Oakridge Riverside equals 4. The number of adult parrot in Pine Ridge equals 4. The number of adult crow in Oakridge Riverside equals 4 times the total number of adult animals in Pine Ridge. The number of adult crow in Pine Ridge equals 4 plus the number of adult parrot in Pine Ridge.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult parrot in Pine Ridge as N; so N = 4. Define adult crow in Pine Ridge as X; s = N = 4; so X = 4 + s = 4 + 4 = 8. Define total number of adult animals in Pine Ridge as V; so V = X + N = 8 + 4 = 12. Define adult crow in Oakridge Riverside as f; o = V = 12; so f = 4 * o = 4 * 12 = 48. Define adult parrot in Oakridge Riverside as R; so R = 4. Define total number of adult animals in Oakridge Riverside as r; so r = f + R = 48 + 4 = 52. Answer: 52.


The number of public highschool in Shoreline City equals 3. The number of culinarian school in Ruby Bay equals 3. The number of private middle school in Riverton City equals 1 plus the sum of the total number of schools in Ruby Bay, the number of private middle school in Ruby Bay, and the number of culinarian school in Ruby Bay. The number of culinarian school in Riverton City equals 2 times the sum of the number of private middle school in Riverton City, the total number of schools in Ruby Bay, and the total number of schools in Shoreline City. The number of public highschool in Riverton City equals the number of culinarian school in Ruby Bay. The number of private middle school in Ruby Bay equals 3. The number of private middle school in Shoreline City equals 3. The number of culinarian school in Shoreline City equals 2 plus the total number of schools in Ruby Bay. The number of public highschool in Ruby Bay equals the number of culinarian school in Ruby Bay.

Question: How many private middle school does Riverton City have?

Solution: Define culinarian school in Ruby Bay as m; so m = 3. Define public highschool in Ruby Bay as X; so X = m = 3. Define private middle school in Ruby Bay as h; so h = 3. Define total number of schools in Ruby Bay as J; n = X + h = 3 + 3 = 6; so J = n + m = 6 + 3 = 9. Define private middle school in Riverton City as c; b = J + h = 9 + 3 = 12; Q = b + m = 12 + 3 = 15; so c = 1 + Q = 1 + 15 = 16. Answer: 16.


The number of culinarian school in Clearwater Bay equals 2 times the total number of schools in Ruby Bay. The number of public highschool in Clearwater Bay equals the total number of schools in Ruby Bay. The number of elementary school in Ruby Bay equals 2. The number of culinarian school in Ruby Bay equals 3 plus the number of elementary school in Ruby Bay.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Ruby Bay as O; so O = 2. Define culinarian school in Ruby Bay as s; K = O = 2; so s = 3 + K = 3 + 2 = 5. Define total number of schools in Ruby Bay as o; so o = s + O = 5 + 2 = 7. Define public highschool in Clearwater Bay as v; so v = o = 7. Define culinarian school in Clearwater Bay as D; H = o = 7; so D = 2 * H = 2 * 7 = 14. Define total number of schools in Clearwater Bay as T; so T = D + v = 14 + 7 = 21. Answer: 21.


The number of adult parrot in Cedar Valley equals 2. The number of adult parrot in Oakridge Riverside equals 4. The number of adult eagle in Cedar Valley equals the number of adult parrot in Cedar Valley. The number of adult eagle in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley, the number of adult parrot in Cedar Valley, and the number of adult eagle in Cedar Valley.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult parrot in Cedar Valley as Q; so Q = 2. Define adult eagle in Cedar Valley as j; so j = Q = 2. Define total number of adult animals in Cedar Valley as d; so d = j + Q = 2 + 2 = 4. Define adult eagle in Oakridge Riverside as W; Z = d + Q = 4 + 2 = 6; so W = Z + j = 6 + 2 = 8. Define adult parrot in Oakridge Riverside as T; so T = 4. Define total number of adult animals in Oakridge Riverside as o; so o = W + T = 8 + 4 = 12. Answer: 12.


The number of solemn period drama in Festival de Clairmont equals 2 plus the total number of movies in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals 4. The number of upbeat metropolis comedy in Festival de Clairmont equals 1 plus the number of solemn period drama in Cinéma de Montreval. The number of upbeat metropolis comedy in Cinéma de Montreval equals 4.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Cinéma de Montreval as Z; so Z = 4. Define upbeat metropolis comedy in Cinéma de Montreval as P; so P = 4. Define total number of movies in Cinéma de Montreval as i; so i = Z + P = 4 + 4 = 8. Define solemn period drama in Festival de Clairmont as J; r = i = 8; so J = 2 + r = 2 + 8 = 10. Define upbeat metropolis comedy in Festival de Clairmont as Y; D = Z = 4; so Y = 1 + D = 1 + 4 = 5. Define total number of movies in Festival de Clairmont as U; so U = J + Y = 10 + 5 = 15. Answer: 15.


The number of adult eagle in Bundle Ranch equals 2 times the difference between the number of adult blue jay in Bundle Ranch and the number of adult parrot in Bundle Ranch. The number of adult parrot in Mayer Aquarium equals 2 times the number of adult blue jay in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals the number of adult eagle in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 4. The number of adult blue jay in Jefferson Circus equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult parrot in Mayer Aquarium, and the number of adult blue jay in Mayer Aquarium. The number of adult parrot in Bundle Ranch equals 1 plus the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals 3. The number of adult parrot in Jefferson Circus equals 3. The number of adult eagle in Jefferson Circus equals 4.

Question: How many adult blue jay does Jefferson Circus have?

Solution: Define adult eagle in Mayer Aquarium as i; so i = 4. Define adult blue jay in Mayer Aquarium as q; so q = i = 4. Define adult parrot in Mayer Aquarium as O; g = q = 4; so O = 2 * g = 2 * 4 = 8. Define total number of adult animals in Mayer Aquarium as P; A = q + i = 4 + 4 = 8; so P = A + O = 8 + 8 = 16. Define adult blue jay in Jefferson Circus as L; m = P + O = 16 + 8 = 24; so L = m + q = 24 + 4 = 28. Answer: 28.


The number of adult crow in Hamilton Farm equals 1 plus the number of adult parrot in Hamilton Farm. The number of adult eagle in Jefferson Circus equals 4. The number of adult parrot in Mayer Aquarium equals 4 plus the difference between the number of adult owl in Hamilton Farm and the number of adult eagle in Hamilton Farm. The number of adult crow in Mayer Aquarium equals the sum of the number of adult owl in Hamilton Farm, the number of adult eagle in Jefferson Circus, and the number of adult owl in Mayer Aquarium. The number of adult owl in Jefferson Circus equals the number of adult eagle in Mayer Aquarium. The number of adult crow in Jefferson Circus equals 2. The number of adult parrot in Hamilton Farm equals 2. The number of adult eagle in Hamilton Farm equals the number of adult owl in Hamilton Farm. The number of adult owl in Hamilton Farm equals 4 plus the number of adult parrot in Hamilton Farm. The number of adult eagle in Mayer Aquarium equals 4 times the number of adult eagle in Jefferson Circus. The number of adult parrot in Jefferson Circus equals the number of adult owl in Jefferson Circus. The number of adult owl in Mayer Aquarium equals the difference between the number of adult parrot in Hamilton Farm and the number of adult eagle in Hamilton Farm.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in Hamilton Farm as F; so F = 2. Define adult owl in Hamilton Farm as O; b = F = 2; so O = 4 + b = 4 + 2 = 6. Define adult eagle in Hamilton Farm as h; so h = O = 6. Define adult crow in Hamilton Farm as K; o = F = 2; so K = 1 + o = 1 + 2 = 3. Define total number of adult animals in Hamilton Farm as B; R = K + h = 3 + 6 = 9; l = R + F = 9 + 2 = 11; so B = l + O = 11 + 6 = 17. Answer: 17.


The number of adult parrot in Beverly Forest equals the total number of adult animals in Oakridge Riverside. The number of adult crow in Beverly Forest equals 2 plus the number of adult parrot in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals 4 plus the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 2.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult parrot in Oakridge Riverside as x; so x = 2. Define adult crow in Oakridge Riverside as u; r = x = 2; so u = 4 + r = 4 + 2 = 6. Define total number of adult animals in Oakridge Riverside as n; so n = u + x = 6 + 2 = 8. Define adult parrot in Beverly Forest as e; so e = n = 8. Define adult crow in Beverly Forest as m; F = x = 2; so m = 2 + F = 2 + 2 = 4. Define total number of adult animals in Beverly Forest as X; so X = m + e = 4 + 8 = 12. Answer: 12.


The number of culinarian school in Brightford equals 2. The number of elementary school in Glenfield City equals 3 plus the number of regional medical school in Evervale City. The number of elementary school in Evervale City equals 4 plus the difference between the total number of schools in Glenfield City and the number of regional medical school in Evervale City. The number of regional medical school in Glenfield City equals the number of elementary school in Glenfield City. The number of regional medical school in Evervale City equals the number of culinarian school in Brightford.

Question: How many elementary school does Evervale City have?

Solution: Define culinarian school in Brightford as S; so S = 2. Define regional medical school in Evervale City as G; so G = S = 2. Define elementary school in Glenfield City as N; m = G = 2; so N = 3 + m = 3 + 2 = 5. Define regional medical school in Glenfield City as s; so s = N = 5. Define total number of schools in Glenfield City as T; so T = N + s = 5 + 5 = 10. Define elementary school in Evervale City as j; e = T - G = 10 - 2 = 8; so j = 4 + e = 4 + 8 = 12. Answer: 12.


The number of regional medical school in Hawkesbury equals 3 times the difference between the total number of schools in Brightford and the number of culinarian school in Brightford. The number of culinarian school in Evervale City equals 2. The number of elementary school in Brightford equals the number of culinarian school in Brightford. The number of regional medical school in Evervale City equals the number of culinarian school in Brightford. The number of elementary school in Evervale City equals the number of culinarian school in Evervale City. The number of culinarian school in Brightford equals the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 2. The number of regional medical school in Brightford equals the number of elementary school in Hawkesbury.

Question: How many regional medical school does Hawkesbury have?

Solution: Define elementary school in Hawkesbury as C; so C = 2. Define culinarian school in Brightford as Y; so Y = C = 2. Define regional medical school in Brightford as S; so S = C = 2. Define elementary school in Brightford as T; so T = Y = 2. Define total number of schools in Brightford as D; d = S + Y = 2 + 2 = 4; so D = d + T = 4 + 2 = 6. Define regional medical school in Hawkesbury as n; U = D - Y = 6 - 2 = 4; so n = 3 * U = 3 * 4 = 12. Answer: 12.


The number of regional medical school in Evervale City equals 1. The number of public highschool in Evervale City equals 2. The number of private middle school in Glenfield City equals 2. The number of culinarian school in Evervale City equals the sum of the total number of schools in Westhaven City, the number of regional medical school in Westhaven City, and the number of public highschool in Evervale City. The number of regional medical school in Westhaven City equals 2. The number of regional medical school in Glenfield City equals 2.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Westhaven City as t; so t = 2. Define total number of schools in Westhaven City as v; so v = t = 2. Define public highschool in Evervale City as E; so E = 2. Define regional medical school in Evervale City as j; so j = 1. Define culinarian school in Evervale City as n; W = v + t = 2 + 2 = 4; so n = W + E = 4 + 2 = 6. Define total number of schools in Evervale City as k; Y = j + n = 1 + 6 = 7; so k = Y + E = 7 + 2 = 9. Answer: 9.


The number of solemn period drama in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4. The number of solemn period drama in Rêves de Belleville equals the sum of the total number of movies in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the number of solemn period drama in Festival de Saint-Rivage.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define upbeat metropolis comedy in Festival de Saint-Rivage as v; so v = 4. Define solemn period drama in Festival de Saint-Rivage as Z; so Z = v = 4. Define total number of movies in Festival de Saint-Rivage as R; so R = v + Z = 4 + 4 = 8. Define solemn period drama in Rêves de Belleville as A; t = R + v = 8 + 4 = 12; so A = t + Z = 12 + 4 = 16. Define upbeat metropolis comedy in Rêves de Belleville as x; so x = 4. Define total number of movies in Rêves de Belleville as L; so L = A + x = 16 + 4 = 20. Answer: 20.


The number of regional medical school in Brightford equals 1. The number of private middle school in Glenfield City equals 4 plus the sum of the number of private middle school in Westhaven City, the total number of schools in Hawkesbury, and the number of culinarian school in Westhaven City. The number of public highschool in Hawkesbury equals 3. The number of regional medical school in Westhaven City equals 4. The number of regional medical school in Hawkesbury equals 4. The number of culinarian school in Westhaven City equals 3 plus the number of regional medical school in Brightford. The number of private middle school in Westhaven City equals 3 times the total number of schools in Brightford. The number of culinarian school in Hawkesbury equals 2.

Question: What is the total number of schools in Westhaven City?

Solution: Define regional medical school in Brightford as u; so u = 1. Define total number of schools in Brightford as O; so O = u = 1. Define culinarian school in Westhaven City as B; X = u = 1; so B = 3 + X = 3 + 1 = 4. Define regional medical school in Westhaven City as t; so t = 4. Define private middle school in Westhaven City as l; g = O = 1; so l = 3 * g = 3 * 1 = 3. Define total number of schools in Westhaven City as d; x = l + B = 3 + 4 = 7; so d = x + t = 7 + 4 = 11. Answer: 11.


The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of calm road movie in Golden Banana Movie Festival equals 4 times the number of calm road movie in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 plus the difference between the total number of movies in Taylor Movie Festival and the total number of movies in Verdi Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 plus the difference between the total number of movies in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of intense detective thriller in Verdi Movie Festival equals 3. The number of calm road movie in Verdi Movie Festival equals 3. The number of intense detective thriller in Golden Banana Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 4 plus the sum of the number of solemn period drama in Golden Banana Movie Festival, the total number of movies in Taylor Movie Festival, and the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival.

Question: How many solemn period drama does Golden Banana Movie Festival have?

Solution: Define intense detective thriller in Taylor Movie Festival as F; so F = 2. Define upbeat metropolis comedy in Taylor Movie Festival as A; so A = 3. Define solemn period drama in Taylor Movie Festival as h; so h = A - F = 3 - 2 = 1. Define total number of movies in Taylor Movie Festival as G; S = A + h = 3 + 1 = 4; so G = S + F = 4 + 2 = 6. Define solemn period drama in Golden Banana Movie Festival as t; k = G - F = 6 - 2 = 4; so t = 2 + k = 2 + 4 = 6. Answer: 6.


The number of elementary school in Westhaven City equals the number of elementary school in Hawkesbury. The number of regional medical school in Westhaven City equals the sum of the total number of schools in Hawkesbury, the number of elementary school in Westhaven City, and the number of elementary school in Hawkesbury. The number of regional medical school in Hawkesbury equals the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 4.

Question: What is the total number of schools in Westhaven City?

Solution: Define elementary school in Hawkesbury as p; so p = 4. Define elementary school in Westhaven City as a; so a = p = 4. Define regional medical school in Hawkesbury as f; so f = p = 4. Define total number of schools in Hawkesbury as P; so P = p + f = 4 + 4 = 8. Define regional medical school in Westhaven City as n; T = P + a = 8 + 4 = 12; so n = T + p = 12 + 4 = 16. Define total number of schools in Westhaven City as H; so H = a + n = 4 + 16 = 20. Answer: 20.


The number of adult crow in Oakridge Riverside equals the total number of adult animals in Maple Creek. The number of adult blue jay in Maple Creek equals 4 times the number of adult crow in Maple Creek. The number of adult crow in Maple Creek equals 3. The number of adult blue jay in Oakridge Riverside equals 4 times the number of adult crow in Oakridge Riverside.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult crow in Maple Creek as d; so d = 3. Define adult blue jay in Maple Creek as e; j = d = 3; so e = 4 * j = 4 * 3 = 12. Define total number of adult animals in Maple Creek as L; so L = d + e = 3 + 12 = 15. Define adult crow in Oakridge Riverside as t; so t = L = 15. Define adult blue jay in Oakridge Riverside as R; q = t = 15; so R = 4 * q = 4 * 15 = 60. Define total number of adult animals in Oakridge Riverside as Q; so Q = t + R = 15 + 60 = 75. Answer: 75.


The number of calm road movie in Cinéma de Montreval equals 1 plus the number of futuristic sci-fi movie in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The number of intense detective thriller in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Rêves de Belleville equals the number of calm road movie in Rêves de Belleville. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of futuristic sci-fi movie in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 2. The number of calm road movie in Festival de Saint-Rivage equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Rêves de Belleville equals 2. The number of intense detective thriller in Cinéma de Montreval equals the number of calm road movie in Cinéma de Montreval.

Question: How many intense detective thriller does Festival de Saint-Rivage have?

Solution: Define futuristic sci-fi movie in Rêves de Belleville as f; so f = 3. Define calm road movie in Cinéma de Montreval as n; V = f = 3; so n = 1 + V = 1 + 3 = 4. Define intense detective thriller in Cinéma de Montreval as N; so N = n = 4. Define futuristic sci-fi movie in Cinéma de Montreval as g; so g = f = 3. Define total number of movies in Cinéma de Montreval as Q; O = N + g = 4 + 3 = 7; so Q = O + n = 7 + 4 = 11. Define calm road movie in Festival de Saint-Rivage as c; so c = Q = 11. Define intense detective thriller in Festival de Saint-Rivage as Y; so Y = c = 11. Answer: 11.


The number of calm road movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Cinéma de Montreval equals 3 plus the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals 4 plus the sum of the total number of movies in Cinéma de Montreval, the number of calm road movie in Cinéma de Montreval, and the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Cinéma de Montreval equals 4.

Question: How many solemn period drama does Festival Lumière de Valmont have?

Solution: Define calm road movie in Festival Lumière de Valmont as P; so P = 3. Define calm road movie in Cinéma de Montreval as x; J = P = 3; so x = 3 + J = 3 + 3 = 6. Define solemn period drama in Cinéma de Montreval as I; so I = 4. Define total number of movies in Cinéma de Montreval as B; so B = x + I = 6 + 4 = 10. Define solemn period drama in Festival Lumière de Valmont as j; l = B + x = 10 + 6 = 16; n = l + P = 16 + 3 = 19; so j = 4 + n = 4 + 19 = 23. Answer: 23.


The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 2. The number of calm road movie in Taylor Movie Festival equals the total number of movies in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 3. The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the number of upbeat metropolis comedy in Northwood Movie Festival, and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of calm road movie in Northwood Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2 plus the total number of movies in Golden Banana Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define intense detective thriller in Golden Banana Movie Festival as y; so y = 2. Define futuristic sci-fi movie in Golden Banana Movie Festival as l; so l = 2. Define total number of movies in Golden Banana Movie Festival as R; so R = y + l = 2 + 2 = 4. Define calm road movie in Northwood Movie Festival as w; q = R = 4; so w = 2 + q = 2 + 4 = 6. Define upbeat metropolis comedy in Northwood Movie Festival as F; N = w = 6; so F = 1 + N = 1 + 6 = 7. Define total number of movies in Northwood Movie Festival as a; so a = F + w = 7 + 6 = 13. Answer: 13.


The number of private middle school in Evervale City equals 2 times the number of culinarian school in Evervale City. The number of private middle school in Glenfield City equals 4 times the sum of the total number of schools in Evervale City, the number of culinarian school in Evervale City, and the number of private middle school in Evervale City. The number of culinarian school in Evervale City equals 4.

Question: What is the total number of schools in Glenfield City?

Solution: Define culinarian school in Evervale City as L; so L = 4. Define private middle school in Evervale City as o; Y = L = 4; so o = 2 * Y = 2 * 4 = 8. Define total number of schools in Evervale City as T; so T = L + o = 4 + 8 = 12. Define private middle school in Glenfield City as h; U = T + L = 12 + 4 = 16; r = U + o = 16 + 8 = 24; so h = 4 * r = 4 * 24 = 96. Define total number of schools in Glenfield City as F; so F = h = 96. Answer: 96.


The number of culinarian school in Oakbridge City equals 2. The number of elementary school in Oakbridge City equals 1. The number of culinarian school in Ruby Bay equals the number of elementary school in Oakbridge City. The number of elementary school in Ruby Bay equals the sum of the total number of schools in Oakbridge City, the number of culinarian school in Oakbridge City, and the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define culinarian school in Oakbridge City as R; so R = 2. Define elementary school in Oakbridge City as u; so u = 1. Define total number of schools in Oakbridge City as z; so z = u + R = 1 + 2 = 3. Define elementary school in Ruby Bay as F; k = z + R = 3 + 2 = 5; so F = k + u = 5 + 1 = 6. Define culinarian school in Ruby Bay as U; so U = u = 1. Define total number of schools in Ruby Bay as q; so q = F + U = 6 + 1 = 7. Answer: 7.


The number of private middle school in Glenfield City equals the sum of the total number of schools in Evervale City, the number of public highschool in Evervale City, and the number of private middle school in Evervale City. The number of public highschool in Evervale City equals 3. The number of public highschool in Glenfield City equals 2. The number of private middle school in Evervale City equals the number of public highschool in Evervale City.

Question: What is the total number of schools in Glenfield City?

Solution: Define public highschool in Evervale City as S; so S = 3. Define private middle school in Evervale City as q; so q = S = 3. Define total number of schools in Evervale City as A; so A = S + q = 3 + 3 = 6. Define private middle school in Glenfield City as l; g = A + S = 6 + 3 = 9; so l = g + q = 9 + 3 = 12. Define public highschool in Glenfield City as F; so F = 2. Define total number of schools in Glenfield City as I; so I = F + l = 2 + 12 = 14. Answer: 14.


The number of adult owl in Jefferson Circus equals 2 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult crow in Mayer Aquarium, and the number of adult owl in Mayer Aquarium. The number of adult owl in Mayer Aquarium equals 2 plus the number of adult crow in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 2.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult crow in Mayer Aquarium as U; so U = 2. Define adult owl in Mayer Aquarium as i; a = U = 2; so i = 2 + a = 2 + 2 = 4. Define total number of adult animals in Mayer Aquarium as S; so S = U + i = 2 + 4 = 6. Define adult owl in Jefferson Circus as y; v = S + U = 6 + 2 = 8; X = v + i = 8 + 4 = 12; so y = 2 * X = 2 * 12 = 24. Define total number of adult animals in Jefferson Circus as A; so A = y = 24. Answer: 24.


The number of culinarian school in Shoreline City equals 1 plus the number of regional medical school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals the sum of the total number of schools in Shoreline City, the number of culinarian school in Shoreline City, the number of regional medical school in Shoreline City, and the number of regional medical school in Clearwater Bay. The number of regional medical school in Shoreline City equals the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 3.

Question: How many culinarian school does Clearwater Bay have?

Solution: Define regional medical school in Clearwater Bay as Z; so Z = 3. Define regional medical school in Shoreline City as P; so P = Z = 3. Define culinarian school in Shoreline City as c; Q = Z = 3; so c = 1 + Q = 1 + 3 = 4. Define total number of schools in Shoreline City as v; so v = P + c = 3 + 4 = 7. Define culinarian school in Clearwater Bay as j; K = v + c = 7 + 4 = 11; A = K + P = 11 + 3 = 14; so j = A + Z = 14 + 3 = 17. Answer: 17.


The number of calm road movie in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 1 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4. The number of calm road movie in Northwood Movie Festival equals the difference between the number of futuristic sci-fi movie in Northwood Movie Festival and the number of solemn period drama in Taylor Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 3 times the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the sum of the number of futuristic sci-fi movie in Verdi Movie Festival, the number of upbeat metropolis comedy in Verdi Movie Festival, and the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The number of calm road movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define futuristic sci-fi movie in Verdi Movie Festival as D; so D = 4. Define solemn period drama in Verdi Movie Festival as T; j = D = 4; so T = 1 + j = 1 + 4 = 5. Define upbeat metropolis comedy in Verdi Movie Festival as N; t = D = 4; so N = 4 + t = 4 + 4 = 8. Define calm road movie in Verdi Movie Festival as f; so f = N = 8. Define total number of movies in Verdi Movie Festival as m; G = T + N = 5 + 8 = 13; a = G + D = 13 + 4 = 17; so m = a + f = 17 + 8 = 25. Answer: 25.


The number of adult parrot in Beverly Forest equals 4. The number of adult parrot in Maple Creek equals 3. The number of adult owl in Maple Creek equals 4 plus the sum of the total number of adult animals in Beverly Forest and the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 4.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult parrot in Beverly Forest as h; so h = 4. Define adult owl in Beverly Forest as R; so R = 4. Define total number of adult animals in Beverly Forest as c; so c = R + h = 4 + 4 = 8. Define adult owl in Maple Creek as B; F = c + R = 8 + 4 = 12; so B = 4 + F = 4 + 12 = 16. Define adult parrot in Maple Creek as O; so O = 3. Define total number of adult animals in Maple Creek as e; so e = O + B = 3 + 16 = 19. Answer: 19.


The number of solemn period drama in Festival de Saint-Rivage equals 2 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of solemn period drama in Festival de Clairmont equals 2 times the sum of the total number of movies in Festival de Saint-Rivage, the number of futuristic sci-fi movie in Festival de Saint-Rivage, and the number of solemn period drama in Festival de Saint-Rivage.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as H; so H = 4. Define solemn period drama in Festival de Saint-Rivage as f; v = H = 4; so f = 2 * v = 2 * 4 = 8. Define total number of movies in Festival de Saint-Rivage as F; so F = H + f = 4 + 8 = 12. Define solemn period drama in Festival de Clairmont as a; T = F + H = 12 + 4 = 16; b = T + f = 16 + 8 = 24; so a = 2 * b = 2 * 24 = 48. Define total number of movies in Festival de Clairmont as w; so w = a = 48. Answer: 48.


The number of adult blue jay in Oakridge Riverside equals 2. The number of adult crow in Pine Ridge equals 2 times the total number of adult animals in Cedar Valley. The number of adult parrot in Pine Ridge equals 4. The number of adult owl in Cedar Valley equals 4 plus the sum of the number of adult blue jay in Cedar Valley and the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Pine Ridge equals 1. The number of adult parrot in Oakridge Riverside equals the difference between the number of adult owl in Pine Ridge and the number of adult crow in Pine Ridge. The number of adult owl in Pine Ridge equals the number of adult crow in Pine Ridge. The number of adult blue jay in Cedar Valley equals the number of adult blue jay in Oakridge Riverside.

Question: How many adult owl does Pine Ridge have?

Solution: Define adult blue jay in Oakridge Riverside as b; so b = 2. Define adult blue jay in Cedar Valley as h; so h = b = 2. Define adult owl in Cedar Valley as s; U = h + b = 2 + 2 = 4; so s = 4 + U = 4 + 4 = 8. Define total number of adult animals in Cedar Valley as g; so g = h + s = 2 + 8 = 10. Define adult crow in Pine Ridge as j; k = g = 10; so j = 2 * k = 2 * 10 = 20. Define adult owl in Pine Ridge as E; so E = j = 20. Answer: 20.


The number of culinarian school in Westhaven City equals the sum of the number of private middle school in Westhaven City, the number of private middle school in Evervale City, and the total number of schools in Evervale City. The number of private middle school in Westhaven City equals 3 plus the difference between the total number of schools in Evervale City and the number of culinarian school in Evervale City. The number of culinarian school in Evervale City equals 4. The number of private middle school in Evervale City equals the number of culinarian school in Evervale City.

Question: How many culinarian school does Westhaven City have?

Solution: Define culinarian school in Evervale City as l; so l = 4. Define private middle school in Evervale City as z; so z = l = 4. Define total number of schools in Evervale City as C; so C = l + z = 4 + 4 = 8. Define private middle school in Westhaven City as V; h = C - l = 8 - 4 = 4; so V = 3 + h = 3 + 4 = 7. Define culinarian school in Westhaven City as n; d = V + z = 7 + 4 = 11; so n = d + C = 11 + 8 = 19. Answer: 19.


The number of adult parrot in Hamilton Farm equals the number of adult parrot in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 2. The number of adult parrot in Mayer Aquarium equals 3 times the number of adult eagle in Mayer Aquarium. The number of adult eagle in Hamilton Farm equals 1 plus the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult eagle in Mayer Aquarium as U; so U = 2. Define adult parrot in Mayer Aquarium as a; b = U = 2; so a = 3 * b = 3 * 2 = 6. Define total number of adult animals in Mayer Aquarium as p; so p = a + U = 6 + 2 = 8. Define adult eagle in Hamilton Farm as W; y = p = 8; so W = 1 + y = 1 + 8 = 9. Define adult parrot in Hamilton Farm as u; so u = a = 6. Define total number of adult animals in Hamilton Farm as E; so E = u + W = 6 + 9 = 15. Answer: 15.


The number of upbeat metropolis comedy in Festival de Clairmont equals 4 times the number of futuristic sci-fi movie in Rêves de Belleville. The number of calm road movie in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3. The number of intense detective thriller in Festival Lumière de Valmont equals the number of calm road movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3 times the difference between the total number of movies in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Rêves de Belleville equals 4 plus the difference between the number of futuristic sci-fi movie in Rêves de Belleville and the number of upbeat metropolis comedy in Festival de Clairmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define solemn period drama in Festival de Saint-Rivage as Z; so Z = 2. Define calm road movie in Festival de Saint-Rivage as S; so S = Z = 2. Define total number of movies in Festival de Saint-Rivage as s; so s = Z + S = 2 + 2 = 4. Define futuristic sci-fi movie in Festival Lumière de Valmont as R; Y = s - Z = 4 - 2 = 2; so R = 3 * Y = 3 * 2 = 6. Define intense detective thriller in Festival Lumière de Valmont as E; so E = S = 2. Define total number of movies in Festival Lumière de Valmont as M; so M = E + R = 2 + 6 = 8. Answer: 8.


The number of regional medical school in Shoreline City equals 2 plus the sum of the number of culinarian school in Clearwater Bay and the number of culinarian school in Shoreline City. The number of culinarian school in Clearwater Bay equals 4. The number of culinarian school in Shoreline City equals 3 plus the sum of the total number of schools in Clearwater Bay and the number of culinarian school in Clearwater Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define culinarian school in Clearwater Bay as c; so c = 4. Define total number of schools in Clearwater Bay as D; so D = c = 4. Define culinarian school in Shoreline City as N; O = D + c = 4 + 4 = 8; so N = 3 + O = 3 + 8 = 11. Define regional medical school in Shoreline City as a; J = c + N = 4 + 11 = 15; so a = 2 + J = 2 + 15 = 17. Define total number of schools in Shoreline City as b; so b = a + N = 17 + 11 = 28. Answer: 28.


The number of adult wolf in Jefferson Circus equals 2 times the sum of the total number of adult animals in Hamilton Farm, the number of adult racoon in Hamilton Farm, and the number of adult wolf in Hamilton Farm. The number of adult wolf in Hamilton Farm equals 2 times the number of adult racoon in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult racoon in Hamilton Farm as i; so i = 2. Define adult wolf in Hamilton Farm as B; I = i = 2; so B = 2 * I = 2 * 2 = 4. Define total number of adult animals in Hamilton Farm as K; so K = B + i = 4 + 2 = 6. Define adult wolf in Jefferson Circus as d; Q = K + i = 6 + 2 = 8; u = Q + B = 8 + 4 = 12; so d = 2 * u = 2 * 12 = 24. Define total number of adult animals in Jefferson Circus as r; so r = d = 24. Answer: 24.


The number of culinarian school in Westhaven City equals 4. The number of regional medical school in Westhaven City equals 2 times the number of culinarian school in Westhaven City. The number of regional medical school in Hawkesbury equals 3 plus the total number of schools in Westhaven City. The number of culinarian school in Hawkesbury equals the number of regional medical school in Hawkesbury.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Westhaven City as d; so d = 4. Define regional medical school in Westhaven City as x; s = d = 4; so x = 2 * s = 2 * 4 = 8. Define total number of schools in Westhaven City as W; so W = d + x = 4 + 8 = 12. Define regional medical school in Hawkesbury as b; R = W = 12; so b = 3 + R = 3 + 12 = 15. Define culinarian school in Hawkesbury as V; so V = b = 15. Define total number of schools in Hawkesbury as I; so I = b + V = 15 + 15 = 30. Answer: 30.


The number of adult deer in Bundle Ranch equals 2 times the number of adult bear in Bundle Ranch. The number of adult bear in Hamilton Farm equals 2 plus the sum of the total number of adult animals in Bundle Ranch, the number of adult bear in Bundle Ranch, and the number of adult deer in Bundle Ranch. The number of adult bear in Bundle Ranch equals 1.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult bear in Bundle Ranch as Y; so Y = 1. Define adult deer in Bundle Ranch as u; D = Y = 1; so u = 2 * D = 2 * 1 = 2. Define total number of adult animals in Bundle Ranch as p; so p = Y + u = 1 + 2 = 3. Define adult bear in Hamilton Farm as F; r = p + Y = 3 + 1 = 4; j = r + u = 4 + 2 = 6; so F = 2 + j = 2 + 6 = 8. Define total number of adult animals in Hamilton Farm as V; so V = F = 8. Answer: 8.


The number of adult blue jay in Cedar Valley equals the number of adult eagle in Cedar Valley. The number of adult eagle in Oakridge Riverside equals 3 times the total number of adult animals in Cedar Valley. The number of adult blue jay in Oakridge Riverside equals 3 times the number of adult eagle in Cedar Valley. The number of adult eagle in Cedar Valley equals 2.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult eagle in Cedar Valley as K; so K = 2. Define adult blue jay in Oakridge Riverside as c; W = K = 2; so c = 3 * W = 3 * 2 = 6. Define adult blue jay in Cedar Valley as z; so z = K = 2. Define total number of adult animals in Cedar Valley as S; so S = K + z = 2 + 2 = 4. Define adult eagle in Oakridge Riverside as v; t = S = 4; so v = 3 * t = 3 * 4 = 12. Define total number of adult animals in Oakridge Riverside as h; so h = v + c = 12 + 6 = 18. Answer: 18.


The number of upbeat metropolis comedy in Rêves de Belleville equals the difference between the total number of movies in Festival de Saint-Rivage and the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 3 plus the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4. The number of intense detective thriller in Rêves de Belleville equals the number of upbeat metropolis comedy in Festival de Saint-Rivage.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define upbeat metropolis comedy in Festival de Saint-Rivage as d; so d = 4. Define intense detective thriller in Festival de Saint-Rivage as U; G = d = 4; so U = 3 + G = 3 + 4 = 7. Define total number of movies in Festival de Saint-Rivage as q; so q = U + d = 7 + 4 = 11. Define upbeat metropolis comedy in Rêves de Belleville as X; so X = q - U = 11 - 7 = 4. Define intense detective thriller in Rêves de Belleville as O; so O = d = 4. Define total number of movies in Rêves de Belleville as I; so I = O + X = 4 + 4 = 8. Answer: 8.


The number of futuristic sci-fi movie in Festival de Clairmont equals 3. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 times the sum of the total number of movies in Festival de Clairmont and the number of futuristic sci-fi movie in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Festival de Clairmont as N; so N = 3. Define upbeat metropolis comedy in Festival de Clairmont as L; so L = N = 3. Define total number of movies in Festival de Clairmont as E; so E = L + N = 3 + 3 = 6. Define upbeat metropolis comedy in Festival de Saint-Rivage as i; C = E + N = 6 + 3 = 9; so i = 2 * C = 2 * 9 = 18. Define futuristic sci-fi movie in Festival de Saint-Rivage as A; so A = 4. Define total number of movies in Festival de Saint-Rivage as a; so a = i + A = 18 + 4 = 22. Answer: 22.


The number of culinarian school in Ruby Bay equals 4 plus the sum of the number of regional medical school in Ruby Bay and the number of culinarian school in Shoreline City. The number of private middle school in Shoreline City equals 3 plus the number of private middle school in Riverton City. The number of regional medical school in Riverton City equals the number of private middle school in Riverton City. The number of private middle school in Ruby Bay equals 3 times the number of culinarian school in Shoreline City. The number of regional medical school in Ruby Bay equals the number of culinarian school in Shoreline City. The number of private middle school in Riverton City equals 3. The number of culinarian school in Shoreline City equals 1. The number of regional medical school in Shoreline City equals the sum of the number of private middle school in Riverton City and the number of regional medical school in Riverton City. The number of culinarian school in Riverton City equals the total number of schools in Ruby Bay.

Question: What is the total number of schools in Ruby Bay?

Solution: Define culinarian school in Shoreline City as l; so l = 1. Define private middle school in Ruby Bay as z; D = l = 1; so z = 3 * D = 3 * 1 = 3. Define regional medical school in Ruby Bay as H; so H = l = 1. Define culinarian school in Ruby Bay as g; Y = H + l = 1 + 1 = 2; so g = 4 + Y = 4 + 2 = 6. Define total number of schools in Ruby Bay as k; u = g + z = 6 + 3 = 9; so k = u + H = 9 + 1 = 10. Answer: 10.


The number of regional medical school in Evervale City equals 3. The number of regional medical school in Brightford equals 3. The number of public highschool in Evervale City equals the difference between the number of public highschool in Brightford and the number of regional medical school in Brightford. The number of elementary school in Evervale City equals the number of public highschool in Evervale City. The number of public highschool in Brightford equals 3 plus the number of regional medical school in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Brightford as g; so g = 3. Define public highschool in Brightford as m; T = g = 3; so m = 3 + T = 3 + 3 = 6. Define public highschool in Evervale City as V; so V = m - g = 6 - 3 = 3. Define elementary school in Evervale City as i; so i = V = 3. Define regional medical school in Evervale City as c; so c = 3. Define total number of schools in Evervale City as C; h = c + V = 3 + 3 = 6; so C = h + i = 6 + 3 = 9. Answer: 9.


The number of adult racoon in Mayer Aquarium equals 3 times the number of adult deer in Mayer Aquarium. The number of adult racoon in Bundle Ranch equals 4 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult deer in Mayer Aquarium, and the number of adult racoon in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult deer in Mayer Aquarium as v; so v = 4. Define adult racoon in Mayer Aquarium as z; D = v = 4; so z = 3 * D = 3 * 4 = 12. Define total number of adult animals in Mayer Aquarium as i; so i = z + v = 12 + 4 = 16. Define adult racoon in Bundle Ranch as T; Y = i + v = 16 + 4 = 20; R = Y + z = 20 + 12 = 32; so T = 4 * R = 4 * 32 = 128. Define total number of adult animals in Bundle Ranch as O; so O = T = 128. Answer: 128.


The number of private middle school in Glenfield City equals the number of private middle school in Hawkesbury. The number of private middle school in Brightford equals the number of public highschool in Hawkesbury. The number of culinarian school in Brightford equals 3. The number of public highschool in Glenfield City equals 2 times the sum of the number of regional medical school in Westhaven City, the total number of schools in Glenfield City, and the number of private middle school in Hawkesbury. The number of culinarian school in Westhaven City equals the sum of the total number of schools in Westhaven City, the total number of schools in Hawkesbury, and the number of private middle school in Brightford. The number of public highschool in Hawkesbury equals the number of private middle school in Hawkesbury. The number of public highschool in Brightford equals the sum of the total number of schools in Hawkesbury, the number of private middle school in Hawkesbury, and the number of regional medical school in Hawkesbury. The number of regional medical school in Hawkesbury equals 4 plus the number of public highschool in Hawkesbury. The number of private middle school in Hawkesbury equals 4. The number of public highschool in Westhaven City equals 3. The number of regional medical school in Brightford equals 2. The number of culinarian school in Glenfield City equals 4 plus the number of regional medical school in Hawkesbury. The number of regional medical school in Westhaven City equals 4.

Question: How many public highschool does Brightford have?

Solution: Define private middle school in Hawkesbury as T; so T = 4. Define public highschool in Hawkesbury as O; so O = T = 4. Define regional medical school in Hawkesbury as M; p = O = 4; so M = 4 + p = 4 + 4 = 8. Define total number of schools in Hawkesbury as K; J = M + O = 8 + 4 = 12; so K = J + T = 12 + 4 = 16. Define public highschool in Brightford as b; m = K + T = 16 + 4 = 20; so b = m + M = 20 + 8 = 28. Answer: 28.


The number of futuristic sci-fi movie in Cinéma de Montreval equals 4. The number of intense detective thriller in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Cinéma de Montreval equals the sum of the total number of movies in Festival de Clairmont, the number of intense detective thriller in Festival de Clairmont, and the number of futuristic sci-fi movie in Festival de Clairmont.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define intense detective thriller in Festival de Clairmont as p; so p = 3. Define futuristic sci-fi movie in Festival de Clairmont as k; so k = p = 3. Define total number of movies in Festival de Clairmont as h; so h = p + k = 3 + 3 = 6. Define intense detective thriller in Cinéma de Montreval as a; Z = h + p = 6 + 3 = 9; so a = Z + k = 9 + 3 = 12. Define futuristic sci-fi movie in Cinéma de Montreval as e; so e = 4. Define total number of movies in Cinéma de Montreval as W; so W = e + a = 4 + 12 = 16. Answer: 16.


The number of regional medical school in Brightford equals 3 plus the number of elementary school in Brightford. The number of elementary school in Brightford equals 3. The number of regional medical school in Evervale City equals the total number of schools in Brightford. The number of elementary school in Evervale City equals 2 plus the total number of schools in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Brightford as e; so e = 3. Define regional medical school in Brightford as E; n = e = 3; so E = 3 + n = 3 + 3 = 6. Define total number of schools in Brightford as c; so c = e + E = 3 + 6 = 9. Define regional medical school in Evervale City as Z; so Z = c = 9. Define elementary school in Evervale City as F; a = c = 9; so F = 2 + a = 2 + 9 = 11. Define total number of schools in Evervale City as H; so H = F + Z = 11 + 9 = 20. Answer: 20.


The number of adult racoon in Oakridge Riverside equals 1 plus the total number of adult animals in Maple Creek. The number of adult fox in Oakridge Riverside equals the sum of the number of adult racoon in Maple Creek and the total number of adult animals in Maple Creek. The number of adult fox in Maple Creek equals the number of adult racoon in Maple Creek. The number of adult racoon in Maple Creek equals 3.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult racoon in Maple Creek as H; so H = 3. Define adult fox in Maple Creek as Q; so Q = H = 3. Define total number of adult animals in Maple Creek as I; so I = H + Q = 3 + 3 = 6. Define adult racoon in Oakridge Riverside as C; K = I = 6; so C = 1 + K = 1 + 6 = 7. Define adult fox in Oakridge Riverside as r; so r = H + I = 3 + 6 = 9. Define total number of adult animals in Oakridge Riverside as q; so q = C + r = 7 + 9 = 16. Answer: 16.


The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3 times the difference between the total number of movies in Taylor Movie Festival and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2 plus the difference between the total number of movies in Golden Banana Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the total number of movies in Golden Banana Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as u; so u = 4. Define calm road movie in Taylor Movie Festival as s; so s = u = 4. Define total number of movies in Taylor Movie Festival as b; so b = s + u = 4 + 4 = 8. Define solemn period drama in Golden Banana Movie Festival as F; L = b - u = 8 - 4 = 4; so F = 3 * L = 3 * 4 = 12. Define calm road movie in Golden Banana Movie Festival as A; so A = s = 4. Define total number of movies in Golden Banana Movie Festival as i; so i = A + F = 4 + 12 = 16. Answer: 16.


The number of solemn period drama in Rêves de Belleville equals 4 times the total number of movies in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4 plus the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Festival Lumière de Valmont as A; so A = 3. Define futuristic sci-fi movie in Rêves de Belleville as N; so N = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as l; o = A = 3; so l = 4 + o = 4 + 3 = 7. Define total number of movies in Festival Lumière de Valmont as R; so R = A + l = 3 + 7 = 10. Define solemn period drama in Rêves de Belleville as c; B = R = 10; so c = 4 * B = 4 * 10 = 40. Define total number of movies in Rêves de Belleville as g; so g = c + N = 40 + 3 = 43. Answer: 43.


The number of elementary school in Westhaven City equals 2. The number of public highschool in Westhaven City equals 4 times the number of elementary school in Westhaven City. The number of elementary school in Evervale City equals the number of public highschool in Westhaven City. The number of public highschool in Evervale City equals 3 plus the total number of schools in Westhaven City.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Westhaven City as B; so B = 2. Define public highschool in Westhaven City as J; m = B = 2; so J = 4 * m = 4 * 2 = 8. Define total number of schools in Westhaven City as o; so o = J + B = 8 + 2 = 10. Define public highschool in Evervale City as s; a = o = 10; so s = 3 + a = 3 + 10 = 13. Define elementary school in Evervale City as g; so g = J = 8. Define total number of schools in Evervale City as h; so h = s + g = 13 + 8 = 21. Answer: 21.


The number of regional medical school in Glenfield City equals 4. The number of culinarian school in Brightford equals 4 plus the sum of the total number of schools in Glenfield City, the number of regional medical school in Glenfield City, and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 4 times the number of regional medical school in Glenfield City.

Question: What is the total number of schools in Brightford?

Solution: Define regional medical school in Glenfield City as R; so R = 4. Define culinarian school in Glenfield City as M; e = R = 4; so M = 4 * e = 4 * 4 = 16. Define total number of schools in Glenfield City as W; so W = M + R = 16 + 4 = 20. Define culinarian school in Brightford as I; p = W + R = 20 + 4 = 24; Y = p + M = 24 + 16 = 40; so I = 4 + Y = 4 + 40 = 44. Define total number of schools in Brightford as Q; so Q = I = 44. Answer: 44.


The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 times the number of intense detective thriller in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the sum of the number of intense detective thriller in Festival Lumière de Valmont and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 4 times the number of intense detective thriller in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 times the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 4.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define intense detective thriller in Festival Lumière de Valmont as h; so h = 4. Define intense detective thriller in Festival de Saint-Rivage as t; H = h = 4; so t = 4 * H = 4 * 4 = 16. Define futuristic sci-fi movie in Festival de Saint-Rivage as b; B = h = 4; so b = 3 * B = 3 * 4 = 12. Define upbeat metropolis comedy in Festival de Saint-Rivage as i; so i = h + b = 4 + 12 = 16. Define total number of movies in Festival de Saint-Rivage as R; o = i + b = 16 + 12 = 28; so R = o + t = 28 + 16 = 44. Answer: 44.


The number of culinarian school in Evervale City equals 2. The number of public highschool in Evervale City equals 2 times the number of culinarian school in Evervale City. The number of culinarian school in Brightford equals the number of culinarian school in Evervale City. The number of private middle school in Hawkesbury equals 3 plus the number of culinarian school in Hawkesbury. The number of public highschool in Glenfield City equals the sum of the number of private middle school in Evervale City and the number of culinarian school in Evervale City. The number of elementary school in Glenfield City equals the number of culinarian school in Hawkesbury. The number of public highschool in Brightford equals the difference between the number of culinarian school in Evervale City and the number of public highschool in Glenfield City. The number of private middle school in Brightford equals 4 times the difference between the number of elementary school in Brightford and the number of private middle school in Evervale City. The number of elementary school in Brightford equals 4. The number of culinarian school in Glenfield City equals 2 times the difference between the number of private middle school in Hawkesbury and the number of public highschool in Hawkesbury. The number of culinarian school in Hawkesbury equals 1. The number of elementary school in Evervale City equals the number of private middle school in Evervale City. The number of private middle school in Glenfield City equals 2. The number of public highschool in Hawkesbury equals 1 plus the number of culinarian school in Hawkesbury. The number of private middle school in Evervale City equals 4. The number of elementary school in Hawkesbury equals the number of culinarian school in Hawkesbury.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Hawkesbury as F; so F = 1. Define elementary school in Hawkesbury as p; so p = F = 1. Define public highschool in Hawkesbury as r; n = F = 1; so r = 1 + n = 1 + 1 = 2. Define private middle school in Hawkesbury as Y; O = F = 1; so Y = 3 + O = 3 + 1 = 4. Define total number of schools in Hawkesbury as Z; q = Y + r = 4 + 2 = 6; t = q + p = 6 + 1 = 7; so Z = t + F = 7 + 1 = 8. Answer: 8.


The number of adult fox in Bundle Ranch equals 1. The number of adult racoon in Mayer Aquarium equals 2 plus the sum of the total number of adult animals in Hamilton Farm, the number of adult wolf in Hamilton Farm, and the number of adult fox in Hamilton Farm. The number of adult wolf in Hamilton Farm equals 3. The number of adult fox in Hamilton Farm equals 4 plus the number of adult wolf in Hamilton Farm. The number of adult racoon in Bundle Ranch equals 1 plus the sum of the number of adult racoon in Mayer Aquarium and the number of adult wolf in Hamilton Farm. The number of adult wolf in Bundle Ranch equals the number of adult wolf in Hamilton Farm.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult wolf in Hamilton Farm as I; so I = 3. Define adult fox in Hamilton Farm as N; F = I = 3; so N = 4 + F = 4 + 3 = 7. Define total number of adult animals in Hamilton Farm as a; so a = N + I = 7 + 3 = 10. Define adult racoon in Mayer Aquarium as u; K = a + I = 10 + 3 = 13; g = K + N = 13 + 7 = 20; so u = 2 + g = 2 + 20 = 22. Define total number of adult animals in Mayer Aquarium as p; so p = u = 22. Answer: 22.


The number of adult wolf in Cedar Valley equals 1 plus the difference between the number of adult racoon in Cedar Valley and the total number of adult animals in Beverly Forest. The number of adult wolf in Beverly Forest equals 3. The number of adult racoon in Cedar Valley equals 1 plus the sum of the total number of adult animals in Beverly Forest and the number of adult wolf in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Beverly Forest as m; so m = 3. Define total number of adult animals in Beverly Forest as G; so G = m = 3. Define adult racoon in Cedar Valley as q; L = G + m = 3 + 3 = 6; so q = 1 + L = 1 + 6 = 7. Define adult wolf in Cedar Valley as s; g = q - G = 7 - 3 = 4; so s = 1 + g = 1 + 4 = 5. Define total number of adult animals in Cedar Valley as t; so t = s + q = 5 + 7 = 12. Answer: 12.


The number of regional medical school in Shoreline City equals 2 plus the sum of the total number of schools in Riverton City, the number of regional medical school in Riverton City, and the number of private middle school in Riverton City. The number of private middle school in Riverton City equals 3 plus the number of regional medical school in Riverton City. The number of regional medical school in Riverton City equals 3.

Question: What is the total number of schools in Shoreline City?

Solution: Define regional medical school in Riverton City as v; so v = 3. Define private middle school in Riverton City as S; o = v = 3; so S = 3 + o = 3 + 3 = 6. Define total number of schools in Riverton City as X; so X = S + v = 6 + 3 = 9. Define regional medical school in Shoreline City as b; O = X + v = 9 + 3 = 12; Q = O + S = 12 + 6 = 18; so b = 2 + Q = 2 + 18 = 20. Define total number of schools in Shoreline City as Z; so Z = b = 20. Answer: 20.


The number of adult owl in South Zoo equals 3 times the sum of the number of adult crow in South Zoo and the total number of adult animals in Bundle Ranch. The number of adult crow in South Zoo equals 1 plus the sum of the total number of adult animals in Bundle Ranch and the number of adult owl in Bundle Ranch. The number of adult owl in Bundle Ranch equals 2.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult owl in Bundle Ranch as i; so i = 2. Define total number of adult animals in Bundle Ranch as D; so D = i = 2. Define adult crow in South Zoo as R; L = D + i = 2 + 2 = 4; so R = 1 + L = 1 + 4 = 5. Define adult owl in South Zoo as s; y = R + D = 5 + 2 = 7; so s = 3 * y = 3 * 7 = 21. Define total number of adult animals in South Zoo as K; so K = s + R = 21 + 5 = 26. Answer: 26.


The number of adult parrot in Oakridge Riverside equals 3 plus the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Cedar Valley equals 3 times the total number of adult animals in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 3. The number of adult parrot in Cedar Valley equals the number of adult blue jay in Cedar Valley.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult blue jay in Oakridge Riverside as O; so O = 3. Define adult parrot in Oakridge Riverside as j; B = O = 3; so j = 3 + B = 3 + 3 = 6. Define total number of adult animals in Oakridge Riverside as V; so V = O + j = 3 + 6 = 9. Define adult blue jay in Cedar Valley as M; e = V = 9; so M = 3 * e = 3 * 9 = 27. Define adult parrot in Cedar Valley as R; so R = M = 27. Define total number of adult animals in Cedar Valley as u; so u = M + R = 27 + 27 = 54. Answer: 54.


The number of private middle school in Clearwater Bay equals 3 plus the difference between the total number of schools in Ruby Bay and the number of elementary school in Ruby Bay. The number of private middle school in Riverton City equals 4 plus the sum of the total number of schools in Riverton City, the total number of schools in Ruby Bay, and the number of elementary school in Oakbridge City. The number of elementary school in Oakbridge City equals the number of regional medical school in Riverton City. The number of elementary school in Clearwater Bay equals the number of private middle school in Clearwater Bay. The number of elementary school in Ruby Bay equals 2. The number of regional medical school in Riverton City equals 4 plus the total number of schools in Clearwater Bay. The number of culinarian school in Riverton City equals 1.

Question: How many regional medical school does Riverton City have?

Solution: Define elementary school in Ruby Bay as l; so l = 2. Define total number of schools in Ruby Bay as Y; so Y = l = 2. Define private middle school in Clearwater Bay as q; D = Y - l = 2 - 2 = 0; so q = 3 + D = 3 + 0 = 3. Define elementary school in Clearwater Bay as j; so j = q = 3. Define total number of schools in Clearwater Bay as P; so P = j + q = 3 + 3 = 6. Define regional medical school in Riverton City as U; a = P = 6; so U = 4 + a = 4 + 6 = 10. Answer: 10.


The number of adult eagle in Maple Creek equals the number of adult eagle in Pine Ridge. The number of adult crow in Maple Creek equals 4 times the total number of adult animals in Pine Ridge. The number of adult crow in Pine Ridge equals 4. The number of adult eagle in Pine Ridge equals 3 plus the number of adult crow in Pine Ridge.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult crow in Pine Ridge as S; so S = 4. Define adult eagle in Pine Ridge as d; O = S = 4; so d = 3 + O = 3 + 4 = 7. Define total number of adult animals in Pine Ridge as H; so H = d + S = 7 + 4 = 11. Define adult eagle in Maple Creek as w; so w = d = 7. Define adult crow in Maple Creek as o; Y = H = 11; so o = 4 * Y = 4 * 11 = 44. Define total number of adult animals in Maple Creek as u; so u = w + o = 7 + 44 = 51. Answer: 51.


The number of calm road movie in Taylor Movie Festival equals 4. The number of solemn period drama in Taylor Movie Festival equals 3. The number of solemn period drama in Northwood Movie Festival equals 4 plus the number of calm road movie in Taylor Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3 times the difference between the number of upbeat metropolis comedy in Northwood Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 times the sum of the number of solemn period drama in Northwood Movie Festival and the number of calm road movie in Taylor Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define calm road movie in Taylor Movie Festival as f; so f = 4. Define solemn period drama in Northwood Movie Festival as Q; L = f = 4; so Q = 4 + L = 4 + 4 = 8. Define intense detective thriller in Northwood Movie Festival as e; so e = f = 4. Define upbeat metropolis comedy in Northwood Movie Festival as u; W = Q + f = 8 + 4 = 12; so u = 4 * W = 4 * 12 = 48. Define total number of movies in Northwood Movie Festival as X; m = Q + u = 8 + 48 = 56; so X = m + e = 56 + 4 = 60. Answer: 60.


The number of adult fox in Jefferson Circus equals the total number of adult animals in Hamilton Farm. The number of adult bear in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult fox in Hamilton Farm, and the total number of adult animals in Hamilton Farm. The number of adult fox in Hamilton Farm equals 3. The number of adult racoon in Jefferson Circus equals the number of adult fox in Hamilton Farm.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult fox in Hamilton Farm as w; so w = 3. Define total number of adult animals in Hamilton Farm as Z; so Z = w = 3. Define adult racoon in Jefferson Circus as y; so y = w = 3. Define adult fox in Jefferson Circus as z; so z = Z = 3. Define total number of adult animals in Jefferson Circus as t; so t = z + y = 3 + 3 = 6. Define adult bear in South Zoo as X; R = t + w = 6 + 3 = 9; so X = R + Z = 9 + 3 = 12. Define total number of adult animals in South Zoo as p; so p = X = 12. Answer: 12.


The number of adult blue jay in Beverly Forest equals 1. The number of adult eagle in Oakridge Riverside equals 4. The number of adult blue jay in Oakridge Riverside equals 2 times the number of adult eagle in Oakridge Riverside. The number of adult eagle in Beverly Forest equals 4 plus the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult eagle in Oakridge Riverside as c; so c = 4. Define adult blue jay in Oakridge Riverside as t; Y = c = 4; so t = 2 * Y = 2 * 4 = 8. Define total number of adult animals in Oakridge Riverside as x; so x = t + c = 8 + 4 = 12. Define adult eagle in Beverly Forest as a; W = x = 12; so a = 4 + W = 4 + 12 = 16. Define adult blue jay in Beverly Forest as d; so d = 1. Define total number of adult animals in Beverly Forest as G; so G = a + d = 16 + 1 = 17. Answer: 17.


The number of private middle school in Riverton City equals the number of culinarian school in Riverton City. The number of regional medical school in Oakbridge City equals 4 times the total number of schools in Riverton City. The number of culinarian school in Riverton City equals 3. The number of private middle school in Oakbridge City equals 4 times the number of private middle school in Riverton City. The number of culinarian school in Shoreline City equals 3.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Riverton City as d; so d = 3. Define private middle school in Riverton City as C; so C = d = 3. Define total number of schools in Riverton City as p; so p = d + C = 3 + 3 = 6. Define regional medical school in Oakbridge City as V; S = p = 6; so V = 4 * S = 4 * 6 = 24. Define private middle school in Oakbridge City as h; u = C = 3; so h = 4 * u = 4 * 3 = 12. Define total number of schools in Oakbridge City as m; so m = V + h = 24 + 12 = 36. Answer: 36.


The number of adult wolf in Hamilton Farm equals 4. The number of adult racoon in South Zoo equals the total number of adult animals in Hamilton Farm. The number of adult deer in Hamilton Farm equals 3 plus the number of adult wolf in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2 plus the sum of the number of adult wolf in Hamilton Farm and the number of adult deer in Hamilton Farm. The number of adult wolf in Mayer Aquarium equals 3 times the number of adult deer in South Zoo. The number of adult deer in Mayer Aquarium equals the number of adult deer in South Zoo. The number of adult racoon in Mayer Aquarium equals 3. The number of adult wolf in South Zoo equals 4 times the difference between the number of adult deer in South Zoo and the number of adult racoon in Hamilton Farm. The number of adult deer in South Zoo equals 1.

Question: How many adult racoon does South Zoo have?

Solution: Define adult wolf in Hamilton Farm as O; so O = 4. Define adult deer in Hamilton Farm as J; E = O = 4; so J = 3 + E = 3 + 4 = 7. Define adult racoon in Hamilton Farm as g; z = O + J = 4 + 7 = 11; so g = 2 + z = 2 + 11 = 13. Define total number of adult animals in Hamilton Farm as L; q = J + g = 7 + 13 = 20; so L = q + O = 20 + 4 = 24. Define adult racoon in South Zoo as T; so T = L = 24. Answer: 24.


The number of culinarian school in Riverton City equals 2 plus the sum of the total number of schools in Clearwater Bay, the number of public highschool in Clearwater Bay, and the number of elementary school in Clearwater Bay. The number of elementary school in Oakbridge City equals 4. The number of regional medical school in Oakbridge City equals 4. The number of regional medical school in Ruby Bay equals 3. The number of elementary school in Clearwater Bay equals 2 plus the number of public highschool in Clearwater Bay. The number of elementary school in Ruby Bay equals the difference between the total number of schools in Clearwater Bay and the number of regional medical school in Oakbridge City. The number of culinarian school in Oakbridge City equals the number of regional medical school in Ruby Bay. The number of public highschool in Clearwater Bay equals 3.

Question: What is the total number of schools in Riverton City?

Solution: Define public highschool in Clearwater Bay as W; so W = 3. Define elementary school in Clearwater Bay as w; j = W = 3; so w = 2 + j = 2 + 3 = 5. Define total number of schools in Clearwater Bay as a; so a = W + w = 3 + 5 = 8. Define culinarian school in Riverton City as k; t = a + W = 8 + 3 = 11; H = t + w = 11 + 5 = 16; so k = 2 + H = 2 + 16 = 18. Define total number of schools in Riverton City as M; so M = k = 18. Answer: 18.


The number of public highschool in Shoreline City equals 2. The number of public highschool in Riverton City equals the sum of the total number of schools in Shoreline City, the number of elementary school in Shoreline City, and the number of public highschool in Shoreline City. The number of elementary school in Shoreline City equals 3. The number of elementary school in Riverton City equals 1.

Question: What is the total number of schools in Riverton City?

Solution: Define elementary school in Shoreline City as C; so C = 3. Define public highschool in Shoreline City as Z; so Z = 2. Define total number of schools in Shoreline City as X; so X = Z + C = 2 + 3 = 5. Define public highschool in Riverton City as v; d = X + C = 5 + 3 = 8; so v = d + Z = 8 + 2 = 10. Define elementary school in Riverton City as V; so V = 1. Define total number of schools in Riverton City as l; so l = v + V = 10 + 1 = 11. Answer: 11.


The number of culinarian school in Shoreline City equals 4. The number of culinarian school in Riverton City equals 4 times the total number of schools in Shoreline City. The number of public highschool in Shoreline City equals 1 plus the number of culinarian school in Shoreline City. The number of public highschool in Riverton City equals the number of public highschool in Shoreline City.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Shoreline City as r; so r = 4. Define public highschool in Shoreline City as w; f = r = 4; so w = 1 + f = 1 + 4 = 5. Define total number of schools in Shoreline City as t; so t = r + w = 4 + 5 = 9. Define culinarian school in Riverton City as s; n = t = 9; so s = 4 * n = 4 * 9 = 36. Define public highschool in Riverton City as Z; so Z = w = 5. Define total number of schools in Riverton City as E; so E = s + Z = 36 + 5 = 41. Answer: 41.


The number of futuristic sci-fi movie in West Sahara Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of solemn period drama in Verdi Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 2 plus the difference between the total number of movies in Verdi Movie Festival and the number of solemn period drama in Verdi Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals the difference between the number of solemn period drama in Taylor Movie Festival and the number of solemn period drama in Verdi Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as D; so D = 4. Define total number of movies in Verdi Movie Festival as r; so r = D = 4. Define intense detective thriller in Golden Banana Movie Festival as W; q = r - D = 4 - 4 = 0; so W = 2 + q = 2 + 0 = 2. Define calm road movie in Golden Banana Movie Festival as B; P = r + D = 4 + 4 = 8; so B = P + W = 8 + 2 = 10. Define total number of movies in Golden Banana Movie Festival as J; so J = W + B = 2 + 10 = 12. Answer: 12.


The number of adult wolf in Maple Creek equals 1 plus the number of adult bear in Beverly Forest. The number of adult bear in Cedar Valley equals the total number of adult animals in Oakridge Riverside. The number of adult racoon in Cedar Valley equals 3 plus the number of adult bear in Cedar Valley. The number of adult racoon in Oakridge Riverside equals 3. The number of adult deer in Maple Creek equals the number of adult racoon in Oakridge Riverside. The number of adult racoon in Beverly Forest equals 4 plus the difference between the number of adult bear in Beverly Forest and the number of adult wolf in Maple Creek. The number of adult bear in Beverly Forest equals 4. The number of adult bear in Oakridge Riverside equals 4 times the number of adult racoon in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult racoon in Oakridge Riverside as y; so y = 3. Define adult bear in Oakridge Riverside as k; t = y = 3; so k = 4 * t = 4 * 3 = 12. Define total number of adult animals in Oakridge Riverside as i; so i = y + k = 3 + 12 = 15. Define adult bear in Cedar Valley as s; so s = i = 15. Define adult racoon in Cedar Valley as O; A = s = 15; so O = 3 + A = 3 + 15 = 18. Define total number of adult animals in Cedar Valley as z; so z = O + s = 18 + 15 = 33. Answer: 33.


The number of adult blue jay in Maple Creek equals 2. The number of adult eagle in Pine Ridge equals 4. The number of adult owl in Maple Creek equals 4 times the number of adult eagle in Beverly Forest. The number of adult blue jay in Cedar Valley equals 2 plus the sum of the number of adult eagle in Cedar Valley and the number of adult owl in Cedar Valley. The number of adult blue jay in Pine Ridge equals 2. The number of adult eagle in Cedar Valley equals 2. The number of adult eagle in Oakridge Riverside equals the total number of adult animals in Cedar Valley. The number of adult blue jay in Oakridge Riverside equals 3 plus the difference between the total number of adult animals in Oakridge Riverside and the number of adult blue jay in Maple Creek. The number of adult owl in Pine Ridge equals 3. The number of adult blue jay in Beverly Forest equals the sum of the number of adult blue jay in Pine Ridge, the number of adult eagle in Cedar Valley, and the total number of adult animals in Pine Ridge. The number of adult eagle in Beverly Forest equals 4. The number of adult owl in Cedar Valley equals 4 times the number of adult eagle in Cedar Valley.

Question: How many adult eagle does Oakridge Riverside have?

Solution: Define adult eagle in Cedar Valley as m; so m = 2. Define adult owl in Cedar Valley as u; N = m = 2; so u = 4 * N = 4 * 2 = 8. Define adult blue jay in Cedar Valley as J; y = m + u = 2 + 8 = 10; so J = 2 + y = 2 + 10 = 12. Define total number of adult animals in Cedar Valley as g; t = u + J = 8 + 12 = 20; so g = t + m = 20 + 2 = 22. Define adult eagle in Oakridge Riverside as I; so I = g = 22. Answer: 22.


The number of regional medical school in Clearwater Bay equals 2 times the sum of the number of regional medical school in Ruby Bay and the number of elementary school in Ruby Bay. The number of regional medical school in Ruby Bay equals 3. The number of elementary school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of elementary school in Ruby Bay equals 4.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Ruby Bay as T; so T = 4. Define regional medical school in Ruby Bay as X; so X = 3. Define total number of schools in Ruby Bay as e; so e = T + X = 4 + 3 = 7. Define elementary school in Clearwater Bay as H; so H = e = 7. Define regional medical school in Clearwater Bay as F; U = X + T = 3 + 4 = 7; so F = 2 * U = 2 * 7 = 14. Define total number of schools in Clearwater Bay as o; so o = F + H = 14 + 7 = 21. Answer: 21.


The number of calm road movie in Rêves de Belleville equals the sum of the total number of movies in Festival Lumière de Valmont, the number of calm road movie in Festival Lumière de Valmont, and the number of intense detective thriller in Festival Lumière de Valmont. The number of intense detective thriller in Rêves de Belleville equals the sum of the number of calm road movie in Rêves de Belleville, the total number of movies in Festival Lumière de Valmont, and the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Festival Lumière de Valmont equals 3.

Question: How many intense detective thriller does Rêves de Belleville have?

Solution: Define calm road movie in Festival Lumière de Valmont as L; so L = 4. Define intense detective thriller in Festival Lumière de Valmont as V; so V = 3. Define total number of movies in Festival Lumière de Valmont as u; so u = L + V = 4 + 3 = 7. Define calm road movie in Rêves de Belleville as n; o = u + L = 7 + 4 = 11; so n = o + V = 11 + 3 = 14. Define intense detective thriller in Rêves de Belleville as O; l = n + u = 14 + 7 = 21; so O = l + V = 21 + 3 = 24. Answer: 24.


The number of public highschool in Hawkesbury equals the number of regional medical school in Evervale City. The number of regional medical school in Hawkesbury equals 2 times the difference between the number of public highschool in Evervale City and the number of public highschool in Hawkesbury. The number of regional medical school in Evervale City equals 4. The number of public highschool in Evervale City equals 3 times the sum of the number of public highschool in Hawkesbury and the number of regional medical school in Evervale City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Evervale City as y; so y = 4. Define public highschool in Hawkesbury as T; so T = y = 4. Define public highschool in Evervale City as L; z = T + y = 4 + 4 = 8; so L = 3 * z = 3 * 8 = 24. Define regional medical school in Hawkesbury as H; N = L - T = 24 - 4 = 20; so H = 2 * N = 2 * 20 = 40. Define total number of schools in Hawkesbury as S; so S = T + H = 4 + 40 = 44. Answer: 44.


The number of public highschool in Riverton City equals 3 plus the difference between the number of regional medical school in Riverton City and the number of public highschool in Oakbridge City. The number of regional medical school in Riverton City equals the number of public highschool in Oakbridge City. The number of regional medical school in Oakbridge City equals the sum of the total number of schools in Riverton City, the number of public highschool in Riverton City, and the number of regional medical school in Riverton City. The number of public highschool in Oakbridge City equals 4.

Question: How many regional medical school does Oakbridge City have?

Solution: Define public highschool in Oakbridge City as k; so k = 4. Define regional medical school in Riverton City as b; so b = k = 4. Define public highschool in Riverton City as Q; d = b - k = 4 - 4 = 0; so Q = 3 + d = 3 + 0 = 3. Define total number of schools in Riverton City as N; so N = b + Q = 4 + 3 = 7. Define regional medical school in Oakbridge City as C; V = N + Q = 7 + 3 = 10; so C = V + b = 10 + 4 = 14. Answer: 14.