The number of upbeat metropolis comedy in Cinéma de Montreval equals 4 times the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage exists, and its number is greater than 0. The total number of movies in Festival de Saint-Rivage equals 9. The number of solemn period drama in Festival de Clairmont equals 2. The number of solemn period drama in Festival de Saint-Rivage equals 1 plus the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Festival de Clairmont equals 4.

Question: How many upbeat metropolis comedy does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Saint-Rivage as A; k = x = x; so A = 1 + k = 1 + x = x + 1. Define total number of movies in Festival de Saint-Rivage as U; so U = A + x = x + 1 + x = 2*x + 1. We know U = 9, so we have 2*x + 1 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 9. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of solemn period drama in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2 plus the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival exists, and its number is greater than 0. The total number of movies in Northwood Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals 3.

Question: How many upbeat metropolis comedy does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Taylor Movie Festival as B; so B = x = x. Define intense detective thriller in Northwood Movie Festival as k; S = B = x; so k = 2 + S = 2 + x = x + 2. Define total number of movies in Northwood Movie Festival as Z; so Z = k = x + 2. We know Z = 4, so we have x + 2 = 4 and we solve it through the following steps: Simplifying the equation: x + 2 = 4. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of adult wolf in Maple Creek equals 2. The number of adult fox in Beverly Forest equals the sum of the total number of adult animals in Maple Creek, the number of adult wolf in Maple Creek, and the number of adult racoon in Oakridge Riverside. The number of adult fox in Maple Creek equals 2. The number of adult racoon in Maple Creek equals 4 plus the number of adult racoon in Oakridge Riverside. The number of adult racoon in Beverly Forest equals 4. The number of adult wolf in Beverly Forest equals 3. The number of adult wolf in Oakridge Riverside exists, and its number is greater than 0. The number of adult racoon in Oakridge Riverside equals 3 times the number of adult wolf in Oakridge Riverside. The total number of adult animals in Oakridge Riverside equals 8.

Question: How many adult wolf does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult racoon in Oakridge Riverside as v; n = x = x; so v = 3 * n = (3) * (x) = 3*x. Define total number of adult animals in Oakridge Riverside as M; so M = v + x = 3*x + x = 4*x. We know M = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.


The total number of movies in Verdi Movie Festival equals 12. The number of calm road movie in Verdi Movie Festival equals 2 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival exists, and its number is greater than 0. The number of calm road movie in West Sahara Movie Festival equals 3 plus the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4.

Question: How many futuristic sci-fi movie does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Verdi Movie Festival as E; s = x = x; so E = 2 * s = (2) * (x) = 2*x. Define total number of movies in Verdi Movie Festival as n; so n = E + x = 2*x + x = 3*x. We know n = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.


The number of upbeat metropolis comedy in Festival de Saint-Rivage exists, and its number is greater than 0. The number of calm road movie in Cinéma de Montreval equals the total number of movies in Rêves de Belleville. The number of futuristic sci-fi movie in Cinéma de Montreval equals 4. The total number of movies in Rêves de Belleville equals 3. The number of upbeat metropolis comedy in Rêves de Belleville equals 1 plus the total number of movies in Festival de Saint-Rivage.

Question: How many upbeat metropolis comedy does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as y; so y = x = x. Define upbeat metropolis comedy in Rêves de Belleville as d; Z = y = x; so d = 1 + Z = 1 + x = x + 1. Define total number of movies in Rêves de Belleville as W; so W = d = x + 1. We know W = 3, so we have x + 1 = 3 and we solve it through the following steps: Simplifying the equation: x + 1 = 3. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of adult wolf in Jefferson Circus equals the sum of the number of adult bear in Mayer Aquarium, the total number of adult animals in Bundle Ranch, and the number of adult wolf in Mayer Aquarium. The number of adult bear in Mayer Aquarium exists, and its number is greater than 0. The number of adult bear in Bundle Ranch equals 4. The number of adult bear in Jefferson Circus equals 4. The number of adult wolf in Bundle Ranch equals 24. The number of adult wolf in Mayer Aquarium equals 1 plus the number of adult racoon in Mayer Aquarium. The number of adult racoon in Mayer Aquarium equals the sum of the number of adult wolf in Bundle Ranch and the total number of adult animals in Bundle Ranch. The number of adult racoon in Bundle Ranch equals 3 plus the number of adult bear in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals 4 times the number of adult racoon in Bundle Ranch. The number of adult racoon in Jefferson Circus equals 3 plus the sum of the number of adult racoon in Bundle Ranch and the number of adult wolf in Mayer Aquarium.

Question: How many adult bear does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult racoon in Bundle Ranch as I; V = x = x; so I = 3 + V = 3 + x = x + 3. Define adult wolf in Bundle Ranch as r; W = I = x + 3; so r = 4 * W = (4) * (x + 3) = 4*x + 12. We know r = 24, so we have 4*x + 12 = 24 and we solve it through the following steps: Simplifying the equation: 4*x + 12 = 24. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of adult racoon in Beverly Forest equals 4. The number of adult wolf in Maple Creek equals the sum of the total number of adult animals in Oakridge Riverside and the number of adult racoon in Oakridge Riverside. The total number of adult animals in Maple Creek equals 4. The number of adult deer in Beverly Forest equals 2. The number of adult racoon in Oakridge Riverside exists, and its number is greater than 0.

Question: How many adult racoon does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define total number of adult animals in Oakridge Riverside as K; so K = x = x. Define adult wolf in Maple Creek as t; so t = K + x = x + x = 2*x. Define total number of adult animals in Maple Creek as N; so N = t = 2*x. We know N = 4, so we have 2*x = 4 and we solve it through the following steps: Simplifying the equation: 2*x = 4. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult eagle in Pine Ridge exists, and its number is greater than 0. The total number of adult animals in Pine Ridge equals 5. The number of adult owl in Cedar Valley equals the number of adult eagle in Cedar Valley. The number of adult eagle in Cedar Valley equals 3. The number of adult owl in Pine Ridge equals 1 plus the number of adult eagle in Pine Ridge.

Question: How many adult eagle does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult owl in Pine Ridge as w; y = x = x; so w = 1 + y = 1 + x = x + 1. Define total number of adult animals in Pine Ridge as a; so a = w + x = x + 1 + x = 2*x + 1. We know a = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult owl in Pine Ridge exists, and its number is greater than 0. The number of adult parrot in Beverly Forest equals 2. The number of adult owl in Oakridge Riverside equals 4 times the sum of the number of adult parrot in Pine Ridge, the number of adult parrot in Beverly Forest, and the number of adult owl in Beverly Forest. The number of adult eagle in Oakridge Riverside equals the number of adult parrot in Pine Ridge. The number of adult owl in Beverly Forest equals 4. The number of adult eagle in Beverly Forest equals 4 times the number of adult parrot in Beverly Forest. The number of adult parrot in Oakridge Riverside equals the number of adult owl in Beverly Forest. The total number of adult animals in Pine Ridge equals 11. The number of adult parrot in Pine Ridge equals 3 plus the number of adult owl in Pine Ridge.

Question: How many adult owl does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult parrot in Pine Ridge as e; R = x = x; so e = 3 + R = 3 + x = x + 3. Define total number of adult animals in Pine Ridge as b; so b = x + e = x + x + 3 = 2*x + 3. We know b = 11, so we have 2*x + 3 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 11. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The total number of movies in Northwood Movie Festival equals 12. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4. The number of calm road movie in Northwood Movie Festival exists, and its number is greater than 0. The number of calm road movie in West Sahara Movie Festival equals 3. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 times the number of calm road movie in Northwood Movie Festival.

Question: How many calm road movie does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Northwood Movie Festival as g; R = x = x; so g = 2 * R = (2) * (x) = 2*x. Define total number of movies in Northwood Movie Festival as V; so V = g + x = 2*x + x = 3*x. We know V = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.


The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 5. The number of calm road movie in Festival Lumière de Valmont exists, and its number is greater than 0. The number of intense detective thriller in Festival de Clairmont equals 2. The number of calm road movie in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 3. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 1 plus the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 4 times the number of calm road movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Saint-Rivage equals 2.

Question: How many calm road movie does Festival Lumière de Valmont have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define calm road movie in Festival de Saint-Rivage as p; N = x = x; so p = 4 * N = (4) * (x) = 4*x. Define upbeat metropolis comedy in Festival Lumière de Valmont as O; n = p = 4*x; so O = 1 + n = 1 + 4*x = 4*x + 1. We know O = 5, so we have 4*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 4*x + 1 = 5. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of public highschool in Ruby Bay equals the sum of the number of elementary school in Oakbridge City, the total number of schools in Ruby Bay, the total number of schools in Shoreline City, and the number of public highschool in Oakbridge City. The number of public highschool in Oakbridge City equals 2 times the sum of the number of elementary school in Shoreline City, the number of private middle school in Ruby Bay, and the number of private middle school in Shoreline City. The number of private middle school in Ruby Bay equals 4 times the number of public highschool in Shoreline City. The number of private middle school in Oakbridge City equals 18. The number of public highschool in Shoreline City exists, and its number is greater than 0. The number of elementary school in Shoreline City equals 3. The number of private middle school in Oakbridge City equals 2 plus the number of private middle school in Ruby Bay. The number of elementary school in Oakbridge City equals 4. The number of private middle school in Shoreline City equals 3. The number of elementary school in Ruby Bay equals the sum of the number of private middle school in Ruby Bay, the number of public highschool in Shoreline City, the total number of schools in Shoreline City, and the number of private middle school in Oakbridge City.

Question: How many public highschool does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Shoreline City as x; we don't know its value yet but will find it out later. Define private middle school in Ruby Bay as q; F = x = x; so q = 4 * F = (4) * (x) = 4*x. Define private middle school in Oakbridge City as m; f = q = 4*x; so m = 2 + f = 2 + 4*x = 4*x + 2. We know m = 18, so we have 4*x + 2 = 18 and we solve it through the following steps: Simplifying the equation: 4*x + 2 = 18. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of adult deer in Oakridge Riverside equals 2. The number of adult racoon in Oakridge Riverside equals the total number of adult animals in Beverly Forest. The number of adult deer in Beverly Forest equals 4 plus the number of adult racoon in Beverly Forest. The total number of adult animals in Beverly Forest equals 8. The number of adult racoon in Beverly Forest exists, and its number is greater than 0.

Question: How many adult racoon does Beverly Forest have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Beverly Forest as x; we don't know its value yet but will find it out later. Define adult deer in Beverly Forest as H; g = x = x; so H = 4 + g = 4 + x = x + 4. Define total number of adult animals in Beverly Forest as d; so d = x + H = x + x + 4 = 2*x + 4. We know d = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of intense detective thriller in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Rêves de Belleville equals 5. The number of intense detective thriller in Rêves de Belleville equals 1 plus the number of calm road movie in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 2 plus the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of calm road movie in Festival Lumière de Valmont equals 2 times the total number of movies in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals 2 plus the number of calm road movie in Festival Lumière de Valmont.

Question: How many futuristic sci-fi movie does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define calm road movie in Rêves de Belleville as j; M = x = x; so j = 2 + M = 2 + x = x + 2. Define intense detective thriller in Rêves de Belleville as E; K = j = x + 2; so E = 1 + K = 1 + x + 2 = x + 3. We know E = 5, so we have x + 3 = 5 and we solve it through the following steps: Simplifying the equation: x + 3 = 5. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of private middle school in Evervale City equals 3. The number of private middle school in Brightford exists, and its number is greater than 0. The number of elementary school in Brightford equals 4 plus the number of private middle school in Brightford. The number of elementary school in Hawkesbury equals 3. The number of private middle school in Brightford exists, and its number is greater than 0. The number of elementary school in Evervale City equals the sum of the total number of schools in Brightford and the number of public highschool in Hawkesbury. The number of private middle school in Brightford exists, and its number is greater than 0. The total number of schools in Brightford equals 8. The number of public highschool in Evervale City equals the difference between the number of elementary school in Evervale City and the total number of schools in Brightford.

Question: How many private middle school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Brightford as x; we don't know its value yet but will find it out later. Define elementary school in Brightford as F; h = x = x; so F = 4 + h = 4 + x = x + 4. Define total number of schools in Brightford as q; so q = x + F = x + x + 4 = 2*x + 4. We know q = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of private middle school in Ruby Bay equals 2. The number of public highschool in Riverton City exists, and its number is greater than 0. The total number of schools in Riverton City equals 5. The number of private middle school in Riverton City equals 1 plus the number of public highschool in Riverton City. The number of public highschool in Ruby Bay equals 1.

Question: How many public highschool does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define private middle school in Riverton City as W; l = x = x; so W = 1 + l = 1 + x = x + 1. Define total number of schools in Riverton City as A; so A = x + W = x + x + 1 = 2*x + 1. We know A = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult racoon in South Zoo equals 4 plus the number of adult deer in South Zoo. The number of adult deer in Hamilton Farm equals the number of adult racoon in South Zoo. The total number of adult animals in South Zoo equals 12. The number of adult bear in Hamilton Farm equals the number of adult deer in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2. The number of adult deer in South Zoo exists, and its number is greater than 0.

Question: How many adult deer does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult deer in South Zoo as x; we don't know its value yet but will find it out later. Define adult racoon in South Zoo as O; u = x = x; so O = 4 + u = 4 + x = x + 4. Define total number of adult animals in South Zoo as T; so T = x + O = x + x + 4 = 2*x + 4. We know T = 12, so we have 2*x + 4 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 12. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The total number of schools in Ruby Bay equals 10. The number of elementary school in Ruby Bay equals 4 times the number of private middle school in Ruby Bay. The number of private middle school in Clearwater Bay equals 1 plus the total number of schools in Ruby Bay. The number of private middle school in Ruby Bay exists, and its number is greater than 0. The number of elementary school in Clearwater Bay equals 1.

Question: How many private middle school does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Ruby Bay as x; we don't know its value yet but will find it out later. Define elementary school in Ruby Bay as E; A = x = x; so E = 4 * A = (4) * (x) = 4*x. Define total number of schools in Ruby Bay as N; so N = E + x = 4*x + x = 5*x. We know N = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.


The total number of schools in Oakbridge City equals 9. The number of culinarian school in Riverton City equals 3. The number of private middle school in Riverton City equals 2. The number of private middle school in Oakbridge City exists, and its number is greater than 0. The number of culinarian school in Oakbridge City equals 1 plus the number of private middle school in Oakbridge City.

Question: How many private middle school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Oakbridge City as x; we don't know its value yet but will find it out later. Define culinarian school in Oakbridge City as G; N = x = x; so G = 1 + N = 1 + x = x + 1. Define total number of schools in Oakbridge City as b; so b = G + x = x + 1 + x = 2*x + 1. We know b = 9, so we have 2*x + 1 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 9. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of regional medical school in Riverton City exists, and its number is greater than 0. The number of regional medical school in Clearwater Bay equals 3. The number of private middle school in Clearwater Bay equals the sum of the number of regional medical school in Ruby Bay, the number of private middle school in Riverton City, and the total number of schools in Riverton City. The number of regional medical school in Ruby Bay equals 3. The total number of schools in Riverton City equals 15. The number of private middle school in Riverton City equals 4 times the number of regional medical school in Riverton City. The number of private middle school in Ruby Bay equals 4 times the number of regional medical school in Ruby Bay.

Question: How many regional medical school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Riverton City as x; we don't know its value yet but will find it out later. Define private middle school in Riverton City as i; e = x = x; so i = 4 * e = (4) * (x) = 4*x. Define total number of schools in Riverton City as W; so W = i + x = 4*x + x = 5*x. We know W = 15, so we have 5*x = 15 and we solve it through the following steps: Simplifying the equation: 5*x = 15. Move all terms to one side: 5*x - 15 = 0. Isolate the term with x: 5*x = 15. Divide both sides by 5: x = 15 / 5. Solution: x = 3. Answer: 3.


The number of public highschool in Brightford exists, and its number is greater than 0. The total number of schools in Brightford equals 8. The number of public highschool in Hawkesbury equals 2. The number of culinarian school in Hawkesbury equals 3 times the sum of the total number of schools in Brightford and the number of public highschool in Brightford. The number of culinarian school in Brightford equals 2 plus the number of public highschool in Brightford.

Question: How many public highschool does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Brightford as x; we don't know its value yet but will find it out later. Define culinarian school in Brightford as a; C = x = x; so a = 2 + C = 2 + x = x + 2. Define total number of schools in Brightford as M; so M = a + x = x + 2 + x = 2*x + 2. We know M = 8, so we have 2*x + 2 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 8. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult bear in Oakridge Riverside equals 2 times the number of adult bear in Cedar Valley. The number of adult deer in Oakridge Riverside equals 3. The number of adult bear in Cedar Valley exists, and its number is greater than 0. The number of adult deer in Maple Creek equals 2 plus the total number of adult animals in Cedar Valley. The total number of adult animals in Maple Creek equals 6.

Question: How many adult bear does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Cedar Valley as x; we don't know its value yet but will find it out later. Define total number of adult animals in Cedar Valley as Y; so Y = x = x. Define adult deer in Maple Creek as I; k = Y = x; so I = 2 + k = 2 + x = x + 2. Define total number of adult animals in Maple Creek as K; so K = I = x + 2. We know K = 6, so we have x + 2 = 6 and we solve it through the following steps: Simplifying the equation: x + 2 = 6. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.


The number of elementary school in Glenfield City equals 4 plus the number of private middle school in Glenfield City. The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of private middle school in Hawkesbury equals 3. The total number of schools in Glenfield City equals 8. The number of elementary school in Hawkesbury equals 4 times the number of private middle school in Hawkesbury.

Question: How many private middle school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define elementary school in Glenfield City as M; N = x = x; so M = 4 + N = 4 + x = x + 4. Define total number of schools in Glenfield City as t; so t = M + x = x + 4 + x = 2*x + 4. We know t = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The total number of adult animals in Pine Ridge equals 4. The number of adult eagle in Pine Ridge equals 3 times the number of adult parrot in Pine Ridge. The number of adult parrot in Pine Ridge exists, and its number is greater than 0. The number of adult parrot in Pine Ridge exists, and its number is greater than 0. The number of adult eagle in Cedar Valley equals 4.

Question: How many adult parrot does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult parrot in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult eagle in Pine Ridge as O; W = x = x; so O = 3 * W = (3) * (x) = 3*x. Define total number of adult animals in Pine Ridge as h; so h = x + O = x + 3*x = 4*x. We know h = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of adult fox in South Zoo exists, and its number is greater than 0. The number of adult fox in Jefferson Circus equals 2. The number of adult bear in South Zoo equals 2 times the number of adult fox in South Zoo. The number of adult bear in Jefferson Circus equals 2 times the sum of the total number of adult animals in South Zoo and the number of adult fox in South Zoo. The total number of adult animals in South Zoo equals 9.

Question: How many adult fox does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in South Zoo as x; we don't know its value yet but will find it out later. Define adult bear in South Zoo as D; B = x = x; so D = 2 * B = (2) * (x) = 2*x. Define total number of adult animals in South Zoo as a; so a = x + D = x + 2*x = 3*x. We know a = 9, so we have 3*x = 9 and we solve it through the following steps: Simplifying the equation: 3*x = 9. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.


The number of regional medical school in Clearwater Bay equals 3 times the difference between the number of culinarian school in Shoreline City and the number of regional medical school in Shoreline City. The number of public highschool in Clearwater Bay equals 3 plus the sum of the number of culinarian school in Shoreline City and the number of regional medical school in Oakbridge City. The number of culinarian school in Clearwater Bay equals the number of public highschool in Clearwater Bay. The number of public highschool in Oakbridge City equals the number of culinarian school in Clearwater Bay. The number of regional medical school in Shoreline City equals 4 times the number of public highschool in Shoreline City. The number of culinarian school in Shoreline City equals the number of regional medical school in Oakbridge City. The number of public highschool in Shoreline City equals 1. The number of regional medical school in Oakbridge City exists, and its number is greater than 0. The number of culinarian school in Oakbridge City equals 3. The number of public highschool in Clearwater Bay equals 7.

Question: How many regional medical school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Oakbridge City as x; we don't know its value yet but will find it out later. Define culinarian school in Shoreline City as g; so g = x = x. Define public highschool in Clearwater Bay as V; S = g + x = x + x = 2*x; so V = 3 + S = 3 + 2*x = 2*x + 3. We know V = 7, so we have 2*x + 3 = 7 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 7. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of solemn period drama in Cinéma de Montreval equals 2 times the number of intense detective thriller in Cinéma de Montreval. The total number of movies in Cinéma de Montreval equals 3. The number of intense detective thriller in Festival Lumière de Valmont equals 3 plus the number of upbeat metropolis comedy in Rêves de Belleville. The number of intense detective thriller in Cinéma de Montreval exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals the total number of movies in Cinéma de Montreval. The number of solemn period drama in Festival Lumière de Valmont equals 2. The number of intense detective thriller in Rêves de Belleville equals 2 times the number of solemn period drama in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals 3.

Question: How many intense detective thriller does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define solemn period drama in Cinéma de Montreval as p; A = x = x; so p = 2 * A = (2) * (x) = 2*x. Define total number of movies in Cinéma de Montreval as w; so w = p + x = 2*x + x = 3*x. We know w = 3, so we have 3*x = 3 and we solve it through the following steps: Simplifying the equation: 3*x = 3. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.


The number of upbeat metropolis comedy in Rêves de Belleville equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 4 times the number of futuristic sci-fi movie in Festival de Clairmont. The total number of movies in Festival de Clairmont equals 20. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0.

Question: How many futuristic sci-fi movie does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival de Clairmont as u; B = x = x; so u = 4 * B = (4) * (x) = 4*x. Define total number of movies in Festival de Clairmont as M; so M = u + x = 4*x + x = 5*x. We know M = 20, so we have 5*x = 20 and we solve it through the following steps: Simplifying the equation: 5*x = 20. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.


The number of culinarian school in Riverton City equals 4 plus the number of public highschool in Riverton City. The number of public highschool in Oakbridge City equals the number of culinarian school in Oakbridge City. The number of culinarian school in Oakbridge City equals 2. The number of public highschool in Riverton City exists, and its number is greater than 0. The total number of schools in Riverton City equals 12.

Question: How many public highschool does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define culinarian school in Riverton City as R; q = x = x; so R = 4 + q = 4 + x = x + 4. Define total number of schools in Riverton City as D; so D = x + R = x + x + 4 = 2*x + 4. We know D = 12, so we have 2*x + 4 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 12. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 times the number of solemn period drama in Festival Lumière de Valmont. The total number of movies in Festival Lumière de Valmont equals 12. The number of intense detective thriller in Rêves de Belleville equals 4. The number of solemn period drama in Festival de Saint-Rivage equals 3 plus the sum of the number of solemn period drama in Festival Lumière de Valmont, the total number of movies in Festival Lumière de Valmont, and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3. The number of solemn period drama in Festival Lumière de Valmont exists, and its number is greater than 0.

Question: How many solemn period drama does Festival Lumière de Valmont have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival Lumière de Valmont as j; J = x = x; so j = 3 * J = (3) * (x) = 3*x. Define total number of movies in Festival Lumière de Valmont as o; so o = j + x = 3*x + x = 4*x. We know o = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The total number of movies in Festival de Saint-Rivage equals 6. The number of calm road movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals 2 times the number of calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Rêves de Belleville equals the sum of the number of intense detective thriller in Festival de Saint-Rivage and the total number of movies in Festival de Saint-Rivage. The number of calm road movie in Rêves de Belleville equals 2.

Question: How many calm road movie does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define intense detective thriller in Festival de Saint-Rivage as b; j = x = x; so b = 2 * j = (2) * (x) = 2*x. Define total number of movies in Festival de Saint-Rivage as D; so D = x + b = x + 2*x = 3*x. We know D = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.


The total number of movies in Verdi Movie Festival equals 12. The number of solemn period drama in Northwood Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the total number of movies in Northwood Movie Festival.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Northwood Movie Festival as w; so w = x = x. Define futuristic sci-fi movie in Verdi Movie Festival as s; R = w = x; so s = 4 * R = (4) * (x) = 4*x. Define total number of movies in Verdi Movie Festival as M; so M = s = 4*x. We know M = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of futuristic sci-fi movie in Golden Banana Movie Festival exists, and its number is greater than 0. The total number of movies in Golden Banana Movie Festival equals 12. The number of solemn period drama in Golden Banana Movie Festival equals 3 times the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of solemn period drama in West Sahara Movie Festival equals 1 plus the number of futuristic sci-fi movie in West Sahara Movie Festival.

Question: How many futuristic sci-fi movie does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in Golden Banana Movie Festival as l; c = x = x; so l = 3 * c = (3) * (x) = 3*x. Define total number of movies in Golden Banana Movie Festival as f; so f = l + x = 3*x + x = 4*x. We know f = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of adult wolf in Cedar Valley exists, and its number is greater than 0. The number of adult bear in Cedar Valley equals 3 times the number of adult fox in Oakridge Riverside. The number of adult bear in Cedar Valley equals 36. The number of adult fox in Oakridge Riverside equals 3 times the number of adult wolf in Cedar Valley. The number of adult fox in Cedar Valley equals the number of adult bear in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals 4. The number of adult wolf in Oakridge Riverside equals 4.

Question: How many adult wolf does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult fox in Oakridge Riverside as o; K = x = x; so o = 3 * K = (3) * (x) = 3*x. Define adult bear in Cedar Valley as m; l = o = 3*x; so m = 3 * l = (3) * (3*x) = 9*x. We know m = 36, so we have 9*x = 36 and we solve it through the following steps: Simplifying the equation: 9*x = 36. Move all terms to one side: 9*x - 36 = 0. Isolate the term with x: 9*x = 36. Divide both sides by 9: x = 36 / 9. Solution: x = 4. Answer: 4.


The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The total number of adult animals in Mayer Aquarium equals 10. The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The number of adult wolf in Jefferson Circus equals 2. The number of adult racoon in Mayer Aquarium equals 4 plus the number of adult wolf in Mayer Aquarium.

Question: How many adult wolf does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult racoon in Mayer Aquarium as a; Q = x = x; so a = 4 + Q = 4 + x = x + 4. Define total number of adult animals in Mayer Aquarium as Y; so Y = a + x = x + 4 + x = 2*x + 4. We know Y = 10, so we have 2*x + 4 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 10. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult racoon in Maple Creek equals the number of adult bear in Maple Creek. The number of adult bear in Cedar Valley equals 1 plus the number of adult racoon in Cedar Valley. The number of adult bear in Maple Creek equals 4. The total number of adult animals in Cedar Valley equals 9. The number of adult racoon in Cedar Valley exists, and its number is greater than 0.

Question: How many adult racoon does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult bear in Cedar Valley as q; Z = x = x; so q = 1 + Z = 1 + x = x + 1. Define total number of adult animals in Cedar Valley as g; so g = q + x = x + 1 + x = 2*x + 1. We know g = 9, so we have 2*x + 1 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 9. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of adult crow in South Zoo equals 1 plus the number of adult eagle in South Zoo. The number of adult eagle in Hamilton Farm equals the difference between the number of adult crow in Hamilton Farm and the number of adult crow in South Zoo. The number of adult crow in Hamilton Farm equals 3. The total number of adult animals in South Zoo equals 9. The number of adult eagle in South Zoo exists, and its number is greater than 0.

Question: How many adult eagle does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in South Zoo as x; we don't know its value yet but will find it out later. Define adult crow in South Zoo as p; A = x = x; so p = 1 + A = 1 + x = x + 1. Define total number of adult animals in South Zoo as H; so H = p + x = x + 1 + x = 2*x + 1. We know H = 9, so we have 2*x + 1 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 9. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of elementary school in Glenfield City exists, and its number is greater than 0. The total number of schools in Glenfield City equals 11. The number of elementary school in Glenfield City exists, and its number is greater than 0. The number of elementary school in Westhaven City equals 3. The number of culinarian school in Glenfield City equals 3 plus the number of elementary school in Glenfield City. The number of private middle school in Westhaven City equals 2.

Question: How many elementary school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Glenfield City as x; we don't know its value yet but will find it out later. Define culinarian school in Glenfield City as z; J = x = x; so z = 3 + J = 3 + x = x + 3. Define total number of schools in Glenfield City as L; so L = x + z = x + x + 3 = 2*x + 3. We know L = 11, so we have 2*x + 3 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 11. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of public highschool in Evervale City equals 3. The number of elementary school in Evervale City equals the number of elementary school in Hawkesbury. The number of public highschool in Hawkesbury equals 3. The total number of schools in Brightford equals 10. The number of private middle school in Brightford exists, and its number is greater than 0. The number of elementary school in Hawkesbury equals 1 plus the number of public highschool in Hawkesbury. The number of public highschool in Brightford equals 4 plus the number of private middle school in Brightford.

Question: How many private middle school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Brightford as x; we don't know its value yet but will find it out later. Define public highschool in Brightford as s; n = x = x; so s = 4 + n = 4 + x = x + 4. Define total number of schools in Brightford as H; so H = s + x = x + 4 + x = 2*x + 4. We know H = 10, so we have 2*x + 4 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 10. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of regional medical school in Glenfield City equals the number of elementary school in Glenfield City. The number of elementary school in Glenfield City equals 4. The total number of schools in Westhaven City equals 4. The number of private middle school in Westhaven City equals 4 times the total number of schools in Brightford. The number of elementary school in Brightford exists, and its number is greater than 0.

Question: How many elementary school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as u; so u = x = x. Define private middle school in Westhaven City as Y; A = u = x; so Y = 4 * A = (4) * (x) = 4*x. Define total number of schools in Westhaven City as G; so G = Y = 4*x. We know G = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of adult wolf in South Zoo exists, and its number is greater than 0. The number of adult racoon in South Zoo equals 2 plus the number of adult wolf in South Zoo. The number of adult wolf in Hamilton Farm equals 3. The total number of adult animals in South Zoo equals 6. The number of adult racoon in Hamilton Farm equals 3.

Question: How many adult wolf does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in South Zoo as x; we don't know its value yet but will find it out later. Define adult racoon in South Zoo as u; b = x = x; so u = 2 + b = 2 + x = x + 2. Define total number of adult animals in South Zoo as i; so i = u + x = x + 2 + x = 2*x + 2. We know i = 6, so we have 2*x + 2 = 6 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 6. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of upbeat metropolis comedy in Festival de Clairmont equals 3 times the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The total number of movies in Festival de Clairmont equals 12. The number of upbeat metropolis comedy in Rêves de Belleville equals 3.

Question: How many futuristic sci-fi movie does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival de Clairmont as W; y = x = x; so W = 3 * y = (3) * (x) = 3*x. Define total number of movies in Festival de Clairmont as I; so I = x + W = x + 3*x = 4*x. We know I = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of public highschool in Shoreline City equals 3. The number of private middle school in Riverton City equals 4 times the number of culinarian school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 1 plus the number of culinarian school in Clearwater Bay. The number of culinarian school in Riverton City equals 3. The number of private middle school in Shoreline City equals 2. The total number of schools in Clearwater Bay equals 5. The number of public highschool in Riverton City equals 4. The number of culinarian school in Clearwater Bay exists, and its number is greater than 0.

Question: How many culinarian school does Clearwater Bay have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define private middle school in Clearwater Bay as Z; b = x = x; so Z = 1 + b = 1 + x = x + 1. Define total number of schools in Clearwater Bay as T; so T = x + Z = x + x + 1 = 2*x + 1. We know T = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult bear in Hamilton Farm equals 4. The number of adult fox in South Zoo equals 3 times the number of adult bear in South Zoo. The number of adult bear in South Zoo exists, and its number is greater than 0. The number of adult fox in Hamilton Farm equals 4. The total number of adult animals in South Zoo equals 12.

Question: How many adult bear does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in South Zoo as x; we don't know its value yet but will find it out later. Define adult fox in South Zoo as b; r = x = x; so b = 3 * r = (3) * (x) = 3*x. Define total number of adult animals in South Zoo as a; so a = b + x = 3*x + x = 4*x. We know a = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The total number of movies in Verdi Movie Festival equals 5. The number of solemn period drama in Verdi Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Verdi Movie Festival equals 4 times the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 3 times the sum of the total number of movies in Verdi Movie Festival, the number of intense detective thriller in Verdi Movie Festival, and the number of solemn period drama in Verdi Movie Festival.

Question: How many solemn period drama does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in Verdi Movie Festival as w; i = x = x; so w = 4 * i = (4) * (x) = 4*x. Define total number of movies in Verdi Movie Festival as J; so J = w + x = 4*x + x = 5*x. We know J = 5, so we have 5*x = 5 and we solve it through the following steps: Simplifying the equation: 5*x = 5. Move all terms to one side: 5*x - 5 = 0. Isolate the term with x: 5*x = 5. Divide both sides by 5: x = 5 / 5. Solution: x = 1. Answer: 1.


The number of adult crow in Bundle Ranch equals the number of adult crow in Mayer Aquarium. The number of adult crow in Hamilton Farm equals 3 times the number of adult owl in Hamilton Farm. The number of adult owl in Mayer Aquarium equals 4 plus the sum of the total number of adult animals in Hamilton Farm, the number of adult crow in Hamilton Farm, and the number of adult owl in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals 4. The number of adult owl in Hamilton Farm exists, and its number is greater than 0. The total number of adult animals in Hamilton Farm equals 4. The number of adult crow in Mayer Aquarium equals 2 times the number of adult crow in Hamilton Farm. The number of adult owl in Bundle Ranch equals the number of adult owl in Hamilton Farm.

Question: How many adult owl does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult crow in Hamilton Farm as h; M = x = x; so h = 3 * M = (3) * (x) = 3*x. Define total number of adult animals in Hamilton Farm as S; so S = x + h = x + 3*x = 4*x. We know S = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of futuristic sci-fi movie in Cinéma de Montreval equals 2 times the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval exists, and its number is greater than 0. The number of solemn period drama in Festival Lumière de Valmont equals 1. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3 plus the difference between the total number of movies in Cinéma de Montreval and the number of futuristic sci-fi movie in Cinéma de Montreval. The total number of movies in Cinéma de Montreval equals 6.

Question: How many solemn period drama does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Cinéma de Montreval as g; h = x = x; so g = 2 * h = (2) * (x) = 2*x. Define total number of movies in Cinéma de Montreval as S; so S = x + g = x + 2*x = 3*x. We know S = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.


The number of adult blue jay in Bundle Ranch exists, and its number is greater than 0. The number of adult owl in Bundle Ranch equals 4 plus the number of adult blue jay in Bundle Ranch. The total number of adult animals in Bundle Ranch equals 8.

Question: How many adult blue jay does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult owl in Bundle Ranch as j; S = x = x; so j = 4 + S = 4 + x = x + 4. Define total number of adult animals in Bundle Ranch as l; so l = j + x = x + 4 + x = 2*x + 4. We know l = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of public highschool in Shoreline City exists, and its number is greater than 0. The total number of schools in Shoreline City equals 8. The number of regional medical school in Shoreline City equals 4 plus the number of public highschool in Shoreline City. The number of regional medical school in Riverton City equals 4 times the difference between the number of public highschool in Shoreline City and the number of public highschool in Riverton City. The number of public highschool in Riverton City equals 1.

Question: How many public highschool does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Shoreline City as x; we don't know its value yet but will find it out later. Define regional medical school in Shoreline City as Y; s = x = x; so Y = 4 + s = 4 + x = x + 4. Define total number of schools in Shoreline City as L; so L = Y + x = x + 4 + x = 2*x + 4. We know L = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2 plus the number of intense detective thriller in Taylor Movie Festival. The total number of movies in Taylor Movie Festival equals 10.

Question: How many intense detective thriller does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Taylor Movie Festival as D; b = x = x; so D = 2 + b = 2 + x = x + 2. Define total number of movies in Taylor Movie Festival as O; so O = x + D = x + x + 2 = 2*x + 2. We know O = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of adult wolf in Pine Ridge equals 3 times the number of adult bear in Pine Ridge. The number of adult bear in Pine Ridge exists, and its number is greater than 0. The number of adult wolf in Beverly Forest equals the difference between the number of adult bear in Beverly Forest and the total number of adult animals in Pine Ridge. The number of adult bear in Beverly Forest equals 4. The total number of adult animals in Pine Ridge equals 16.

Question: How many adult bear does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult wolf in Pine Ridge as U; L = x = x; so U = 3 * L = (3) * (x) = 3*x. Define total number of adult animals in Pine Ridge as c; so c = U + x = 3*x + x = 4*x. We know c = 16, so we have 4*x = 16 and we solve it through the following steps: Simplifying the equation: 4*x = 16. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of adult parrot in Beverly Forest equals the sum of the total number of adult animals in Pine Ridge, the number of adult parrot in Pine Ridge, and the number of adult blue jay in Pine Ridge. The total number of adult animals in Pine Ridge equals 8. The number of adult blue jay in Beverly Forest equals the difference between the number of adult parrot in Beverly Forest and the total number of adult animals in Pine Ridge. The number of adult blue jay in Pine Ridge exists, and its number is greater than 0. The number of adult parrot in Pine Ridge equals 4 plus the number of adult blue jay in Pine Ridge.

Question: How many adult blue jay does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult parrot in Pine Ridge as K; n = x = x; so K = 4 + n = 4 + x = x + 4. Define total number of adult animals in Pine Ridge as Q; so Q = x + K = x + x + 4 = 2*x + 4. We know Q = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of culinarian school in Clearwater Bay equals the total number of schools in Shoreline City. The total number of schools in Shoreline City equals 12. The number of culinarian school in Shoreline City exists, and its number is greater than 0. The number of private middle school in Shoreline City equals 3 times the number of culinarian school in Shoreline City. The number of private middle school in Clearwater Bay equals 3.

Question: How many culinarian school does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Shoreline City as x; we don't know its value yet but will find it out later. Define private middle school in Shoreline City as Y; M = x = x; so Y = 3 * M = (3) * (x) = 3*x. Define total number of schools in Shoreline City as k; so k = Y + x = 3*x + x = 4*x. We know k = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of private middle school in Brightford equals 4 times the number of regional medical school in Westhaven City. The total number of schools in Glenfield City equals 3. The number of elementary school in Glenfield City equals 1 plus the number of private middle school in Glenfield City. The number of regional medical school in Westhaven City equals 4 plus the number of regional medical school in Brightford. The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of regional medical school in Brightford equals the difference between the number of elementary school in Brightford and the number of private middle school in Westhaven City. The number of elementary school in Brightford equals 3. The number of private middle school in Westhaven City equals 3 times the number of elementary school in Brightford.

Question: How many private middle school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define elementary school in Glenfield City as h; m = x = x; so h = 1 + m = 1 + x = x + 1. Define total number of schools in Glenfield City as F; so F = x + h = x + x + 1 = 2*x + 1. We know F = 3, so we have 2*x + 1 = 3 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 3. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.


The number of adult fox in Pine Ridge exists, and its number is greater than 0. The total number of adult animals in Beverly Forest equals 16. The number of adult racoon in Beverly Forest equals 4 times the total number of adult animals in Pine Ridge.

Question: How many adult fox does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Pine Ridge as x; we don't know its value yet but will find it out later. Define total number of adult animals in Pine Ridge as V; so V = x = x. Define adult racoon in Beverly Forest as N; I = V = x; so N = 4 * I = (4) * (x) = 4*x. Define total number of adult animals in Beverly Forest as C; so C = N = 4*x. We know C = 16, so we have 4*x = 16 and we solve it through the following steps: Simplifying the equation: 4*x = 16. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The total number of movies in Northwood Movie Festival equals 8. The number of solemn period drama in Northwood Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 plus the number of solemn period drama in Northwood Movie Festival.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Northwood Movie Festival as s; Z = x = x; so s = 4 + Z = 4 + x = x + 4. Define total number of movies in Northwood Movie Festival as B; so B = x + s = x + x + 4 = 2*x + 4. We know B = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of private middle school in Glenfield City equals 3 plus the number of public highschool in Glenfield City. The number of private middle school in Brightford equals 4. The number of public highschool in Brightford equals 4. The total number of schools in Glenfield City equals 9. The number of public highschool in Glenfield City exists, and its number is greater than 0.

Question: How many public highschool does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Glenfield City as x; we don't know its value yet but will find it out later. Define private middle school in Glenfield City as H; Y = x = x; so H = 3 + Y = 3 + x = x + 3. Define total number of schools in Glenfield City as q; so q = x + H = x + x + 3 = 2*x + 3. We know q = 9, so we have 2*x + 3 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 9. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult wolf in Bundle Ranch equals 2 plus the total number of adult animals in South Zoo. The number of adult bear in South Zoo exists, and its number is greater than 0. The total number of adult animals in Bundle Ranch equals 5.

Question: How many adult bear does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in South Zoo as x; we don't know its value yet but will find it out later. Define total number of adult animals in South Zoo as R; so R = x = x. Define adult wolf in Bundle Ranch as P; b = R = x; so P = 2 + b = 2 + x = x + 2. Define total number of adult animals in Bundle Ranch as V; so V = P = x + 2. We know V = 5, so we have x + 2 = 5 and we solve it through the following steps: Simplifying the equation: x + 2 = 5. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of adult racoon in Mayer Aquarium exists, and its number is greater than 0. The total number of adult animals in Mayer Aquarium equals 10. The number of adult racoon in Jefferson Circus equals the number of adult wolf in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals 4 times the number of adult racoon in Mayer Aquarium. The number of adult wolf in Jefferson Circus equals 1.

Question: How many adult racoon does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult wolf in Mayer Aquarium as A; i = x = x; so A = 4 * i = (4) * (x) = 4*x. Define total number of adult animals in Mayer Aquarium as b; so b = A + x = 4*x + x = 5*x. We know b = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.


The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 2 plus the total number of movies in Festival Lumière de Valmont. The total number of movies in Festival de Saint-Rivage equals 5. The number of calm road movie in Festival de Clairmont equals 4. The number of calm road movie in Festival Lumière de Valmont exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival de Clairmont equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 4.

Question: How many calm road movie does Festival Lumière de Valmont have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival Lumière de Valmont as l; so l = x = x. Define futuristic sci-fi movie in Festival de Saint-Rivage as B; G = l = x; so B = 2 + G = 2 + x = x + 2. Define total number of movies in Festival de Saint-Rivage as Z; so Z = B = x + 2. We know Z = 5, so we have x + 2 = 5 and we solve it through the following steps: Simplifying the equation: x + 2 = 5. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of regional medical school in Clearwater Bay equals 2. The number of private middle school in Riverton City equals the sum of the total number of schools in Ruby Bay and the number of regional medical school in Ruby Bay. The number of private middle school in Clearwater Bay equals 2. The number of regional medical school in Ruby Bay exists, and its number is greater than 0. The number of elementary school in Clearwater Bay equals the number of private middle school in Clearwater Bay. The total number of schools in Riverton City equals 4.

Question: How many regional medical school does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Ruby Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Ruby Bay as q; so q = x = x. Define private middle school in Riverton City as P; so P = q + x = x + x = 2*x. Define total number of schools in Riverton City as C; so C = P = 2*x. We know C = 4, so we have 2*x = 4 and we solve it through the following steps: Simplifying the equation: 2*x = 4. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of elementary school in Westhaven City equals the number of culinarian school in Westhaven City. The number of culinarian school in Glenfield City equals 2 times the number of elementary school in Glenfield City. The number of elementary school in Glenfield City exists, and its number is greater than 0. The number of culinarian school in Westhaven City equals 2. The total number of schools in Glenfield City equals 12.

Question: How many elementary school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Glenfield City as x; we don't know its value yet but will find it out later. Define culinarian school in Glenfield City as t; D = x = x; so t = 2 * D = (2) * (x) = 2*x. Define total number of schools in Glenfield City as Q; so Q = t + x = 2*x + x = 3*x. We know Q = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.


The number of private middle school in Riverton City equals 2 plus the number of culinarian school in Riverton City. The number of culinarian school in Riverton City exists, and its number is greater than 0. The total number of schools in Riverton City equals 10. The number of culinarian school in Ruby Bay equals the difference between the total number of schools in Riverton City and the number of culinarian school in Riverton City. The number of private middle school in Ruby Bay equals 3.

Question: How many culinarian school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Riverton City as x; we don't know its value yet but will find it out later. Define private middle school in Riverton City as b; D = x = x; so b = 2 + D = 2 + x = x + 2. Define total number of schools in Riverton City as u; so u = b + x = x + 2 + x = 2*x + 2. We know u = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of adult bear in Beverly Forest equals 4. The number of adult fox in Cedar Valley exists, and its number is greater than 0. The total number of adult animals in Cedar Valley equals 7. The number of adult deer in Cedar Valley equals 1 plus the number of adult fox in Cedar Valley. The number of adult bear in Pine Ridge equals the total number of adult animals in Cedar Valley. The number of adult fox in Pine Ridge equals 4. The number of adult deer in Pine Ridge equals 4.

Question: How many adult fox does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult deer in Cedar Valley as n; u = x = x; so n = 1 + u = 1 + x = x + 1. Define total number of adult animals in Cedar Valley as y; so y = x + n = x + x + 1 = 2*x + 1. We know y = 7, so we have 2*x + 1 = 7 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 7. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult owl in Bundle Ranch equals 4. The number of adult parrot in South Zoo equals the sum of the number of adult crow in South Zoo and the number of adult owl in Bundle Ranch. The number of adult owl in South Zoo equals the number of adult parrot in Jefferson Circus. The number of adult crow in Bundle Ranch equals the number of adult parrot in Jefferson Circus. The number of adult crow in Jefferson Circus exists, and its number is greater than 0. The total number of adult animals in Jefferson Circus equals 4. The number of adult parrot in Jefferson Circus equals 2 plus the number of adult crow in Jefferson Circus. The number of adult crow in South Zoo equals 4.

Question: How many adult crow does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult crow in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult parrot in Jefferson Circus as r; i = x = x; so r = 2 + i = 2 + x = x + 2. Define total number of adult animals in Jefferson Circus as m; so m = r + x = x + 2 + x = 2*x + 2. We know m = 4, so we have 2*x + 2 = 4 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 4. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.


The number of intense detective thriller in Cinéma de Montreval exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals 4 times the number of futuristic sci-fi movie in Cinéma de Montreval. The total number of movies in Cinéma de Montreval equals 5. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the difference between the number of intense detective thriller in Cinéma de Montreval and the number of futuristic sci-fi movie in Cinéma de Montreval. The number of futuristic sci-fi movie in Cinéma de Montreval equals 1 plus the number of intense detective thriller in Cinéma de Montreval.

Question: How many intense detective thriller does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Cinéma de Montreval as O; y = x = x; so O = 1 + y = 1 + x = x + 1. Define total number of movies in Cinéma de Montreval as I; so I = O + x = x + 1 + x = 2*x + 1. We know I = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of adult fox in Cedar Valley equals 4. The number of adult bear in Pine Ridge exists, and its number is greater than 0. The number of adult bear in Cedar Valley equals 4 plus the total number of adult animals in Pine Ridge. The total number of adult animals in Pine Ridge equals 3. The number of adult fox in Pine Ridge equals 1 plus the number of adult bear in Pine Ridge.

Question: How many adult bear does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult fox in Pine Ridge as f; K = x = x; so f = 1 + K = 1 + x = x + 1. Define total number of adult animals in Pine Ridge as q; so q = f + x = x + 1 + x = 2*x + 1. We know q = 3, so we have 2*x + 1 = 3 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 3. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.


The number of adult wolf in Mayer Aquarium equals 4. The number of adult bear in Hamilton Farm equals 3 times the number of adult wolf in Hamilton Farm. The total number of adult animals in Hamilton Farm equals 12. The number of adult wolf in Bundle Ranch equals 4. The number of adult wolf in Hamilton Farm exists, and its number is greater than 0. The number of adult bear in Mayer Aquarium equals 3 plus the sum of the total number of adult animals in Hamilton Farm, the number of adult bear in Hamilton Farm, and the number of adult wolf in Bundle Ranch. The number of adult wolf in Hamilton Farm exists, and its number is greater than 0. The number of adult racoon in Bundle Ranch equals the number of adult wolf in Hamilton Farm. The number of adult wolf in Hamilton Farm exists, and its number is greater than 0.

Question: How many adult wolf does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult bear in Hamilton Farm as f; B = x = x; so f = 3 * B = (3) * (x) = 3*x. Define total number of adult animals in Hamilton Farm as l; so l = f + x = 3*x + x = 4*x. We know l = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of solemn period drama in Taylor Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Northwood Movie Festival equals the sum of the number of calm road movie in Taylor Movie Festival, the total number of movies in Taylor Movie Festival, the total number of movies in Golden Banana Movie Festival, and the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2. The total number of movies in Golden Banana Movie Festival equals 7. The number of calm road movie in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3 plus the number of calm road movie in Golden Banana Movie Festival.

Question: How many calm road movie does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in Golden Banana Movie Festival as v; L = x = x; so v = 3 + L = 3 + x = x + 3. Define total number of movies in Golden Banana Movie Festival as H; so H = x + v = x + x + 3 = 2*x + 3. We know H = 7, so we have 2*x + 3 = 7 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 7. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of public highschool in Brightford equals 2 times the total number of schools in Hawkesbury. The total number of schools in Brightford equals 6. The number of private middle school in Glenfield City equals 4. The number of regional medical school in Hawkesbury exists, and its number is greater than 0. The number of public highschool in Glenfield City equals 3 times the number of private middle school in Glenfield City.

Question: How many regional medical school does Hawkesbury have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Hawkesbury as x; we don't know its value yet but will find it out later. Define total number of schools in Hawkesbury as W; so W = x = x. Define public highschool in Brightford as Z; g = W = x; so Z = 2 * g = (2) * (x) = 2*x. Define total number of schools in Brightford as I; so I = Z = 2*x. We know I = 6, so we have 2*x = 6 and we solve it through the following steps: Simplifying the equation: 2*x = 6. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of culinarian school in Riverton City equals 3 plus the number of regional medical school in Riverton City. The number of culinarian school in Clearwater Bay equals 4. The total number of schools in Riverton City equals 11. The number of regional medical school in Riverton City exists, and its number is greater than 0. The number of regional medical school in Clearwater Bay equals 4.

Question: How many regional medical school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Riverton City as x; we don't know its value yet but will find it out later. Define culinarian school in Riverton City as O; y = x = x; so O = 3 + y = 3 + x = x + 3. Define total number of schools in Riverton City as f; so f = x + O = x + x + 3 = 2*x + 3. We know f = 11, so we have 2*x + 3 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 11. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The total number of movies in Cinéma de Montreval equals 3. The number of intense detective thriller in Cinéma de Montreval equals 1 plus the total number of movies in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage exists, and its number is greater than 0.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as J; so J = x = x. Define intense detective thriller in Cinéma de Montreval as W; F = J = x; so W = 1 + F = 1 + x = x + 1. Define total number of movies in Cinéma de Montreval as w; so w = W = x + 1. We know w = 3, so we have x + 1 = 3 and we solve it through the following steps: Simplifying the equation: x + 1 = 3. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of upbeat metropolis comedy in Festival de Clairmont equals 4 plus the number of futuristic sci-fi movie in Festival de Clairmont. The total number of movies in Festival de Clairmont equals 8. The number of upbeat metropolis comedy in Rêves de Belleville equals 2. The number of futuristic sci-fi movie in Rêves de Belleville equals 1 plus the number of upbeat metropolis comedy in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0.

Question: How many futuristic sci-fi movie does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival de Clairmont as b; k = x = x; so b = 4 + k = 4 + x = x + 4. Define total number of movies in Festival de Clairmont as K; so K = x + b = x + x + 4 = 2*x + 4. We know K = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.


The number of culinarian school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of private middle school in Ruby Bay equals 3 times the number of culinarian school in Ruby Bay. The number of public highschool in Riverton City equals 1. The number of private middle school in Clearwater Bay equals the number of public highschool in Riverton City. The number of culinarian school in Riverton City equals the number of culinarian school in Clearwater Bay. The number of public highschool in Clearwater Bay equals 2 plus the sum of the number of culinarian school in Ruby Bay, the number of culinarian school in Clearwater Bay, and the total number of schools in Ruby Bay. The total number of schools in Ruby Bay equals 8. The number of private middle school in Riverton City equals the sum of the total number of schools in Riverton City and the total number of schools in Ruby Bay. The number of culinarian school in Ruby Bay exists, and its number is greater than 0.

Question: How many culinarian school does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Ruby Bay as x; we don't know its value yet but will find it out later. Define private middle school in Ruby Bay as l; j = x = x; so l = 3 * j = (3) * (x) = 3*x. Define total number of schools in Ruby Bay as K; so K = l + x = 3*x + x = 4*x. We know K = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.


The number of adult parrot in Bundle Ranch equals 4 times the number of adult crow in South Zoo. The number of adult crow in Bundle Ranch equals 1. The total number of adult animals in South Zoo equals 7. The number of adult parrot in South Zoo equals 1 plus the number of adult crow in South Zoo. The number of adult crow in South Zoo exists, and its number is greater than 0.

Question: How many adult crow does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult crow in South Zoo as x; we don't know its value yet but will find it out later. Define adult parrot in South Zoo as A; U = x = x; so A = 1 + U = 1 + x = x + 1. Define total number of adult animals in South Zoo as c; so c = x + A = x + x + 1 = 2*x + 1. We know c = 7, so we have 2*x + 1 = 7 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 7. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of solemn period drama in Festival de Saint-Rivage exists, and its number is greater than 0. The total number of movies in Festival de Saint-Rivage equals 16. The number of calm road movie in Festival de Saint-Rivage equals 3 times the number of solemn period drama in Festival de Saint-Rivage.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define calm road movie in Festival de Saint-Rivage as r; T = x = x; so r = 3 * T = (3) * (x) = 3*x. Define total number of movies in Festival de Saint-Rivage as h; so h = x + r = x + 3*x = 4*x. We know h = 16, so we have 4*x = 16 and we solve it through the following steps: Simplifying the equation: 4*x = 16. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of culinarian school in Shoreline City equals 4 plus the total number of schools in Oakbridge City. The number of culinarian school in Oakbridge City exists, and its number is greater than 0. The number of private middle school in Ruby Bay equals 2. The total number of schools in Shoreline City equals 7. The number of elementary school in Ruby Bay equals 3 times the number of private middle school in Ruby Bay.

Question: How many culinarian school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Oakbridge City as x; we don't know its value yet but will find it out later. Define total number of schools in Oakbridge City as O; so O = x = x. Define culinarian school in Shoreline City as p; v = O = x; so p = 4 + v = 4 + x = x + 4. Define total number of schools in Shoreline City as d; so d = p = x + 4. We know d = 7, so we have x + 4 = 7 and we solve it through the following steps: Simplifying the equation: x + 4 = 7. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of regional medical school in Riverton City equals the number of regional medical school in Clearwater Bay. The number of culinarian school in Riverton City equals 1. The total number of schools in Clearwater Bay equals 4. The number of regional medical school in Clearwater Bay exists, and its number is greater than 0. The number of culinarian school in Clearwater Bay equals 3 times the number of regional medical school in Clearwater Bay.

Question: How many regional medical school does Clearwater Bay have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define culinarian school in Clearwater Bay as L; G = x = x; so L = 3 * G = (3) * (x) = 3*x. Define total number of schools in Clearwater Bay as Q; so Q = x + L = x + 3*x = 4*x. We know Q = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of public highschool in Oakbridge City equals 4 plus the total number of schools in Riverton City. The number of regional medical school in Riverton City exists, and its number is greater than 0. The total number of schools in Oakbridge City equals 5.

Question: How many regional medical school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Riverton City as x; we don't know its value yet but will find it out later. Define total number of schools in Riverton City as q; so q = x = x. Define public highschool in Oakbridge City as z; I = q = x; so z = 4 + I = 4 + x = x + 4. Define total number of schools in Oakbridge City as F; so F = z = x + 4. We know F = 5, so we have x + 4 = 5 and we solve it through the following steps: Simplifying the equation: x + 4 = 5. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of adult racoon in Hamilton Farm exists, and its number is greater than 0. The number of adult racoon in Bundle Ranch equals 4 times the total number of adult animals in Hamilton Farm. The number of adult fox in South Zoo equals 4 plus the total number of adult animals in Hamilton Farm. The total number of adult animals in Bundle Ranch equals 4. The number of adult wolf in South Zoo equals 1.

Question: How many adult racoon does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as q; so q = x = x. Define adult racoon in Bundle Ranch as z; N = q = x; so z = 4 * N = (4) * (x) = 4*x. Define total number of adult animals in Bundle Ranch as U; so U = z = 4*x. We know U = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.