The number of elementary school in Brightford equals 4 times the sum of the number of private middle school in Glenfield City and the number of private middle school in Brightford. The total number of schools in Brightford equals 32. The number of culinarian school in Glenfield City equals 3. The number of elementary school in Hawkesbury equals the number of elementary school in Glenfield City. The number of culinarian school in Brightford exists, and its number is greater than 0. The number of culinarian school in Hawkesbury equals the number of elementary school in Glenfield City. The number of private middle school in Brightford equals 4. The number of elementary school in Glenfield City equals 1. The number of private middle school in Glenfield City equals 2. The number of private middle school in Hawkesbury equals the sum of the number of private middle school in Brightford, the number of elementary school in Brightford, the number of culinarian school in Glenfield City, and the number of culinarian school in Brightford.

Question: How many culinarian school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Brightford as A; so A = 4. Define private middle school in Glenfield City as N; so N = 2. Define elementary school in Brightford as G; m = N + A = 2 + 4 = 6; so G = 4 * m = (4) * (6) = 24. Define culinarian school in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as w; c = G + A = 24 + 4 = 28; so w = c + x = 28 + x = x + 28. We know w = 32, so we have x + 28 = 32 and we solve it through the following steps: Simplifying the equation: x + 28 = 32. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.


The number of private middle school in Ruby Bay equals the number of culinarian school in Ruby Bay. The total number of schools in Shoreline City equals 6. The number of private middle school in Shoreline City equals the number of private middle school in Ruby Bay. The number of culinarian school in Ruby Bay exists, and its number is greater than 0. The number of culinarian school in Shoreline City equals the difference between the total number of schools in Ruby Bay and the number of private middle school in Ruby Bay.

Question: How many culinarian school does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Ruby Bay as x; we don't know its value yet but will find it out later. Define private middle school in Ruby Bay as k; so k = x = x. Define total number of schools in Ruby Bay as M; so M = x + k = x + x = 2*x. Define culinarian school in Shoreline City as s; so s = M - k = (2*x) - (x) = x. Define private middle school in Shoreline City as T; so T = k = x. Define total number of schools in Shoreline City as O; so O = s + T = x + x = 2*x. We know O = 6, so we have 2*x = 6 and we solve it through the following steps: Simplifying the equation: 2*x = 6. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of adult wolf in Bundle Ranch equals 3 times the number of adult bear in Bundle Ranch. The number of adult racoon in South Zoo equals 2 plus the difference between the number of adult racoon in Hamilton Farm and the number of adult wolf in Hamilton Farm. The number of adult racoon in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm and the number of adult bear in Hamilton Farm. The number of adult racoon in Hamilton Farm equals the number of adult bear in Hamilton Farm. The number of adult bear in Bundle Ranch equals 2. The number of adult deer in Mayer Aquarium equals 2. The number of adult bear in Hamilton Farm equals 2 plus the number of adult deer in Mayer Aquarium. The number of adult bear in South Zoo equals the sum of the number of adult deer in Mayer Aquarium and the number of adult racoon in Bundle Ranch. The number of adult deer in Bundle Ranch equals 3. The number of adult wolf in Hamilton Farm equals the difference between the number of adult bear in Hamilton Farm and the number of adult deer in Mayer Aquarium. The number of adult wolf in South Zoo equals the number of adult bear in Bundle Ranch.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult deer in Mayer Aquarium as m; so m = 2. Define adult bear in Hamilton Farm as F; I = m = 2; so F = 2 + I = 2 + 2 = 4. Define adult wolf in Hamilton Farm as M; so M = F - m = 4 - 2 = 2. Define adult racoon in Hamilton Farm as V; so V = F = 4. Define total number of adult animals in Hamilton Farm as G; e = F + V = 4 + 4 = 8; so G = e + M = 8 + 2 = 10. Answer: 10.


The number of adult wolf in Bundle Ranch equals the number of adult racoon in South Zoo. The number of adult racoon in South Zoo equals 3 times the number of adult bear in Bundle Ranch. The number of adult bear in Jefferson Circus equals the number of adult bear in Bundle Ranch. The number of adult racoon in Mayer Aquarium equals 3. The number of adult fox in Bundle Ranch equals 4 plus the total number of adult animals in Mayer Aquarium. The number of adult wolf in South Zoo equals 2 plus the difference between the number of adult bear in Mayer Aquarium and the number of adult fox in South Zoo. The number of adult fox in South Zoo equals 4. The number of adult bear in Bundle Ranch equals 1. The number of adult racoon in Jefferson Circus equals 4. The number of adult fox in Jefferson Circus equals 1. The number of adult fox in Mayer Aquarium equals the number of adult racoon in Mayer Aquarium. The number of adult bear in South Zoo equals 4. The number of adult bear in Mayer Aquarium equals 4 plus the number of adult racoon in Mayer Aquarium.

Question: How many adult fox does Bundle Ranch have?

Solution: Define adult racoon in Mayer Aquarium as X; so X = 3. Define adult bear in Mayer Aquarium as j; H = X = 3; so j = 4 + H = 4 + 3 = 7. Define adult fox in Mayer Aquarium as U; so U = X = 3. Define total number of adult animals in Mayer Aquarium as d; P = U + j = 3 + 7 = 10; so d = P + X = 10 + 3 = 13. Define adult fox in Bundle Ranch as A; B = d = 13; so A = 4 + B = 4 + 13 = 17. Answer: 17.


The number of elementary school in Oakbridge City equals the sum of the total number of schools in Ruby Bay, the number of regional medical school in Clearwater Bay, and the total number of schools in Clearwater Bay. The number of private middle school in Ruby Bay equals 3. The number of regional medical school in Clearwater Bay equals the sum of the number of culinarian school in Shoreline City, the total number of schools in Ruby Bay, and the number of private middle school in Ruby Bay. The number of culinarian school in Shoreline City equals 4 times the total number of schools in Ruby Bay. The number of private middle school in Shoreline City equals 4. The number of elementary school in Shoreline City equals the sum of the number of regional medical school in Clearwater Bay and the total number of schools in Ruby Bay. The number of regional medical school in Oakbridge City equals the number of private middle school in Shoreline City.

Question: How many elementary school does Shoreline City have?

Solution: Define private middle school in Ruby Bay as y; so y = 3. Define total number of schools in Ruby Bay as w; so w = y = 3. Define culinarian school in Shoreline City as f; s = w = 3; so f = 4 * s = 4 * 3 = 12. Define regional medical school in Clearwater Bay as c; Q = f + w = 12 + 3 = 15; so c = Q + y = 15 + 3 = 18. Define elementary school in Shoreline City as W; so W = c + w = 18 + 3 = 21. Answer: 21.


The number of calm road movie in Festival de Saint-Rivage equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals 4 plus the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Clairmont exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the number of calm road movie in Festival de Clairmont and the number of upbeat metropolis comedy in Festival de Clairmont. The total number of movies in Festival de Clairmont equals 16. The number of calm road movie in Festival Lumière de Valmont equals 3 times the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of solemn period drama in Festival Lumière de Valmont equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3.

Question: How many upbeat metropolis comedy does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define calm road movie in Festival de Clairmont as P; so P = x = x. Define solemn period drama in Festival de Saint-Rivage as K; so K = P + x = x + x = 2*x. Define solemn period drama in Festival de Clairmont as W; N = K = 2*x; so W = 4 + N = 4 + 2*x = 2*x + 4. Define total number of movies in Festival de Clairmont as Z; I = W + x = 2*x + 4 + x = 3*x + 4; so Z = I + P = 3*x + 4 + x = 4*x + 4. We know Z = 16, so we have 4*x + 4 = 16 and we solve it through the following steps: Simplifying the equation: 4*x + 4 = 16. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of adult crow in South Zoo equals 2. The number of adult eagle in South Zoo equals 2. The number of adult eagle in Jefferson Circus equals the difference between the total number of adult animals in Bundle Ranch and the number of adult eagle in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 3 plus the number of adult parrot in Bundle Ranch. The number of adult parrot in Jefferson Circus equals 4 times the sum of the number of adult eagle in South Zoo, the number of adult crow in South Zoo, and the number of adult crow in Jefferson Circus. The number of adult crow in Jefferson Circus equals the number of adult crow in South Zoo. The number of adult parrot in South Zoo equals 4 plus the sum of the number of adult crow in South Zoo, the number of adult parrot in Jefferson Circus, and the number of adult eagle in South Zoo. The number of adult parrot in Bundle Ranch equals 3. The number of adult crow in Bundle Ranch equals 4.

Question: How many adult eagle does Jefferson Circus have?

Solution: Define adult parrot in Bundle Ranch as D; so D = 3. Define adult eagle in Bundle Ranch as w; e = D = 3; so w = 3 + e = 3 + 3 = 6. Define adult crow in Bundle Ranch as l; so l = 4. Define total number of adult animals in Bundle Ranch as L; q = D + l = 3 + 4 = 7; so L = q + w = 7 + 6 = 13. Define adult eagle in Jefferson Circus as Q; so Q = L - w = 13 - 6 = 7. Answer: 7.


The number of public highschool in Glenfield City equals 3 times the sum of the number of elementary school in Glenfield City and the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City exists, and its number is greater than 0. The number of culinarian school in Westhaven City exists, and its number is greater than 0. The number of public highschool in Brightford equals 4. The number of culinarian school in Glenfield City equals 40. The number of public highschool in Westhaven City equals 2 plus the sum of the number of elementary school in Glenfield City, the number of public highschool in Glenfield City, and the number of culinarian school in Westhaven City. The number of elementary school in Glenfield City equals 4 plus the number of culinarian school in Westhaven City. The number of elementary school in Westhaven City equals the total number of schools in Brightford.

Question: How many culinarian school does Westhaven City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Westhaven City as x; we don't know its value yet but will find it out later. Define elementary school in Glenfield City as R; D = x = x; so R = 4 + D = 4 + x = x + 4. Define public highschool in Glenfield City as K; I = R + x = x + 4 + x = 2*x + 4; so K = 3 * I = (3) * (2*x + 4) = 6*x + 12. Define culinarian school in Glenfield City as j; z = K + x = 6*x + 12 + x = 7*x + 12; so j = z + R = 7*x + 12 + x + 4 = 8*x + 16. We know j = 40, so we have 8*x + 16 = 40 and we solve it through the following steps: Simplifying the equation: 8*x + 16 = 40. Move all terms to one side: 8*x - 24 = 0. Isolate the term with x: 8*x = 24. Divide both sides by 8: x = 24 / 8. Solution: x = 3. Answer: 3.


The number of elementary school in Westhaven City equals the number of culinarian school in Evervale City. The number of culinarian school in Evervale City exists, and its number is greater than 0. The number of regional medical school in Brightford equals the sum of the number of elementary school in Westhaven City and the number of elementary school in Brightford. The number of elementary school in Brightford equals 4 times the total number of schools in Evervale City. The total number of schools in Brightford equals 27.

Question: How many culinarian school does Evervale City have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Evervale City as x; we don't know its value yet but will find it out later. Define total number of schools in Evervale City as i; so i = x = x. Define elementary school in Brightford as R; s = i = x; so R = 4 * s = (4) * (x) = 4*x. Define elementary school in Westhaven City as B; so B = x = x. Define regional medical school in Brightford as G; so G = B + R = x + 4*x = 5*x. Define total number of schools in Brightford as t; so t = R + G = 4*x + 5*x = 9*x. We know t = 27, so we have 9*x = 27 and we solve it through the following steps: Simplifying the equation: 9*x = 27. Move all terms to one side: 9*x - 27 = 0. Isolate the term with x: 9*x = 27. Divide both sides by 9: x = 27 / 9. Solution: x = 3. Answer: 3.


The number of adult parrot in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The number of adult eagle in Mayer Aquarium exists, and its number is greater than 0. The total number of adult animals in Hamilton Farm equals 5. The number of adult owl in Hamilton Farm equals the number of adult eagle in Mayer Aquarium. The number of adult eagle in Hamilton Farm equals 1 plus the total number of adult animals in Mayer Aquarium.

Question: How many adult eagle does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define total number of adult animals in Mayer Aquarium as U; so U = x = x. Define adult eagle in Hamilton Farm as b; t = U = x; so b = 1 + t = 1 + x = x + 1. Define adult owl in Hamilton Farm as f; so f = x = x. Define adult parrot in Hamilton Farm as Q; so Q = b = x + 1. Define total number of adult animals in Hamilton Farm as s; r = b + Q = x + 1 + x + 1 = 2*x + 2; so s = r + f = 2*x + 2 + x = 3*x + 2. We know s = 5, so we have 3*x + 2 = 5 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 5. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.


The number of public highschool in Riverton City exists, and its number is greater than 0. The number of culinarian school in Oakbridge City equals 3. The number of public highschool in Oakbridge City equals 1. The number of elementary school in Riverton City equals the number of public highschool in Riverton City. The number of public highschool in Shoreline City equals 1 plus the total number of schools in Riverton City. The number of culinarian school in Shoreline City equals the number of elementary school in Riverton City. The total number of schools in Shoreline City equals 10.

Question: How many public highschool does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define elementary school in Riverton City as I; so I = x = x. Define total number of schools in Riverton City as d; so d = I + x = x + x = 2*x. Define public highschool in Shoreline City as p; J = d = 2*x; so p = 1 + J = 1 + 2*x = 2*x + 1. Define culinarian school in Shoreline City as t; so t = I = x. Define total number of schools in Shoreline City as P; so P = t + p = x + 2*x + 1 = 3*x + 1. We know P = 10, so we have 3*x + 1 = 10 and we solve it through the following steps: Simplifying the equation: 3*x + 1 = 10. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.


The number of elementary school in Riverton City equals 4 plus the number of public highschool in Ruby Bay. The number of public highschool in Oakbridge City equals 3. The number of regional medical school in Ruby Bay equals the sum of the number of public highschool in Oakbridge City, the total number of schools in Riverton City, and the number of public highschool in Ruby Bay. The number of public highschool in Ruby Bay equals 2. The number of regional medical school in Riverton City equals the difference between the number of elementary school in Riverton City and the number of public highschool in Ruby Bay. The number of elementary school in Oakbridge City equals the sum of the total number of schools in Riverton City and the number of regional medical school in Riverton City.

Question: How many elementary school does Oakbridge City have?

Solution: Define public highschool in Ruby Bay as E; so E = 2. Define elementary school in Riverton City as L; J = E = 2; so L = 4 + J = 4 + 2 = 6. Define regional medical school in Riverton City as f; so f = L - E = 6 - 2 = 4. Define total number of schools in Riverton City as R; so R = f + L = 4 + 6 = 10. Define elementary school in Oakbridge City as D; so D = R + f = 10 + 4 = 14. Answer: 14.


The number of public highschool in Oakbridge City equals 1 plus the number of elementary school in Oakbridge City. The number of elementary school in Riverton City equals 2 times the number of public highschool in Riverton City. The number of elementary school in Oakbridge City exists, and its number is greater than 0. The number of public highschool in Riverton City equals 3 times the number of public highschool in Oakbridge City. The total number of schools in Riverton City equals 18.

Question: How many elementary school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Oakbridge City as x; we don't know its value yet but will find it out later. Define public highschool in Oakbridge City as K; H = x = x; so K = 1 + H = 1 + x = x + 1. Define public highschool in Riverton City as C; M = K = x + 1; so C = 3 * M = (3) * (x + 1) = 3*x + 3. Define elementary school in Riverton City as E; F = C = 3*x + 3; so E = 2 * F = (2) * (3*x + 3) = 6*x + 6. Define total number of schools in Riverton City as V; so V = E + C = 6*x + 6 + 3*x + 3 = 9*x + 9. We know V = 18, so we have 9*x + 9 = 18 and we solve it through the following steps: Simplifying the equation: 9*x + 9 = 18. Move all terms to one side: 9*x - 9 = 0. Isolate the term with x: 9*x = 9. Divide both sides by 9: x = 9 / 9. Solution: x = 1. Answer: 1.


The number of adult parrot in Bundle Ranch equals the number of adult blue jay in Bundle Ranch. The number of adult crow in Hamilton Farm equals 3. The total number of adult animals in Bundle Ranch equals 24. The number of adult parrot in South Zoo equals the difference between the number of adult blue jay in Hamilton Farm and the number of adult crow in Bundle Ranch. The number of adult crow in Bundle Ranch equals 4 times the number of adult parrot in Bundle Ranch. The number of adult blue jay in South Zoo equals 4 times the number of adult parrot in Hamilton Farm. The number of adult blue jay in Hamilton Farm exists, and its number is greater than 0. The number of adult parrot in Hamilton Farm equals 3. The number of adult blue jay in Bundle Ranch equals 2 plus the number of adult blue jay in Hamilton Farm.

Question: How many adult blue jay does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult blue jay in Bundle Ranch as Y; Q = x = x; so Y = 2 + Q = 2 + x = x + 2. Define adult parrot in Bundle Ranch as m; so m = Y = x + 2. Define adult crow in Bundle Ranch as w; f = m = x + 2; so w = 4 * f = (4) * (x + 2) = 4*x + 8. Define total number of adult animals in Bundle Ranch as M; J = w + m = 4*x + 8 + x + 2 = 5*x + 10; so M = J + Y = 5*x + 10 + x + 2 = 6*x + 12. We know M = 24, so we have 6*x + 12 = 24 and we solve it through the following steps: Simplifying the equation: 6*x + 12 = 24. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.


The number of elementary school in Westhaven City equals 4. The number of elementary school in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of regional medical school in Hawkesbury equals 4 times the total number of schools in Westhaven City. The number of public highschool in Westhaven City equals 4.

Question: What is the total number of schools in Hawkesbury?

Solution: Define public highschool in Westhaven City as f; so f = 4. Define elementary school in Westhaven City as R; so R = 4. Define total number of schools in Westhaven City as x; so x = f + R = 4 + 4 = 8. Define regional medical school in Hawkesbury as T; L = x = 8; so T = 4 * L = 4 * 8 = 32. Define elementary school in Hawkesbury as i; so i = T = 32. Define total number of schools in Hawkesbury as o; so o = i + T = 32 + 32 = 64. Answer: 64.


The number of adult fox in South Zoo equals 3. The number of adult bear in Bundle Ranch equals 4. The number of adult deer in South Zoo equals 4 times the sum of the number of adult fox in Bundle Ranch, the total number of adult animals in Bundle Ranch, and the number of adult wolf in Bundle Ranch. The number of adult bear in Jefferson Circus equals the difference between the total number of adult animals in Jefferson Circus and the number of adult deer in Bundle Ranch. The number of adult fox in Bundle Ranch equals the number of adult wolf in Bundle Ranch. The number of adult deer in Jefferson Circus equals the number of adult fox in Bundle Ranch. The number of adult wolf in Jefferson Circus equals 3 plus the number of adult fox in South Zoo. The number of adult wolf in South Zoo equals the number of adult deer in South Zoo. The number of adult bear in South Zoo equals the sum of the number of adult bear in Bundle Ranch and the number of adult fox in Bundle Ranch. The number of adult fox in Jefferson Circus equals 3. The number of adult wolf in Bundle Ranch equals 3 times the number of adult deer in Bundle Ranch. The number of adult deer in Bundle Ranch equals 3.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult deer in Bundle Ranch as r; so r = 3. Define adult wolf in Bundle Ranch as g; X = r = 3; so g = 3 * X = 3 * 3 = 9. Define adult fox in Bundle Ranch as c; so c = g = 9. Define adult bear in Bundle Ranch as j; so j = 4. Define total number of adult animals in Bundle Ranch as s; i = j + g = 4 + 9 = 13; I = i + c = 13 + 9 = 22; so s = I + r = 22 + 3 = 25. Answer: 25.


The number of adult racoon in Mayer Aquarium equals 4 plus the number of adult wolf in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals the total number of adult animals in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals the number of adult wolf in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 3.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in Mayer Aquarium as i; so i = 3. Define adult racoon in Mayer Aquarium as c; S = i = 3; so c = 4 + S = 4 + 3 = 7. Define total number of adult animals in Mayer Aquarium as x; so x = c + i = 7 + 3 = 10. Define adult racoon in Hamilton Farm as P; so P = x = 10. Define adult wolf in Hamilton Farm as v; so v = i = 3. Define total number of adult animals in Hamilton Farm as z; so z = P + v = 10 + 3 = 13. Answer: 13.


The number of adult eagle in Bundle Ranch equals the difference between the number of adult blue jay in Bundle Ranch and the number of adult crow in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 4 plus the number of adult crow in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 4. The number of adult crow in Mayer Aquarium equals 4. The number of adult crow in Bundle Ranch equals 4. The number of adult blue jay in Hamilton Farm equals the number of adult owl in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals the total number of adult animals in Mayer Aquarium. The number of adult owl in Mayer Aquarium equals 2. The number of adult eagle in Hamilton Farm equals 4 times the number of adult crow in Mayer Aquarium. The number of adult owl in Hamilton Farm equals the number of adult owl in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult crow in Mayer Aquarium as P; so P = 4. Define adult blue jay in Bundle Ranch as L; n = P = 4; so L = 4 + n = 4 + 4 = 8. Define adult eagle in Bundle Ranch as b; so b = L - P = 8 - 4 = 4. Define adult crow in Bundle Ranch as r; so r = 4. Define total number of adult animals in Bundle Ranch as Z; E = r + L = 4 + 8 = 12; so Z = E + b = 12 + 4 = 16. Answer: 16.


The number of intense detective thriller in Verdi Movie Festival equals 4. The total number of movies in Northwood Movie Festival equals 11. The number of intense detective thriller in Northwood Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in Taylor Movie Festival equals the total number of movies in Verdi Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2. The number of futuristic sci-fi movie in Taylor Movie Festival equals the total number of movies in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3.

Question: How many intense detective thriller does Northwood Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Verdi Movie Festival as t; so t = 2. Define intense detective thriller in Verdi Movie Festival as R; so R = 4. Define total number of movies in Verdi Movie Festival as s; so s = R + t = 4 + 2 = 6. Define futuristic sci-fi movie in Northwood Movie Festival as n; Y = s = 6; so n = 4 + Y = 4 + 6 = 10. Define intense detective thriller in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Northwood Movie Festival as N; so N = n + x = 10 + x = x + 10. We know N = 11, so we have x + 10 = 11 and we solve it through the following steps: Simplifying the equation: x + 10 = 11. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of adult racoon in Maple Creek equals 2 times the number of adult wolf in Maple Creek. The number of adult bear in Maple Creek exists, and its number is greater than 0. The number of adult racoon in Cedar Valley equals the sum of the number of adult bear in Oakridge Riverside, the number of adult wolf in Maple Creek, and the total number of adult animals in Maple Creek. The number of adult bear in Cedar Valley equals 3. The number of adult racoon in Oakridge Riverside equals the difference between the total number of adult animals in Oakridge Riverside and the total number of adult animals in Maple Creek. The number of adult wolf in Maple Creek equals 2 plus the number of adult bear in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 3. The number of adult bear in Oakridge Riverside equals 3. The total number of adult animals in Maple Creek equals 19. The number of adult wolf in Cedar Valley equals 4.

Question: How many adult bear does Maple Creek have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Oakridge Riverside as D; so D = 3. Define adult wolf in Maple Creek as m; Y = D = 3; so m = 2 + Y = 2 + 3 = 5. Define adult bear in Maple Creek as x; we don't know its value yet but will find it out later. Define adult racoon in Maple Creek as L; i = m = 5; so L = 2 * i = (2) * (5) = 10. Define total number of adult animals in Maple Creek as G; J = L + m = 10 + 5 = 15; so G = J + x = 15 + x = x + 15. We know G = 19, so we have x + 15 = 19 and we solve it through the following steps: Simplifying the equation: x + 15 = 19. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.


The number of adult owl in Pine Ridge exists, and its number is greater than 0. The total number of adult animals in Maple Creek equals 30. The number of adult owl in Beverly Forest equals 2. The number of adult parrot in Beverly Forest equals 3. The number of adult parrot in Pine Ridge equals the sum of the total number of adult animals in Maple Creek, the number of adult parrot in Maple Creek, the total number of adult animals in Pine Ridge, and the number of adult owl in Maple Creek. The number of adult crow in Maple Creek equals 4 times the number of adult owl in Pine Ridge. The number of adult crow in Pine Ridge equals 2. The number of adult owl in Maple Creek equals the number of adult parrot in Maple Creek. The number of adult crow in Beverly Forest equals 4 times the number of adult parrot in Beverly Forest. The number of adult parrot in Maple Creek equals the difference between the number of adult crow in Maple Creek and the number of adult owl in Pine Ridge.

Question: How many adult owl does Pine Ridge have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult crow in Maple Creek as u; Z = x = x; so u = 4 * Z = (4) * (x) = 4*x. Define adult parrot in Maple Creek as i; so i = u - x = (4*x) - (x) = 3*x. Define adult owl in Maple Creek as A; so A = i = 3*x. Define total number of adult animals in Maple Creek as z; r = A + i = 3*x + 3*x = 6*x; so z = r + u = 6*x + 4*x = 10*x. We know z = 30, so we have 10*x = 30 and we solve it through the following steps: Simplifying the equation: 10*x = 30. Move all terms to one side: 10*x - 30 = 0. Isolate the term with x: 10*x = 30. Divide both sides by 10: x = 30 / 10. Solution: x = 3. Answer: 3.


The number of adult bear in South Zoo equals 2 times the number of adult wolf in Bundle Ranch. The number of adult fox in Hamilton Farm equals 4. The number of adult wolf in South Zoo exists, and its number is greater than 0. The total number of adult animals in South Zoo equals 17. The number of adult wolf in Bundle Ranch equals 3. The number of adult bear in Bundle Ranch equals the number of adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals the sum of the number of adult wolf in Hamilton Farm, the number of adult fox in Hamilton Farm, and the number of adult fox in Bundle Ranch. The number of adult wolf in Hamilton Farm equals the number of adult fox in Hamilton Farm. The number of adult fox in South Zoo equals 2 plus the number of adult bear in South Zoo. The number of adult fox in Bundle Ranch equals 3 times the difference between the number of adult fox in Hamilton Farm and the number of adult wolf in Hamilton Farm.

Question: How many adult wolf does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Bundle Ranch as i; so i = 3. Define adult bear in South Zoo as A; J = i = 3; so A = 2 * J = (2) * (3) = 6. Define adult fox in South Zoo as w; e = A = 6; so w = 2 + e = 2 + 6 = 8. Define adult wolf in South Zoo as x; we don't know its value yet but will find it out later. Define total number of adult animals in South Zoo as W; B = x + w = x + 8 = x + 8; so W = B + A = x + 8 + 6 = x + 14. We know W = 17, so we have x + 14 = 17 and we solve it through the following steps: Simplifying the equation: x + 14 = 17. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of culinarian school in Glenfield City equals 20. The number of public highschool in Glenfield City equals 4 times the difference between the number of culinarian school in Westhaven City and the number of private middle school in Westhaven City. The number of public highschool in Evervale City equals 4 plus the number of private middle school in Glenfield City. The number of culinarian school in Westhaven City equals 3. The number of private middle school in Westhaven City equals 4 times the number of culinarian school in Westhaven City. The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of culinarian school in Evervale City equals 2 times the number of public highschool in Evervale City. The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of public highschool in Westhaven City equals the difference between the total number of schools in Evervale City and the number of private middle school in Glenfield City. The number of private middle school in Evervale City equals 4.

Question: How many private middle school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define public highschool in Evervale City as l; N = x = x; so l = 4 + N = 4 + x = x + 4. Define culinarian school in Evervale City as S; V = l = x + 4; so S = 2 * V = (2) * (x + 4) = 2*x + 8. Define culinarian school in Glenfield City as K; M = S + x = 2*x + 8 + x = 3*x + 8; y = M + l = 3*x + 8 + x + 4 = 4*x + 12; so K = 4 + y = 4 + 4*x + 12 = 4*x + 16. We know K = 20, so we have 4*x + 16 = 20 and we solve it through the following steps: Simplifying the equation: 4*x + 16 = 20. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3 plus the total number of movies in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals the total number of movies in West Sahara Movie Festival. The total number of movies in Northwood Movie Festival equals 11. The number of futuristic sci-fi movie in West Sahara Movie Festival exists, and its number is greater than 0.

Question: How many futuristic sci-fi movie does West Sahara Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in West Sahara Movie Festival as i; so i = x = x. Define calm road movie in Taylor Movie Festival as N; so N = i = x. Define total number of movies in Taylor Movie Festival as P; so P = N = x. Define futuristic sci-fi movie in Northwood Movie Festival as Y; u = P = x; so Y = 3 + u = 3 + x = x + 3. Define upbeat metropolis comedy in Northwood Movie Festival as g; so g = P = x. Define total number of movies in Northwood Movie Festival as k; so k = g + Y = x + x + 3 = 2*x + 3. We know k = 11, so we have 2*x + 3 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 11. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of public highschool in Riverton City equals 1 plus the number of public highschool in Shoreline City. The number of elementary school in Shoreline City equals 3. The number of elementary school in Riverton City exists, and its number is greater than 0. The number of elementary school in Ruby Bay equals the total number of schools in Riverton City. The number of regional medical school in Ruby Bay equals 3. The number of regional medical school in Shoreline City equals 3. The total number of schools in Riverton City equals 8. The number of regional medical school in Riverton City equals 1. The number of public highschool in Shoreline City equals 4 plus the number of elementary school in Riverton City. The number of public highschool in Ruby Bay equals 2 times the number of regional medical school in Riverton City.

Question: How many elementary school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Riverton City as h; so h = 1. Define elementary school in Riverton City as x; we don't know its value yet but will find it out later. Define public highschool in Shoreline City as l; n = x = x; so l = 4 + n = 4 + x = x + 4. Define public highschool in Riverton City as Q; e = l = x + 4; so Q = 1 + e = 1 + x + 4 = x + 5. Define total number of schools in Riverton City as p; S = x + Q = x + x + 5 = 2*x + 5; so p = S + h = 2*x + 5 + 1 = 2*x + 6. We know p = 8, so we have 2*x + 6 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 8. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.


The number of adult wolf in Beverly Forest equals 2 plus the difference between the number of adult wolf in Maple Creek and the number of adult fox in Cedar Valley. The number of adult bear in Cedar Valley equals 2. The number of adult fox in Cedar Valley equals 1. The number of adult wolf in Maple Creek equals 4. The number of adult fox in Maple Creek equals 4 plus the total number of adult animals in Cedar Valley.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult fox in Cedar Valley as y; so y = 1. Define adult bear in Cedar Valley as C; so C = 2. Define total number of adult animals in Cedar Valley as O; so O = y + C = 1 + 2 = 3. Define adult wolf in Maple Creek as w; so w = 4. Define adult fox in Maple Creek as U; b = O = 3; so U = 4 + b = 4 + 3 = 7. Define total number of adult animals in Maple Creek as R; so R = U + w = 7 + 4 = 11. Answer: 11.


The number of adult wolf in Hamilton Farm equals the sum of the number of adult bear in Mayer Aquarium, the number of adult bear in Hamilton Farm, and the number of adult deer in Hamilton Farm. The number of adult bear in Mayer Aquarium equals 4. The number of adult deer in Hamilton Farm equals 4. The number of adult bear in South Zoo equals the number of adult wolf in South Zoo. The number of adult bear in Jefferson Circus equals 3. The number of adult deer in Mayer Aquarium equals 3. The number of adult fox in South Zoo equals the sum of the number of adult bear in South Zoo and the number of adult bear in Jefferson Circus. The number of adult fox in Jefferson Circus equals the sum of the number of adult wolf in South Zoo and the number of adult deer in Hamilton Farm. The number of adult wolf in Jefferson Circus equals 3. The number of adult bear in Hamilton Farm equals 3. The number of adult wolf in South Zoo equals 4 times the sum of the number of adult bear in Hamilton Farm, the number of adult bear in Mayer Aquarium, and the number of adult deer in Hamilton Farm. The number of adult fox in Mayer Aquarium equals the number of adult wolf in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult bear in Hamilton Farm as W; so W = 3. Define adult deer in Hamilton Farm as U; so U = 4. Define adult bear in Mayer Aquarium as L; so L = 4. Define adult wolf in Hamilton Farm as z; k = L + W = 4 + 3 = 7; so z = k + U = 7 + 4 = 11. Define total number of adult animals in Hamilton Farm as c; t = z + W = 11 + 3 = 14; so c = t + U = 14 + 4 = 18. Answer: 18.


The number of adult owl in Hamilton Farm equals 4 times the number of adult crow in South Zoo. The number of adult parrot in South Zoo equals 4. The number of adult eagle in Bundle Ranch equals the sum of the number of adult crow in Mayer Aquarium, the total number of adult animals in Mayer Aquarium, and the number of adult crow in South Zoo. The number of adult crow in South Zoo equals 3 times the number of adult parrot in South Zoo. The number of adult crow in Mayer Aquarium equals 4 times the sum of the number of adult owl in Hamilton Farm, the number of adult parrot in South Zoo, and the number of adult crow in South Zoo.

Question: How many adult crow does Mayer Aquarium have?

Solution: Define adult parrot in South Zoo as g; so g = 4. Define adult crow in South Zoo as h; J = g = 4; so h = 3 * J = 3 * 4 = 12. Define adult owl in Hamilton Farm as V; v = h = 12; so V = 4 * v = 4 * 12 = 48. Define adult crow in Mayer Aquarium as c; M = V + g = 48 + 4 = 52; N = M + h = 52 + 12 = 64; so c = 4 * N = 4 * 64 = 256. Answer: 256.


The number of regional medical school in Glenfield City equals 4. The number of private middle school in Hawkesbury equals the number of private middle school in Brightford. The number of regional medical school in Hawkesbury equals 2 times the total number of schools in Brightford. The number of regional medical school in Brightford equals the number of private middle school in Brightford. The number of private middle school in Evervale City equals 3 times the difference between the number of regional medical school in Glenfield City and the number of regional medical school in Evervale City. The number of private middle school in Glenfield City equals the number of private middle school in Evervale City. The number of private middle school in Brightford equals 3. The number of regional medical school in Evervale City equals 3 times the number of regional medical school in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Brightford as J; so J = 3. Define regional medical school in Brightford as l; so l = J = 3. Define total number of schools in Brightford as m; so m = J + l = 3 + 3 = 6. Define regional medical school in Hawkesbury as I; n = m = 6; so I = 2 * n = 2 * 6 = 12. Define private middle school in Hawkesbury as e; so e = J = 3. Define total number of schools in Hawkesbury as X; so X = e + I = 3 + 12 = 15. Answer: 15.


The number of private middle school in Westhaven City equals the total number of schools in Glenfield City. The number of culinarian school in Hawkesbury equals the total number of schools in Westhaven City. The total number of schools in Hawkesbury equals 9. The number of elementary school in Westhaven City equals 3 plus the total number of schools in Glenfield City. The number of elementary school in Glenfield City exists, and its number is greater than 0.

Question: How many elementary school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Glenfield City as x; we don't know its value yet but will find it out later. Define total number of schools in Glenfield City as p; so p = x = x. Define elementary school in Westhaven City as Z; P = p = x; so Z = 3 + P = 3 + x = x + 3. Define private middle school in Westhaven City as y; so y = p = x. Define total number of schools in Westhaven City as v; so v = y + Z = x + x + 3 = 2*x + 3. Define culinarian school in Hawkesbury as r; so r = v = 2*x + 3. Define total number of schools in Hawkesbury as Y; so Y = r = 2*x + 3. We know Y = 9, so we have 2*x + 3 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 9. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of upbeat metropolis comedy in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2. The number of solemn period drama in Verdi Movie Festival equals 1. The number of intense detective thriller in Taylor Movie Festival equals 1. The number of intense detective thriller in West Sahara Movie Festival equals 2. The number of calm road movie in Verdi Movie Festival equals the difference between the total number of movies in Taylor Movie Festival and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of futuristic sci-fi movie in Taylor Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the difference between the number of solemn period drama in Verdi Movie Festival and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2 plus the number of solemn period drama in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 1 plus the number of intense detective thriller in West Sahara Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as k; so k = 4. Define calm road movie in Golden Banana Movie Festival as B; i = k = 4; so B = 2 + i = 2 + 4 = 6. Define total number of movies in Golden Banana Movie Festival as W; so W = B + k = 6 + 4 = 10. Define futuristic sci-fi movie in Taylor Movie Festival as E; so E = W = 10. Define intense detective thriller in Taylor Movie Festival as Z; so Z = 1. Define total number of movies in Taylor Movie Festival as e; so e = Z + E = 1 + 10 = 11. Answer: 11.


The number of calm road movie in Festival de Clairmont equals 4 plus the total number of movies in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals the total number of movies in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals the number of upbeat metropolis comedy in Rêves de Belleville. The number of calm road movie in Cinéma de Montreval exists, and its number is greater than 0. The total number of movies in Festival de Clairmont equals 10.

Question: How many calm road movie does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define total number of movies in Cinéma de Montreval as L; so L = x = x. Define upbeat metropolis comedy in Rêves de Belleville as e; so e = L = x. Define solemn period drama in Rêves de Belleville as d; so d = e = x. Define total number of movies in Rêves de Belleville as k; so k = e + d = x + x = 2*x. Define calm road movie in Festival de Clairmont as V; K = k = 2*x; so V = 4 + K = 4 + 2*x = 2*x + 4. Define total number of movies in Festival de Clairmont as b; so b = V = 2*x + 4. We know b = 10, so we have 2*x + 4 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 10. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of private middle school in Shoreline City equals the total number of schools in Riverton City. The total number of schools in Shoreline City equals 18. The number of private middle school in Riverton City exists, and its number is greater than 0. The number of elementary school in Shoreline City equals the total number of schools in Riverton City. The number of elementary school in Riverton City equals 3 plus the number of private middle school in Riverton City.

Question: How many private middle school does Riverton City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Riverton City as x; we don't know its value yet but will find it out later. Define elementary school in Riverton City as s; l = x = x; so s = 3 + l = 3 + x = x + 3. Define total number of schools in Riverton City as L; so L = s + x = x + 3 + x = 2*x + 3. Define private middle school in Shoreline City as K; so K = L = 2*x + 3. Define elementary school in Shoreline City as u; so u = L = 2*x + 3. Define total number of schools in Shoreline City as P; so P = u + K = 2*x + 3 + 2*x + 3 = 4*x + 6. We know P = 18, so we have 4*x + 6 = 18 and we solve it through the following steps: Simplifying the equation: 4*x + 6 = 18. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of private middle school in Evervale City exists, and its number is greater than 0. The total number of schools in Evervale City equals 14. The number of public highschool in Westhaven City equals the sum of the number of public highschool in Evervale City, the total number of schools in Westhaven City, and the number of regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of public highschool in Hawkesbury equals 4 times the number of regional medical school in Hawkesbury. The number of public highschool in Evervale City equals 3 plus the number of regional medical school in Evervale City. The number of regional medical school in Hawkesbury equals 3. The number of private middle school in Westhaven City equals 1. The number of private middle school in Hawkesbury equals 2 plus the sum of the total number of schools in Westhaven City and the total number of schools in Evervale City. The number of regional medical school in Evervale City equals 3 plus the number of regional medical school in Westhaven City.

Question: How many private middle school does Evervale City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Westhaven City as Z; so Z = 2. Define regional medical school in Evervale City as u; Y = Z = 2; so u = 3 + Y = 3 + 2 = 5. Define public highschool in Evervale City as Q; P = u = 5; so Q = 3 + P = 3 + 5 = 8. Define private middle school in Evervale City as x; we don't know its value yet but will find it out later. Define total number of schools in Evervale City as n; L = Q + u = 8 + 5 = 13; so n = L + x = 13 + x = x + 13. We know n = 14, so we have x + 13 = 14 and we solve it through the following steps: Simplifying the equation: x + 13 = 14. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of solemn period drama in Festival Lumière de Valmont equals 1. The number of intense detective thriller in Cinéma de Montreval equals 2 times the number of solemn period drama in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Rêves de Belleville equals the sum of the total number of movies in Cinéma de Montreval and the number of solemn period drama in Cinéma de Montreval. The total number of movies in Rêves de Belleville equals 10. The number of solemn period drama in Cinéma de Montreval exists, and its number is greater than 0.

Question: How many solemn period drama does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Festival Lumière de Valmont as M; so M = 1. Define intense detective thriller in Cinéma de Montreval as K; y = M = 1; so K = 2 * y = (2) * (1) = 2. Define solemn period drama in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define total number of movies in Cinéma de Montreval as R; so R = x + K = x + 2 = x + 2. Define upbeat metropolis comedy in Rêves de Belleville as T; so T = R + x = x + 2 + x = 2*x + 2. Define total number of movies in Rêves de Belleville as e; so e = T = 2*x + 2. We know e = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The number of adult blue jay in Hamilton Farm equals 3 times the total number of adult animals in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals the number of adult eagle in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 2. The number of adult eagle in Hamilton Farm equals 3.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult eagle in Bundle Ranch as h; so h = 2. Define adult blue jay in Bundle Ranch as z; so z = h = 2. Define total number of adult animals in Bundle Ranch as S; so S = h + z = 2 + 2 = 4. Define adult blue jay in Hamilton Farm as p; x = S = 4; so p = 3 * x = 3 * 4 = 12. Define adult eagle in Hamilton Farm as P; so P = 3. Define total number of adult animals in Hamilton Farm as G; so G = P + p = 3 + 12 = 15. Answer: 15.


The number of adult fox in Hamilton Farm equals 2. The number of adult deer in Hamilton Farm equals 2. The number of adult fox in Jefferson Circus equals 2. The number of adult wolf in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult fox in South Zoo equals 3 plus the total number of adult animals in Jefferson Circus. The total number of adult animals in South Zoo equals 10. The number of adult wolf in Hamilton Farm equals 2. The number of adult deer in South Zoo exists, and its number is greater than 0.

Question: How many adult deer does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Jefferson Circus as d; so d = 2. Define adult wolf in Jefferson Circus as I; so I = d = 2. Define total number of adult animals in Jefferson Circus as T; so T = I + d = 2 + 2 = 4. Define adult fox in South Zoo as l; U = T = 4; so l = 3 + U = 3 + 4 = 7. Define adult deer in South Zoo as x; we don't know its value yet but will find it out later. Define total number of adult animals in South Zoo as u; so u = x + l = x + 7 = x + 7. We know u = 10, so we have x + 7 = 10 and we solve it through the following steps: Simplifying the equation: x + 7 = 10. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of calm road movie in Rêves de Belleville equals the number of futuristic sci-fi movie in Rêves de Belleville. The total number of movies in Festival de Clairmont equals 15. The number of futuristic sci-fi movie in Rêves de Belleville equals 4. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0. The number of calm road movie in Festival de Clairmont equals the sum of the total number of movies in Rêves de Belleville and the number of futuristic sci-fi movie in Rêves de Belleville.

Question: How many futuristic sci-fi movie does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Rêves de Belleville as J; so J = 4. Define calm road movie in Rêves de Belleville as D; so D = J = 4. Define total number of movies in Rêves de Belleville as B; so B = J + D = 4 + 4 = 8. Define calm road movie in Festival de Clairmont as R; so R = B + J = 8 + 4 = 12. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Clairmont as A; so A = x + R = x + 12 = x + 12. We know A = 15, so we have x + 12 = 15 and we solve it through the following steps: Simplifying the equation: x + 12 = 15. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of adult deer in Hamilton Farm exists, and its number is greater than 0. The number of adult deer in Bundle Ranch equals 2. The number of adult racoon in Bundle Ranch equals the total number of adult animals in Hamilton Farm. The number of adult racoon in Jefferson Circus equals the sum of the total number of adult animals in Hamilton Farm and the number of adult deer in Hamilton Farm. The number of adult racoon in Hamilton Farm equals the number of adult deer in Hamilton Farm. The total number of adult animals in Jefferson Circus equals 4. The number of adult deer in Jefferson Circus equals the number of adult deer in Hamilton Farm.

Question: How many adult deer does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult racoon in Hamilton Farm as a; so a = x = x. Define adult deer in Jefferson Circus as C; so C = x = x. Define total number of adult animals in Hamilton Farm as A; so A = a + x = x + x = 2*x. Define adult racoon in Jefferson Circus as u; so u = A + x = 2*x + x = 3*x. Define total number of adult animals in Jefferson Circus as e; so e = u + C = 3*x + x = 4*x. We know e = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of adult parrot in Mayer Aquarium equals 2 plus the number of adult eagle in Mayer Aquarium. The number of adult owl in Jefferson Circus equals the total number of adult animals in Mayer Aquarium. The total number of adult animals in Jefferson Circus equals 12. The number of adult parrot in Jefferson Circus exists, and its number is greater than 0. The number of adult eagle in Mayer Aquarium equals 4. The number of adult owl in South Zoo equals 4 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult owl in Jefferson Circus, and the number of adult eagle in Mayer Aquarium.

Question: How many adult parrot does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in Mayer Aquarium as R; so R = 4. Define adult parrot in Mayer Aquarium as G; w = R = 4; so G = 2 + w = 2 + 4 = 6. Define total number of adult animals in Mayer Aquarium as h; so h = R + G = 4 + 6 = 10. Define adult owl in Jefferson Circus as e; so e = h = 10. Define adult parrot in Jefferson Circus as x; we don't know its value yet but will find it out later. Define total number of adult animals in Jefferson Circus as a; so a = e + x = 10 + x = x + 10. We know a = 12, so we have x + 10 = 12 and we solve it through the following steps: Simplifying the equation: x + 10 = 12. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of adult wolf in Beverly Forest equals the total number of adult animals in Maple Creek. The total number of adult animals in Maple Creek equals 10. The number of adult fox in Beverly Forest equals the sum of the number of adult wolf in Cedar Valley, the number of adult bear in Cedar Valley, the number of adult bear in Beverly Forest, and the number of adult wolf in Maple Creek. The number of adult wolf in Cedar Valley exists, and its number is greater than 0. The number of adult fox in Maple Creek equals the sum of the number of adult bear in Maple Creek and the number of adult wolf in Cedar Valley. The number of adult bear in Cedar Valley equals 2. The number of adult fox in Cedar Valley equals the difference between the number of adult bear in Beverly Forest and the number of adult bear in Cedar Valley. The number of adult bear in Beverly Forest equals 4 times the number of adult bear in Cedar Valley. The number of adult bear in Maple Creek equals 2 plus the number of adult wolf in Cedar Valley. The number of adult wolf in Maple Creek equals the number of adult bear in Maple Creek.

Question: How many adult wolf does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult bear in Maple Creek as h; P = x = x; so h = 2 + P = 2 + x = x + 2. Define adult fox in Maple Creek as k; so k = h + x = x + 2 + x = 2*x + 2. Define adult wolf in Maple Creek as G; so G = h = x + 2. Define total number of adult animals in Maple Creek as H; E = G + k = x + 2 + 2*x + 2 = 3*x + 4; so H = E + h = 3*x + 4 + x + 2 = 4*x + 6. We know H = 10, so we have 4*x + 6 = 10 and we solve it through the following steps: Simplifying the equation: 4*x + 6 = 10. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.


The number of calm road movie in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Festival de Clairmont equals the sum of the number of calm road movie in Festival de Clairmont and the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Festival de Clairmont equals the total number of movies in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals the number of calm road movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define calm road movie in Festival Lumière de Valmont as q; so q = 4. Define intense detective thriller in Festival Lumière de Valmont as T; so T = q = 4. Define total number of movies in Festival Lumière de Valmont as g; so g = q + T = 4 + 4 = 8. Define calm road movie in Festival de Clairmont as x; so x = g = 8. Define intense detective thriller in Festival de Clairmont as H; so H = x + T = 8 + 4 = 12. Define total number of movies in Festival de Clairmont as C; so C = x + H = 8 + 12 = 20. Answer: 20.


The total number of adult animals in Oakridge Riverside equals 17. The number of adult fox in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside and the number of adult racoon in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 4. The number of adult racoon in Oakridge Riverside equals 3 plus the number of adult fox in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 4 plus the number of adult fox in Cedar Valley. The number of adult fox in Cedar Valley exists, and its number is greater than 0. The number of adult racoon in Cedar Valley equals 3. The number of adult wolf in Cedar Valley equals 4 plus the number of adult racoon in Cedar Valley. The number of adult wolf in Pine Ridge equals 3. The number of adult racoon in Pine Ridge equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the number of adult fox in Oakridge Riverside.

Question: How many adult fox does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Oakridge Riverside as J; so J = 4. Define adult racoon in Oakridge Riverside as T; e = J = 4; so T = 3 + e = 3 + 4 = 7. Define adult fox in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult wolf in Oakridge Riverside as C; B = x = x; so C = 4 + B = 4 + x = x + 4. Define total number of adult animals in Oakridge Riverside as N; w = J + T = 4 + 7 = 11; so N = w + C = 11 + x + 4 = x + 15. We know N = 17, so we have x + 15 = 17 and we solve it through the following steps: Simplifying the equation: x + 15 = 17. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of adult crow in Hamilton Farm equals 3. The number of adult blue jay in Hamilton Farm equals the number of adult crow in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 2. The number of adult owl in Bundle Ranch equals 4. The number of adult parrot in Bundle Ranch equals 4 times the number of adult crow in Bundle Ranch. The number of adult crow in Bundle Ranch equals 4. The number of adult parrot in Hamilton Farm equals 3 times the sum of the number of adult parrot in Bundle Ranch, the number of adult blue jay in Bundle Ranch, and the number of adult crow in Bundle Ranch. The number of adult owl in Mayer Aquarium equals 3. The number of adult crow in Mayer Aquarium equals 4 plus the number of adult crow in Hamilton Farm.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult crow in Bundle Ranch as n; so n = 4. Define adult parrot in Bundle Ranch as e; c = n = 4; so e = 4 * c = 4 * 4 = 16. Define adult owl in Bundle Ranch as t; so t = 4. Define adult blue jay in Bundle Ranch as K; so K = 2. Define total number of adult animals in Bundle Ranch as N; X = K + n = 2 + 4 = 6; P = X + e = 6 + 16 = 22; so N = P + t = 22 + 4 = 26. Answer: 26.


The number of adult parrot in Jefferson Circus equals the difference between the number of adult crow in South Zoo and the number of adult parrot in South Zoo. The number of adult crow in Jefferson Circus equals 1. The number of adult parrot in South Zoo equals the number of adult crow in South Zoo. The number of adult owl in Hamilton Farm equals the sum of the number of adult crow in South Zoo, the number of adult parrot in Jefferson Circus, and the number of adult owl in South Zoo. The total number of adult animals in South Zoo equals 96. The number of adult parrot in Hamilton Farm equals 3 plus the difference between the number of adult crow in Jefferson Circus and the number of adult crow in Hamilton Farm. The number of adult owl in South Zoo equals 4 times the number of adult parrot in South Zoo. The number of adult crow in South Zoo equals 4 times the number of adult owl in Jefferson Circus. The number of adult crow in Hamilton Farm equals 2 times the number of adult crow in Jefferson Circus. The number of adult owl in Jefferson Circus exists, and its number is greater than 0.

Question: How many adult owl does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult crow in South Zoo as j; N = x = x; so j = 4 * N = (4) * (x) = 4*x. Define adult parrot in South Zoo as o; so o = j = 4*x. Define adult owl in South Zoo as w; L = o = 4*x; so w = 4 * L = (4) * (4*x) = 16*x. Define total number of adult animals in South Zoo as C; W = w + j = 16*x + 4*x = 20*x; so C = W + o = 20*x + 4*x = 24*x. We know C = 96, so we have 24*x = 96 and we solve it through the following steps: Simplifying the equation: 24*x = 96. Move all terms to one side: 24*x - 96 = 0. Isolate the term with x: 24*x = 96. Divide both sides by 24: x = 96 / 24. Solution: x = 4. Answer: 4.


The number of adult owl in South Zoo equals the sum of the number of adult eagle in South Zoo and the number of adult crow in South Zoo. The number of adult crow in Bundle Ranch equals 3. The number of adult owl in Mayer Aquarium exists, and its number is greater than 0. The number of adult eagle in Mayer Aquarium equals the number of adult owl in Bundle Ranch. The number of adult owl in Bundle Ranch equals 4. The total number of adult animals in South Zoo equals 6. The number of adult eagle in Bundle Ranch equals 2. The number of adult crow in South Zoo equals the number of adult owl in Mayer Aquarium. The number of adult eagle in South Zoo equals 2 times the number of adult owl in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 3 times the number of adult eagle in Bundle Ranch.

Question: How many adult owl does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult eagle in South Zoo as m; a = x = x; so m = 2 * a = (2) * (x) = 2*x. Define adult crow in South Zoo as g; so g = x = x. Define adult owl in South Zoo as P; so P = m + g = 2*x + x = 3*x. Define total number of adult animals in South Zoo as N; z = m + g = 2*x + x = 3*x; so N = z + P = 3*x + 3*x = 6*x. We know N = 6, so we have 6*x = 6 and we solve it through the following steps: Simplifying the equation: 6*x = 6. Move all terms to one side: 6*x - 6 = 0. Isolate the term with x: 6*x = 6. Divide both sides by 6: x = 6 / 6. Solution: x = 1. Answer: 1.


The number of elementary school in Shoreline City exists, and its number is greater than 0. The number of private middle school in Oakbridge City equals 2 plus the number of elementary school in Shoreline City. The number of culinarian school in Oakbridge City equals 1 plus the number of elementary school in Oakbridge City. The total number of schools in Oakbridge City equals 13. The number of private middle school in Clearwater Bay equals 1. The number of elementary school in Clearwater Bay equals the number of culinarian school in Shoreline City. The number of elementary school in Oakbridge City equals the number of private middle school in Oakbridge City. The number of private middle school in Shoreline City equals the number of culinarian school in Oakbridge City. The number of culinarian school in Shoreline City equals 4. The number of culinarian school in Clearwater Bay equals the difference between the number of culinarian school in Shoreline City and the number of private middle school in Clearwater Bay.

Question: How many elementary school does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Shoreline City as x; we don't know its value yet but will find it out later. Define private middle school in Oakbridge City as e; D = x = x; so e = 2 + D = 2 + x = x + 2. Define elementary school in Oakbridge City as r; so r = e = x + 2. Define culinarian school in Oakbridge City as Y; S = r = x + 2; so Y = 1 + S = 1 + x + 2 = x + 3. Define total number of schools in Oakbridge City as f; s = r + e = x + 2 + x + 2 = 2*x + 4; so f = s + Y = 2*x + 4 + x + 3 = 3*x + 7. We know f = 13, so we have 3*x + 7 = 13 and we solve it through the following steps: Simplifying the equation: 3*x + 7 = 13. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.


The number of elementary school in Glenfield City equals 3. The number of elementary school in Brightford equals 1. The number of culinarian school in Brightford equals 1 plus the number of elementary school in Brightford. The number of culinarian school in Glenfield City equals the total number of schools in Brightford.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Brightford as E; so E = 1. Define culinarian school in Brightford as H; i = E = 1; so H = 1 + i = 1 + 1 = 2. Define total number of schools in Brightford as t; so t = H + E = 2 + 1 = 3. Define culinarian school in Glenfield City as K; so K = t = 3. Define elementary school in Glenfield City as c; so c = 3. Define total number of schools in Glenfield City as R; so R = K + c = 3 + 3 = 6. Answer: 6.


The number of adult bear in Cedar Valley equals the number of adult racoon in Cedar Valley. The number of adult fox in Cedar Valley equals 4. The total number of adult animals in Maple Creek equals 23. The number of adult racoon in Cedar Valley equals 1 plus the number of adult fox in Cedar Valley. The number of adult fox in Pine Ridge equals 4. The number of adult racoon in Pine Ridge equals 3. The number of adult fox in Maple Creek equals 3 times the number of adult bear in Pine Ridge. The number of adult racoon in Maple Creek exists, and its number is greater than 0. The number of adult bear in Pine Ridge equals 3. The number of adult bear in Maple Creek equals the sum of the number of adult fox in Maple Creek and the number of adult bear in Pine Ridge.

Question: How many adult racoon does Maple Creek have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Pine Ridge as h; so h = 3. Define adult fox in Maple Creek as Q; d = h = 3; so Q = 3 * d = (3) * (3) = 9. Define adult racoon in Maple Creek as x; we don't know its value yet but will find it out later. Define adult bear in Maple Creek as C; so C = Q + h = 9 + 3 = 12. Define total number of adult animals in Maple Creek as w; s = C + x = 12 + x = x + 12; so w = s + Q = x + 12 + 9 = x + 21. We know w = 23, so we have x + 21 = 23 and we solve it through the following steps: Simplifying the equation: x + 21 = 23. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of elementary school in Oakbridge City equals the difference between the number of public highschool in Clearwater Bay and the number of regional medical school in Oakbridge City. The number of public highschool in Clearwater Bay equals 2 times the number of regional medical school in Oakbridge City. The number of regional medical school in Oakbridge City equals 2. The number of private middle school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of regional medical school in Ruby Bay equals 3. The number of culinarian school in Shoreline City equals the total number of schools in Oakbridge City. The number of public highschool in Riverton City equals 3 plus the number of regional medical school in Ruby Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define regional medical school in Oakbridge City as N; so N = 2. Define public highschool in Clearwater Bay as X; g = N = 2; so X = 2 * g = 2 * 2 = 4. Define elementary school in Oakbridge City as W; so W = X - N = 4 - 2 = 2. Define total number of schools in Oakbridge City as Q; so Q = W + N = 2 + 2 = 4. Define culinarian school in Shoreline City as E; so E = Q = 4. Define total number of schools in Shoreline City as n; so n = E = 4. Answer: 4.


The number of adult wolf in Cedar Valley equals 4. The number of adult deer in Beverly Forest equals 3. The number of adult deer in Cedar Valley equals 2. The number of adult bear in Oakridge Riverside equals 3. The number of adult fox in Pine Ridge equals the sum of the number of adult deer in Beverly Forest and the number of adult fox in Beverly Forest. The number of adult fox in Cedar Valley equals 2. The number of adult wolf in Oakridge Riverside equals 4. The number of adult deer in Pine Ridge equals 4. The number of adult wolf in Beverly Forest equals 1. The number of adult wolf in Pine Ridge equals 4. The number of adult bear in Pine Ridge equals 2 plus the number of adult deer in Pine Ridge. The number of adult fox in Beverly Forest equals the sum of the total number of adult animals in Beverly Forest, the total number of adult animals in Oakridge Riverside, and the number of adult bear in Oakridge Riverside. The number of adult bear in Cedar Valley equals 2 plus the number of adult deer in Cedar Valley. The number of adult bear in Beverly Forest equals 4. The number of adult deer in Oakridge Riverside equals 1. The number of adult fox in Oakridge Riverside equals the sum of the number of adult fox in Cedar Valley, the total number of adult animals in Cedar Valley, the number of adult bear in Cedar Valley, and the number of adult deer in Cedar Valley.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult deer in Cedar Valley as O; so O = 2. Define adult bear in Cedar Valley as i; b = O = 2; so i = 2 + b = 2 + 2 = 4. Define adult wolf in Cedar Valley as Z; so Z = 4. Define adult fox in Cedar Valley as f; so f = 2. Define total number of adult animals in Cedar Valley as M; x = f + i = 2 + 4 = 6; g = x + O = 6 + 2 = 8; so M = g + Z = 8 + 4 = 12. Answer: 12.


The number of adult crow in Hamilton Farm equals the total number of adult animals in Mayer Aquarium. The total number of adult animals in Hamilton Farm equals 20. The number of adult owl in Hamilton Farm equals 4 times the total number of adult animals in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals the number of adult owl in Mayer Aquarium. The number of adult owl in Mayer Aquarium exists, and its number is greater than 0.

Question: How many adult owl does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult crow in Mayer Aquarium as B; so B = x = x. Define total number of adult animals in Mayer Aquarium as S; so S = B + x = x + x = 2*x. Define adult owl in Hamilton Farm as m; s = S = 2*x; so m = 4 * s = (4) * (2*x) = 8*x. Define adult crow in Hamilton Farm as I; so I = S = 2*x. Define total number of adult animals in Hamilton Farm as j; so j = I + m = 2*x + 8*x = 10*x. We know j = 20, so we have 10*x = 20 and we solve it through the following steps: Simplifying the equation: 10*x = 20. Move all terms to one side: 10*x - 20 = 0. Isolate the term with x: 10*x = 20. Divide both sides by 10: x = 20 / 10. Solution: x = 2. Answer: 2.


The number of adult parrot in Jefferson Circus equals 3. The number of adult owl in Jefferson Circus equals the number of adult owl in Mayer Aquarium. The number of adult crow in South Zoo equals 2. The number of adult crow in Mayer Aquarium equals 4 plus the number of adult owl in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 3. The number of adult owl in Mayer Aquarium equals 4 times the number of adult parrot in Jefferson Circus. The number of adult crow in Jefferson Circus equals the number of adult owl in Bundle Ranch. The number of adult owl in Bundle Ranch equals 2. The number of adult blue jay in South Zoo equals 2 times the total number of adult animals in Bundle Ranch. The number of adult blue jay in Mayer Aquarium equals 3 plus the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult owl in Bundle Ranch as L; so L = 2. Define adult blue jay in Bundle Ranch as P; so P = 3. Define total number of adult animals in Bundle Ranch as F; so F = L + P = 2 + 3 = 5. Define adult blue jay in South Zoo as f; b = F = 5; so f = 2 * b = 2 * 5 = 10. Define adult crow in South Zoo as R; so R = 2. Define total number of adult animals in South Zoo as S; so S = R + f = 2 + 10 = 12. Answer: 12.


The number of regional medical school in Shoreline City equals the number of culinarian school in Shoreline City. The number of regional medical school in Clearwater Bay equals 3 times the total number of schools in Shoreline City. The number of culinarian school in Shoreline City equals 3. The number of regional medical school in Riverton City equals the number of culinarian school in Clearwater Bay. The number of elementary school in Clearwater Bay equals the total number of schools in Shoreline City. The number of culinarian school in Riverton City equals the total number of schools in Shoreline City. The number of elementary school in Shoreline City equals 4 times the number of culinarian school in Shoreline City. The number of culinarian school in Clearwater Bay equals 4. The number of elementary school in Riverton City equals 4 plus the number of regional medical school in Shoreline City.

Question: How many regional medical school does Clearwater Bay have?

Solution: Define culinarian school in Shoreline City as G; so G = 3. Define elementary school in Shoreline City as V; C = G = 3; so V = 4 * C = 4 * 3 = 12. Define regional medical school in Shoreline City as R; so R = G = 3. Define total number of schools in Shoreline City as J; F = V + R = 12 + 3 = 15; so J = F + G = 15 + 3 = 18. Define regional medical school in Clearwater Bay as x; e = J = 18; so x = 3 * e = 3 * 18 = 54. Answer: 54.


The number of solemn period drama in Northwood Movie Festival equals 4. The number of solemn period drama in West Sahara Movie Festival equals 3 times the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of intense detective thriller in Verdi Movie Festival equals 2 times the difference between the number of intense detective thriller in Northwood Movie Festival and the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals 4 plus the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals 4.

Question: How many solemn period drama does Verdi Movie Festival have?

Solution: Define calm road movie in West Sahara Movie Festival as H; so H = 3. Define solemn period drama in West Sahara Movie Festival as s; W = H = 3; so s = 3 * W = 3 * 3 = 9. Define intense detective thriller in West Sahara Movie Festival as n; so n = 4. Define total number of movies in West Sahara Movie Festival as d; U = H + n = 3 + 4 = 7; so d = U + s = 7 + 9 = 16. Define solemn period drama in Verdi Movie Festival as P; so P = d - H = 16 - 3 = 13. Answer: 13.


The total number of adult animals in South Zoo equals 24. The number of adult eagle in South Zoo equals the sum of the number of adult parrot in South Zoo and the number of adult crow in Mayer Aquarium. The number of adult crow in Hamilton Farm equals 2. The number of adult parrot in Mayer Aquarium equals the number of adult crow in South Zoo. The number of adult crow in Mayer Aquarium exists, and its number is greater than 0. The number of adult eagle in Hamilton Farm equals the number of adult crow in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 3. The number of adult crow in South Zoo equals 3 times the number of adult crow in Mayer Aquarium. The number of adult parrot in Hamilton Farm equals 2. The number of adult parrot in South Zoo equals the number of adult crow in Mayer Aquarium.

Question: How many adult crow does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult crow in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult crow in South Zoo as Y; v = x = x; so Y = 3 * v = (3) * (x) = 3*x. Define adult parrot in South Zoo as n; so n = x = x. Define adult eagle in South Zoo as z; so z = n + x = x + x = 2*x. Define total number of adult animals in South Zoo as S; J = n + z = x + 2*x = 3*x; so S = J + Y = 3*x + 3*x = 6*x. We know S = 24, so we have 6*x = 24 and we solve it through the following steps: Simplifying the equation: 6*x = 24. Move all terms to one side: 6*x - 24 = 0. Isolate the term with x: 6*x = 24. Divide both sides by 6: x = 24 / 6. Solution: x = 4. Answer: 4.


The number of adult bear in Bundle Ranch equals 2 plus the difference between the number of adult deer in South Zoo and the total number of adult animals in Hamilton Farm. The number of adult fox in Hamilton Farm equals 2 times the number of adult deer in Bundle Ranch. The number of adult bear in Hamilton Farm equals the number of adult deer in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals 2 plus the number of adult deer in Bundle Ranch. The number of adult deer in Mayer Aquarium equals the number of adult wolf in Bundle Ranch. The number of adult deer in Hamilton Farm equals 1. The number of adult fox in Bundle Ranch equals 1. The number of adult bear in South Zoo equals the sum of the number of adult wolf in South Zoo and the number of adult deer in South Zoo. The number of adult bear in Mayer Aquarium equals the sum of the number of adult fox in South Zoo, the number of adult wolf in South Zoo, and the number of adult deer in South Zoo. The number of adult deer in South Zoo equals 1. The number of adult wolf in South Zoo equals the number of adult deer in South Zoo. The number of adult fox in South Zoo equals the number of adult deer in South Zoo. The number of adult fox in Mayer Aquarium equals 3 times the difference between the number of adult wolf in Bundle Ranch and the number of adult deer in Bundle Ranch. The number of adult wolf in Hamilton Farm equals 4. The number of adult deer in Bundle Ranch equals 3. The number of adult wolf in Mayer Aquarium equals 1.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult deer in South Zoo as q; so q = 1. Define adult wolf in South Zoo as x; so x = q = 1. Define adult bear in South Zoo as z; so z = x + q = 1 + 1 = 2. Define adult fox in South Zoo as d; so d = q = 1. Define total number of adult animals in South Zoo as c; k = x + q = 1 + 1 = 2; t = k + d = 2 + 1 = 3; so c = t + z = 3 + 2 = 5. Answer: 5.


The total number of adult animals in Oakridge Riverside equals 34. The number of adult parrot in Maple Creek equals 4 times the total number of adult animals in Beverly Forest. The number of adult parrot in Beverly Forest exists, and its number is greater than 0. The number of adult eagle in Oakridge Riverside equals 2 plus the number of adult parrot in Maple Creek. The number of adult owl in Maple Creek equals 4. The number of adult eagle in Maple Creek equals the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 4.

Question: How many adult parrot does Beverly Forest have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Beverly Forest as H; so H = 4. Define adult parrot in Beverly Forest as x; we don't know its value yet but will find it out later. Define total number of adult animals in Beverly Forest as y; so y = H + x = 4 + x = x + 4. Define adult parrot in Maple Creek as B; e = y = x + 4; so B = 4 * e = (4) * (x + 4) = 4*x + 16. Define adult eagle in Oakridge Riverside as h; R = B = 4*x + 16; so h = 2 + R = 2 + 4*x + 16 = 4*x + 18. Define total number of adult animals in Oakridge Riverside as g; so g = h = 4*x + 18. We know g = 34, so we have 4*x + 18 = 34 and we solve it through the following steps: Simplifying the equation: 4*x + 18 = 34. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of regional medical school in Hawkesbury equals the number of private middle school in Hawkesbury. The number of private middle school in Hawkesbury equals 2. The number of elementary school in Brightford equals the sum of the total number of schools in Hawkesbury, the number of private middle school in Glenfield City, the number of regional medical school in Hawkesbury, and the number of regional medical school in Glenfield City. The number of regional medical school in Brightford equals the sum of the number of regional medical school in Hawkesbury, the total number of schools in Glenfield City, and the total number of schools in Hawkesbury. The number of regional medical school in Glenfield City equals 3 plus the total number of schools in Hawkesbury. The number of private middle school in Brightford equals the number of regional medical school in Hawkesbury. The number of private middle school in Glenfield City equals 2.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Hawkesbury as B; so B = 2. Define regional medical school in Hawkesbury as t; so t = B = 2. Define total number of schools in Hawkesbury as l; so l = B + t = 2 + 2 = 4. Define regional medical school in Glenfield City as H; k = l = 4; so H = 3 + k = 3 + 4 = 7. Define private middle school in Glenfield City as i; so i = 2. Define total number of schools in Glenfield City as m; so m = i + H = 2 + 7 = 9. Answer: 9.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 1 plus the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in West Sahara Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the number of futuristic sci-fi movie in West Sahara Movie Festival. The total number of movies in Golden Banana Movie Festival equals 29. The number of calm road movie in West Sahara Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 3 times the number of futuristic sci-fi movie in West Sahara Movie Festival.

Question: How many futuristic sci-fi movie does West Sahara Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Golden Banana Movie Festival as H; r = x = x; so H = 1 + r = 1 + x = x + 1. Define calm road movie in Golden Banana Movie Festival as F; U = x = x; so F = 3 * U = (3) * (x) = 3*x. Define upbeat metropolis comedy in Golden Banana Movie Festival as T; so T = F = 3*x. Define total number of movies in Golden Banana Movie Festival as e; l = T + F = 3*x + 3*x = 6*x; so e = l + H = 6*x + x + 1 = 7*x + 1. We know e = 29, so we have 7*x + 1 = 29 and we solve it through the following steps: Simplifying the equation: 7*x + 1 = 29. Move all terms to one side: 7*x - 28 = 0. Isolate the term with x: 7*x = 28. Divide both sides by 7: x = 28 / 7. Solution: x = 4. Answer: 4.


The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The total number of adult animals in South Zoo equals 26. The number of adult racoon in Jefferson Circus equals the number of adult wolf in Jefferson Circus. The number of adult deer in Jefferson Circus equals 2. The number of adult racoon in South Zoo equals 2 plus the number of adult wolf in Mayer Aquarium. The number of adult wolf in South Zoo equals the sum of the number of adult racoon in South Zoo and the number of adult wolf in Mayer Aquarium. The number of adult deer in South Zoo equals the number of adult wolf in South Zoo. The number of adult wolf in Jefferson Circus equals 3. The number of adult deer in Mayer Aquarium equals 2 times the number of adult wolf in Jefferson Circus. The number of adult racoon in Mayer Aquarium equals 2 plus the difference between the number of adult wolf in Jefferson Circus and the number of adult deer in Mayer Aquarium.

Question: How many adult wolf does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult racoon in South Zoo as N; r = x = x; so N = 2 + r = 2 + x = x + 2. Define adult wolf in South Zoo as W; so W = N + x = x + 2 + x = 2*x + 2. Define adult deer in South Zoo as d; so d = W = 2*x + 2. Define total number of adult animals in South Zoo as w; F = W + N = 2*x + 2 + x + 2 = 3*x + 4; so w = F + d = 3*x + 4 + 2*x + 2 = 5*x + 6. We know w = 26, so we have 5*x + 6 = 26 and we solve it through the following steps: Simplifying the equation: 5*x + 6 = 26. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.


The number of adult eagle in Cedar Valley equals 1 plus the number of adult eagle in Beverly Forest. The number of adult blue jay in Pine Ridge equals the number of adult eagle in Cedar Valley. The number of adult owl in Cedar Valley equals 4. The number of adult eagle in Oakridge Riverside equals 4 times the sum of the number of adult eagle in Cedar Valley and the number of adult eagle in Beverly Forest. The number of adult eagle in Beverly Forest equals 3. The number of adult parrot in Beverly Forest equals the number of adult parrot in Cedar Valley. The number of adult eagle in Pine Ridge equals the number of adult blue jay in Beverly Forest. The number of adult crow in Maple Creek equals the total number of adult animals in Oakridge Riverside. The number of adult parrot in Cedar Valley equals 2 times the number of adult owl in Cedar Valley. The number of adult crow in Pine Ridge equals the sum of the number of adult parrot in Cedar Valley, the number of adult owl in Cedar Valley, and the number of adult owl in Oakridge Riverside. The number of adult crow in Beverly Forest equals the sum of the number of adult blue jay in Beverly Forest, the number of adult owl in Oakridge Riverside, the number of adult eagle in Cedar Valley, and the number of adult owl in Cedar Valley. The number of adult blue jay in Beverly Forest equals the number of adult owl in Cedar Valley. The number of adult owl in Oakridge Riverside equals 4.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult eagle in Beverly Forest as P; so P = 3. Define adult eagle in Cedar Valley as R; d = P = 3; so R = 1 + d = 1 + 3 = 4. Define adult eagle in Oakridge Riverside as S; e = R + P = 4 + 3 = 7; so S = 4 * e = 4 * 7 = 28. Define adult owl in Oakridge Riverside as q; so q = 4. Define total number of adult animals in Oakridge Riverside as I; so I = S + q = 28 + 4 = 32. Answer: 32.


The number of regional medical school in Oakbridge City equals the number of elementary school in Oakbridge City. The number of elementary school in Clearwater Bay equals 3. The number of public highschool in Riverton City equals the sum of the total number of schools in Oakbridge City and the number of regional medical school in Oakbridge City. The number of regional medical school in Clearwater Bay equals the number of elementary school in Oakbridge City. The number of elementary school in Oakbridge City exists, and its number is greater than 0. The number of public highschool in Oakbridge City equals the number of elementary school in Oakbridge City. The total number of schools in Riverton City equals 12.

Question: How many elementary school does Oakbridge City have?

Solution: The question is difficult, so we use equations to solve it. Define elementary school in Oakbridge City as x; we don't know its value yet but will find it out later. Define public highschool in Oakbridge City as M; so M = x = x. Define regional medical school in Oakbridge City as c; so c = x = x. Define total number of schools in Oakbridge City as i; B = c + M = x + x = 2*x; so i = B + x = 2*x + x = 3*x. Define public highschool in Riverton City as v; so v = i + c = 3*x + x = 4*x. Define total number of schools in Riverton City as I; so I = v = 4*x. We know I = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of elementary school in Clearwater Bay equals 3. The number of elementary school in Riverton City equals 3. The number of elementary school in Ruby Bay equals 3 plus the number of elementary school in Riverton City. The number of private middle school in Riverton City equals the number of elementary school in Clearwater Bay. The number of culinarian school in Riverton City equals the sum of the number of elementary school in Clearwater Bay and the number of private middle school in Clearwater Bay. The number of private middle school in Ruby Bay equals the sum of the number of elementary school in Ruby Bay and the number of elementary school in Riverton City. The number of private middle school in Clearwater Bay equals 2 plus the number of elementary school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of culinarian school in Ruby Bay equals the number of elementary school in Riverton City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define elementary school in Riverton City as m; so m = 3. Define elementary school in Ruby Bay as B; p = m = 3; so B = 3 + p = 3 + 3 = 6. Define private middle school in Ruby Bay as L; so L = B + m = 6 + 3 = 9. Define culinarian school in Ruby Bay as W; so W = m = 3. Define total number of schools in Ruby Bay as g; c = W + B = 3 + 6 = 9; so g = c + L = 9 + 9 = 18. Answer: 18.