$\lceil (3.6)^2 \rceil = \lceil 12.96 \rceil = 13$ because the least integer greater than $12.96$ is $13$. $( \lceil 3.6 \rceil ) ^2 = 4^2 = 16$ because the least integer greater than $3.6$ is $4$. Therefore, the answer is $13-16=\boxed{-3}$.
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Evaluate $\lceil (3.6)^2 \rceil - ( \lceil 3.6 \rceil ) ^2$.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
-3
Evaluate $\lceil (3.6)^2 \rceil - ( \lceil 3.6 \rceil ) ^2$.
test