At $t = 2,$ $(x,y) = (2^3 + 7, -3 \cdot 2^2 - 6 \cdot 2 - 5) = \boxed{(15,-29)}.$
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
A curve is parameterized by
\[(x,y) = (t^3 + 7, -3t^2 - 6t - 5).\]Find the point the curve passes through at $t = 2.$
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
(15,-29)
A curve is parameterized by
\[(x,y) = (t^3 + 7, -3t^2 - 6t - 5).\]Find the point the curve passes through at $t = 2.$
test