



def    lowerCamelCase_(lowerCamelCase_    ,   lowerCamelCase_    ) ->       str:
						if number < 0 or shift_amount < 0:
												raise ValueError("both inputs must be positive integers"    )

						UpperCAmelCase         =     str(bin(lowerCamelCase_    )    )
						binary_number += "0" * shift_amount
						return binary_number

def    lowerCamelCase_(lowerCamelCase_    ,   lowerCamelCase_    ) ->       str:
						if number < 0 or shift_amount < 0:
												raise ValueError("both inputs must be positive integers"    )

						UpperCAmelCase         =     str(bin(lowerCamelCase_    )    )[2:]
						if shift_amount >= len(lowerCamelCase_    ):
												return "0b0"
						UpperCAmelCase         =     binary_number[: len(lowerCamelCase_    ) - shift_amount]
						return "0b" + shifted_binary_number

def    lowerCamelCase_(lowerCamelCase_    ,   lowerCamelCase_    ) ->       str:
						if number >= 0:  # Get binary representation of positive number
												UpperCAmelCase         =     "0" + str(bin(lowerCamelCase_    )    ).strip("-"    )[2:]
						else:  # Get binary (2's complement) representation of negative number
												UpperCAmelCase         =     len(bin(lowerCamelCase_    )[3:]    )  # Find 2's complement of number
												UpperCAmelCase         =     bin(abs(lowerCamelCase_    ) - (1 << binary_number_length)    )[3:]
												UpperCAmelCase         =     (
												    "1" + "0" * (binary_number_length - len(lowerCamelCase_    )) + binary_number
												)

						if shift_amount >= len(lowerCamelCase_    ):
												return "0b" + binary_number[0] * len(lowerCamelCase_    )
						return (
						    "0b"
						    + binary_number[0] * shift_amount
						    + binary_number[: len(lowerCamelCase_    ) - shift_amount]
						)


if __name__ == "__main__":
		import doctest

		doctest.testmod()








from __future__ import annotations

def    lowerCamelCase_(lowerCamelCase_    ) ->       int:
						UpperCAmelCase         =     len(lowerCamelCase_    ) // 2

						# choose the middle 3 elements
						UpperCAmelCase         =     lst[m - 1 : m + 2]

						# if middle element is peak
						if three[1] > three[0] and three[1] > three[2]:
												return three[1]

						# if increasing, recurse on right
						elif three[0] < three[2]:
												if len(lst[:m]    ) == 2:
																		m -= 1
												return peak(lst[m:]    )

						# decreasing
						else:
												if len(lst[:m]    ) == 2:
																		m += 1
												return peak(lst[:m]    )


if __name__ == "__main__":
		import doctest

		doctest.testmod()



