is it okay to use it on my laser even if the battery that came with it said it had 3.7 volts and this one is 3.6 volts?
1563700
Should be fine. It might not last as long or be as bright, but I've been using it in my surefire flashlight and still on first charge and I use it quite a bit at work
2022825
you can use any 18 volt milwaukee battery on your drill. The 3.0 is a 3 amp., the 4.0 is a 4 amp. The batteries are the same except the 4.0 amp is 1 amp stronger. You can always go to milwaukeetool.com they can answer any questions you may have. That's where I go to with my questions. Who would know better than the one who makes the tool? I have the same drill and I use the 4.0 battery. I hope this helps!
2101547
I have owned the cold laser for over a year... I use it constantly.. I have not had any problem with the battery.
2058623
Yes , I had Dewalt heated jacket 20 v . I used my new 4amps battery on my jacket . It is last longer than 3amps battery
991631
The mAh does not matter, but I am unsure what the 2.6 means. As long as it is 3.7V, it should work.
2136235
That is what I got it for. It works great for the bullet. I have four of them. I did recently learn that since it is 15v PoE that it is not good for most other PoE devices. The standard is 48v.
636602
You should have no problems with that battery. I hooked up the light to a 12V supply I have. The light uses 0.8A.
1819851
The laser is &lt; 1mW 650 nm (red) diode module. It was the only real negative - the rest works great. I recently replaced the laser diode module with a 5 mW 650 nm laser module. It's not that difficult to do but not for the faint of heart (requires soldering and cutting of a small piece of plastic with a knife). There isn't much space so a small laser diode module is required (about 6 mm in diameter). I considered a green laser module but they are expensive, have different voltage requirements (this is a 3V unit), and the power draw is about 10x that of a red diode module.
1311741
It is a 14.4 volt battery. I would think this particular voltage battery is correct for your type drill. Hope this helps.
74994
The battery is a CR2 3 volt battery. Depending on how much you use the light it should last many months. I have mine on a Glock 19 that I use for home defense as a night stand gun and the battery lasted over a year. I would definitely recommend this light. Great price. Great quality.
1780707
Unlikely as the 3.6V battery is slightly larger in size than AA batteries, both in width, and more importantly, in length. It is not a great difference, but most likely enough to make it too large for your flashlight.
337645
1.5v primary lithium should be fine. Don't use the 3.7v but I don't have any to test for you. Check in the candlepower forum's to get a more knowledgable answer. Don't want you to fry your light on the count of me. Those guys over at the forums are very knowledgable with this sort of thing.
2031036
Well if the gun takes an 11.1 volts battery and fits inside the gun, no problem. but you have to find out the voltage in the gun first.
2204079
It should work fine. The laser is mounted under the barrel not off to the side. Also, the on button can be activated from either side. Off is in the middle. I really like mine now that it's zeroed in. It takes a few rounds to get it there but it seems to hold well so far. I haven't had any problems like,the other person who answered.
987150
I don't know for sure but I replaced my battery for exercise bike and the battery looked similar to the one I had but had a different number. It worked just fine. It was six volts with 2.5 A but it's number was 9223w. That was different than the one I replaced and as I say it worked fine.
18977
The LaserLyte target is sensitive to the amount of light hitting it. If you turn a light on that is too close to the target it won't work right. The CT lasers are fired by 3 volt batteries, the LaserLyte lasers use 1.5 volt. I would not expect the target to work with a 3 volt laser and you could burn it out.
1138580
Yes if the go over 3.72V then it will compromise the battery and it will explode or fail.