Amps for this water heater?
1112998
Hi Karen, From what i've learned You can calculate amps from watts and volts. So the amps are equal to watts divided by volts. 1650watts/120volts=13.75 amps
1901935
I think there is a horsepower requirement. Look at your pump and compare this to the spec for the heater.
381587
Dont know.... bought this as a gift ...I never recieved it .... but I've done enough Appliance repairs to know that 1500 Watts translatesto 15 Amperes: +/- oneAmp, and many times a low setting is about half that..... Hair Dryers, esp.......
890548
Yes and with ease. A water heater draws many more amps when both elements are on and this switch works great for that...............
894513
Sorry but this is not the set we bought. Don't know if this links will help you but it's worth a try. Here's the best deal (if the gauss readings are accurate)Main one for the house inlet:http://magneticwatertech.com/Medium-Size-Perfect-Mid-Size-w-Extra-Power-PER-SET-OF-2-M-10426.htmHere's the one for the water heater:http://magneticwatertech.com/Duplex-Model-Magnetic-Water-Softener-2X-Power-Great-For-Heaters-D-10546.htm
2284356
Math: Amps = Watts / Volts. 7500 Watts / 120 Volts = 750 / 12 = approx 62 Amps. BUT! My guess is that this is a 30 Amp balanced (2-sided) circuit system. That means you could get 30 Amps from one side & 30 Amps from the other side, yielding a total of 60 Amps of 120 Volt power, but only 30 amps each side of the output circuit. Then the most you can feed a single appliance is 30 Amps. Then it will not feed 50 amps 120 Volts to an appliance. And also it will feed only 30 Amps at 240 volts. If you had two separate heaters to your hot tub, each taking 25 Amps at 120 Volts, you could certainly run both heaters to get a total of 50 amp heating. But do you have a 50 amp 240 Volt hot tub? if so, that means 50 x 240 = 12,000 Watts.
25433
The Owners Manual and the Installation Manual are very thorough but don't identity the AMPS. You can search them on the Hayward web site in case I missed it.
743379
watt = amp * voltThis unit reads 120vac/15A.120 volts alternating current * 15 ampere = 1800 watts.It worked great this past winter for a 6' long by 3' wide by 2' deep oval fish pond heater.
204058
I threw the unit out, so I can't verify the amperage rating. I was running a 38/4 hp swamp cooler with it and had no problems running the motor. It was the temperature settings that were the problem. You can probably find the amp rating at the LuxPro web site.
1623420
I have not used it in a while. As I recall, 2 amps to get it started 5 amps to make it run nice
1454745
I'm pretty sure it's a 750 watt heater and since it's a resistive load the AC power factor is 1. That translates to a little less than 7 amps at 120 Volts (US).
809898
12.5 amps or less. Depends on the setting. The quality on this unit is atypical of Friedrich units. This one's made in china. Poor quality compared to the USA made units. I would not buy it again. Too expensive to send back or have serviced.
298267
I pull at least 40 amps through mine 24/7 during winter. Large instant water heater. To heat a detached garage floor. Works great!
719656
I do not know where to look for the amp number, did you look at the spec info on the products page?
1956988
1,3 amps, nothing important since airflow is quite large operating time is pretty short for airbeds even a serious 10ft dinghy.
621186
It recommended that it be a 20 amp. As to whether that has to be dedicated or not, I don't know, but I know that on my breaker, it is on its own circuit. I think the heater takes a fair amount of energy so it should be on its own.
1841585
Assuming you live in the US and you are using a resistive heater (most likely), 120V (A) 15 Resistive Amps (copied from product description), P=IV, 120*15 = 1800. Seems good to go!