how much power can each cell generate , voltage and current? why the seller is not clarifying this critical info. about his product ?
1670813
Hi I bought this kit and the specs for the cells is the following:Cell Specifications: Average Power (Watts): 1.75 Wp Average Current (Amps): 3.5 Imax Average Voltage (Volts): 0.5 Vmax Thickness 200 ìm = 0.2 mm Exact dimension: 3 1/4 inches x 6 inches, or 80 mm by 150 mm Weight: Just above 6 grams, or 0.2 oz.
1670814
I'm glen I am getting 3.5 amps and .55 volts depending on sun intensity per cell
1670815
Hi I bought this kit and the specs for the cells is the following: Cell Specifications: Average Power (Watts): 1.75 Wp Average Current (Amps): 3.5 Imax Average Voltage (Volts): 0.5 Vmax Thickness 200 m = 0.2 mm Exact dimension: 3 1/4 inches x 6 inches, or 80 mm by 150 mm Weight: Just above 6 grams, or 0.2 oz.
114092
Call the manufacturer and get them to tell you exactly how much current it draws when running. Then you'll have to do the math. Everyone's power company charges a little bit different amount per kilowatt hour.
1353335
The cells do not appear to have any external components. They do not have any wires either. The front surface is coated with a thin rigid clear material. The rear surface has solder terminals. I have installed them in an outdoor application about a month ago (july 2014) and they are still functioning as expected. Each of my cells is driving a network of 4 microprocessors. In full sun typically they output about 200 ma @5.1 volts. With sun behind a dense cloud, the output current drops to about 60 ma @ 2.2 volts.
1207496
if you use 2.4Ahr batts x 4 @ 1.2vdc each thats 4.8vdc 2.4Ahr.... (yes the charger actually uses 2.4vdc x 4.8Ahr) theres switching losses and controller losses in getting it up to 5vdc(20% ?) and your phones batt of 1.3Ahr also has losses in charging electronics(20% ?) as well as the battery losses itself(???)....... no one thought you could move and change power without loss.. did they? but still ~50% loss seems a little high... mabey it can charge it ~1.3 times? thats more like 20% loss on both devices as you might expect from cheap consumer goods
524540
Your question needs to be clearer - do you mean physical dimensions, voltage, capacity? Are you thinking of common batteries, such as AA, C, D, etc., or are you willing to use the less common ones like lithium coin cells or LiPos? How long would you like these to light before the battery is depleted? The community is happy to help you, but you need to provide more info on your requirements and limitations.
700923
First, the answer is NOT 500ma (.5) as someone else replied. That is the no-load idle current, NOT the MAXIMUM current. While I don't see an official answer, based on the claimed 87% efficiency, the maximum load and surge, and a battery voltage estimate of 13 volts, a little rough math gives us a possible full load current of a bit over 132 amps, with a possible surge current reaching twice that number. Keep in mind these are just some quick back of the napkin figures, and are not a substitute for the manufacturer's published rating. BOTTOM LINE: Contact them before wiring it, I'm just somebody on the Internet making unreliable wild-eyed claims about electricity.
291945
They are probably overrated, but 1000 mha is 1amp for 1 hour. that is how long the battery will provide 1 amp worth of energy. I would consider this rating useless as there is no energy draw stated for most electronics.
704676
I never really measured it, but I'm sure it is in the mW. I powered a whole circuit board with a micro-controller and off a car battery adapter stepped down to 5 volts. You can also look up the specs on it and it should give you the power ratings. Nice unit!
836899
The claim is this unit uses the standard 18650 Lithium Ion Power Cell which is nominally rated at 2800 mAh each (x4 = 11200mAh). Obviously the only question is the quality of the cells used in this product. Sorry I do not have the means to verify the rating but compared to another power pack (rated at 8800mAh) I previously used, this one lasts twice as long.
239846
This is a 6 cell battery with 1500mamphr of power. My laptop is used as a desk top so I don't stress battery as it is normally plugged in. However when old battery failed I had to remove it to avoid error msgs. This was very low priced solution for my needs.
1036952
I installed mine recently, and measured the power, but not the current directly. In standby, the KillAWatt shows 0W, and powered it draws 4.7W. This includes a small wall wart PS, with the illuminator attached by a 100' siamese cable. These numbers are close to what gth posted, so I'd rely on his more precise numbers.
1492485
We do not include it. We use only high quality new cells that have negligible nighttime current loss. More power is lost across the diode.If you still want one contact us and we will send it for free. rich j
422720
you are correct. the more deep cell batteries you have the more you can convert to elec. you will also need and inverter to change the dc power to ac. power. i have 8 of these panels and 9 deep cell batteries, and a 3600ac converter. this allows me to power my computer, printer, monitor, tv, and vcr/dvd player. for 4-5 hrs. the queastion is how much do you want to power?
1438474
Probably more than enough. A laptop is typically somewhere around 90-140 watts. Charging a phone through the USB port will draw up to 2.1 amps @ 5 volts = 10.5 watts. I have no idea on the printer, but it's certainly less than the remaining 250 or so watts. Assuming it's an inkjet, that is, and not a laser printer.
1530900
Let me add, you can go to hisgadget.com, call them and ask for the the number for their tech support for oxyled lamps. Then call that guy and ask him your question. It is possible they may have tested it or have a more scientific estimate based on battery capacity and power consumption. If you get to the right person they actually know their stuff.
2108538
if I recall correctly its .5v at 3.6A which would set it at 1.8 watts per cell.
700924
First, the answer is NOT 500ma (.5) as someone else replied. That is the no-load idle current, NOT the MAXIMUM current. While I don't see an official answer, based on the claimed 87% efficiency, the maximum load and surge, and a battery voltage estimate of 13 volts, a little rough math gives us a possible full load current of a bit over 132 amps, with a possible surge current reaching twice that number. Keep in mind these are just some quick back of the napkin figures, and are not a substitute for the manufacturer's published rating. BOTTOM LINE: Contact them before wiring it, I'm just somebody on the Internet making unreliable wild-eyed claims about electricity. First, the answer is NOT 500ma (.5) as someone else replied. That is the no-load idle current, NOT the MAXIMUM current. While I don't see an official answer, based on the claimed 87% efficiency, the maximum load and surge, and a battery voltage estimate of 13 volts, a little rough math gives us a possible full load current of a bit over 132 amps, with a possible surge current reaching twice that number. Keep in mind these are just some quick back of the napkin figures, and are not a substitute for the manufacturer's published rating. BOTTOM LINE: Contact them before wiring it, I'm just... » Read More First, the answer is NOT 500ma (.5) as someone else replied. That is the no-load idle current, NOT the MAXIMUM current. While I don't see an official answer, based on the claimed 87% efficiency, the maximum load and surge, and a battery voltage estimate of 13 volts, a little rough math gives us a possible full load current of a bit over 132 amps, with a possible surge current reaching twice that number. Keep in mind these are just some quick back of the napkin figures, and are not a substitute for the manufacturer's published rating. BOTTOM LINE: Contact them before wiring it, I'm just somebody on the Internet making unreliable wild-eyed claims about electricity. « Show Less