how many moles of salt are produced in the reaction?
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Multiply the resulting number by the number of grams per mole of product to find the mass of product able to be produced by the given amount of reactant. There are 2.1749 moles of NaCl and one mole equals 58.243 grams. 2.1749 × 58.243 = 126.67, so the 50.000 g of Na used in the reaction can create 126.67 g of NaCl.
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So, one mole of water (6.022 x 10 23 molecules) has a mass of 18.02 g. One mol of NaCl (6.02 x1023 formulas) has a mass of 58.44 g.
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['Multiply the volume by the density to get the mass.', 'Divide the mass by the molar mass to get the number of moles.']
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One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions).
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['Write the chemical equation.', 'Calculate the moles of product from the first reactant.', 'Calculate the moles of product from the second reactant.', 'Identify the limiting reactant and the excess reactant.', 'Calculate the mass of excess reactant used up.', 'Calculate the mass of unused excess reactant.']
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Reactions of Acids and Bases A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl.
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One mole equals the molar mass of the solute which is 58.4538 grams. Divide the mass of the solute by the molar mass to get the number of moles of solute.
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From the Periodic Table you can see that Na is 22.99 g/mole and Cl is 35.45 g/mole. This makes NaCl 22.99 + 35.45 = 58.44 g/mole, and 100g of NaCl about 100/58.44 ~ 1.711 moles.
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So 1 mole of NaCl weighs 58.5g. So now we need to convert grams into moles by dividing mass in grams by the mass of 1 mole. This means that in 1dm3 of solution there must be 1 mole of sodium ions. The number of particles in 1 mole is given by the Avogadro Constant which is equal to 6.02x1023mol−1 .
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Therefore it would take . 25 moles of sulfuric acid to react with . 5 moles of sodium hydroxide.
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The reaction is shown like this. If 6 moles of hydrogen react with nitrogen 4 moles of ammonia produced.
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A balance chemical equation shows the ratio in which substances react and are produced. This is called the stoichiometry of a reaction. This balanced chemical equation shows that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to form 1 mole of magnesium chloride and 1 mole of hydrogen.
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Answer : The number of moles of water produced are, 4.4 moles. By the stoichiometry we can say that, 2 moles of hydrogen gas react with 1 mole of oxygen gas to give 2 moles of water as a product.
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Divide the mass of your anhydrous (heated) salt sample by the molar mass of the anhydrous compound to get the number of moles of compound present. In our example, 16 grams / 160 grams per mole = 0.1 moles. Divide the mass of water lost when you heated the salt by the molar mass of water, roughly 18 grams per mole.
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Answer and Explanation: In the above reaction, 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas. Therefore, 2 moles of nitrogen gas will react with 3×2=6 3 × 2 = 6 moles of hydrogen gas.
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A 1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution. Hence, a 1M solution of NaCl contains 58.44 g.
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A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.