how to find how many moles are needed to react?
73427
Determine the number of moles needed to react by multiplying by moles of the known substance by the stoichiometric ratio of the unknown substance to the known substance.
1018336
['The concentration of reactant decreases linearly with time.[ A]t = [A]0 - kt.', 'The time required for the reaction to be complete, i.e., time at which [A] is zero. tcompletion = [A]0/k = (Initial concentration)/(Rate constant)', 'The units of k are mol L-1 time-1.']
339718
To find the number of moles in a sample, simply weigh it and divide the weight by the molecular weight. The quotient is equal to the number of moles.
785927
The ratio of Cl2 to NaCl is 1:2, so for every mole of Cl2 that reacts, two moles of NaCl will be produced. 0.35458 × 2 = 0.70916 moles of NaCl. Multiply the resulting number by the number of grams per mole of product to find the amount of product able to be produced by the second reactant.
206170
Divide Grams by Grams per Mole Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749. 2.1749 moles of Na are used in this reaction.
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['Calculate the moles of HCl needed. ... ', 'Calculate the mass of HCl Needed. ... ', 'Calculate the mass of solution required.']
315636
['Step 1: Calculate the number of moles of OH-.', 'Molarity = moles/volume.', 'moles = Molarity x Volume.', 'moles OH- = 0.02 M/100 milliliters.', 'moles OH- = 0.02 M/0.1 liters.', 'moles OH- = 0.002 moles.']
330769
['If 1 mole of HCl or NaOH gives you 1 mole of H2O , then the number of moles in H2O is: [ 1÷1×1 ] = 1 mole.', 'Now you have to find out the molar mass (M) of water ( H2O ). ... ', 'Therefore the molar mass (M) of H2O is: ... ', 'Last step, find the mass (m) of water.']
114955
Avogadro's number is a very important relationship to remember: 1 mole = 6.022×1023 6.022 × 10 23 atoms, molecules, protons, etc. To convert from moles to atoms, multiply the molar amount by Avogadro's number. To convert from atoms to moles, divide the atom amount by Avogadro's number (or multiply by its reciprocal).
508239
Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation: 3N2H4(l)→4NH3(g)+N2(g) 2.6mol N2H4.
311257
Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749. 2.1749 moles of Na are used in this reaction.
494819
First, determine the mass of each of the elements in 100 g of the substance. Next, determine how many moles there are of each element in 100 g of the substance by using the molar mass of each element. Divide each one by the smallest number of moles. So, the empirical formula is CH2Cl.
478231
Divide Grams by Grams per Mole Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol.
567996
To find the number of moles of a compound you have on hand, look up the molecular weight of the compound and divide that number into the weight you have on hand. If you know the number of moles, you can find the weight by multiplying the number of moles by the molecular weight.
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Multiply the resulting number by the number of grams per mole of product to find the mass of product able to be produced by the given amount of reactant. There are 2.1749 moles of NaCl and one mole equals 58.243 grams. 2.1749 × 58.243 = 126.67, so the 50.000 g of Na used in the reaction can create 126.67 g of NaCl.
139683
['Determine the mass of the water that has left the compound. ... ', 'Convert the mass of water to moles. ... ', 'Convert the mass of anhydrate that is left over to moles. ... ', 'Find the water-to-anhydrate mole ratio. ... ', 'Use the mole ratio to write the formula.']
806487
You need to balance the equation and see the mole ratio between the reactants. For this equation, the mole ratio is 3 moles of O2 : 4 moles of Al. So, you would then multiply: 14.8 moles*(3/4) = 11.1 moles. 11.1 moles O2 are needed to react completely with 14.8 moles of Al.