how to calculate distance between two trains?
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If both trains leave the station at the same time, how far apart will they be at the end of two hours? Train A traveled 120 miles, and train B traveled 140 miles. Because they're traveling in the same direction, you subtract to find the distance between them: 140 – 120 = 20. The two trains are 20 miles apart.
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1. Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2. 3.
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We can calculate the average speed by finding the total distance traveled divided by the elapsed time: Average speed=–s=Total distanceElapsed time. Average speed = s – = Total distance Elapsed time .
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The (shortest) distance between a pair of skew lines can be found by obtaining the length of the line segment that meets perpendicularly with both lines, which is d d d in the figure below. Find the distance between the following pair of skew lines: x = − y + 2 = − z + 2 and x − 2 = − y + 1 = z + 1.
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To calculate the circumference, you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each revolution. Then you can multiply by the number of revolutions per minute. That will give you the distance traveled in each minute.
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When we want to find the distance between two integers using the difference, the best way is to plot them on number line. And then count distance between them. For example -3 and -1. But distance can not be negative.
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Many everyday problems involve rates of speed, using distance and time. We can solve these problems using proportions and cross products. However, it's easier to use a handy formula: rate equals distance divided by time: r = d/t.
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Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2.
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Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2. 3.
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1 Expert Answer Let x = speed of freight train, so x + 6 = speed of passenger train. Distance = (rate)(time), so Time = (Distance)/(Rate). We know that Tf = Tp, so 310/x = 340/(x+6).
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For example, a car travels 400 miles in seven hours and you want to know how fast, on average, the car traveled. Using the equation s = d ÷ t, plug in the distance of 400 miles for d and time of seven hours in for t: s = 400 miles ÷ 7 hours = 57.1 miles/hour.
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['Go to Rail. ... ', 'Choose your route.', 'Select your travel date/s.', 'Select the number of passengers traveling, and indicate children if any.']
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By the way, what you are actually doing is using the Pythagorean Theorem on an imaginary right triangle with the line joining the two lines being the hypotenuse. The general formula for distance between two points is the following: √x2+y2 x 2 + y 2 , where x and y are the change in x and y between the two points.
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['The distance formula is really just a restatement of the Pythagorean theorem. ... ', '(change in x)2 + (change in y)2 = (distance)2 ... ', 'From there, if we solve for distance, we find:', 'D = √(Δx2 + Δy2)', 'If you have any further questions, please let me know.']
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You can use distanceFromLocation to find the distance between two coordinates. Code Snippets: CLLocation *loc1 = [[CLLocation alloc] initWithLatitude:lat1 longitude:lng1]; CLLocation *loc2 = [[CLLocation alloc] initWithLatitude:lat2 longitude:lng2]; CLLocationDistance distance = [loc1 distanceFromLocation:loc2];
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['A car travels 500 m in 50 s, then 1500 m in 75 s. Calculate its average speed for the whole journey. First calculate total distance travelled:', '500 + 1500 = 2000 m. Then calculate total time taken:', '50 + 75 = 125 s. Then use the formula to calculate average speed:']
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['public double GetDistanceBetweenPoints(double lat1, double long1, double lat2, double long2)', '{', 'double distance = 0;', 'double dLat = (lat2 - lat1) / 180* Math.PI;', 'double dLong = (long2 - long1) / 180 * Math.PI;', 'double a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2)']