how many combinations are there with a 4 digit code?
10234
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
16468
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times.
135457
For example, 1234. Each combination of this type has 24 different box combinations, so your odds of winning by playing one "single" box combination would be approximately 1 in 417. Double (12-way): Two of the four positions have the same digit, and the third and fourth digits are different.
414282
Well you have n choices for the nth digit. In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating. Without repeating digits 24 four digit numbers can be made .
38270
Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.
1458010
With respect to that technical meaning, there is only one combination of the four numbers 4, 5, 8, and 7, taken four at a time: All four of them. There are 24 combinations. 4578, 4587, 4758, 4785, 4857, 4875, 5478, 5487, 5748, 5784, 5847, 5874, 7458, 7485, 7548, 7584, 7845, 7854, 8457, 8475, 8547, 8574, 8745, and 8754.
208608
Again there ae 4 choices so the number of possible 3 digit numbers is 4 4 4. Finally there are 4 choices for the last digit so the number of possible 4 digit numbers is 4 4 4 = 256.
1166886
I.e. there are 4 objects, so the total number of possible combinations that they can be arranged in is 4! = 4 x 3 x 2 x 1 = 24.
1031102
Answer and Explanation: The number of possible 16-digit combinations, where repetition is allowed is 10,000,000,000,000,000.
944460
Assuming repetition is allowed, you can have 7-digit numbers from 1,000,000 to 9,999,999 which is a total of 9,000,000 7-digit numbers. These are all the possible 7-digit numbers. In general, there are 9 × 10^(n-1) possible n-digit numbers.
151182
If you include 3, 2 and 1 digit numbers then it would be 24 + 24 + 12 + 4 = 64 combinations.
237587
there are 64,000 possible combinations on a standard 40-number Master Lock. With this method, however, you can quickly narrow that down to 100 combinations, a workable number to try if you've got the time and the inclination to give it a shot.
1092073
By dividing a binary number up into groups of 4 bits, each group or set of 4 digits can now have a possible value of between “0000” (0) and “1111” ( 8+4+2+1 = 15 ) giving a total of 16 different number combinations from 0 to 15.
16574
Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
1106697
Explanation: There are 5 choices for the first digit. giving 5×5=25 possible combinations. giving 5×4=20 possible combinations.
195649
For the third digit there are only 2 choices and for the last digit, one choice. Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.
768495
The number of combinations is 8,145,060. This is because there are 45!/(6!