how many different combinations of 3 things?
234999
You have three different colors, lets say red (R), green (G) and blue (B) and you choose 3 colors. The colors can repeat. The following can be mathematically represented as 33 = 27.
279311
Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total. But…
1004049
So there are possible numbers of length 4. It's easy. The first digit can be 1,2,3,4,5 or 6 (6 combinations). We choose the second,third and fourth digit the same way we did it with the first (so it's 6*6*6 combinations) and the final answer is 6*6*6*6=1296 combinations.
733916
Five single-colour combinations, ten two-colour combinations, ten three-colour combinations, five four-colour combinations, and a combination of all five colours, plus colourless.
771255
As you can see, there are six combinations of the three colors. Table 3. Six Combinations.
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r!( n – r)! And we input the number 5 for n, and 3 for r, and so we know that there 10 possible combinations.
57490
The number of ways you pick 3 out of 5 is the same as you pick 2 out of 5 if the order doesn't matter. Certified Physics and Math Teacher G.S. This is the number of combinations of 3 elements out of 5. these are all possible combinations, 10.
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Hence there are 26 × 26 possible two letter words. You can extend each of these possible two letter words into a three letter word by adding one of 26 possible letters and hence there are 26 × 26 × 26 possible three letter words.
75778
This brings us to the final bracket. With 63 games and 2 possible selections for each one, that's 9,223,372,036,854,775,808 possible combinations.
431600
We conclude that there are 35−3×25+3=150 combinations. If there were no restrictions, the number of five digit codes that could be formed with the digits 1, 2, 3 would be 35 since there are three ways to choose each of the five digits.
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Dana F Anderson, Just interested in math is all. Kinda a hobby. Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
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The total number of combinations is then: 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000 ≈ 18 million.
64961
If I have 3 colours (Black, White and Red), there are 3 possible combination (Black+White, Black+Red, White+Red). If I have 4 colours, there are 5 possible combinations and if I have 5 colours there are 10 possible combinations.
699776
Answer and Explanation: There are 216 possible combinations with 3 standard dice. Each die has 6 possible outcomes because it has 6 sides. The number of possible combinations...
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With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
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Hi Mike. If order mattered, we would say select the first number (10 choices), then the second (9 choices) then the third (8 choices). So there would be 10 x 9 x 8 = 720 possible choices.
192017
Answer and Explanation: Thus, total number of different combination is 35 .