how many atoms and molecules of sulphur present in 64 gram of sulphur?
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We begin by getting molar mass of S₈. The number of atoms in S₈ : 6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.
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1 molecule of Na2SO4 contains 2 atoms of Na, 1 atom of sulfur and 4 atoms of oxygen.
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Thus 1 mol of SO2 will contain 6.022 x 1023 molecules of SO2.
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Sulphur molecules have 8 atoms in it because of its high catenation property.
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How many atoms of barium are present in 1.37 grams of barium? There's 6.0221415*10^23 atoms in a mole of an element, so the number of atoms in 1.37g of Barium is: (9.976188222*10^-3)*(6.0221415*10^23)=6.007801771*10^21 plus or minus a few atoms.
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Number of molecules present in 1.28 gm of SO2 = 1.2044 * 10^22.
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Number of molecules = 1.47 × 10^(23) molecules. Thus, there are 1.47 × 10^(23) molecules present in 122 grams of NO2.
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So then we will have 63.52g of iron and 36.48g of sulphur. So the empirical formula of the compound is FeS.
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One sulfuric (H2SO4) molecule has 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms.
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Number of atomsof sulphur (S8) = 8 x 1.50 × 1023 molecules = 1.20× 1023 atoms.
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4 grams (2 moles) of hydrogen molecules contains 4 moles of hydrogen atoms.
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02×1023 molecules are present in one gram of hydrogen.
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Answer Expert Verified The number of atoms in S₈ : 6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.
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1gram atom is the number of atom present in only one gram but one mole of atom is the number of atom present in one mole , which is equal to 6.022×10^23 atom .
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There are 1(Cu) + 1(S) + 4(O) + 5(2(H) + 1(O)) = 6 + 5x3 = 21 atoms per molecule. There are Avagadro's number of Molecules / Mole. There are The molecular weight grams in a mole W gram/Mole.
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(i) In an H2S molecule, three atoms are present; two of hydrogen and one of sulphur. (ii) In a PO43-ion, five atoms are present; one of phosphorus and four of oxygen.
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Therefore 32 GMs of sulfur consists of 6.022 x 10^23 atoms.