how to subtract date in mssql?
233200
['Add 30 days to a date SELECT DATEADD(DD,30,@Date)', 'Add 3 hours to a date SELECT DATEADD(HOUR,-3,@Date)', 'Subtract 90 minutes from date SELECT DATEADD(MINUTE,-90,@Date)', 'Check out the chart to get a list of all options.']
1067585
["(DATEDIFF('day',[Day1],[Day2]) - (7-DATEPART('weekday',[Day1])) - DATEPART('weekday',[Day2]) ) / 7*5. + MIN(5,(7-(DATEPART('weekday',[Day1])))) ... ", "(DATEDIFF('day',[Day1],[Day2])", "- (7-DATEPART('weekday',[Day1]))", "- DATEPART('weekday',[Day2])", "+ MIN(5,(7-(DATEPART('weekday',[Day1]))))", "+ MIN(5,(DATEPART('weekday',[Day2])-1))"]
1432112
["You convert string to date with a different format. Try this. select to_char(to_date('25-SEP-14','DD-MON-YY'), 'DD/MM/YYYY') FROM DUAL. ... ", 'For a simple test, try this: select to_char(sysdate,\'DD/MM/YYYY\') "Converted" from dual; ... ', "If it is already a data field in the table then use. to_char(date_field,'DD/MM/YYYY')"]
616378
If your existing data is in MM/DD/YYYY format, then you want: select to_date(date_column,'MM/DD/YYYY') from table; to convert the existing data to DATE values.
882783
['Description. The Microsoft Access DateValue function converts a string to a date.', 'Syntax. The syntax for the DateValue function in MS Access is: DateValue ( string_date ) ... ', 'Returns. The DateValue function returns a date value.', 'Note. ... ', 'Applies To. ... ', 'Example. ... ', 'Example in VBA Code. ... ', 'Example in SQL/Queries.']
66379
['Change the time of both dates to midnight.', 'Convert the dates to milliseconds.', 'Find the difference between the two dates.', 'Divide the result by the number of milliseconds in a day (24 * 60 * 60 * 1000).', 'The result should be the difference in days.']
417581
['Enter your due dates in column A.', 'Enter the number of days to add or subtract in column B. You can enter a negative number to subtract days from your start date, and a positive number to add to your date.', 'In cell C2, enter =A2+B2, and copy down as needed.']
335372
["From Oracle SQL Developer's menu go to: Tools > Preferences.", 'From the Preferences dialog, select Database > NLS from the left panel.', 'From the list of NLS parameters, enter DD-MON-RR HH24:MI:SS into the Date Format field.', 'Save and close the dialog, done!']
601452
The difference between the two dates can be found by just subtracting the two.
332269
You may also try this: select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss') as run_time from some_table; It displays time in more human readable form, like: 00:01:34.
1314947
1 Answer. In first, you need to join the table to itself by Customer and Order fields. Then use DATEDIFF() function to get days number between two dates.
574331
["Sub Main() ' Start date.", "Dim startDate As DateTime = New DateTime(2005, 2, 1, 3, 4, 12, 56) ' End date. ... ", "Dim diffDate As TimeSpan = endDate.Subtract(startDate) ' Spit it out. ... ", 'Console.WriteLine(diffDate.Hours.ToString() + " Hours") Console.WriteLine(diffDate.Minutes.ToString() + " Minutes") ... ', 'Console.ReadKey() End Sub.']
214782
If you need the difference in seconds (i.e.: you're comparing dates with timestamps, and not whole days), you can simply convert two date or timestamp strings in the format 'YYYY-MM-DD HH:MM:SS' (or specify your string date format explicitly) using unix_timestamp(), and then subtract them from each other to get the ...
368197
['Days: endDate.Subtract(firstDate).TotalDays; or. endDate.Subtract(firstDate).Days;', 'Months: ((endDate.Year - firstDate.Year) * 12) + (endDate.Month - firstDate.Month);', 'Years: endDate.Year - firstDate.Year;']
249258
SELECT sysdate-TO_date('15/12/2011', 'dd/mm/yyyy') DAYS FROM DUAL; By the way, If you are using difference between two dates in PL. You can use following simple query.
1024501
['The query with DATEDIFF: SELECT DATEDIFF(year, \'2010-03-13\', GETDATE()) AS "Years Difference"; ... ', 'The query: SELECT *, GETDATE() AS "Current Date", ... ', 'For Year: year, yy, yyyy.', 'Month: month, mm, m.', 'Day of Year: dayofyear, dy, y.', 'Day: day, dd, d.', 'Week: week, wk, ww.', 'Hour: hour, hh.']
373200
['Dim dt1 As DateTime = Convert.ToDateTime(DateTimePicker1.Value.ToString("dd/MM/yyy"))', 'Dim dt2 As DateTime = Convert.ToDateTime(DateTimePicker2.Value.ToString("dd/MM/yyy"))', "''count total day between selected your date.", 'Dim ts As TimeSpan = dt2.Subtract(dt1)']