what is the probability of getting a head and an even number?
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Explanation: The coin is fair, the probabilities of getting a head and a tail are equal to 12 . The probability of getting an even number on a die is 36=12 because among 6 results there are 3 even numbers.
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The probability of rolling an even number on a six sided die is 3/6, or 1/2.
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The probability of heads on the first toss is 50%, just as it is on all subsequent tosses of the coin. The two outcomes of the toss of a coin are heads or tails. For any individual toss of the coin, the outcome will be either heads or tails.
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In the long run, the relative frequency of an event will be close to the (theoretical) probability. For example, if you toss a die 100 times, you should expect to get a four about one sixth of the time; that is, around 16 or 17 times. But the relative frequency describes how many times you actually got a four.
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So, there are 12 such outcome-duos generating a number multiple of 3. Therefore, the probability = (12 / 36) = (1 / 3).
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['Determine a single event with a single outcome. ... ', 'Identify the total number of outcomes that can occur. ... ', 'Divide the number of events by the number of possible outcomes. ... ', 'Determine each event you will calculate. ... ', 'Calculate the probability of each event. ... ', 'Multiply all probabilities together.']
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['140 combinations, 14.0% chance of receiving the No. ... ', '140 combinations, 14.0% chance.', '140 combinations, 14.0% chance.', '125 combinations, 12.5% chance.', '105 combinations, 10.5% chance.', '90 combinations, 9.0% chance.', '75 combinations, 7.5% chance.']
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The chance of getting on even number on two dice is therefore 1/2 x 1/2… which is 1/4, or 25%.
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2 Dices thrown simultaneously give these many sets whose sum will be a even number: (1,1),(2,2),(3,3),(4,4),(5,5),(6,6),(1… So the probability will be 12/12=1.
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The Standard Deviation Rule applies: the probability is approximately 0.95 that p-hat falls within 2 standard deviations of the mean, that is, between 0.6 – 2(0.05) and 0.6 + 2(0.05). There is roughly a 95% chance that p-hat falls in the interval (0.5, 0.7) for samples of this size.
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There are three even numbers on each die (2, 4, & 6). You have a 50-50 chance of rolling one of these numbers on a single die. This can also be written as 1/2. The chance of getting on even number on two dice is therefore 1/2 x 1/2… which is 1/4, or 25%.
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If you mean at least one of the dice shows an odd number, then since there's a 0.25 = 0.5 x 0.5 probability of both dice being even, there's a 1 - 0.25 = 0.75 probability at least one of the dice is odd.
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Let us take the experiment of tossing two coins simultaneously: When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail. TOTAL 4 outcomes.
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For every 15, odds are that 13 will be a particular event and 2 will be another event. There is a 86.67 percent probability of a particular outcome and 13.33 percent probability of another outcome. If you bet 1 on a game with 13 to 2 odds and you win, your total payout will be 7.50 which is your bet plus 6.50 profit.
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If A and B are independent, then the probability that events A and B both occur is: p(A and B) ... Two events must occur: a head on the first toss and a head on the second toss. Since the probability of each event is 1/2, the probability of both events is: 1/2 x 1/2 = 1/4.
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Assuming a fair coin in which there are equal probabilies of heads and tails, then the probability of getting 0 tails is… (Probability of heads on 1 flip)^5 = (0.5)^5 = 0.03125. Thus, the probability of getting at least one tail is… 1 - (Probability of 0 tails) = 1- 0.03125 = 0.96875.
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If you are asking what is the probability of selecting a heart or a face card at random in a single draw, the probability is 16/52 = 8/26 = 4/13.