what is the equation of the perpendicular bisector of the line segment?
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The slope of the perpendicular bisector = -1/slope of the line. Step 4: Once we find the slope as above, we can find the equation with the slope and the midpoints. By solving the above, we get the equation y-5 = -2.5 (x-9/2).
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The general equation of a straight line is y = m x + c , where is the gradient and the coordinates of the y-intercept.
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1 Answer. Segment joining a vertex to the mid-point of opposite side is called a median. ... A Line which passes through the mid-point of a segment and is perpendicular on the segment is called the perpendicular bisector of the segment.
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1 Answer. Segment joining a vertex to the mid-point of opposite side is called a median. Perpendicular from a vertex to opposite side is called altitude. A Line which passes through the mid-point of a segment and is perpendicular on the segment is called the perpendicular bisector of the segment.
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The angle bisector of an angle of a triangle is a straight line that divides the angle into two congruent angles. The three angle bisectors of the angles of a triangle meet in a single point, called the incenter . ... For an equilateral triangle the incenter and the circumcenter will be the same.
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Answer Expert Verified The equation of a line in point-slope form. is the equation of the line containing point (x1, y1) and having slope, m. The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.
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The general equation of a straight line is y = mx + c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis. Key Point. The equation of a straight line with gradient m and intercept c on the y-axis is y = mx + c.
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A line perpendicular to Line M will have a negative reciprocal slope. Thus, the answer is y = (1/7)x + 3.
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Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 8x + 6y = 15 is m = –4/3. Therefore, the slope of the line perpendicular to this line would have to be m = 3/4.
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Correct answer: Find the slope of the given line. The perpendicular slope will be the opposite reciprocal of the original slope. Use the slope-intercept form (y = mx + b) and substitute in the given point and the new slope to find the intercept, b. Convert back to standard form of an equation: ax + by = c.
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Two vectors are perpendicular when their dot product equals to .
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Given: In ∆ ABC, AD is the perpendicular bisector of BC. To Prove: A ABC is an isosceles triangle in which AB = AC. ... ∆ABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see figure).
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Two lines are perpendicular if and only if their slopes are negative reciprocals. To find the slope, we must put the equation into slope-intercept form, , where equals the slope of the line.
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Correct answer: Two lines are perpendicular if and only if their slopes are negative reciprocals. To find the slope, we must put the equation into slope-intercept form, , where equals the slope of the line.
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Diagonal line AC is the perpendicular bisector of BD. The intersection E of line AC and line BD is the midpoint of BD.
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Equation of a Straight Line. Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
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AD is perpendicular to the internal bisector of ∠ABC of △ABC. DE is drawn through D and parallel to BC to meet AC at E. If the length of AC is 12 cm, then the length of AB (in cm.) is. E will be mid point of AC.