how to find how many combinations?
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Remember that combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula nCr = n! / r! * (n - r)!, where n represents the number of items, and r represents the number of items being chosen at a time.
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For instance, with 3 6-sided dice, there are 6 ways of rolling 123 but only 3 ways of rolling 114 and 1 way of rolling 111. To work out the total number of outcomes, multiply the number of dice by the number of sides on each die. For 5 6-sided dice, there are 305 possible combinations.
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Given 100, choose 98, there are 161,700 combinations. The number of combinations gets bigger fast. 100, choose 95, is over 7 million combinations. The largest number of combinations given a set of 100 elements, will be 100, choose 50.
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COMBINATION PLAY. When you choose an eight-number Combination Play, the eight numbers are arranged in combinations of seven numbers, giving you eight unique selections. For each such unique selection, you also receive two sets of computer-generated numbers, for a total of 24 seven-number combinations.
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[You don't want to include (40,20) and (20, 40).] So that means you need to know how many different permutations there are for each combination. If there are two numbers, there are two permutations per combination. Divide the possible permutations by number of permutations per combination: 2450 / 2 = 1225.
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I.e. there are 4 objects, so the total number of possible combinations that they can be arranged in is 4! = 4 x 3 x 2 x 1 = 24.
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Enter your objects (or the names of them), one per line in the box below, then click "Show me!" to see how many ways they can be arranged, and what those arrangements are. Note: 8 items have a total of 40,320 different combinations.
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The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
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2! See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can't be the fist number and next two are repeated from 10 numbers hence 10!/2! So 99 combinations have 10!/2! Permutations hence total ways are 99*10!/2!
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using 1 to 50 there are 50 possible one-number combinations. With 49 cards left over, there are 50x49 two-number combinations, 50x49x48 three-number combinations, and 50x49x48x47 four-number combinations.
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Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total. But…
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There are 3 numbers. So the number of permutations (arrangements) of three items equals 1 x 2 x 3 = 6. Thus, there are six permutations per combination. The number of combinations therefore is 6480 / 6 = 1080.
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Assuming no five-digit number can begin with zero, there are 9 possible choices for the first digit. Then there are 10 possible choices for each of the remaining four digits. Therefore, you have 9 x 10 x 10 x 10 x 10 combinations, or 9 x 10^4, which is 90,000 different combinations.
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Answer and Explanation: The number of combinations possible with 6 numbers between 1 and 59 is 45,057,474.
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To find the number of permutations it is all about choices. You know the 4 digits, but you don't know the order. So this is 4 × 3 × 2 × 1 = 24, if all 4 digits are different.
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The number of possible combinations on any Slot machine is easy to calculate. You need to multiply the total number of symbols (stops) each Slot (reel) has. On a three-reel machine with six symbols apiece, the total number of possible combinations is 6 x 6 x 6 = 216 combinations.
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All Possible 5/36 Number Combinations. Total Combinations - 376,992. 50K-1M number combinations per file. View in any word processor or Excel.