how many possible combinations are there rolling 2 dice?
235688
Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b.
585858
There are 36 equally likely outcomes from throwing two fair dice. In this case you are successful with 4 outcomes: 2 ,6; 6,2 ;3,4; 4,3. So required probability is 4/36 or 1/9.
811343
Solution : When two different dice are thrown, the total number of outcomes is 36 and all the out-comes are equally likely. (i) The outcomes favourable to the event 'sum of two number is 9' are (6, 3), (5, 4), (4, 5) and (3, 6) these are 4 in number. ∴ P (sum of 9) =436=19.
929310
The total number of outcomes equals the number of different ways we can roll two six-sided dice. We find this number by multiplying 6 x 6. ... Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12 (E).
713033
What is the probability of getting two numbers whose product is even? Explanation: In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36. n(E) = 27.
81304
To calculate your chance of rolling doubles, add up all the possible ways to roll doubles (1,1; 2,2; 3,3; 4,4; 5,5; 6,6). There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice.
852537
If you mean at least one of the dice shows an odd number, then since there's a 0.25 = 0.5 x 0.5 probability of both dice being even, there's a 1 - 0.25 = 0.75 probability at least one of the dice is odd.
1217337
There are 36 possible results when rolling two six sided dice. Of those, 10 have one six, and 1 has two sixes. Thus there are 11 rolls which have at least one six. The odds of getting at least one six must be 11/36.
1380314
There are 36 possible rolls when rolling two six sided dice. There are three ways to get a 10 (4&6,6&4,5&5) and five ways to get an 8 (2&6,6&2,3&5,5&3,4&4). 3+5=8 ways to get either an 8 or a 10. So the probability is 8/36=2/9.
650304
two dice rolled once has 6x6= 36 possible outcomes. There 6 ways of having a doublet. Thus p(doublet) = 6/36 = 1/6. ... Originally Answered: Two different dice are tossed together.
751385
Three of those will result in an even product, and only one (both odd) will give an odd product. Thus, the chance of rolling two dice with an even product is 3/4.
1028399
The probability of getting a total of 10 or 11 with two die thrown simultaneously is %13.89. This breaks down as: Getting a total of 10 is possible with a 4+6, 5+5 or a 6+4 for 3 of 36 possible combinations. ... Two dice are rolled.
1383571
Originally Answered: Two different dice are tossed together. ... two dice rolled once has 6x6= 36 possible outcomes. There 6 ways of having a doublet. Thus p(doublet) = 6/36 = 1/6.
1004288
There a four possible rolls with a single die less than 5 (1, 2, 3, and 4). If you were asking about the probability of rolling TWO dice, with the resultant sum being less than 5, there are 6 ways to do so in 36 possible outcomes. The answer is 6/36, or 1/6, or 16.67%.
1133468
Two dice are thrown once. ... The probability of getting an even number on the first die is 18/36 or 1/2. The probability of getting a sum of 8 is 5/36, as there are 36 possible outcomes and five of them -- 26, 35, 44, 53, and 62 -- have a sum of 8.
611311
If two dice are thrown at the same time, then possible outcomes are 36. i.e., n( S) = 36.
319401
Thanks for the A2A. Hint: A double of 6 is obtained when both dice throws result in 6. The probability for such an event is 1/36.