how many oxygen molecules are needed to synthesize 0.245g of carbon monoxide?
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1 mole of oxygen reacts with 2 moles of carbon to produce 2 moles of CO. Now 0.245g of CO = 0.245/28 = 0.0088 mole and this will require 0.0088/2 = 0.0044 mole of oxygen. Every mole of oxygen contains 6.022 x 10^23 molecules of oxygen.
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According to Avagadro, there are 6.022 × 10^23 molecules in 1 mole of any compound, irrespective of elements or the mass of compound. Thus in 3 moles of O2, there are 3 ×6.022× 10^23 molecules of O2, that is, 18.066×10^23 molecules of O2.
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The number of molecules in 16 gm of oxygen are 0.5 (= 16/32 moles). Thus the number of molecules in 16 gm or 0.5 mole of oxygen gas are 0.5 x 6.023 x 10^(23) = 3.012 x 10^(23) molecules.
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Therefore, the number of molecules in 2.5 moles of CO2 would be: (6.022 X 10^23 X 2.5)=1.5055 X 10^24 molecules of carbon (IV) oxide.
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Multiply the given moles C2H6 by the mole ratio between O2 and C2H6 in the balanced equation, so that moles C2H6 cancel, leaving moles O2. ~11 moles of O2 are required to react completely with 3.2 moles of C2H6.
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CO2 molecule is made of one carbon atom and 2 oxygen atoms. 1 Kg of carbon on complete combustion will produce 3.67 Kg. of CO2.
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The percent composition of carbon monoxide, the molecule with a chemical formula of CO, 42.88 percent carbon and 57.12 percent oxygen.
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The percentage by mass of oxygen in carbon monoxide is about 57.14% .
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Answer. 0.5 moles of methane are required to produce 22g og on combustion.
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There are 6.022 X 1023 molecules of CO2 in a mole, enough to make the grams in the mole equal the mass...
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1 mole of nitrogen reacts with 1 mol of oxygen to make 2 moles of nitrogen monoxide.
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The reactants have one carbon atom, four hydrogen atoms, and four oxygen atoms. The products have one carbon atom, four hydrogen atoms, and four oxygen atoms.
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Note that the front number "2Fe" and "3CO" represents the number of molecules used as mole ratio. The mole ratio between Fe:CO is 2:3. If 2 moles of iron (Fe) gives you 3 moles of carbon monoxide (CO), then 2.003577818 moles of 2Fe must give you: [2.003577818 moles ÷ 2, then × 3] = 3.0053667263 moles of CO.
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Answer: The amount of KClO3 required 196 g. Given: 196 g of is requires to produce 2.4 moles of oxygen.
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From the above reaction, 2 moles of hydrogen will react with 1 mole of oxygen. Hence, 1 mole of oxygen is required.
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This means that 1 mole of carbon dioxide has a mass of 44.01 g . Oxygen has a molar mass of 16.0 g mol−1 , so 1 mole of oxygen atoms has a mass of 16.0 g . Therefore, carbon dioxide has a percent composition of 72.7% oxygen, i.e. for every 100 g of carbon dioxide you get 72.7 g of oxygen.
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Well, one mole is equal to Avogadro's Number, or 6.02210 x 10^23 particles. Since you are not talking about the amount of oxygen atoms in 3 moles of O2, no extra multiplication is needed to compensate for that. 3 moles x (6.02210 x 10^23) O2 molecules per mole = 1.80663 x 10^24 O2 molecules.