CREATE TABLE table_name_47 (name VARCHAR, rank VARCHAR, height_feet___m VARCHAR)

What is the building's name that is 617 / 188 in height and ranked less than 6?
SELECT name FROM table_name_47 WHERE rank < 6 AND height_feet___m = "617 / 188"
SELECT "name" FROM "table_name_47" WHERE "617 / 188" = "height_feet___m" AND "rank" < 6