CREATE TABLE table_name_39 (date VARCHAR, score_in_the_final VARCHAR)

How many days had a score of 4 6, 4 6?
SELECT COUNT(date) FROM table_name_39 WHERE score_in_the_final = "4–6, 4–6"
SELECT COUNT("date") FROM "table_name_39" WHERE "4–6, 4–6" = "score_in_the_final"