CREATE TABLE table_23423_2 (deaths_per_year VARCHAR, life_expectancy_females VARCHAR)

How many deaths per year have 66.3 as the life expectancy females?
SELECT deaths_per_year FROM table_23423_2 WHERE life_expectancy_females = "66.3"
SELECT "deaths_per_year" FROM "table_23423_2" WHERE "66.3" = "life_expectancy_females"