CREATE TABLE table_65706 ("Score" TEXT, "2007" TEXT, "2008" TEXT, "2009" TEXT, "2010" TEXT, "2011" TEXT, "2012" TEXT)

What 2008 has 14.2% as the 2009?
SELECT "2008" FROM table_65706 WHERE "2009" = '14.2%'
SELECT "2008" FROM "table_65706" WHERE "2009" = '14.2%'