CREATE TABLE table_name_33 (date VARCHAR, road_team VARCHAR, result VARCHAR)

Which Date has a Road Team of chicago, and a Result of 88-85 (ot)?
SELECT date FROM table_name_33 WHERE road_team = "chicago" AND result = "88-85 (ot)"
SELECT "date" FROM "table_name_33" WHERE "88-85 (ot)" = "result" AND "chicago" = "road_team"