CREATE TABLE table_12544 ("Tournament" TEXT, "1973" TEXT, "1974" TEXT, "1975" TEXT, "1976" TEXT, "1977" TEXT, "1978" TEXT, "1979" TEXT, "1983" TEXT, "1984" TEXT, "1985" TEXT, "1986" TEXT)

What 1984 has a 1978 of 46 15?
SELECT "1984" FROM table_12544 WHERE "1978" = '46–15'
SELECT "1984" FROM "table_12544" WHERE "1978" = '46–15'