CREATE TABLE table_name_8 (money___ INT, to_par VARCHAR, score VARCHAR)

What is the average money ( ) that has +8 as the to par, with 73-72-72-71=288 as the score?
SELECT AVG(money___) AS £__ FROM table_name_8 WHERE to_par = "+8" AND score = 73 - 72 - 72 - 71 = 288
SELECT AVG("money___") AS "£__" FROM "table_name_8" WHERE "+8" = "to_par" AND "score" = FALSE