CREATE TABLE table_name_7 (safari VARCHAR, opera VARCHAR, internet_explorer VARCHAR)

What is the safari value with a 2.4% opera and 29.9% internet explorer?
SELECT safari FROM table_name_7 WHERE opera = "2.4%" AND internet_explorer = "29.9%"
SELECT "safari" FROM "table_name_7" WHERE "2.4%" = "opera" AND "29.9%" = "internet_explorer"