CREATE TABLE table_40818 ("1935" TEXT, "1936" TEXT, "1937" TEXT, "1938" TEXT, "1939" TEXT, "1940" TEXT, "1941" TEXT, "1943" TEXT, "1945" TEXT, "1946" TEXT, "1947" TEXT, "1948" TEXT, "1949" TEXT, "1950" TEXT, "1951" TEXT, "1952" TEXT, "1953" TEXT)

What 1953 has 2 as a 1949, and 3 as 1952?
SELECT "1953" FROM table_40818 WHERE "1949" = '2' AND "1952" = '3'
SELECT "1953" FROM "table_40818" WHERE "1949" = '2' AND "1952" = '3'