CREATE TABLE table_name_42 (surface VARCHAR, score_in_the_final VARCHAR)

Which Surface has a Score in the final of 2 6, 6 7?
SELECT surface FROM table_name_42 WHERE score_in_the_final = "2–6, 6–7"
SELECT "surface" FROM "table_name_42" WHERE "2–6, 6–7" = "score_in_the_final"