CREATE TABLE table_70953 ("D 47 +" TEXT, "D 46 +" TEXT, "D 45 +" TEXT, "D 44 +" TEXT, "D 43 O" TEXT, "D 42 O" TEXT, "D 41 \\u221a" TEXT, "D 40 \\u221a" TEXT)

Name the D 44 which has D 42 O of d 33
SELECT "D 44 +" FROM table_70953 WHERE "D 42 O" = 'd 33'
SELECT "D 44 +" FROM "table_70953" WHERE "D 42 O" = 'd 33'