CREATE TABLE table_12543 ("Tournament" TEXT, "1973" TEXT, "1974" TEXT, "1975" TEXT, "1976" TEXT, "1977" TEXT, "1978" TEXT, "1979" TEXT, "1983" TEXT, "1984" TEXT, "1985" TEXT, "1986" TEXT)

What 1978 has a 1976 of 62%?
SELECT "1978" FROM table_12543 WHERE "1976" = '62%'
SELECT "1978" FROM "table_12543" WHERE "1976" = '62%'