CREATE TABLE table_name_58 (year VARCHAR, score VARCHAR)

What year had a score of 6 2, 2 6, 5 7, 7 6, 8 6?
SELECT year FROM table_name_58 WHERE score = "6–2, 2–6, 5–7, 7–6, 8–6"
SELECT "year" FROM "table_name_58" WHERE "6–2, 2–6, 5–7, 7–6, 8–6" = "score"