CREATE TABLE table_name_82 (surface VARCHAR, result VARCHAR)

What was the surface when the result was 6 7 (6 7) , 7 6 (9 7) , 6 7 (4 7) , 7 5, 3 6?
SELECT surface FROM table_name_82 WHERE result = "6–7 (6–7) , 7–6 (9–7) , 6–7 (4–7) , 7–5, 3–6"
SELECT "surface" FROM "table_name_82" WHERE "6–7 (6–7) , 7–6 (9–7) , 6–7 (4–7) , 7–5, 3–6" = "result"