CREATE TABLE table_name_31 (change INT, centre VARCHAR, rank VARCHAR)

Which Change is the average one that has a Centre of buenos aires, and a Rank smaller than 46?
SELECT AVG(change) FROM table_name_31 WHERE centre = "buenos aires" AND rank < 46
SELECT AVG("change") FROM "table_name_31" WHERE "buenos aires" = "centre" AND "rank" < 46