CREATE TABLE table_name_88 (year VARCHAR, score VARCHAR)

Which Year has a Score of 5 7, 4 6, 6 3, 1 6?
SELECT year FROM table_name_88 WHERE score = "5–7, 4–6, 6–3, 1–6"
SELECT "year" FROM "table_name_88" WHERE "5–7, 4–6, 6–3, 1–6" = "score"