CREATE TABLE table_26708105_5 (common_name VARCHAR, accession_number VARCHAR)

How many times is the accession number xp_001843282?
SELECT COUNT(common_name) FROM table_26708105_5 WHERE accession_number = "XP_001843282"
SELECT COUNT("common_name") FROM "table_26708105_5" WHERE "XP_001843282" = "accession_number"