CREATE TABLE table_name_78 (location VARCHAR, year VARCHAR, score VARCHAR)

Which Location has a Year larger than 2006, and a Score of 6 3, 6 3?
SELECT location FROM table_name_78 WHERE year > 2006 AND score = "6–3, 6–3"
SELECT "location" FROM "table_name_78" WHERE "6–3, 6–3" = "score" AND "year" > 2006