CREATE TABLE table_64270 ("Period" TEXT, "Internet Explorer" TEXT, "Chrome" TEXT, "Firefox" TEXT, "Safari" TEXT, "Opera" TEXT, "Other Mozilla" TEXT)

What internet explorer has 7.89% as the safari, and 8.22% as the chrome?
SELECT "Internet Explorer" FROM table_64270 WHERE "Safari" = '7.89%' AND "Chrome" = '8.22%'
SELECT "Internet Explorer" FROM "table_64270" WHERE "Chrome" = '8.22%' AND "Safari" = '7.89%'