CREATE TABLE table_name_58 (_2013_projection VARCHAR, july_1 VARCHAR, rank VARCHAR)

How many July 1, 2013 projections have a Rank of 27?
SELECT COUNT(july_1), _2013_projection FROM table_name_58 WHERE rank = "27"
SELECT COUNT("july_1"), "_2013_projection" FROM "table_name_58" WHERE "27" = "rank"