CREATE TABLE table_name_98 (s_registered_user VARCHAR, userpics_free VARCHAR)

What is the S Registered User, when Userpics Free is 6 [free] or 15 [plus]?
SELECT s_registered_user FROM table_name_98 WHERE userpics_free = "6 [free] or 15 [plus]"
SELECT "s_registered_user" FROM "table_name_98" WHERE "6 [free] or 15 [plus]" = "userpics_free"