CREATE TABLE table_52014 ("D 40 \\u221a" TEXT, "D 41 \\u221a" TEXT, "D 42 \\u221a" TEXT, "D 43 \\u221a" TEXT, "D 44 \\u221a" TEXT, "D 45 O" TEXT, "D 46 O" TEXT, "R 53 +" TEXT, "R 52 +" TEXT, "R 51 +" TEXT)

Name the R 53 + which has a D 42 of d 17
SELECT "R 53 +" FROM table_52014 WHERE "D 42 \u221a" = 'd 17'
SELECT "R 53 +" FROM "table_52014" WHERE "D 42 \u221a" = 'd 17'