CREATE TABLE table_name_80 (literacy_rate___percentage____2001_census VARCHAR, _percentage_increase VARCHAR)

What was the literacy rate published in the 2001 census for the state that saw a 12.66% increase?
SELECT literacy_rate___percentage____2001_census FROM table_name_80 WHERE _percentage_increase = "12.66%"
SELECT "literacy_rate___percentage____2001_census" FROM "table_name_80" WHERE "12.66%" = "_percentage_increase"