CREATE TABLE table_name_95 (points INT, record VARCHAR, march VARCHAR)

Record of 42 16 8, and a March larger than 5 has what average points?
SELECT AVG(points) FROM table_name_95 WHERE record = "42–16–8" AND march > 5
SELECT AVG("points") FROM "table_name_95" WHERE "42–16–8" = "record" AND "march" > 5