CREATE TABLE table_25042332_16 (median_income___intl INT, below_60_percentage_of_median_income VARCHAR)

What is the median income for the region where 24.4% pf people make below 60% of the median income?
SELECT MIN(median_income___intl) AS $__ FROM table_25042332_16 WHERE below_60_percentage_of_median_income = "24.4%"
SELECT MIN("median_income___intl") AS $__ FROM "table_25042332_16" WHERE "24.4%" = "below_60_percentage_of_median_income"