CREATE TABLE table_name_19 (average INT, rank VARCHAR, celebrity VARCHAR)

What is the highest average of celebrity Natalia Lesz, who is ranked greater than 4?
SELECT MAX(average) FROM table_name_19 WHERE rank > 4 AND celebrity = "natalia lesz"
SELECT MAX("average") FROM "table_name_19" WHERE "celebrity" = "natalia lesz" AND "rank" > 4