CREATE TABLE Apartments (apt_type_code VARCHAR, bathroom_count INT)

Show the most common apartment type code among apartments with more than 1 bathroom.
SELECT apt_type_code FROM Apartments WHERE bathroom_count > 1 GROUP BY apt_type_code ORDER BY COUNT(*) DESC LIMIT 1
SELECT "apt_type_code" FROM "Apartments" WHERE "bathroom_count" > 1 GROUP BY "apt_type_code" ORDER BY COUNT(*) DESC NULLS LAST LIMIT 1