CREATE TABLE table_12834 ("2013" TEXT, "2012" TEXT, "2011" TEXT, "2010" TEXT, "2009" TEXT, "2008" TEXT, "2007" TEXT)

What 2009 has 52-75 as the 2010?
SELECT "2009" FROM table_12834 WHERE "2010" = '52-75'
SELECT "2009" FROM "table_12834" WHERE "2010" = '52-75'