CREATE TABLE table_12836 ("2013" TEXT, "2012" TEXT, "2011" TEXT, "2010" TEXT, "2009" TEXT, "2008" TEXT, "2007" TEXT)

What 2009 has 39th as the 2011?
SELECT "2009" FROM table_12836 WHERE "2011" = '39th'
SELECT "2009" FROM "table_12836" WHERE "2011" = '39th'