CREATE TABLE table_40490 ("Tournament" TEXT, "2004" TEXT, "2005" TEXT, "2006" TEXT, "2007" TEXT)

What is 2006 has a 2007 of 3r?
SELECT "2006" FROM table_40490 WHERE "2007" = '3r'
SELECT "2006" FROM "table_40490" WHERE "2007" = '3r'