#!/usr/bin/env python
# -*- coding: utf-8 -*-

from runner.koan import *
import re
class AboutRegex(Koan):
    """
        These koans are based on the Ben's book: Regular Expressions in 10 minutes.
        I found this books very useful so I decided to write a koans in order to practice everything I had learned from it.
        http://www.forta.com/books/0672325667/
    """

    def test_matching_literal_text(self):
        


    def test_matching_literal_text_how_many(self):
        """
            Lesson 1 How many matches?

            The default behaviour of most regular expression engines is to return just the first match.
            In python you have the next options:

                match()    -->  Determine if the RE matches at the beginning of the string.
                search()   -->  Scan through a string, looking for any location where this RE matches.
                findall()  -->  Find all substrings where the RE matches, and returns them as a list.
                finditer() -->  Find all substrings where the RE matches, and returns them as an iterator.

        """
        string = "Hello, my name is Felix and this koans are based on the Ben's book: Regular Expressions in 10 minutes. Repeat My name is Felix"
        m = len(re.findall('Felix', string)) #TIP: Maybe match it's not the best option

        # I want to know how many times appears my name
        self.assertEqual(m, 2)

    def test_matching_literal_text_not_case_sensitivity(self):
        """
            Lesson 1 Matching Literal String non case sensitivity.
            Most regex implementations also support matches that are not case sensitive. In python you can use re.IGNORECASE, in
            Javascript you can specify the optional i flag.
            In Ben's book you can see more languages.

        """
        string = "Hello, my name is Felix or felix and this koans is based on the Ben's book: Regular Expressions in 10 minutes."

        self.assertEqual(re.findall("felix", string), ['felix'])
        self.assertEqual(re.findall("felix", string, re.IGNORECASE), ['Felix', 'felix'])

    def test_matching_any_character(self):
        """
            Lesson 1 Matching any character

            . matches any character, alphabetic characters, digits and .
        """
        string = "pecks.xlx\n"    \
                + "orders1.xls\n" \
                + "apec1.xls\n"   \
                + "na1.xls\n"     \
                + "na2.xls\n"     \
                + "sa1.xls"

        # TIP: remember the name of this lesson

        change_this_search_string = r'a.\.xl.' # <-- I want to find all uses of myArray
        self.assertEquals(len(re.findall(change_this_search_string, string)),3)

    def test_matching_set_character(self):
        """
            Lesson 2 Matching sets of characters

            A set of characters is defined using the metacharacters [ and ]. Everything between them is part of the set and
            any one of the set members must match (but not all).
        """
        string = "sales.xlx\n"    \
                + "sales1.xls\n"  \
                + "orders3.xls\n" \
                + "apac1.xls\n" \
                + "sales2.xls\n"  \
                + "na1.xls\n"  \
                + "na2.xls\n"  \
                + "sa1.xls\n"  \
                + "ca1.xls"
        # I want to find all files for North America(na) or South America(sa), but not (ca)
        # TIP you can use the pattern .a. which matches in above test but in this case matches more than you want
        change_this_search_string = '[ns]a[0-9].xls'
        self.assertEquals(len(re.findall(change_this_search_string, string)),3)

    def test_anything_but_matching(self):
        """
            Lesson 2 Using character set ranges
            Occasionally, you'll want a list of characters that you don't want to match.
            Character sets can be negated using the ^ metacharacter.

        """
        string = "sales.xlx\n"    \
                + "sales1.xls\n"  \
                + "orders3.xls\n" \
                + "apac1.xls\n" \
                + "sales2.xls\n"  \
                + "sales3.xls\n"  \
                + "europe2.xls\n"  \
                + "sam.xls\n"  \
                + "na1.xls\n"  \
                + "na2.xls\n"  \
                + "sa1.xls\n"  \
                + "ca1.xls"

        # I want to find the name sam
        change_this_search_string = '[^nc]am.xls'
        self.assertEquals(re.findall(change_this_search_string, string), ['sam.xls'])


"""
            Lesson 1 Matching Literal String
        """
        string = "Hello, my name is Felix and this koans are based on the Ben's book: Regular Expressions in 10 minutes."
        m = re.search(r'Felix', string)
        self.assertTrue(m and m.group(0) and m.group(0)== 'Felix', "I want my name")