# Given a set of distinct integers, nums, return all possible subsets.

# Note: The solution set must not contain duplicate subsets.

# For example,
# If nums = [1,2,3], a solution is:

# [
# [3],
# [1],
# [2],
# [1,2,3],
# [1,3],
# [2,3],
# [1,2],
# []
# ]


# O(2**n)


def subsets(nums):
    res = []
    backtrack(res, nums, [], 0)
    return res


def backtrack(res, nums, stack, pos):
    if pos == len(nums):
        res.append(list(stack))
    else:
        # take nums[pos]
        



# simplified backtrack

# def backtrack(res, nums, cur, pos):
# if pos >= len(nums):
# res.append(cur)
# else:
# backtrack(res, nums, cur+[nums[pos]], pos+1)
# backtrack(res, nums, cur, pos+1)


# Iteratively
def subsets2(self, nums):
    res = [[]]
    for num in sorted(nums):
        res += [item + [num] for item in res]
    return res


test = [1, 2, 3]
print(test)
print(subsets(test))

stack.append(nums[pos])
        backtrack(res, nums, stack, pos + 1)
        stack.pop()
        # dont take nums[pos]
        backtrack(res, nums, stack, pos + 1)