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The dataset generation failed
Error code: DatasetGenerationError
Exception: EmptyDataError
Message: No columns to parse from file
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1568, in _prepare_split_single
for key, record in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 609, in wrapped
for item in generator(*args, **kwargs):
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/packaged_modules/folder_based_builder/folder_based_builder.py", line 386, in _generate_examples
for pa_metadata_table in self._read_metadata(downloaded_metadata_file, metadata_ext=metadata_ext):
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/packaged_modules/folder_based_builder/folder_based_builder.py", line 295, in _read_metadata
csv_file_reader = pd.read_csv(metadata_file, iterator=True, dtype=dtype, chunksize=chunksize)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/streaming.py", line 73, in wrapper
return function(*args, download_config=download_config, **kwargs)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/utils/file_utils.py", line 1199, in xpandas_read_csv
return pd.read_csv(xopen(filepath_or_buffer, "rb", download_config=download_config), **kwargs)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1026, in read_csv
return _read(filepath_or_buffer, kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 620, in _read
parser = TextFileReader(filepath_or_buffer, **kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1620, in __init__
self._engine = self._make_engine(f, self.engine)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1898, in _make_engine
return mapping[engine](f, **self.options)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/c_parser_wrapper.py", line 93, in __init__
self._reader = parsers.TextReader(src, **kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "pandas/_libs/parsers.pyx", line 581, in pandas._libs.parsers.TextReader.__cinit__
pandas.errors.EmptyDataError: No columns to parse from file
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1320, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 911, in stream_convert_to_parquet
builder._prepare_split(
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1447, in _prepare_split
for job_id, done, content in self._prepare_split_single(
^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1604, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
video
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hi guys it's me teacher going in today's video we will talk about plotting of points on Cartesian plane so last time maroon Time video we're in we discussed the different parts of the Artisan plane
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here and we also have the part of that video where in we identified the quadrant of each given points on the Cartesian plane and right now our topic today is
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all about plotting of points I will link I will put the links are in description box
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you're more on about Cartesian plane so without further Ado let's do this topic we are asked here to plot the following
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points we have here five different given points or ordered pairs
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okay about identifying the quadrant because it will help you to easily identify consang Cartesian plane located in Union points so let's say for example
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[Music] 5 comma 3 since 5 comma tree are both positive and positive meaning the location of that is here starting
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quadrant number one points compensating you guys you aren't in Cartesian plane are you adding ordered pair and Kanye
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um format talaga is X comma why see
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this is your X and this is your y if 5 is equal to X
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meaning you will go through the x axis over is five or positive 5 starting x axis and definitely it is located here
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it's a right side okay next nothing
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if your Y is equal to 3 or positive 3 you will go through the y axis and an Optimum positive three now is
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simply draw a line here I will show you step by step process until
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magnitude perpendicular lines between five from x-axis and three from y-axis and definitely adding at implotted Point
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okay I think nothing plotted point and to help you understand it well I also just so we have here five
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comma three for that point okay next let's move on with item number two for number number two we have negative
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five gamma 2. vertical non-broken lines okay I just showed you uh the basic way on how to do it pero let's try without the broken lines negative five comma two
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this is her ex and this is her why since your X is negative 5 then your Y is negative 2 I your Y is
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positive two hundred b n quadrant number two so start with negative five negative five Tata is
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so this is your negative five comma two okay negative five comma two
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okay next let's move on with number three number three are both negative we have negative one and negative three so dito since the two
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ordered pairs or the two coordinates are both negative quadrant number three start with this this is for x at the end negative one
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Dot here Y is negative three from here
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[Music] negative three and here's the location of negative one comma 3.
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comma negative three yeah next number four so for number four we have this four and
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negative two so dito positive V on X here Y is negative this is definitely the quadrant number four okay
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four so x axis the right side as a positive you have year four and then since your Y is negative 2 from here we will go down
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two units one and two so this is the location of four
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and negative two all right guys I hope so for first for example is not an concept now let's move on with item number five
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for number five you have zero comma negative three
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either X or Y and Nasha it belongs to the axis located
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and x-axis
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now a negative 3 and why nothing we will go down three units one and two one two and three negative three
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this is the point your X is zero x axis start here sex axis then since your Y is negative
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three you will go to the units one two and three and here is the location of zero comma negative three
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so I hope guys you learned something from this video on how to plot points on partition plane so again guys if you're new to my channel don't forget to like And subscribe button hit the Bell button
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for you to be updated starting latest uploads again it's me teacher gone foreign
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we saw how we could find the length of a line which was neither parallel to the xaxis not parallel to the Y AIS but the procedure to find the length was a bit
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lengthy to avoid repeating the same procedure again we can generalize the formula to find the length of such a
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line let one of the end points be a X1 comma y1 and B X2 comma Y 2
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to get the length of ab we need to form a triangle in which ab is the hypotenuse so we drop a perpendicular to
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the x- axis and then draw another perpendicular to BC so the coordinates of Point D would be X2 comma
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y1 X2 will be here on the x axis and y1 will be here on the Y AIS now we find the length of a and b BD and then use Pythagoras Theorem to find
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the length of ab since BD is parallel to the Y AIS it will equal the absolute value of Y2 minus
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y1 and since a d is parallel to the x- axis it will equal absolute value of X2 -
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X1 using the Pythagoras theorem in this triangle we get ab 2 = a^ 2 + BD
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squ substituting these values the expression will equal X2 - X1 the whole 2 plus Y2 - y1 the whole SAR so length
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of ab will be the square root of the addition of these two now the formula has been generalized all we need to know is the coordinates of the two end points and we can just
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feed it into this formula notice that X1 and and y1 are coordinates of point a and X2 and Y2 are
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coordinates of point B this by the way is called the distance formula let's zoom out to understand a special case of the distance
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formula if we have a line like this which starts from the origin then the formula gets simpler let the coordinates
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of point a be X comma y the coordinates
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of the origin are Z 0a 0 in this case X2
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Y2 are x y and X1 y1 are 0 comma 0 so using the distance formula we get
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the length of O A as the square < TK of x - 0 the whole 2 + y - 0 the whole 2
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that would equal Square < TK of X2 + y^ 2 if the line segment starts from the origin its length will be the square
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root of X2 + Y 2 where X and Y are the coordinates of the other end [Music]
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hello everyone a very very good evening so how are you all doing yes so who all we have here sunali nayak ujjwal
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gungun mohit hiya radhya excited yes i am excited too goongoon yes yes nagendra
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sonali good evening ayush hi tanusha hi es nagendra yes good evening sonali
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all right all right hi yashwee kavyash abhirami satheesh good evening hi nitin yes
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hey ritu good evening uh
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yes very excited uh for the last session of this chapter wow wow wow i'm so glad that you all are liking these sessions and you're so excited for this session perfectly visible and
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audible all right awesome so there is no glitch at all so we can start so my name is khushboo and a very very warm welcome to yet another wonderful session so what are we going to learn today uh as you
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can see the title of the video that's rational numbers but we have already studied rational numbers so what are we going to learn today love this platform and this session thank you
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hi tech game i am doing really well thank you yes so what are we going to learn in this session because we have already studied rational numbers yes revision so we studied rational numbers in different
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different sessions right it was bifurcated in separate different sessions so what we will do is whatever you learned in those sessions we are going to learn all that in just one session so a quick revision of this
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chapter so whomsoever has missed the previous session now it's a good time for you to do the quick revision with me yes yes today we will revise and you can note down the important points wherever
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you feel because trust me the notes that you make while learning any concepts these are very fruitful before your exam day right all right all right so let's get started
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yes are you all ready yes so important questions as well some good questions also we'll be solving right all right yes absolutely it's going to be very
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useful all right all right so let's get started so before i start this session let me just quickly take you through the all the topics that i'm going to cover today so the journey for today's session so first we will i'll give you a quick
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introduction then we will discuss the properties of rational numbers followed by distributivity of rational numbers and then we will quickly discuss how to represent rational numbers on the number line and we will end this session by
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discussing how to find rational number between any two rational numbers yes yes absolutely yes we after this session you all will be pro in rational numbers i'm
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pretty sure about that right right neha thank you all right so let's get started but before that please please subscribe the channel if you haven't yet because you
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will keep getting notifications about the upcoming sessions right all right i hope that all of you have subscribed the channel yes
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wow super excited yay all right all right so let's get started so first as i said i'll be discussing all these topics one by one right so first we will start off with the
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introduction a quick introduction about the rational numbers yes i can see that everybody's like already subscribed wow that's amazing all right so let's get started first let me give you a quick introduction about
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the rational numbers so you can see these two kids over here right and there's a tree which has got apples on it so the smart kid is asking the other one can you count the number of apples on the ground
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the other one says oh wow that's really simple there are one two three three apples that we can see here right so it's really simple for anyone for anybody would be able to count it out right
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so here now the other kid says but wait tell me how are we going to distribute these three apples between us only three apples so the smart kid is saying we can
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keep one apple each and the remaining one apple we can cut into two equal pieces so what does that mean each one of one of them is basically going to get one and a half piece of apple right so the other one says this doesn't look
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like an integer right he's absolutely right so he's asking can we write such numbers on the number line which we just discussed he's talking about those those numbers at one and a half the smart kid says yes
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absolutely we can do that now he's going to explain him how we can show them on the number line yes any doubts absolutely that's 1.5 one and a half it's 1.5 only right
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all right all right so he says all right so since it is one and a half one and a half means each one as you said it's 1.5 it's going to lie between one and two so let's zoom in between these two integers one and two
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i know kriti i'll answer to that question don't worry all right so between one and two we can see here that let's zoom in so here is one here is two what you can see here is
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that there's so many numbers so many numbers in between one and two right and as i said one and a half lies in the middle of one and two which is nothing but that's 15 by 10 over here now you
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might be thinking ma'am you said one and a half and here you are showing 15 by 10 what is it actually and similarly this kid is also confused he says oh it means we can represent any rational number on the number line because you can see there are so many rational numbers on
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the number line any rational number can be represented that means so what are ration numbers actually basically these can be written in the p by q form when i'm saying p by q your p and q are
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basically integers where q cannot be equal to 0 please remember this thing that denominator of a rational number cannot be 0 yes right all right so like let's take some
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examples like we have minus 1 by 2 minus 1 by 4 1 by 4 1 by 2 these all are nothing but these are rational numbers only right all right all right
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so the number that i showed you that was 15 by 10 but we were talking about how to distribute one and a half apple between the two between the two kids right so this one and a half and fifteen by ten are those both them both of them
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the same thing yes because there is something called standard form in rational numbers so rational numbers are in standard form where p and q have no common factors right and the denominator will be a
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positive integer when i'm talking about 15 by 10 this is not in the standard form because because as i said this is representing q p and this is representing q they should have nothing
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common between them no common factor i can reduce this this is 5 times 3 it is 5 times 2 this is 3 by 2 this is the standard form for this rational number right and if you divide it if you try to
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convert that in mixed fraction it's going to be one and a half only right yes absolutely lowest term so nali standard form lowest term or you can say
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reducing it they all mean the same thing yes
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wow your maths examples today are so how was it so that's what i'm explaining the standard form when i'm saying standard form you have to reduce it to the lowest form so that
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there is nothing common between the numerator and the denominator i hope standard form is clear to everyone now quickly give me thumbs up smileys if this is clear to you yes
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thank you astha wow amazing that's nice pritisha no mentee today no no no we are just we're doing a quick revision of the entire chapter that we have covered
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