marcelohaps/translated_sql · Datasets at Hugging Face

Unnamed: 0 int64 0 78.6k	answer stringlengths 18 557	question stringlengths 12 244	context stringlengths 27 489	translated_answer stringlengths 12 992
300	SELECT billing_country, COUNT() FROM invoices GROUP BY billing_country ORDER BY COUNT() DESC LIMIT 5	A list of the top 5 countries by number of invoices. List country name and number of invoices.	CREATE TABLE invoices (billing_country VARCHAR)	Uma lista dos 5 principais países por número de faturas. Listar o nome do país e número de faturas.
301	SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8	A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.	CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)	Uma lista dos 8 principais países pelo tamanho bruto/total da fatura. Listar o nome do país e o tamanho bruto da fatura.
302	SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10	A list of the top 10 countries by average invoice size. List country name and average invoice size.	CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)	Uma lista dos 10 principais países pelo tamanho médio da fatura. Listar o nome do país e o tamanho médio da fatura.
303	SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5	Find out 5 customers who most recently purchased something. List customers' first and last name.	CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR, invoice_date VARCHAR)	Descubra 5 clientes que mais recentemente compraram algo. Liste o primeiro e o último nome dos clientes.
304	SELECT T1.first_name, T1.last_name, COUNT() FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT() DESC LIMIT 10	Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.	CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)	Descubra os 10 melhores clientes pelo número total de pedidos. Liste o primeiro e o último nome dos clientes e o número total de pedidos.
305	SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10	List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.	CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR)	Liste os 10 principais clientes pelo total de vendas brutas. Liste o primeiro e o último nome dos clientes e o total de vendas brutas.
306	SELECT T1.name, COUNT() FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT() DESC LIMIT 5	List the top 5 genres by number of tracks. List genres name and total tracks.	CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)	Liste os 5 principais gêneros por número de faixas. Liste o nome dos gêneros e o total de faixas.
307	SELECT title FROM albums	List every album's title.	CREATE TABLE albums (title VARCHAR)	Liste o título de cada álbum.
308	SELECT title FROM albums ORDER BY title	List every album ordered by album title in ascending order.	CREATE TABLE albums (title VARCHAR)	Liste todos os álbuns ordenados pelo título do álbum em ordem crescente.
309	SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title	List every album whose title starts with A in alphabetical order.	CREATE TABLE albums (title VARCHAR)	Listar todos os álbuns cujo título começa com A em ordem alfabética.
310	SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10	List the customers first and last name of 10 least expensive invoices.	CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)	Liste o primeiro e o último nome dos clientes de 10 faturas menos caras.
311	SELECT SUM(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"	List total amount of invoice from Chicago, IL.	CREATE TABLE invoices (total INTEGER, billing_city VARCHAR, billing_state VARCHAR)	Liste o valor total da fatura de Chicago, IL.
312	SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"	List the number of invoices from Chicago, IL.	CREATE TABLE invoices (billing_city VARCHAR, billing_state VARCHAR)	Liste o número de faturas de Chicago, IL.
313	SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state	List the number of invoices from the US, grouped by state.	CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)	Liste o número de faturas dos EUA, agrupadas por estado.
314	SELECT billing_state, COUNT() FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT() DESC LIMIT 1	List the state in the US with the most invoices.	CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)	Liste o estado dos EUA com o maior número de faturas.
315	SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = "CA"	List the number of invoices and the invoice total from California.	CREATE TABLE invoices (billing_state VARCHAR, total INTEGER)	Liste o número de faturas e o total da fatura da Califórnia.
316	SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"	List Aerosmith's albums.	CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)	Listar álbuns do Aerosmith.
317	SELECT COUNT(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"	How many albums does Billy Cobham has?	CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (artist_id VARCHAR)	Quantos álbuns Billy Cobham tem?
318	SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"	Eduardo Martins is a customer at which company?	CREATE TABLE customers (company VARCHAR, first_name VARCHAR, last_name VARCHAR)	Eduardo Martins é um cliente em que empresa?
319	SELECT email, phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"	What is Astrid Gruber's email and phone number?	CREATE TABLE customers (email VARCHAR, phone VARCHAR, first_name VARCHAR, last_name VARCHAR)	O que é o e-mail e número de telefone da Astrid Gruber?
320	SELECT COUNT(*) FROM customers WHERE city = "Prague"	How many customers live in Prague city?	CREATE TABLE customers (city VARCHAR)	Quantos clientes vivem na cidade de Praga?
321	SELECT COUNT(*) FROM customers WHERE state = "CA"	How many customers in state of CA?	CREATE TABLE customers (state VARCHAR)	Quantos clientes estão no estado da Califórnia?
322	SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"	What country does Roberto Almeida live?	CREATE TABLE customers (country VARCHAR, first_name VARCHAR, last_name VARCHAR)	Que país vive Roberto Almeida?
323	SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'	List the name of albums that are released by aritist whose name has 'Led'	CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)	Listar o nome dos álbuns que são lançados por aritist cujo nome tem "Led"
324	SELECT COUNT(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"	How many customers does Steve Johnson support?	CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)	Quantos clientes o Steve Johnson oferece?
325	SELECT title, phone, hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"	What is the title, phone and hire date of Nancy Edwards?	CREATE TABLE employees (title VARCHAR, phone VARCHAR, hire_date VARCHAR, first_name VARCHAR, last_name VARCHAR)	Qual é o título, telefone e data de aluguer de Nancy Edwards?
326	SELECT T2.first_name, T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"	find the full name of employees who report to Nancy Edwards?	CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, reports_to VARCHAR)	encontrar o nome completo dos funcionários que se reportam a Nancy Edwards?
327	SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"	What is the address of employee Nancy Edwards?	CREATE TABLE employees (address VARCHAR, first_name VARCHAR, last_name VARCHAR)	Qual é o endereço da funcionária Nancy Edwards?
328	SELECT T1.first_name, T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1	Find the full name of employee who supported the most number of customers.	CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)	Encontre o nome completo do funcionário que deu suporte ao maior número de clientes.
329	SELECT COUNT(*) FROM employees WHERE country = "Canada"	How many employees are living in Canada?	CREATE TABLE employees (country VARCHAR)	Quantos funcionários vivem no Canadá?
330	SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"	What is employee Nancy Edwards's phone number?	CREATE TABLE employees (phone VARCHAR, first_name VARCHAR, last_name VARCHAR)	Qual é o número de telefone da empregada Nancy Edwards?
331	SELECT first_name, last_name FROM employees ORDER BY birth_date DESC LIMIT 1	Who is the youngest employee in the company? List employee's first and last name.	CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, birth_date VARCHAR)	Quem é o funcionário mais jovem da empresa? Liste o primeiro e o último nome do funcionário.
332	SELECT first_name, last_name FROM employees ORDER BY hire_date LIMIT 10	List top 10 employee work longest in the company. List employee's first and last name.	CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, hire_date VARCHAR)	Liste os 10 melhores funcionários que trabalham mais na empresa. Liste o primeiro e o último nome do funcionário.
333	SELECT COUNT(*), city FROM employees WHERE title = 'IT Staff' GROUP BY city	Find the number of employees whose title is IT Staff from each city?	CREATE TABLE employees (city VARCHAR, title VARCHAR)	Encontre o número de funcionários cujo título é Equipe de TI de cada cidade?
334	SELECT T2.first_name, T2.last_name, COUNT(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY COUNT(T1.reports_to) DESC LIMIT 1	Which employee manage most number of peoples? List employee's first and last name, and number of people report to that employee.	CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE employees (reports_to VARCHAR)	Qual funcionário gerencia o maior número de pessoas? Liste o primeiro e o último nome do funcionário e o número de pessoas que se reportam a esse funcionário.
335	SELECT COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"	How many orders does Lucas Mancini has?	CREATE TABLE invoices (customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)	Quantas encomendas tem Lucas Mancini?
336	SELECT SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"	What is the total amount of money spent by Lucas Mancini?	CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)	Qual é a quantidade total de dinheiro gasto por Lucas Mancini?
337	SELECT name FROM media_types	List all media types.	CREATE TABLE media_types (name VARCHAR)	Liste todos os tipos de mídia.
338	SELECT DISTINCT name FROM genres	List all different genre types.	CREATE TABLE genres (name VARCHAR)	Liste todos os tipos de gênero diferentes.
339	SELECT name FROM playlists	List the name of all playlist.	CREATE TABLE playlists (name VARCHAR)	Liste o nome de todas as listas de reprodução.
340	SELECT composer FROM tracks WHERE name = "Fast As a Shark"	Who is the composer of track Fast As a Shark?	CREATE TABLE tracks (composer VARCHAR, name VARCHAR)	Quem é o compositor da faixa Fast As a Shark?
341	SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark"	How long does track Fast As a Shark has?	CREATE TABLE tracks (milliseconds VARCHAR, name VARCHAR)	Quanto tempo dura o Fast As a Shark?
342	SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock"	What is the name of tracks whose genre is Rock?	CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)	Qual é o nome das faixas cujo gênero é Rock?
343	SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall"	What is title of album which track Balls to the Wall belongs to?	CREATE TABLE tracks (genre_id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)	Qual é o título do álbum a que a faixa Balls to the Wall pertence?
344	SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall"	List name of all tracks in Balls to the Wall.	CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR); CREATE TABLE albums (id VARCHAR, title VARCHAR)	Listar o nome de todas as faixas em Balls to the Wall.
345	SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING COUNT(T1.id) > 10	List title of albums have the number of tracks greater than 10.	CREATE TABLE tracks (album_id VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)	O título da lista de álbuns tem o número de faixas maiores que 10.
346	SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file"	List the name of tracks belongs to genre Rock and whose media type is MPEG audio file.	CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)	Listar o nome das faixas pertence ao gênero Rock e cujo tipo de mídia é arquivo de áudio MPEG.
347	SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file"	List the name of tracks belongs to genre Rock or media type is MPEG audio file.	CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)	Listar o nome das faixas pertence ao gênero Rock ou tipo de mídia é arquivo de áudio MPEG.
348	SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz"	List the name of tracks belongs to genre Rock or genre Jazz.	CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)	Listar o nome das faixas pertence ao gênero Rock ou gênero Jazz.
349	SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies"	List the name of all tracks in the playlists of Movies.	CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)	Liste o nome de todas as faixas nas listas de reprodução de Filmes.
350	SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING COUNT(T1.track_id) > 100	List the name of playlist which has number of tracks greater than 100.	CREATE TABLE playlist_tracks (playlist_id VARCHAR, track_id VARCHAR); CREATE TABLE playlists (name VARCHAR, id VARCHAR)	Listar o nome da lista de reprodução que tem número de faixas superior a 100.
351	SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters"	List all tracks bought by customer Daan Peeters.	CREATE TABLE invoices (id VARCHAR, customer_id VARCHAR); CREATE TABLE invoice_lines (track_id VARCHAR, invoice_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)	Listar todas as faixas compradas pelo cliente Daan Peeters.
352	SELECT unit_price FROM tracks WHERE name = "Fast As a Shark"	How much is the track Fast As a Shark?	CREATE TABLE tracks (unit_price VARCHAR, name VARCHAR)	Quanto é a faixa Fast As a Shark?
353	SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'	Find the name of tracks which are in Movies playlist but not in music playlist.	CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)	Encontre o nome das faixas que estão na lista de reprodução de filmes, mas não na lista de reprodução de música.
354	SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'	Find the name of tracks which are in both Movies and music playlists.	CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)	Encontre o nome das faixas que estão nas listas de reprodução de filmes e músicas.
355	SELECT COUNT(*), T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name	Find number of tracks in each genre?	CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)	Encontrar o número de faixas em cada gênero?
356	SELECT COUNT(*) FROM editor	How many editors are there?	CREATE TABLE editor (Id VARCHAR)	Quantos editores existem?
357	SELECT Name FROM editor ORDER BY Age	List the names of editors in ascending order of age.	CREATE TABLE editor (Name VARCHAR, Age VARCHAR)	Listar os nomes dos editores em ordem crescente de idade.
358	SELECT Name, Age FROM editor	What are the names and ages of editors?	CREATE TABLE editor (Name VARCHAR, Age VARCHAR)	Quais são os nomes e idades dos editores?
359	SELECT Name FROM editor WHERE Age > 25	List the names of editors who are older than 25.	CREATE TABLE editor (Name VARCHAR, Age INTEGER)	Listar os nomes dos editores com mais de 25 anos.
360	SELECT Name FROM editor WHERE Age = 24 OR Age = 25	Show the names of editors of age either 24 or 25.	CREATE TABLE editor (Name VARCHAR, Age VARCHAR)	Mostre os nomes dos editores de idade 24 ou 25.
361	SELECT Name FROM editor ORDER BY Age LIMIT 1	What is the name of the youngest editor?	CREATE TABLE editor (Name VARCHAR, Age VARCHAR)	Qual é o nome do editor mais jovem?
362	SELECT Age, COUNT(*) FROM editor GROUP BY Age	What are the different ages of editors? Show each age along with the number of editors of that age.	CREATE TABLE editor (Age VARCHAR)	Quais são as diferentes idades dos editores? Mostre cada idade junto com o número de editores dessa idade.
363	SELECT Age FROM editor GROUP BY Age ORDER BY COUNT(*) DESC LIMIT 1	Please show the most common age of editors.	CREATE TABLE editor (Age VARCHAR)	Por favor, mostre a idade mais comum dos editores.
364	SELECT DISTINCT Theme FROM journal	Show the distinct themes of journals.	CREATE TABLE journal (Theme VARCHAR)	Mostre os temas distintos dos periódicos.
365	SELECT T2.Name, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID	Show the names of editors and the theme of journals for which they serve on committees.	CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)	Mostre os nomes dos editores e o tema das revistas para as quais eles servem em comitês.
366	SELECT T2.Name, T2.age, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY T3.Theme	Show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme.	CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, age VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)	Mostrar os nomes e idades dos editores e o tema dos periódicos para os quais atuam em comitês, em ordem alfabética ascendente do tema.
367	SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000	Show the names of editors that are on the committee of journals with sales bigger than 3000.	CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Journal_ID VARCHAR, Sales INTEGER)	Mostre os nomes dos editores que estão no comitê de periódicos com vendas maiores que 3000.
368	SELECT T1.editor_id, T1.Name, COUNT(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id	Show the id, name of each editor and the number of journal committees they are on.	CREATE TABLE editor (editor_id VARCHAR, Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)	Mostre o ID, o nome de cada editor e o número de comitês de periódicos em que estão.
369	SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT(*) >= 2	Show the names of editors that are on at least two journal committees.	CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)	Mostre os nomes dos editores que estão em pelo menos dois comitês de periódicos.
370	SELECT Name FROM editor WHERE NOT editor_id IN (SELECT editor_id FROM journal_committee)	List the names of editors that are not on any journal committee.	CREATE TABLE editor (Name VARCHAR, editor_id VARCHAR); CREATE TABLE journal_committee (Name VARCHAR, editor_id VARCHAR)	Liste os nomes dos editores que não estão em nenhum comitê de periódicos.
371	SELECT date, theme, sales FROM journal EXCEPT SELECT T1.date, T1.theme, T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID	List the date, theme and sales of the journal which did not have any of the listed editors serving on committee.	CREATE TABLE journal_committee (journal_ID VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR, journal_ID VARCHAR)	Liste a data, o tema e as vendas da revista que não tinha nenhum dos editores listados servindo no comitê.
372	SELECT AVG(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo'	What is the average sales of the journals that have an editor whose work type is 'Photo'?	CREATE TABLE journal_committee (journal_ID VARCHAR, work_type VARCHAR); CREATE TABLE journal (sales INTEGER, journal_ID VARCHAR)	Qual é a média de vendas dos periódicos que têm um editor cujo tipo de trabalho é 'Foto'?
373	SELECT COUNT(*) FROM Accounts	How many accounts do we have?	CREATE TABLE Accounts (Id VARCHAR)	Quantas contas temos?
374	SELECT account_id, customer_id, account_name FROM Accounts	Show ids, customer ids, names for all accounts.	CREATE TABLE Accounts (account_id VARCHAR, customer_id VARCHAR, account_name VARCHAR)	Mostre IDs, IDs de clientes, nomes para todas as contas.
375	SELECT other_account_details FROM Accounts WHERE account_name = "338"	Show other account details for account with name 338.	CREATE TABLE Accounts (other_account_details VARCHAR, account_name VARCHAR)	Mostrar outros detalhes da conta com o nome 338.
376	SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162"	What is the first name, last name, and phone of the customer with account name 162?	CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR, account_name VARCHAR)	Qual é o primeiro nome, sobrenome e telefone do cliente com o nome da conta 162?
377	SELECT COUNT(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"	How many accounts does the customer with first name Art and last name Turcotte have?	CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)	Quantas contas tem o cliente com o primeiro nome Art e o último nome Turcotte?
378	SELECT customer_id, COUNT(*) FROM Accounts GROUP BY customer_id	Show all customer ids and the number of accounts for each customer.	CREATE TABLE Accounts (customer_id VARCHAR)	Mostrar todos os IDs de clientes e o número de contas para cada cliente.
379	SELECT customer_id, COUNT() FROM Accounts GROUP BY customer_id ORDER BY COUNT() DESC LIMIT 1	Show the customer id and number of accounts with most accounts.	CREATE TABLE Accounts (customer_id VARCHAR)	Mostre o ID do cliente e o número de contas com a maioria das contas.
380	SELECT T2.customer_first_name, T2.customer_last_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1	What is the customer first, last name and id with least number of accounts.	CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)	Qual é o primeiro, último nome e ID do cliente com o menor número de contas?
381	SELECT COUNT(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Accounts)	Show the number of all customers without an account.	CREATE TABLE Customers (customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR)	Mostre o número de todos os clientes sem uma conta.
382	SELECT customer_first_name, customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id	Show the first names and last names of customers without any account.	CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR)	Mostre os primeiros nomes e sobrenomes dos clientes sem qualquer conta.
383	SELECT DISTINCT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id	Show distinct first and last names for all customers with an account.	CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)	Mostre nomes próprios e sobrenomes distintos para todos os clientes com uma conta.
384	SELECT COUNT(DISTINCT customer_id) FROM Accounts	How many customers have an account?	CREATE TABLE Accounts (customer_id VARCHAR)	Quantos clientes têm uma conta?
385	SELECT COUNT(*) FROM Customers	How many customers do we have?	CREATE TABLE Customers (Id VARCHAR)	Quantos clientes temos?
386	SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM Customers	Show ids, first names, last names, and phones for all customers.	CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR)	Mostre IDs, primeiros nomes, sobrenomes e telefones para todos os clientes.
387	SELECT customer_phone, customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest"	What is the phone and email for customer with first name Aniyah and last name Feest?	CREATE TABLE Customers (customer_phone VARCHAR, customer_email VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)	Qual é o telefone e e-mail para o cliente com o primeiro nome Aniyah e sobrenome Feest?
388	SELECT COUNT(*) FROM Customers_cards	Show the number of customer cards.	CREATE TABLE Customers_cards (Id VARCHAR)	Mostre o número de cartões de cliente.
389	SELECT card_id, customer_id, card_type_code, card_number FROM Customers_cards	Show ids, customer ids, card type codes, card numbers for all cards.	CREATE TABLE Customers_cards (card_id VARCHAR, customer_id VARCHAR, card_type_code VARCHAR, card_number VARCHAR)	Mostrar IDs, IDs de clientes, códigos de tipo de cartão, números de cartão para todos os cartões.
390	SELECT date_valid_from, date_valid_to FROM Customers_cards WHERE card_number = "4560596484842"	Show the date valid from and the date valid to for the card with card number '4560596484842'.	CREATE TABLE Customers_cards (date_valid_from VARCHAR, date_valid_to VARCHAR, card_number VARCHAR)	Mostrar a data válida de e a data válida para o cartão com o número de cartão '4560596484842'.
391	SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842"	What is the first name, last name, and phone of the customer with card 4560596484842.	CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Customers_cards (customer_id VARCHAR, card_number VARCHAR)	Qual é o primeiro nome, sobrenome e telefone do cliente com o cartão 45605964842.
392	SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"	How many cards does customer Art Turcotte have?	CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)	Quantos cartões tem a Art Turcotte?
393	SELECT COUNT(*) FROM Customers_cards WHERE card_type_code = "Debit"	How many debit cards do we have?	CREATE TABLE Customers_cards (card_type_code VARCHAR)	Quantos cartões de débito temos?
394	SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit"	How many credit cards does customer Blanche Huels have?	CREATE TABLE Customers_cards (customer_id VARCHAR, card_type_code VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)	Quantos cartões de crédito o cliente Blanche Huels tem?
395	SELECT customer_id, COUNT(*) FROM Customers_cards GROUP BY customer_id	Show all customer ids and the number of cards owned by each customer.	CREATE TABLE Customers_cards (customer_id VARCHAR)	Mostre todos os IDs de clientes e o número de cartões de propriedade de cada cliente.
396	SELECT customer_id, COUNT() FROM Customers_cards GROUP BY customer_id ORDER BY COUNT() DESC LIMIT 1	What is the customer id with most number of cards, and how many does he have?	CREATE TABLE Customers_cards (customer_id VARCHAR)	Qual é o ID do cliente com o maior número de cartões, e quantos ele tem?
397	SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) >= 2	Show id, first and last names for all customers with at least two cards.	CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)	Mostrar identificação, primeiro e último nome para todos os clientes com pelo menos dois cartões.
398	SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1	What is the customer id, first and last name with least number of accounts.	CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)	Qual é o ID do cliente, primeiro e último nome com o menor número de contas?
399	SELECT card_type_code, COUNT(*) FROM Customers_cards GROUP BY card_type_code	Show all card type codes and the number of cards in each type.	CREATE TABLE Customers_cards (card_type_code VARCHAR)	Mostrar todos os códigos de tipo de cartão e o número de cartões em cada tipo.

300

SELECT billing_country, COUNT(*) FROM invoices GROUP BY billing_country ORDER BY COUNT(*) DESC LIMIT 5

A list of the top 5 countries by number of invoices. List country name and number of invoices.

CREATE TABLE invoices (billing_country VARCHAR)

Uma lista dos 5 principais países por número de faturas. Listar o nome do país e número de faturas.

301

SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8

A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.

CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)

Uma lista dos 8 principais países pelo tamanho bruto/total da fatura. Listar o nome do país e o tamanho bruto da fatura.

302

SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10

A list of the top 10 countries by average invoice size. List country name and average invoice size.

CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)

Uma lista dos 10 principais países pelo tamanho médio da fatura. Listar o nome do país e o tamanho médio da fatura.

303

SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5

Find out 5 customers who most recently purchased something. List customers' first and last name.

CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR, invoice_date VARCHAR)

Descubra 5 clientes que mais recentemente compraram algo. Liste o primeiro e o último nome dos clientes.

304

SELECT T1.first_name, T1.last_name, COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10

Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.

CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)

Descubra os 10 melhores clientes pelo número total de pedidos. Liste o primeiro e o último nome dos clientes e o número total de pedidos.

305

SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10

List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.

CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR)

Liste os 10 principais clientes pelo total de vendas brutas. Liste o primeiro e o último nome dos clientes e o total de vendas brutas.

306

SELECT T1.name, COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 5

List the top 5 genres by number of tracks. List genres name and total tracks.

CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)

Liste os 5 principais gêneros por número de faixas. Liste o nome dos gêneros e o total de faixas.

307

SELECT title FROM albums

List every album's title.

CREATE TABLE albums (title VARCHAR)

Liste o título de cada álbum.

308

SELECT title FROM albums ORDER BY title

List every album ordered by album title in ascending order.

CREATE TABLE albums (title VARCHAR)

Liste todos os álbuns ordenados pelo título do álbum em ordem crescente.

309

SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title

List every album whose title starts with A in alphabetical order.

CREATE TABLE albums (title VARCHAR)

Listar todos os álbuns cujo título começa com A em ordem alfabética.

310

SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10

List the customers first and last name of 10 least expensive invoices.

CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)

Liste o primeiro e o último nome dos clientes de 10 faturas menos caras.

311

SELECT SUM(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"

List total amount of invoice from Chicago, IL.

CREATE TABLE invoices (total INTEGER, billing_city VARCHAR, billing_state VARCHAR)

Liste o valor total da fatura de Chicago, IL.

312

SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"

List the number of invoices from Chicago, IL.

CREATE TABLE invoices (billing_city VARCHAR, billing_state VARCHAR)

Liste o número de faturas de Chicago, IL.

313

SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state

List the number of invoices from the US, grouped by state.

CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)

Liste o número de faturas dos EUA, agrupadas por estado.

314

SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1

List the state in the US with the most invoices.

CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)

Liste o estado dos EUA com o maior número de faturas.

315

SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = "CA"

List the number of invoices and the invoice total from California.

CREATE TABLE invoices (billing_state VARCHAR, total INTEGER)

Liste o número de faturas e o total da fatura da Califórnia.

316

SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"

List Aerosmith's albums.

CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)

Listar álbuns do Aerosmith.

317

SELECT COUNT(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"

How many albums does Billy Cobham has?

CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (artist_id VARCHAR)

Quantos álbuns Billy Cobham tem?

318

SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"

Eduardo Martins is a customer at which company?

CREATE TABLE customers (company VARCHAR, first_name VARCHAR, last_name VARCHAR)

Eduardo Martins é um cliente em que empresa?

319

SELECT email, phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"

What is Astrid Gruber's email and phone number?

CREATE TABLE customers (email VARCHAR, phone VARCHAR, first_name VARCHAR, last_name VARCHAR)

O que é o e-mail e número de telefone da Astrid Gruber?

320

SELECT COUNT(*) FROM customers WHERE city = "Prague"

How many customers live in Prague city?

CREATE TABLE customers (city VARCHAR)

Quantos clientes vivem na cidade de Praga?

321

SELECT COUNT(*) FROM customers WHERE state = "CA"

How many customers in state of CA?

CREATE TABLE customers (state VARCHAR)

Quantos clientes estão no estado da Califórnia?

322

SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"

What country does Roberto Almeida live?

CREATE TABLE customers (country VARCHAR, first_name VARCHAR, last_name VARCHAR)

Que país vive Roberto Almeida?

323

SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'

List the name of albums that are released by aritist whose name has 'Led'

CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)

Listar o nome dos álbuns que são lançados por aritist cujo nome tem "Led"

324

SELECT COUNT(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"

How many customers does Steve Johnson support?

CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)

Quantos clientes o Steve Johnson oferece?

325

SELECT title, phone, hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"

What is the title, phone and hire date of Nancy Edwards?

CREATE TABLE employees (title VARCHAR, phone VARCHAR, hire_date VARCHAR, first_name VARCHAR, last_name VARCHAR)

Qual é o título, telefone e data de aluguer de Nancy Edwards?

326

SELECT T2.first_name, T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"

find the full name of employees who report to Nancy Edwards?

CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, reports_to VARCHAR)

encontrar o nome completo dos funcionários que se reportam a Nancy Edwards?

327

SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"

What is the address of employee Nancy Edwards?

CREATE TABLE employees (address VARCHAR, first_name VARCHAR, last_name VARCHAR)

Qual é o endereço da funcionária Nancy Edwards?

328

SELECT T1.first_name, T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1

Find the full name of employee who supported the most number of customers.

CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)

Encontre o nome completo do funcionário que deu suporte ao maior número de clientes.

329

SELECT COUNT(*) FROM employees WHERE country = "Canada"

How many employees are living in Canada?

CREATE TABLE employees (country VARCHAR)

Quantos funcionários vivem no Canadá?

330

SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"

What is employee Nancy Edwards's phone number?

CREATE TABLE employees (phone VARCHAR, first_name VARCHAR, last_name VARCHAR)

Qual é o número de telefone da empregada Nancy Edwards?

331

SELECT first_name, last_name FROM employees ORDER BY birth_date DESC LIMIT 1

Who is the youngest employee in the company? List employee's first and last name.

CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, birth_date VARCHAR)

Quem é o funcionário mais jovem da empresa? Liste o primeiro e o último nome do funcionário.

332

SELECT first_name, last_name FROM employees ORDER BY hire_date LIMIT 10

List top 10 employee work longest in the company. List employee's first and last name.

CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, hire_date VARCHAR)

Liste os 10 melhores funcionários que trabalham mais na empresa. Liste o primeiro e o último nome do funcionário.

333

SELECT COUNT(*), city FROM employees WHERE title = 'IT Staff' GROUP BY city

Find the number of employees whose title is IT Staff from each city?

CREATE TABLE employees (city VARCHAR, title VARCHAR)

Encontre o número de funcionários cujo título é Equipe de TI de cada cidade?

334

SELECT T2.first_name, T2.last_name, COUNT(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY COUNT(T1.reports_to) DESC LIMIT 1

Which employee manage most number of peoples? List employee's first and last name, and number of people report to that employee.

CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE employees (reports_to VARCHAR)

Qual funcionário gerencia o maior número de pessoas? Liste o primeiro e o último nome do funcionário e o número de pessoas que se reportam a esse funcionário.

335

SELECT COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"

How many orders does Lucas Mancini has?

CREATE TABLE invoices (customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)

Quantas encomendas tem Lucas Mancini?

336

SELECT SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"

What is the total amount of money spent by Lucas Mancini?

CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)

Qual é a quantidade total de dinheiro gasto por Lucas Mancini?

337

SELECT name FROM media_types

List all media types.

CREATE TABLE media_types (name VARCHAR)

Liste todos os tipos de mídia.

338

SELECT DISTINCT name FROM genres

List all different genre types.

CREATE TABLE genres (name VARCHAR)

Liste todos os tipos de gênero diferentes.

339

SELECT name FROM playlists

List the name of all playlist.

CREATE TABLE playlists (name VARCHAR)

Liste o nome de todas as listas de reprodução.

340

SELECT composer FROM tracks WHERE name = "Fast As a Shark"

Who is the composer of track Fast As a Shark?

CREATE TABLE tracks (composer VARCHAR, name VARCHAR)

Quem é o compositor da faixa Fast As a Shark?

341

SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark"

How long does track Fast As a Shark has?

CREATE TABLE tracks (milliseconds VARCHAR, name VARCHAR)

Quanto tempo dura o Fast As a Shark?

342

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock"

What is the name of tracks whose genre is Rock?

CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)

Qual é o nome das faixas cujo gênero é Rock?

343

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall"

What is title of album which track Balls to the Wall belongs to?

CREATE TABLE tracks (genre_id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)

Qual é o título do álbum a que a faixa Balls to the Wall pertence?

344

SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall"

List name of all tracks in Balls to the Wall.

CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR); CREATE TABLE albums (id VARCHAR, title VARCHAR)

Listar o nome de todas as faixas em Balls to the Wall.

345

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING COUNT(T1.id) > 10

List title of albums have the number of tracks greater than 10.

CREATE TABLE tracks (album_id VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)

O título da lista de álbuns tem o número de faixas maiores que 10.

346

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file"

List the name of tracks belongs to genre Rock and whose media type is MPEG audio file.

CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)

Listar o nome das faixas pertence ao gênero Rock e cujo tipo de mídia é arquivo de áudio MPEG.

347

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file"

List the name of tracks belongs to genre Rock or media type is MPEG audio file.

CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)

Listar o nome das faixas pertence ao gênero Rock ou tipo de mídia é arquivo de áudio MPEG.

348

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz"

List the name of tracks belongs to genre Rock or genre Jazz.

CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)

Listar o nome das faixas pertence ao gênero Rock ou gênero Jazz.

349

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies"

List the name of all tracks in the playlists of Movies.

CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)

Liste o nome de todas as faixas nas listas de reprodução de Filmes.

350

SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING COUNT(T1.track_id) > 100

List the name of playlist which has number of tracks greater than 100.

CREATE TABLE playlist_tracks (playlist_id VARCHAR, track_id VARCHAR); CREATE TABLE playlists (name VARCHAR, id VARCHAR)

Listar o nome da lista de reprodução que tem número de faixas superior a 100.

351

SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters"

List all tracks bought by customer Daan Peeters.

CREATE TABLE invoices (id VARCHAR, customer_id VARCHAR); CREATE TABLE invoice_lines (track_id VARCHAR, invoice_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)

Listar todas as faixas compradas pelo cliente Daan Peeters.

352

SELECT unit_price FROM tracks WHERE name = "Fast As a Shark"

How much is the track Fast As a Shark?

CREATE TABLE tracks (unit_price VARCHAR, name VARCHAR)

Quanto é a faixa Fast As a Shark?

353

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

Find the name of tracks which are in Movies playlist but not in music playlist.

CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)

Encontre o nome das faixas que estão na lista de reprodução de filmes, mas não na lista de reprodução de música.

354

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

Find the name of tracks which are in both Movies and music playlists.

CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)

Encontre o nome das faixas que estão nas listas de reprodução de filmes e músicas.

355

SELECT COUNT(*), T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name

Find number of tracks in each genre?

CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)

Encontrar o número de faixas em cada gênero?

356

SELECT COUNT(*) FROM editor

How many editors are there?

CREATE TABLE editor (Id VARCHAR)

Quantos editores existem?

357

SELECT Name FROM editor ORDER BY Age

List the names of editors in ascending order of age.

CREATE TABLE editor (Name VARCHAR, Age VARCHAR)

Listar os nomes dos editores em ordem crescente de idade.

358

SELECT Name, Age FROM editor

What are the names and ages of editors?

CREATE TABLE editor (Name VARCHAR, Age VARCHAR)

Quais são os nomes e idades dos editores?

359

SELECT Name FROM editor WHERE Age > 25

List the names of editors who are older than 25.

CREATE TABLE editor (Name VARCHAR, Age INTEGER)

Listar os nomes dos editores com mais de 25 anos.

360

SELECT Name FROM editor WHERE Age = 24 OR Age = 25

Show the names of editors of age either 24 or 25.

CREATE TABLE editor (Name VARCHAR, Age VARCHAR)

Mostre os nomes dos editores de idade 24 ou 25.

361

SELECT Name FROM editor ORDER BY Age LIMIT 1

What is the name of the youngest editor?

CREATE TABLE editor (Name VARCHAR, Age VARCHAR)

Qual é o nome do editor mais jovem?

362

SELECT Age, COUNT(*) FROM editor GROUP BY Age

What are the different ages of editors? Show each age along with the number of editors of that age.

CREATE TABLE editor (Age VARCHAR)

Quais são as diferentes idades dos editores? Mostre cada idade junto com o número de editores dessa idade.

363

SELECT Age FROM editor GROUP BY Age ORDER BY COUNT(*) DESC LIMIT 1

Please show the most common age of editors.

CREATE TABLE editor (Age VARCHAR)

Por favor, mostre a idade mais comum dos editores.

364

SELECT DISTINCT Theme FROM journal

Show the distinct themes of journals.

CREATE TABLE journal (Theme VARCHAR)

Mostre os temas distintos dos periódicos.

365

SELECT T2.Name, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID

Show the names of editors and the theme of journals for which they serve on committees.

CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)

Mostre os nomes dos editores e o tema das revistas para as quais eles servem em comitês.

366

SELECT T2.Name, T2.age, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY T3.Theme

Show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme.

CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, age VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)

Mostrar os nomes e idades dos editores e o tema dos periódicos para os quais atuam em comitês, em ordem alfabética ascendente do tema.

367

SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000

Show the names of editors that are on the committee of journals with sales bigger than 3000.

CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Journal_ID VARCHAR, Sales INTEGER)

Mostre os nomes dos editores que estão no comitê de periódicos com vendas maiores que 3000.

368

SELECT T1.editor_id, T1.Name, COUNT(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id

Show the id, name of each editor and the number of journal committees they are on.

CREATE TABLE editor (editor_id VARCHAR, Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)

Mostre o ID, o nome de cada editor e o número de comitês de periódicos em que estão.

369

SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT(*) >= 2

Show the names of editors that are on at least two journal committees.

CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)

Mostre os nomes dos editores que estão em pelo menos dois comitês de periódicos.

370

SELECT Name FROM editor WHERE NOT editor_id IN (SELECT editor_id FROM journal_committee)

List the names of editors that are not on any journal committee.

CREATE TABLE editor (Name VARCHAR, editor_id VARCHAR); CREATE TABLE journal_committee (Name VARCHAR, editor_id VARCHAR)

Liste os nomes dos editores que não estão em nenhum comitê de periódicos.

371

SELECT date, theme, sales FROM journal EXCEPT SELECT T1.date, T1.theme, T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID

List the date, theme and sales of the journal which did not have any of the listed editors serving on committee.

CREATE TABLE journal_committee (journal_ID VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR, journal_ID VARCHAR)

Liste a data, o tema e as vendas da revista que não tinha nenhum dos editores listados servindo no comitê.

372

SELECT AVG(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo'

What is the average sales of the journals that have an editor whose work type is 'Photo'?

CREATE TABLE journal_committee (journal_ID VARCHAR, work_type VARCHAR); CREATE TABLE journal (sales INTEGER, journal_ID VARCHAR)

Qual é a média de vendas dos periódicos que têm um editor cujo tipo de trabalho é 'Foto'?

373

SELECT COUNT(*) FROM Accounts

How many accounts do we have?

CREATE TABLE Accounts (Id VARCHAR)

Quantas contas temos?

374

SELECT account_id, customer_id, account_name FROM Accounts

Show ids, customer ids, names for all accounts.

CREATE TABLE Accounts (account_id VARCHAR, customer_id VARCHAR, account_name VARCHAR)

Mostre IDs, IDs de clientes, nomes para todas as contas.

375

SELECT other_account_details FROM Accounts WHERE account_name = "338"

Show other account details for account with name 338.

CREATE TABLE Accounts (other_account_details VARCHAR, account_name VARCHAR)

Mostrar outros detalhes da conta com o nome 338.

376

SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162"

What is the first name, last name, and phone of the customer with account name 162?

CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR, account_name VARCHAR)

Qual é o primeiro nome, sobrenome e telefone do cliente com o nome da conta 162?

377

SELECT COUNT(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"

How many accounts does the customer with first name Art and last name Turcotte have?

CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)

Quantas contas tem o cliente com o primeiro nome Art e o último nome Turcotte?

378

SELECT customer_id, COUNT(*) FROM Accounts GROUP BY customer_id

Show all customer ids and the number of accounts for each customer.

CREATE TABLE Accounts (customer_id VARCHAR)

Mostrar todos os IDs de clientes e o número de contas para cada cliente.

379

SELECT customer_id, COUNT(*) FROM Accounts GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1

Show the customer id and number of accounts with most accounts.

CREATE TABLE Accounts (customer_id VARCHAR)

Mostre o ID do cliente e o número de contas com a maioria das contas.

380

SELECT T2.customer_first_name, T2.customer_last_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1

What is the customer first, last name and id with least number of accounts.

CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)

Qual é o primeiro, último nome e ID do cliente com o menor número de contas?

381

SELECT COUNT(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Accounts)

Show the number of all customers without an account.

CREATE TABLE Customers (customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR)

Mostre o número de todos os clientes sem uma conta.

382

SELECT customer_first_name, customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

Show the first names and last names of customers without any account.

CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR)

Mostre os primeiros nomes e sobrenomes dos clientes sem qualquer conta.

383

SELECT DISTINCT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

Show distinct first and last names for all customers with an account.

CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)

Mostre nomes próprios e sobrenomes distintos para todos os clientes com uma conta.

384

SELECT COUNT(DISTINCT customer_id) FROM Accounts

How many customers have an account?

CREATE TABLE Accounts (customer_id VARCHAR)

Quantos clientes têm uma conta?

385

SELECT COUNT(*) FROM Customers

How many customers do we have?

CREATE TABLE Customers (Id VARCHAR)

Quantos clientes temos?

386

SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM Customers

Show ids, first names, last names, and phones for all customers.

CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR)

Mostre IDs, primeiros nomes, sobrenomes e telefones para todos os clientes.

387

SELECT customer_phone, customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest"

What is the phone and email for customer with first name Aniyah and last name Feest?

CREATE TABLE Customers (customer_phone VARCHAR, customer_email VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)

Qual é o telefone e e-mail para o cliente com o primeiro nome Aniyah e sobrenome Feest?

388

SELECT COUNT(*) FROM Customers_cards

Show the number of customer cards.

CREATE TABLE Customers_cards (Id VARCHAR)

Mostre o número de cartões de cliente.

389

SELECT card_id, customer_id, card_type_code, card_number FROM Customers_cards

Show ids, customer ids, card type codes, card numbers for all cards.

CREATE TABLE Customers_cards (card_id VARCHAR, customer_id VARCHAR, card_type_code VARCHAR, card_number VARCHAR)

Mostrar IDs, IDs de clientes, códigos de tipo de cartão, números de cartão para todos os cartões.

390

SELECT date_valid_from, date_valid_to FROM Customers_cards WHERE card_number = "4560596484842"

Show the date valid from and the date valid to for the card with card number '4560596484842'.

CREATE TABLE Customers_cards (date_valid_from VARCHAR, date_valid_to VARCHAR, card_number VARCHAR)

Mostrar a data válida de e a data válida para o cartão com o número de cartão '4560596484842'.

391

SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842"

What is the first name, last name, and phone of the customer with card 4560596484842.

CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Customers_cards (customer_id VARCHAR, card_number VARCHAR)

Qual é o primeiro nome, sobrenome e telefone do cliente com o cartão 45605964842.

392

SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"

How many cards does customer Art Turcotte have?

CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)

Quantos cartões tem a Art Turcotte?

393

SELECT COUNT(*) FROM Customers_cards WHERE card_type_code = "Debit"

How many debit cards do we have?

CREATE TABLE Customers_cards (card_type_code VARCHAR)

Quantos cartões de débito temos?

394

SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit"

How many credit cards does customer Blanche Huels have?

CREATE TABLE Customers_cards (customer_id VARCHAR, card_type_code VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)

Quantos cartões de crédito o cliente Blanche Huels tem?

395

SELECT customer_id, COUNT(*) FROM Customers_cards GROUP BY customer_id

Show all customer ids and the number of cards owned by each customer.

CREATE TABLE Customers_cards (customer_id VARCHAR)

Mostre todos os IDs de clientes e o número de cartões de propriedade de cada cliente.

396

SELECT customer_id, COUNT(*) FROM Customers_cards GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1

What is the customer id with most number of cards, and how many does he have?

CREATE TABLE Customers_cards (customer_id VARCHAR)

Qual é o ID do cliente com o maior número de cartões, e quantos ele tem?

397

SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) >= 2

Show id, first and last names for all customers with at least two cards.

CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)

Mostrar identificação, primeiro e último nome para todos os clientes com pelo menos dois cartões.

398

SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1

What is the customer id, first and last name with least number of accounts.

CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)

Qual é o ID do cliente, primeiro e último nome com o menor número de contas?

399

SELECT card_type_code, COUNT(*) FROM Customers_cards GROUP BY card_type_code

Show all card type codes and the number of cards in each type.

CREATE TABLE Customers_cards (card_type_code VARCHAR)

Mostrar todos os códigos de tipo de cartão e o número de cartões em cada tipo.